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Aseir stortu has 41cec Pcak - VDt- height 16 4 feet for Waves hitting the shore; Suppose Elont Progtess With serct stomm class rating Let us Say" that Want t0 ...

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Aseir stortu has 41cec Pcak - VDt- height 16 4 feet for Waves hitting the shore; Suppose Elont Progtess With serct stomm class rating Let us Say" that Want t0 sct upa Aateea ifthe #ave action ( € height) dying donn Cetting Worse_[fyou wanted the hypothesis that the Wares &re dying donu; what would you uSC altctnate hypothesis? Is the Value atea ihe ell;tight; or on both sudes of the mcan?ecaUan I6 ATuc Jei the right of = mcdLenlFmalfeeltke P-value ateaLef ofthe meanMicaiccfeel the Laa

Aseir stortu has 41cec Pcak - VDt- height 16 4 feet for Waves hitting the shore; Suppose Elont Progtess With serct stomm class rating Let us Say" that Want t0 sct upa Aateea ifthe #ave action ( € height) dying donn Cetting Worse_[fyou wanted the hypothesis that the Wares &re dying donu; what would you uSC altctnate hypothesis? Is the Value atea ihe ell;tight; or on both sudes of the mcan? ecaUan I6 A Tuc Jei the right of = mcd LenlFmal feeltke P-value atea Lef ofthe mean Micaicc feel the Laae Ancn the npht of thc mean 4 nat equal t0 16 ' tect thic Pvaluc 4ea tghe ofthe tun 16 Iect; tha P-taluc AC4 i the Iefi ofthe mfan Previous DALL Backspace



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Weatherwise magazine is published in association with the American Meteorological Society. Volume $46,$ Number 6 has a rating system to classify Nor'easter storms that frequently hit New England states and can cause much damage near the ocean coast. A severe storm has an average peak wave height of 16.4 feet for waves hitting the shore. Suppose that a Nor'easter is in progress at the severe storm class rating. (a) Let us say that we want to set up a statistical test to see if the wave action (i.e., height) is dying down or getting worse. What would be the null hypothesis regarding average wave height? (b) If you wanted to test the hypothesis that the storm is getting worse, what would you use for the alternate hypothesis? (c) If you wanted to test the hypothesis that the waves are dying down, what would you use for the alternate hypothesis? (d) Suppose you do not know whether the storm is getting worse or dying out. You just want to test the hypothesis that the average wave height is different (either higher or lower) from the severe storm class rating. What would you use for the alternate hypothesis? (e) For each of the tests in parts (b), (c), and (d), would the area corresponding to the $P$ -value be on the left, on the right, or on both sides of the mean? Explain your answer in each case.

In question seven. Here we have to figure out what the P value is for the test of the hypotheses where the slope of the least squares regression line equals zero. When then the alternative hypothesis is that the slope is positive. And so one thing that you want to take note of initially is what the P value is from the computer output table that's been given. And so if you take a look at the column that's labeled with P, and you go to the row that lines up um with the explanatory variable X. And go across there. This P value is the first number you want to take note of, but that's not the answer for this question. That is the answer to the question. If the alternative hypothesis where that beta were not equal to zero, which is a two tailed test. So if that's the answer for a two tails test, and I want to know what the answer for a one tailed test is, I have to take the P value that is given and divide it by two. And so dividing that by two gives me 0006 and so that is the p value for this question, and that gives me answer choice Hey?

Okay, so we are conducting a one tale test at the 1% significance level Arnold hypothesis is that they're the same. And the alternative is that the first is less than the second the computer have statistic is going to be s one squared divided by S two squared. So this turns out to be approximately 0.17 Our degrees of freedom are one less than each of the sample size is making 18 the numerator and 50 the denominator, We can go to the back of the book in table eight to figure out what are critical value is. Since this is a left tail test, our f statistic is going to be f of one minus point to one, which is going to be equal to F of 099 which has a statistic of 2.78 Of course we take the reciprocal of that. This turns out to be approximately 0.36 So for illustration purposes, we have our F curve, whatever it looks like, and 0.36 is going to be somewhere right here, and 0.17 is going to be clearly on this side in the rejection region. Therefore, we reject the null hypothesis at the 1% significance level.

Mhm. So in this case, the Drug Abuse and Resistance Education Program underwent several major changes to keep up the technology and the issues that the students were facing. Now, after all the changes now, there is a school resource officer that think that the proportion of 12 to 17 year olds who have used marijuana in the past six months has decreased. So what would be the null hypothesis the null hypothesis would be then I like hypothesis would be that P is equal to 6.7%. Right, That P is equal to 0.67 And the alternative hypothesis would be the claim of the officer. That P is less than 0.67 which means that he is actually saying that this program is effective. So these would be a null and alternative hypotheses. Now, if the sample data indicate that the null hypothesis should not be rejected, what would the conclusion be then? I like this should not be rejected now. It would mean, uh okay, so after the test is an ally. But this is not rejected. We would say that we do not have. We do not have enough evidence enough evidence to suggest that the proportion of marijuana users users that the proportion off marijuana users in this age group have decreased right. Which means that whatever changes they made to their system, right, whatever changes this program and event, it is not very effective. Okay, now, the party is supposed, in fact, that the proportion of 2017 year olds who have used marijuana is 6.4. Okay, which means that it has actually decreased. But what we did, what we did was we did not reject, right? Uh, yeah, we did not reject the null hypothesis. Have we committed a type one or type two error? Well, the null hypothesis is that P is equal to 6.7% and we have not rejected than the hypothesis, right? Even though the null hypothesis was wrong, even though the true percent is now 6.4% we did not reject the null hypothesis. This means that we have made a type two error a type two ETA. Right? This is going to be the type two error. Why? Whenever you're not hypothesis is wrong. But you failed to reject it. It is always a type tour. These are answers

Okay. Another non full detest at the 1% significance level and it's a two tailed T test. Since we are asked to find if there is a difference, this is going to look like right here, shaded region, they're shaded region there, so we're gonna have 0.5 there And .5 on this side. Okay, So the difference between the two means is going to be 115 -24. Mhm Right, Yeah, and when we get hold up, did I get that right? one, Nope. Mhm. No. Okay, are you gonna square the oh Square the standard deviation of 79 4, divide that by 51. Mhm Yeah. Mhm. And then we add the other square of the standard deviation of 10.5 divided by 19. Mhm Yeah. Mhm And we end up getting a test statistic of 7.98 Yeah. Mhm. People now we need to find out how many degrees of freedom there are, which is going to be given by this beautiful hunk. And formally all Um plugging in those numbers, we end up getting 54° of freedom. Mhm. Now, on the back of the book we will look at the .05 significance level for 54° of freedom. Oh man! Having trouble, find the back of the book. All right. 54 Degrees of Freedom. 2.670. So what we have here Is 2670. Okay. 7.98 is bigger than that. So, at the 1% significance level, we reject the null hypothesis in favor of the alternative. Okay.


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