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Part AWhat is the intensity of light 9.4 m away Irom a light bulb i the radiating power is 134 W?8.29 Wlm?0.121 Wim20.362 Wlm?14.3 Wlm2...

Question

Part AWhat is the intensity of light 9.4 m away Irom a light bulb i the radiating power is 134 W?8.29 Wlm?0.121 Wim20.362 Wlm?14.3 Wlm2

Part A What is the intensity of light 9.4 m away Irom a light bulb i the radiating power is 134 W? 8.29 Wlm? 0.121 Wim2 0.362 Wlm? 14.3 Wlm2



Answers

About $5 \%$ of the power of a $100 \mathrm{~W}$ light bulb is converted to visible radiation. What is the average intensity of visible radiation (a) at a distance of $1 \mathrm{~m}$ from the bulb? (b) at a distance of $10 \mathrm{~m}$ ? Assume that the radiation is emitted isotropically and neglect reflection.

We want to know what distance we need to put Wonder what light? To produce the same intensity off 75 watt lights 10 meters away. And first we need to know what is this intensity that they produce 10 meters away? So we have intensity off. The second system is 75. Hurry is the power divided by four Pi R square and this power is 75 words divided by four pie in the distance. 10 meters square This is 59 point 68 time Stand to the minus three What's prim unit square. Now that we know this intensity, we need toe equate the intense stuff The first system So I want is you go toe the one divided by for by our once where And this needs to be a good try to and we know by well be one So we so before our what So are one his world off b will be run by four by I to and this iss square root off 100 divided by four pie in the number that you calculated before 59 Do wait time extend to the ministry and this gives us a radius off 100.5 meters away

All right. What is the illumination from a lamp with a luminous flux of 2275 women at a distance 3.1 meters away? Well, the equation for illumination he is equal. Teoh p R. Limits looks over four Pi distance square and so it's just plug in our numbers. P is 2 to 75 loom in for four pi. Distance is 3.0 meters squared and run your numbers and you find that are illumination is equal to the 20 looks.

Okay, So a light boob ready eight slight such that the electrical feuds that's putting here electrical field is 16 years Doesburg, Cruella at a distance of one point 35 meters. And the problem just want to calculate what is the average power off this light bulb. But in order to calculate the average power, I just need to remember to calculate first the intensity because intensity to define a c absolutely not electric off a logical feud square. So the power we know average power is just the intensity multiply by the surface area, which is in this case is a sphere. Therefore, we can say the surface area of this fear is for by are square. So we have here, see? Absolutely not e square they're multiplies for by are square So if we calculate all this, we have the average power equals three times 10 to the eight They moved to place eight point 85 times 10 to the minus 12 them with supplies 16 square for by 1.35 square. Calculating all this, we have finally average power off 15 0.6. What? That's all Thanks for watching

Hello students here We have given that the light intensity which is getting emitted from light bulb change, is inversely proportional to the square of the distance. So the relation is physical. Okay by these No, We have been given a condition that from light but the light intensity and played intensity at a distance of five meters from this label. This is five meters. This distance is five meters Is 90 bad for meters? No, we need to fight from this point from this point. At which point the light in density is going to be 40 meters with Now we need to find this is the distance we need to find if we assume this is Capitally So we need to find Captain. So first of all from this equation, we know that light intensities 94 meters and distance off five meters. So that is these queries 25 meters major square meter stairs canceled and case going to be true to 50 No equation is our musical to 250 that right days No we need to find distance from light but do ended late Bulbul to appoint very in density is going before developer meters. So that is the substitute here. 40 back four meters. Where is going to be 2 to 50 back by these quick here it implies that is going to be square root of 2 to 50 by four and 00 against himself and it is going to be 15 bite two meters? No from here. From this point to this point, the distance is given as that is the distances seven 0.5 meters. That is 15 by two meters. Now we need to find capitally. So from late from 90 meters were in density to 40 per minute per meter. Square intensity. The distances D is going to be 7.5 meters minus five meters is equal to two. Point occurs, so the required solution is easy for 2.5 meters.


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