4

Une Marke-inemanaeer0t 3 Maicr grocety store Jelievesthartne prcbabilty purcnase Suppose thartne following rransition probabilities are appropriazecustomer buying o...

Question

Une Marke-inemanaeer0t 3 Maicr grocety store Jelievesthartne prcbabilty purcnase Suppose thartne following rransition probabilities are appropriazecustomer buying one ofthe two major brands ofroothpaste: Calluge and Crasti_ at hiz atore depeno; onthe cusomer} Mos: recen;ErcmCallugeCrasdcalute Cr5nWhich ofthe following the correct two Deriod (res diagram for cuetome Vho Iart purchased Crasti?(0,i08i-04CallupaCllust(03hi0.Z1Crastt(0 71(0.J)-0.21cllugeCrusli(0.71i0.7i-0.49MacannT0_0-8i-0.[6GallueeC

Une Marke-inemanaeer0t 3 Maicr grocety store Jelievesthartne prcbabilty purcnase Suppose thartne following rransition probabilities are appropriaze customer buying one ofthe two major brands ofroothpaste: Calluge and Crasti_ at hiz atore depeno; onthe cusomer} Mos: recen; Ercm Calluge Crasd calute Cr5n Which ofthe following the correct two Deriod (res diagram for cuetome Vho Iart purchased Crasti? (0,i08i-04 Callupa Cllust (03hi0.Z1 Crastt (0 71(0.J)-0.21 clluge Crusli (0.71i0.7i-0.49 Macann T0_0-8i-0.[6 Galluee Calluge (02(0 2-00 Crali Cr 40.81 (03107 Crxi 40.81(071 036 Mmaet (OJi0.-0.09 Cllege Clerr 10.7)-021 MCen (0.7i08 0 36 Ar (0,71(0 % 014 (0 :1(07, 0 14 Callute (0 21(0J)-006 Cdi Cnst "~Calluge (031(0210 [6 C1n Kete Tollute ICallutt



Answers

A large consumer goods company ran a television advertisement for one of its soap prod-
ucts. On the basis of a survey that was conducted, probabilities were assigned to the fol-
lowing events.
\begin{aligned} B &=\text { individual purchased the product } \\ S &=\text { individual recalls seeing the advertisement } \\ B \cap S &=\text { individual purchased the product and recalls seeing the advertisement } \end{aligned}$
$The probabilities assigned were $P(B)=.20, P(S)=.40,$ and $P(B \cap S)=.12$
$\begin{array}{l}{\text { a. What is the probability of an individual's purchasing the product given that the }} \\ {\text { individual recalls seeing the advertisement? Does seeing the advertisement increase }} \\ {\text { the probability that the individual will purchase the product? As a decision maker, }} \\ {\text { would you recommend continuing the advertisement (assuming that the cost is }} \\ {\text { reasonable)? }}\end{array}$
$\begin{array}{l}{\text { b. Assume that individuals who do not purchase the company's soap product buy from }} \\ {\text { its competitors. What would be your estimate of the company's market share? Would }} \\ {\text { you expect that continuing the advertisement will increase the company's market? }} \\ {\text { share? Why or why not? }}\end{array}$
$\begin{array}{l}{\text { c. The company also tested another advertisement and assigned it values of } P(S)=.30} \\ {\text { and } P(B \cap S)=.10 . \text { What is } P(B | S) \text { for this other advertisement? Which advertise- }} \\ {\text { ment seems to have had the bigger effect on customer purchases? }}\end{array}

So this problem is going to be a binomial probability problem because it meets certain characteristics. As we read through it, you're going to find that there are a fixed number of trials. You're going to find that the trials are independent and you're going to see that there are only two outcomes, and we used usually define those outcomes as success and failure. And whenever you're working with binomial probabilities, there are four variables that you are going to work with. The first one is en, which represents the number of trials X, which would be the possible outcomes, or the count's of how Maney successes P, which is the probability of success, and Q, which is the probability of failure. And there's one formula that we're going to use to govern these types of problems. And that is going to be the probability that an event occurs is equal to N. C. X. So our combination notation multiplied by P, raised to the X power multiplied by Q raised to the n minus X power. So let's read through the problem and gather the values of our variables. So, as we read through, it says that there are 68% of adults would still consider a car, Um, brand, despite the problems, the product recalls. So that means we have a P value of 680.68 And if 68% would still consider the cars, regardless of safety recalls, that means there are 32% that would not. You're randomly going to select 20 adults. So our end is going to be 20 throughout this problem. And then we get into the actual questions. And, it says, find the probability that the number of adults who would still consider a car brand despite the safety recalls is and we're going to do part a. And it's exactly one. So we're talking about X being one in this case. So therefore, we're going to say the probability that X equals one will be 20 c one multiplied by 68 raised to the first power multiplied by 0.32 raised to the 20 minus one power and the probability of finding exactly one out of those 20 when you type this into the calculator gives you an answer. In scientific notations, you're going to see 5.387 515 and in most calculators, you're gonna see e negative nine. And it's because our answer is super small that we end up putting it into scientific notation. And what it means is going to be that you're gonna move the decimal 0.9 places to the left and get this probability 0.5387515 So it's very, very, very highly unlikely that when you select 20 random adults Onley, one would consider the car regardless of the product, safety recalls. Now let's look at Part B, and in doing part B, we're going to have to think a little bit differently. So in part B, you want the probability that the number of adults would be more than one. So that means we're focused on the X values off two or three or four or five 678 all the way up to the 20 Now we could apply that formula once using X being too, and then using X being three, and that's gonna take a lot of time and a lot of room for error. So instead we're going to think slightly different. What you're going to think of is what a probability distribution looks like. And the characteristics of that probability distribution. Now a probability distribution is going to list all the possible outcomes and the probability associated with each. So the possible outcomes could have been zero or one or two or three all the way up to 20 people saying they would still purchase the car regardless of the safety recalls. And any time you have a probability distribution, the some of the PX column is going to always be one. Now we're focused on finding the sum of all of these probabilities here. So what we could Dio is if we take one and take away these two probabilities, we will be left with what these probabilities will total up to. So we're going to do is we're gonna do one, take away the probability that there are no people that would consider the cars, regardless of safety recalls. And then we're going to take away the probability off one as well. And then again, you're left with all the rest from 2 to 20. So if we apply the formula for zero, then it would read 20 c zero multiplied by 68 to the zero power multiplied by 0.32 to the 20 minus zero power. And if we put that into the calculator again, you are going to get some scientific notation. You're going to get a 1.268 Chances are it's in engineering notation with E e and you're going to see a negative 10 here. So that means 0.1268 So we can replace the probability of zero with that value, and then we can replace the probability of one with the answer from part A. So now we're getting one. Minus 0.1268 minus 0.5387515 So part B the probability that X is more than one will equal 0.999999994 five and now we're ready to do part ceased. And in part C, The question is asking you if you randomly select 20 adults, what is the probability that you would find at most one. So if we were to translate at most one into the values, it would be the same thing as the probability of zero plus the probability of one. And we have the probability of zero right here. And we have the probability of one right here. So we're going to just add those two values together. Point 123456789 and then 1268 plus. And then we're gonna take the other one point 12345678538 7515 and we're going to get an answer of 0.5514 28 So recapping the three answers If we randomly select 20 adults, what is the probability that the number of adults who would still consider a car brand despite its product recalls is exactly one that's right here is more than one would be right here and at most one is right here

For his part of the question, say that the customer makes a purge ease off less than $20. So this word in glory probability less than $5 place probably between $5.19.99 dollars. So this would be 0.25 plus 0.37 So 0.62 now the second part says probability off dollar 40 or more. So this would be dollar 40 or more. So we can say that this will be one minus, probably less than $40. So one minus probably less than $40 were including force three So one minus 0.25 plus 0.37 plus 0.11 one minus seven plus one is 89 10 11 12 13 3 34567 0.73 So this would be nine then? Oh, then minus three is seven and nine minutes. Evidence to zero point 17 No, the hard part says Probably be off more than dollar 99.99 So more than 99.99 would be the last two rows, so 0.0 plus 0.3 0.1 Woman The fourth parts is probability less then dollar 100 So what would I be? Probably less than a dollar 100 would be one minus probability created. Unequal dollar 100 So one minus greater than equal dollar 100 of the last two rose 0.80 point 03 one minus 0.1 bun 1.0 minus 0.1 when this would give us 98 so zero point.

For this problem part A asks us To know what is the probability of three people buying ovens if we know that the probability of two people buying ovens is 40. So let's write down the information that we already have. We know that the probability of two people Buying Ovens .40. So we want to find the probability of three people mind opens, So we would do 1- the probability of two people buying Evans, which would be one minus 10.4, Which equals .6. For the second problem, we want to know the probability of somebody buying an electric and a gas. This is really simple. We know that the probability of somebody buying an electric over A gas is .007. While the other probability is 1.04 for gas. So all we do is do one that prevalence because we know the probability of that already. And we want to find the probability of actually is selling at least one of each type. So we would end up getting .889


Similar Solved Questions

5 answers
(9) Find x and if the sequence 2y , 2xy ,2 2is geometric
(9) Find x and if the sequence 2y , 2xy ,2 2 is geometric...
5 answers
Provide the major products of the following reactions_ Pay attention to regiospecificity and stereospecifity (2pts each)HClKMnO4 H;O- beal1) NaNIz 2) CH;CH_Br1) BH; 2) H,O_ OH (44)Lindlar'sI;otCorrect namesthe reactants of the above reactions (19-25} willcountmake up points for point losses this examPage
Provide the major products of the following reactions_ Pay attention to regiospecificity and stereospecifity (2pts each) HCl KMnO4 H;O- beal 1) NaNIz 2) CH;CH_Br 1) BH; 2) H,O_ OH (44) Lindlar's I;ot Correct names the reactants of the above reactions (19-25} willcount make up points for point l...
5 answers
Usina Liplcc sokiethe cqualions below: (Hops) L6 " = '0 =+187=0,2(01 = 0,1(0)=1
Usina Liplcc sokiethe cqualions below: (Hops) L6 " = '0 = +187=0,2(01 = 0,1(0)=1...
5 answers
Hydroxide reacts with 12.51 mLof0.160 M potassium Show steps ,as1,23 neutralization reaction (M) of the sulfuric acid? In an acid-L base acid Calculate molarity 12.65 mL of sulfuric 7 KzSO4 2HzO Given: 2KOH HzSO4Step I:
hydroxide reacts with 12.51 mLof0.160 M potassium Show steps ,as1,23 neutralization reaction (M) of the sulfuric acid? In an acid-L base acid Calculate molarity 12.65 mL of sulfuric 7 KzSO4 2HzO Given: 2KOH HzSO4 Step I:...
5 answers
2 Jmo Douynomiataeqivc D(x) eiche[ syntnelc rdiyson(0 apinip Plx)'(rlaexpre 55 In ute3 8 8 3
2 Jmo Douynomiat aeqivc D(x) eiche[ syntnelc r diyson(0 apinip Plx) '(rla expre 55 In ute 3 8 8 3...
5 answers
M: = 5.98x1024kgexample:Determine the orbital radius of a NO geosynchronous satellite. To be above The Same Spot 0 the Earth Gs (t rotates, the safellite Must be In arbit around the equator. Is Ts a possi / 'Lle orbk ?
M: = 5.98x1024kg example: Determine the orbital radius of a NO geosynchronous satellite. To be above The Same Spot 0 the Earth Gs (t rotates, the safellite Must be In arbit around the equator. Is Ts a possi / 'Lle orbk ?...
5 answers
Meet at [ightangles ) of the figure: (Sides Find the area
meet at [ightangles ) of the figure: (Sides Find the area...
5 answers
Let f : [-1,1] = R be continuous with f(0) = 0 such that f is differentiable atJ f(t) dt 0 and f' (0) = 1. Find lim and show your reason: Hint: 170 22 dxf(t) dt = f(c). )
Let f : [-1,1] = R be continuous with f(0) = 0 such that f is differentiable at J f(t) dt 0 and f' (0) = 1. Find lim and show your reason: Hint: 170 22 dx f(t) dt = f(c). )...
5 answers
Given that f(r) = 7r + 2 and g(k) = 3 12 calculate (a) f(9(0)) = (6) g(f(0))=
Given that f(r) = 7r + 2 and g(k) = 3 12 calculate (a) f(9(0)) = (6) g(f(0))=...
5 answers
Find the final height of a concrete column that is $1.250 mathrm{~m} imes 1.250 mathrm{~m} imes 4.250 mathrm{~m}$ at $0.0^{circ} mathrm{C}$ when the column is heated to $45.0^{circ} mathrm{C}$.
Find the final height of a concrete column that is $1.250 mathrm{~m} imes 1.250 mathrm{~m} imes 4.250 mathrm{~m}$ at $0.0^{circ} mathrm{C}$ when the column is heated to $45.0^{circ} mathrm{C}$....
1 answers
The total amount of protein produced by a dairy cow can be estimated from periodic testing of her milk. The following are the total annual protein production values (lb) for twenty-eight 2 -year-old Holstein cows. Diet, milking procedures, and other conditions were the same 15 for all the animals. $\begin{array}{lllllll}425 & 481 & 477 & 434 & 410 & 397 & 438 \\ 545 & 528 & 496 & 502 & 529 & 500 & 465 \\ 539 & 408 & 513 & 496 & 477
The total amount of protein produced by a dairy cow can be estimated from periodic testing of her milk. The following are the total annual protein production values (lb) for twenty-eight 2 -year-old Holstein cows. Diet, milking procedures, and other conditions were the same 15 for all the animals. $...
5 answers
46 Supporc 3 45 moks of An itkal gns expands to twicv its volutne isothcrmnally Al 298 K A) How: nuuch work i5 dom by Ihc pL?B) Sbow thc work douc on prensur(-voluue (P-V) grophWhat ix the change iu Cutropy of the Kn?
46 Supporc 3 45 moks of An itkal gns expands to twicv its volutne isothcrmnally Al 298 K A) How: nuuch work i5 dom by Ihc pL? B) Sbow thc work douc on prensur(-voluue (P-V) groph What ix the change iu Cutropy of the Kn?...
5 answers
Yinbanotnt €eatanCuailon 6HTrctnotTht acctrmnar"Ien WamyWaaicaeeet alinior'0mzaEcurulon al (ne tcp9.4m/2 LSAchIne Dalle In Irtz (lucaktukaHmaaletmmnadNont aftha above conec:Toltn
Yinbanotnt €eatan Cuailon 6 HTrct not Tht acctrmnar"Ien Wamy Waaicaeeet alinior '0mz aEcurulon al (ne tcp 9.4m/2 L SAchIne Dalle In Irtz (l ucaktuka Hmaaletmmnad Nont aftha above conec: Toltn...
5 answers
2. 6 marks) How many ordered quadruples (11, T2,13, 14) of positive integers satisfy the conditions T1 < T2 T3 < T4 < 15 and Ti+l Ti 2 i for each i = 1,2,3.
2. 6 marks) How many ordered quadruples (11, T2,13, 14) of positive integers satisfy the conditions T1 < T2 T3 < T4 < 15 and Ti+l Ti 2 i for each i = 1,2,3....
5 answers
Key A) Keq [NOBr]?/[NO][Brz] b) Keq = [CO][H;]?/[CH;OH] Keq - [02]3 d) Keq= [NH4+'J[OH-'J[NH;] Keq = = [CO]/[02] f) Keq [AI+B][CH-']3B) a) left b) right c) left left e) right f) no affect g left
Key A) Keq [NOBr]?/[NO][Brz] b) Keq = [CO][H;]?/[CH;OH] Keq - [02]3 d) Keq= [NH4+'J[OH-'J[NH;] Keq = = [CO]/[02] f) Keq [AI+B][CH-']3 B) a) left b) right c) left left e) right f) no affect g left...
5 answers
B = 0.922 km, c =0.387 km, A = 43 degrees 10 minutesSolve the Triangle
b = 0.922 km, c =0.387 km, A = 43 degrees 10 minutes Solve the Triangle...

-- 0.023290--