So using the Bohr model of the hydrogen atom, Um, which is the incorrect model, but it's an easy approximation. Theologian Tron orbits the proton, right? So since there's a hydrogen atom that it's a hydrogen atom has only one proton and one electron, and that has a radius of 0.53 times 10 to the minus 10 meters. The charge here that we're gonna use is the charge Q of equal. 1.6 times 10 to minus 19. Cool. Oh, that's the charge of a proton, Uh, and minus That would be the charge of an electron here. Okay, so for part a okay were asked to calculate the electric potential at the electrons orbit due to the proton. So the potential V is going to be equal to the constant K, which is one over four pi upsilon not equal to 8.99 times 10 to the nine Newton time meter squared per Coolum squared. It's a common constant. You can look up times the charge Q divided by the distance are plugging those values into this expression. We find that the potential is 27 bolts weaken box. Aydin is their solution for part a. Okay for part B. The kinetic energy here can be found from the fact that the magnitude of the net force on the electron, which is an attraction by the proton, is cause eyes causing the circular motion. So therefore, the kinetic energy K E is equal to 1/2 n v squared right, which is going to be equal to Ah, 1/2 okay, times the charge Q times The magnitude of the charge of the electron, which is minus Q, divided by the distance between squared. So where do we get that from? Well, we got that from the fact that the mass times that, uh, speed squared divided by our is the force. Hey, which the force here, of course, using Coombs laws Kay Q times minus Q. The magnitude of minus Q. Divided by are square so open actually had a type of this would be over our right. So then just playing in N v squared for uh, R R k e value, we find that in the squared is equal to K Q times minus the magnitude of minus Q over our. So that's where we got that now, plugging those values that we have into this expression, we find that this is equal to 2.2 times 10 to the minus 18. The units there would be Jules, you can then convert from Jules to electron volts. Son, this is equal to 14 electron volts. You can box the senate. Your solution for part B cancer, not cross out that 18 there. Okay, now moving on to part. See, So the total energy then here for part C of the electron is gonna be the sum of the kinetic energy and potential energy. You can use the equation 17 dash to A to find a potential energy. And it's negative, since the electron here has negative charge. So the total energy is going to be equal to the potential energy plus the kinetic energy. Oh, okay. Well, we, uh we just found the kinetic energy in the previous question, and the potential energy is going to be minus the charge Q times. The potential V. Okay, then plus the kinetic energy, we've found the potential V in part a. So plugging all those values into this expression, we find this is equal to negative 2.2 times 10 to the minus 18 Jules. Okay, well, this is just negative. The answer that we got in part B, right? This is just negative. 14 electron volts. Linkenbach said it is our solution to part. See? Okay. Now for part D. So if the electron is taken to infinity at rest, then both its potential energy and its kinetic energy would be zero. Right? Um, at infinity, there's no potential energy. And if its kinetic energy is zero right, the amount of energy needed by the electron to have a total energy of zero is just the opposite to answer of part. See, So it would be minus. Hey, you can Box said it is the solution for D.