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A solutioncontains 7.69×10-3 M potassiumsulfide and 7.65×10-3 M ammoniumcarbonate.Solid cobalt(II) acetate is added slowlyto this mixture.A. What isthe form...

Question

A solutioncontains 7.69×10-3 M potassiumsulfide and 7.65×10-3 M ammoniumcarbonate.Solid cobalt(II) acetate is added slowlyto this mixture.A. What isthe formula of the substance thatprecipitates first?formula = _________B. What isthe concentration of cobalt(II) ion whenthis precipitation first begins?[Co2+] = _________ M

A solution contains 7.69×10-3 M potassium sulfide and 7.65×10-3 M ammonium carbonate. Solid cobalt(II) acetate is added slowly to this mixture. A. What is the formula of the substance that precipitates first? formula = _________ B. What is the concentration of cobalt(II) ion when this precipitation first begins? [Co2+] = _________ M



Answers

A solution is 0.022 M in Fe2+ and 0.014 M in Mg2+.

a. If potassium carbonate is used to selectively precipitate one of
the cations while leaving the other cation in solution, which
cation precipitates first? What minimum concentration of
K2CO3 will trigger the precipitation of the cation that
precipitates first?

b. What is the remaining concentration of the cation that
precipitates first, when the other cation begins to precipitate?

Okay, So in this video, we're answering question 108 from Dr 17 which tells us we have a solution that is 170.2 to Mueller and F people. It's too ions and 0.1 for Mueller and MG plus two ions. In part they were asked if potassium carbonate is used to selectively precipitate one of the cat ions while leaving the other cat eye. And in solution which cat and will precipitate first. What minimum concentration of potassium carbonate will trigger participation? Precipitation. Sorry of the cat eye on the precipitates first, um so the possible products we conform with our carbonate eye on our iron carbonate and magnesium carbonate and to figure out which one will precipitate first, all we need to do is to compare the scalability product. Constance those equilibrium, Constance, that air calculated from our amounts of ions and solution. So for iron carbonate, we have a lower liability product constant than for my museum carbonate, which means that iron carbonate is the least soluble in the most likely of department precipitate. While magnesium carbonate is the most soluble in the least likely to form precipitate eso, we're going to form a precipitate from iron carbonate before magnesium carbonate. And we want to know what concentration of que Tu Sio three will trigger the precipitation of r F E C 03 s. So, basically, if there are more ions that Aaron the solution, then there would be equilibrium than some of the solid reactant will have to form in order to reach equilibrium. And we're going to form a precipitate. So basically, when our reaction question Q is greater than our Selya bility product, Constant K um, so are our reaction quotient. Q is equal to our iron ions. Times are carbonate I arms and we know that that needs to be greater than our KSB. So basically, we need our concentration of carbonate ions to be greater than the K S p divided by our concentration of iron ions which were given. So we have 3.7 times 10 to the negative 11 for our ke sp divided by 110.2 To moller, that gives us 1.4 times 10 to the negative nine Moeller That's the concentration of potassium carbonate we need in order to initiate this precipitation of iron carbonate out of solution um, Andy were as what is the remaining concentration of the cat eye on the precipitates first, when the other cat eye on begins to precipitate. So what's the remaining concentration of iron ions wants? Magnesium carbonate begins to precipitate. So when is the other cat eye on going to start precipitating on? When are we going to start forming magnesium carbonate? We need to check when Q is greater than K for magnesium carbonate. So Q is just equal to our concentration of my museum ions, times their concentration of carbonate ions. And that needs to be greater than our K S P, which is 6.82 times 10 to the negative six for my museum carbonate. Um, so are carbonate ions. I need to be greater than 6.82 times in the neck of six, divided by our point No. One for Moller from our concentration of my museum ions, that gives us 4.87 times 10 to the negative for Moeller. So the magnesium I owns air going to start precipitating when our carbonate concentration is 4.87 times 10 to the negative for Mueller. Um, so what is our iron concentration when we have that concentration of carbonate ions are so basically all we need to do is plug that carbonate concentration and the K s P of iron carbonate into, um into our equilibrium expression. And what we end up with is 6.3 times 10 to the negative eight Moeller for our iron ion concentration.

So to answer this question first we need to know the case. Be fellow for both bury himself and killed himself. So the gas be velo or the celebrity product constant for bury himself Fit is one point all seven times ten to the four minus ten. And the case Poor fellow for Gelles himself, IQ is seven point ten times going to the bar minus five now, um so a lower case be velo means that compound will dissolve Are that comfortably form precipitated at a lower concentration. So here we can see that the case people so far bury himself for is much lower than the case people off calcium surfeit. And that means when really add on appropriate amount off sodium self it which is our agin for the precipitation. I'm the calm bones then Ah, the berry himself. It which has the lowest gsp velo wait form them precipitate first. So, um, being so far away from their precipitate first with the Saudi himself, edit now to find the minimum concentration. Um, why so find a way Minimum constitution ofthe sodium sulfite that will trigger the precipitation. I'm the cat down to find that first you have to find out the expression for the Curie ation cautioned for the bury himself. It so reaction quotient is basically the product off our alliance produced from the compound. So it'll be a beer Good class times s O four two minus. And so the cubillo reaction cautioned when it is equal to the value ofthe case be, that is the time when, when the precipitation off the ion start so and the point at which Q is equal to case be, that is the point when the precipitation will start to begin. So if he just right this recall, that means very being two plus times. A PSA for two minors is equal to the case P Velo, which is one point oh, salmon time stated about minus ten. Now we have to find a consolation of self around from here, and we know the concentration off Barry and my own, which is basically the concentration of the barium self effect. Because one day a man will be post from one very himself to monocle that men's, um, the constitutional bury himself. It will be the concentration off very ion, which is zero point zero one zero and we have to find there's a for two minus ion concentration from this equation here. And if we just solve this, we'LL find this. Hello, Officer for two minors are the concentration officer for two minutes. Has one point one times ten to the minus eight muller. So this is the value off the are the minimum concentration which will trigger the precipitation. So this is the medium concentrations ofthe sodium self. It Natalie created the precipitation. Now we need to know find out the consolation of their remaining remaining get down. That will precipitate first when the other captain begins to precipitate it. So for that, we have to set up the oration, cautioned equation for kills himself. It so for killed himself at it will be called See a two plus time's so for two minus. And now we have to find the And as you know, that when for the precipitation to begin, the value ofthe this reaction cautioned will have to be called with the case. People off killed him self it. So if you write this tree cool, we can right, See it two plus and crimes is a forty to minors. And they called him the case people. Hello, which is capable of calcium sulfate, which is seven point ten times ten to the barn miners fight. And now from here, we can find on the consolation of this cellphone down. Assuming that the concert interrupt the kill Chairman is equal to the concentration of the killed himself, which is which is given as they're open zero to zero. So you can write a zoo before two miners, Kal Toh, on the seven point ten times today were minors five over. They killed him and concentration zero point zero two zero. And from here we can find the value of self at the concentration of sulfur ion which will be a three point five five times into the poor minus three Mueller. So this is the This is the concentration of the sulfur down at which killed himself will start to start. Oh, precipitate. So now we have to find So if we can find the concentration of barrier my own at at the time self, it will have thiss concentration. So that concentration of barrier man will be the concentration of bury himself at are the counselor from the barium ion at Bryant when um gets himself in real startle precipitate. So he figures, too. Again, right? Precipitation, reaction, Griffin cautioned. And narration caution for B s o for as they call to case pure BSO, for when, um, the president will form. And from here, when can right be it two plus times. As for Gu miners, the gas privileges one point all seven times generally poor minus ten. And here we'LL replace the cellphone concentration by thiss concentration, which is the sulfur and concentration at when kills himself. Ready starts to precipitate. So if we just put the self around concentration here is that one trip one five five Time's a gentle depart minus three times ten to the poor miner stand. And from here we can find the barium ion concentration when cell phone has a constitutional thiss and that point barium and we'LL ever concentrate enough um, three point all times ten to the power miners eight Mueller That means when self around will have this concentration which is basically the concentration at which kills him self. It will start to, um form the precipitate and that concentration barium and will have this concentration. So that means this is the concentration of the Barry, um, I own are the cat I own, which will basically that first at the plant when on the other, um, compound or other get on with start oh, precipitate.

Find out which one precipitates First we need to figure out the lead concentration required to precipitate hide I and the lead concentration required to precipitate carbonate. We'll take case the expression for lead two iodide we arranged to solve for lead get the lead. Concentration is equal to KSB for lead two iodide divided by the iodide concentration squared and the idea concentration was given to us. Appoint one Moeller. So the lead concentration required for lead the ID ID to precipitate is going to be 9.8 10 negative seven and then the lead concentration required for the carbonate to precipitate. Initially, the concentration of 0.1 bowler This being the case p for lead two carbonate you're 7.4 10 the negative 13 malware. So we see that the lead concentration is smallest to initiate precipitation of carbonate and the 1.4 times 10 the negative 13. And as we keep increasing the lead concentration by adding mawr, lead two nitrate. Eventually we will initiate precipitation of the iodide when the lead concentration is 9.8 10 the negative seven. So when the lead concentration is 9.8 10 the negatives ever weaken solve for the carbonate concentration, and all we need to do then is plug in the 9.8 times tendon, 87 for the lead concentration and figure out what the carbonate concentration has been reduced to by simply rearranging the GSP expression for lead. Two carbonate P would be equal to carbonate concentration multiplied by the lead concentration. But we ended up dividing both sides by the lead concentration. So 7.55 times 10 the negative eight will be the carbonate concentration when the eye begins to precipitate.

Have a few different parts to consider, So we'll take a look apart a fast and then we will look at the other parts shortly after. So here we have our equations. We have B A s 04 solid in equilibrium with B A two plus Add eso for two minus. You can see our charges. Balance that. And then we have C A eso thought that is Nick living with C a two plus again two plus charge on S four to minus you Conceive, we've got some nice charges canceling out. So we're looking for a ks p value where we have be a two class ad s 04 to minus concentrations where the K s P is 1.7 times 10 to the minus 10. They were looking for the concentration of S 04 to minus, which is 1.1 times 10 to the minus eight. So then the K SP for the second reaction, see a two plus eso for two miners, we can determine the K SP when we plug in our values to be 7.10 times 10 to the minus five. Therefore, s 04 to minus concentration a 7.10 times 10 to the minus five. Divide by the concentration of CIA two plus no point not to zero does equal to 3.6 times 10 to the minus three. There's one more step. And then so from this we get any to s four concentration that is equal to 1.1 times 10 to the minus eight. There we go. So the second part, what we have is K S P be a two. Plus, they're so four to minus. This is also equal to 1.8 or seven times 10 to the minus 10. So therefore be a two plus legal twan 0.7 times 10 to the minus 10 five by the concentration of our so four to minus, which is of course we know. So we plugged that value in to get 3.0 times 10 to the minus eight. Yeah,


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