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PointsTwo cxamples of a hypothesis &1c Ldcan monthly Incomc from all sources for scnior citizens S841 aud 2) tWenty Percent of juvcnile offenders ultunately arc...

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PointsTwo cxamples of a hypothesis &1c Ldcan monthly Incomc from all sources for scnior citizens S841 aud 2) tWenty Percent of juvcnile offenders ultunately arc caught and sentenced PTISOU Hypothcs1s 1esting procedure based On sampl eridence and probahility thcory to dccide whcthcr thc hypothesis Tcasonaolc staltcuncol Sincc theic morc variability Gamole Weans comDulco Hom smalcC "plee Wchac [o confidetice the resulting Estuuales aud are Icss apt t0 [cject null hypothesis_and (4) arc al

points Two cxamples of a hypothesis &1c Ldcan monthly Incomc from all sources for scnior citizens S841 aud 2) tWenty Percent of juvcnile offenders ultunately arc caught and sentenced PTISOU Hypothcs1s 1esting procedure based On sampl eridence and probahility thcory to dccide whcthcr thc hypothesis Tcasonaolc staltcuncol Sincc theic morc variability Gamole Weans comDulco Hom smalcC "plee Wchac [o confidetice the resulting Estuuales aud are Icss apt t0 [cject null hypothesis_ and (4) arc all correct statemetts (1) and (4) ae COuCC statements but not (iii) (1) 15 COnecl slalemcnt bul IO (1u} . 6). (1) and (ui) are all false statements (1) and (i) are correct statcments bul not (11)- Moving Ihie nexl question Drevents cijmdg: this answer Quejvo Type here search



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Preliminary data analyses indicate that you can reasonably consider the assumptions for using pooled $t$ -procedures satisfied. For each exercise, perform the required hypothesis test by using either the critical-value approach or the P-value approach. Doing Time. The Federal Bureau of Prisons publishes data in Prison Statistics on the times served by prisoners released from federal institutions for the first time. Independent random samples of released prisoners in the fraud and firearms offense catcgories yiclded the following information on time served, in months.

In this problem, we are going to determine the probabilities of certain events. A table is given and two events are given. Is that the offender has 10 or more years of education and B is the event that the offender is convicted within two years after completion of treatment. Now in the first problem, we need to determine the value of p. of E. So that means we need to find the probability that the offender has 10 or more years of education. Now from the table, the total And with the offender has generally year 10 or more years of education is 0.40. So that's the Numerator in the probability and the total is 1.00 from the table. So the probability is 0.40 by 1.00 which is just equals to 0.40. And the second problem, we need to find the value of PMP Which is the probability that the offender is convicted within two years after completion of treatment. And from the table we can see that the numerator will need to be the total for the N. B. Which is he goes to 0.37 And the total number of outcomes. The denominator would be like the previous case 1.00. So that is 0.37 x one which is just equals to 0.37. Next we need to find the value of P. E. Intersection B. Once again the total is 1.00. And from the table b. Of a intersection be the total for a intersection. B means the offender has 10 memorials of education and has also been convicted within two years after completion of treatment. So the total in this case will be 0.10. Which is obtained from the table. So To be 0.10 or 0.1 next we need to find the value of P. E. Union. Be now be of a union, be can be obtained using the addition rule. And the additional rule says the p of a union B. Is supposed to be of A plus P. Of B minus B of a intersection B. So we just found the values of P. A P P and P a intersection B. So we can substitute those values 0.400 point 37 And this would be minus 0.1. So the value for this will be equals to 0.67. Mhm. Next we need to find the value of P. Of a bar. So that's the complementary way. So this is equal to one minus B. Of a. So that's one minus the value of P. Of a 0.40 So one minus 0.40 is equal to 0.60 or 0.6. Next we need to find the value of P. Of the union rebar and that is equal to the value of one minus P. Of a union. Be and that is equals two, 1 -0.67. We just calculated developed p of a union media equals to 0.67 and 1 -0.67 is equals to 0.33. So there is a probability in this case. Next we need to find the value of P. L. E. Intersection B. Bar. So there's a complimentary intersection B. So that we want minus B. Of a intersection B. So that's 1 -0.1, which is equals to 0.9. And that is the probability in this case. Next we need to find the value of P. O. E. Given be. Now using the definition of conditional probability, this is equal to P. Of a intersection, be divided by the F B. The value of p. of a intersection B is equals to 0.1 and the value of PLB equals to 0.37. So that is equal to 10, divided by 37. And that is the probability in this case and last. We need to find the probability of being given. Uh So by the definition of conditional probability that is equal to P of the intersection, he divided by P. L. E. Now, since the intersection, any intersection B is the same thing, so this would be of a intersection be divided by P. L. E. Now the of a intersection B is equal to 0.1 B. Of a. Has already been determined to be 0.40 So that would just be 10 by 40 or one by four. And that is the probability in this case.

The variable is pain. We're looking at the before groups and the after groups. The pears are going to be the before and afters. The pair difference is before minus after. New one is going to be before and Mewtwo is going to be after. Arnel hypothesis is that new one is going to be equal to Me too. And we want to find out if treatment got better. Therefore, new one before group would have to have greater pain than you two. This means that we will be doing a right tail test.

Mhm. So in this case, the Drug Abuse and Resistance Education Program underwent several major changes to keep up the technology and the issues that the students were facing. Now, after all the changes now, there is a school resource officer that think that the proportion of 12 to 17 year olds who have used marijuana in the past six months has decreased. So what would be the null hypothesis the null hypothesis would be then I like hypothesis would be that P is equal to 6.7%. Right, That P is equal to 0.67 And the alternative hypothesis would be the claim of the officer. That P is less than 0.67 which means that he is actually saying that this program is effective. So these would be a null and alternative hypotheses. Now, if the sample data indicate that the null hypothesis should not be rejected, what would the conclusion be then? I like this should not be rejected now. It would mean, uh okay, so after the test is an ally. But this is not rejected. We would say that we do not have. We do not have enough evidence enough evidence to suggest that the proportion of marijuana users users that the proportion off marijuana users in this age group have decreased right. Which means that whatever changes they made to their system, right, whatever changes this program and event, it is not very effective. Okay, now, the party is supposed, in fact, that the proportion of 2017 year olds who have used marijuana is 6.4. Okay, which means that it has actually decreased. But what we did, what we did was we did not reject, right? Uh, yeah, we did not reject the null hypothesis. Have we committed a type one or type two error? Well, the null hypothesis is that P is equal to 6.7% and we have not rejected than the hypothesis, right? Even though the null hypothesis was wrong, even though the true percent is now 6.4% we did not reject the null hypothesis. This means that we have made a type two error a type two ETA. Right? This is going to be the type two error. Why? Whenever you're not hypothesis is wrong. But you failed to reject it. It is always a type tour. These are answers

In this exercise, we're going to be considering a hypothesis test that is performed to determine whether uh the mean wing lands for two sub species of junkers, the migratory and the non migratory jungles are different. So the first thing we'll do is to specify the viable and in this case the viable is the wing land. Next we specify the population. Um The two different populations. Population one hand population too. Now population one is represented by the Migratory Juncos. Yeah. And population to is the non migratory juncos. Next we have the means of the two population populations. And the first one, New one is the mean with England of migratory Juncker's two. Two. Yeah. Yeah. And the second menu too is the mean England okay of the non migratory jungles. Mhm. Next, for the null hypothesis will have New one equals Mewtwo. And for the alternative hypothesis, uh we consider the sentence where we are trying to determine whether the main England's for the two suspicious are Different. So that means we're checking that new one is not equal to Youtube. And this hypothesis is a two tailed hypothesis. The two tailed test


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