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Section: 16.57. What islare the major products of the following reaction?Brzs 50%CAB.BrD. BrBrBrBr BrBrBra. A b. B c. C d. D e. B and D f. A and C...

Question

Section: 16.57. What islare the major products of the following reaction?Brzs 50%CAB.BrD. BrBrBrBr BrBrBra. A b. B c. C d. D e. B and D f. A and C

Section: 16.5 7. What islare the major products of the following reaction? Brzs 50%C A B. Br D. Br Br Br Br Br Br Br a. A b. B c. C d. D e. B and D f. A and C



Answers

What is the major product of the following reaction? (a) (b) (c) (d)

It is we have this compound ledge blooming Emmy floating and honorable. Right? And we have P. H. S. Minus any plus. So what will we get okay buying a tile farmer? My the M. F. D. M. F. Is the polar airport. It's falling. That's why there is a santa. The action takes place. And we know that in the assembly reaction there is inversion takes place. So we will get compound that is browning is presented in the best position and SPS will present death position. S. B. H. Right, So great to meet you and.

I said this question we're talking about, Ah, few of the reactions here. In part a. This question is asking, what's the major product? While these eso just to draw my little action errors I control This is the major product of that reaction going to number two Almost identical. Except this time, just addition of BR instead of C L, uh, this one. Hello? Uh, so for three going over it this time you're standing water. So you're gonna have something like that. And lastly, you just adding that methanol. So you're gonna have something that looks like, uh, I think that instead. Okay, so that's part a, and part of it is predicting the major products. Part B asks what all these reactions haven't common. Um, so I'll just down a little bit. Do be, uh, and Aiken, they all have a car. Boakye on intermediate. And they all proceed about in a very similar mechanism on. Then see is asking, uh, how do all these reactions differ? Um, and one reason one way they differ is what is acting is the nuclear file. Um, so nuclear file. Ah, and that's illustrated. If you look a reaction, one the nuclear power is gonna be chlorine versus bro. Mean versus of water versus methanol. So obviously, they all have different nuclear files. And additionally, three and four actually have an extra step where you need a proton to be attracted. So I can say H plus transfer is another thing that makes these ah, reaction is very different from one another.

Okay. This problem is asking us to predict the products of the follow interactions. Okay, so first up, we have this ether reacting with HBR and heat. So HBR is a super ascetic acid. It's the first thing it's gonna do is prone it. My most basic Adam of this molecule, which is my auction. So the auction is going to go and go ahead and get pollinated. And it's going to make this intermediate and have a positive charge on the option. Okay, So reactions with ethers in acidic conditions. The first thing that we have to identify is if we're to split up that protein into either such as like this. If our to split it up this way or this way, would either direction form a stable car broke down. If not, then I'm going to perform similar to, in essence, the reaction in which I have a leading group leave at the same time my nuclear fall comes in or I'm gonna have It s in one reaction in which I go ahead and straight away form deter sherry or secondary, perhaps carpet pattern. And then I have my nuclear welcome in an attack that stable car cut on. So, um, fr to drop my squiggly line represented a a bond breakage over here. I would realize that I would have a carbon catalon associated with this torture carbon structure kit. And then I would have my alcohol over here. That would be a primary alcohol. So I'm gonna go ahead and do that. I'm going to go ahead and break this bond between the carbon auction leaving the alcohol and then leaving a church here. Carbon hotline Intermediate. So something like this can have a positive charge of that carbon. And then I have my alcohol as my leaving group. Just like that. So now that I have the stable carbon right now, my bro me can come in and attack that carbon like that, producing this compound ch three, the safety ch three and broke my Okay, So that would be the product of that. I would have this one and this one. Okay, next up, let's go ahead and do this one. Okay. So same thing I haven't either Reckon with a super strong asset. And h i, by the way, is even stronger than HBR. So this one is one of the most excited compounds that we're going to encounter in organic chemistry. Okay, so first off, a protein ate my basic Adam, which is my oxygen just like that. So that's going to lead to this compound. Okay, So if you remember what I said, what I'm gonna do next is to draw a squiggly line to represent a bond breakage. So if I break it this way, or if I break it this way, would either direction form a stable carbon dioxide? The answer is no. Because even if I split it this way, I would form a primary carbon cotton right there because this carbon is only connected to one of the carbon, so that would be particularly favourable. So this is going to perform an Essent to like reaction in which, after the pronation, due to my age, I have the deeper in a diversion of HIV, which is just I that is going to behave as medical file, it's going to go ahead and attack the least handed carbon possible. Okay, so it's Annette's interaction. I'm going to attack this carbon, and I'm gonna make this as my legal group, so I'm gonna have my ch three ch Series three and then c h two alcohol. And then my product is C H three. I just like that. So those would be met you products. Okay, next up, let's go ahead and do this one. So that's when I have a primary alcohol. Reckon with H two c r 04 h. Two c r 04 is an oxidizing agent. So what I'm gonna do is recognize that first off, I have a primary alcohol and then notice that this is one of the stronger oxidizing agents actually believe this is Jones, your agent, which is a very strong oxidizing agent. It's gonna go ahead and turn my primary alcohol into a carb oxalic acid. So first it's gonna turn into an overhead, and that's going to continue to oxidize into a carb oxalic acid. So it's going to form this product. So have stage two c h. And then it's actually not ch two any longer, it's gonna be carbon connected to a Carbonell, and it's gonna be can't into the alcohol. Okay, so just like that, Okay. And that would be my answer. Okay, next up, I'm going to active with this primary alcohol Oops. I think I actually do that twice. So let's just forget about our like it moving on to this one. Okay? For this one, I have a nip oxide wrecking with my with oxide and methanol solvent. So because I'm in a mess oxide in the presence of meth oxide, that is considered to be a base. So I have to be thinking action to reactions, not as someone, because that would be considering an acid condition. Basic conditions were going to be considered my base as a nuclear file so that no Cliff all is going to come in and attack my least hindered side of my carbon. And the reason I'm opening up the Depok separate is because because I have a three member during that is has a lot of angle straight, right? We have a lot of tension in those bonds because in reality, if there s p three hybridize way, we would like them to be approximately 109.5 degrees. If they're in that three members confirmation, they're gonna be less than 109.5. We want them to be as close to one of 100 as possible Okay, So what I'm gonna do is attack that park said, move the electrons onto the auction resulting in this compound in which I have my oh ch three. Okay, I'm gonna have my alcohol there, and then I have the connection to my cycle. Hexi. Okay. And then right now, I just do the alcohol, because in reality, it would just be o minus. But then it would get propagated by the methanol into the alcohol. So, like that, that would be the product for this one. And let's just go ahead, and I like that. Okay, moving on to the next world. Okay. On this one, I have sin or six substitutes have that metal group, and I have this alcohol there, sis, to each other. Is that relevant? We'll see. OK, next up, we're going to react it with TSC l or my parent Halloween. So far, Neil chloride and purity that's going to produce a, um, s into reaction because this is going to have a quarrying replaced my alcohol because it turns it into a good leading group. And then my Korean attacks that carpet. So what I'm gonna do is notice that this alcohol is represented in the front. So if it's an asset to reaction and I'm replacing that alcohol with Corey, I'm gonna have a calling coming from back. So it's gonna be like this cycle acsi my ch three unaffected and then my Korean replacing that alcohol because it came in from the back. Okay. And then I have my NSCN. It's gonna come in and attack. Oops. That should not be an alcohol. Should be Corey just like this. Okay, now that NSCN is going to go ahead and attack the carbon in which I have a good leaving group attached to it. So in this case, I have a chlorine. That's a much better looking group. Much, much better. Little group in my ch three. I'm going to go ahead and attack that carbon in order to release this Korean as a leading group. And because this is going to perform in an S and two reaction, I'm going to have an inversion Xterra chemistry because right now I have that Korean represented in the back. My nscn specifically my CNN is gonna come in from the front like that, releasing my Korean, so I should get this as my final product cycle Hack sane ch three. And then I have my the end in the front gets the overall. I had an overall retention of Syria chemistry. I didn't change the cyst nature, but I did eventually get Trans. But then I reverted it back into assists. Okay, next up, I'm going to act this alcohol with N a o c e o. And then that Korb oxalic acid. So this is actually the region for an oxidizing agent. And what I have to do is just turn this alcohol into a Carbonell and there will be no issue with that because this is just a secondary alcohol. That means I'm going to turn it into a car bomb. Uh, Tito, if it were a primary alcohol, then we would have to know a little bit about how strong the oxidizing agent is because we don't know if he would turn into it carb, oxalic acid or just a valve ahead. But because this is a second year alcohol, we just know it's going to turn into a veto. Okay, next up. Oh, yeah. You know, I like that to keep consistency. Okay, Next up, I'm going to wreck this compound with heat. So this right now is an ironic bond. I have a part of charge, and then that's ironically born into this hydroxide. Okay, so in the presence of heat, a reaction is going to occur. And direction that's going to occur is my high drop said, concerning the fact that it's very basic is going to Deep Throat. Nate, my beta carbon right here, this nitrogen, we can consider that Adam zero. So it's called that zero, and then the carbon is directly attached to that are off carbons off carbon, their carbon there and Alfa carbon there. And then the carbons that are attached to those awful carbons are called beta carbons. So beta carbon there and made a carbon there. And then these two, I think I think they will be called Gamma, but those aren't really relevant for this problem. Okay, so next step, I have to undergo deprived nation. So my hydroxide is going to deep rotate the carbon debate a carbon that has the most number of Hodgins. So we're comparing this beta carbon to this basic carpet. So because this one has three Hodgins as opposed to this one of a chest 100. I'm going to dip. Rotate this carbon. So the only taken off 100 moving the electrons between that carbon 100 bond onto the bond between this carbon and this carbon. And in the process of doing that, this carbon will have exceeded its octet. So I need to move a lot Charles away from that nitrogen carbon bond and onto my nitrogen. So my nitrogen in this case is my leaving group, and that's because it has the positive charge in it. So my product is gonna be ch three c C h three c eight ships should be just h and then ch two connected to nitrogen connected to ch three and ch three and no more positive charge because I moved electrons towards that former nitrogen with a positive charge. And then I have my ch two double bonded to my ch two. And then, of course, I have my water, which was the former hydroxide. Okay. And, uh oh, I like that. Okay, next up, we have this one. So this one is my secondary alcohol direction with HBR and heat. So every time we see a reaction on alcohol, doctor the acid like this where we should be thinking of a potential sn. Um, just substitution reaction, but we don't know exactly what yet. So we see that we're going to rotate it. Something appropriate it. I'm going to form this intermediate. Okay. All right. There and my method, but there. So I'm gonna have always to with a positive charge. Okay, next up, I'm going to want to release that. So I'm gonna have this leave like that, and that's because it's on the secondary carbon. If if we're on a tertiary carbon, it would have that alcohol leave no matter what if it were appropriated. But if it was on a primary, then we would have an s and two reaction. And that's because we simply cannot have a substitution reaction. Specifically s and one by the formation of department Takata Primary Carver Collins are just not favorable in general. So this one secondary carbon patterns are a little bit more favorable than primary carbon patterns, but in the sense that we can have them relatively stable by themselves. So if I have that, I'm gonna form this as my next intermediate, in which I have a positive charge right there. So this is where it might get a little tricky because we know that we have a second your carpet cut on, and we see that we do have this metal group right there. So the question is, are we going to undergo any further actions to make this car? Because on even more stable than it already is, right? Do we have the potential to make a tertiary carbon copy? And that is actually dependent upon your teacher? Because some might say that we would have this hydrogen shift over like that to produce this compound. Carla Carla Right there. Mind you. How'd you do? Right there. And then others will say. And they continue to say that we'd have another hydrogen shift over like that to make the carbon cattle eventually come onto this ter share position. And then my bromide would come in, resulting in the nuclear Filic attack of that carbon resulting in this compound. So that is what some teachers might say. But some might say that that is simply too far. That metal group is not interacting in any case with this carbon county right there. So we're just going to get an immediate reaction with that secondary carpet, Captain. So again, I'll draw up the secondary Carbon Qatar. Right there. My metal group. Nothing. There's no hydrogen, the hydrogen. None of those are interacting with that carbon headliner. So we're just going to have a straight up nuclear Philip attack onto that carbon. It's right there. So I would recommend seeing if your teachers taught anything like this. If not, maybe see if you can go ahead and ask him or her. But no matter what, we're going to have one or the other product. So that is actually the product will be something like this. Okay. For this last one, I would recommend I'm asking your teacher to see what they would want to drop because some might say that Method group is too far. Others will say That's just that's perfect. You can still move with those. Hydrogen is over. Okay, So what's highlighted is the answer. And I'm sorry I do this one for twice

On this problem. Six. A global interviewing. They're treated with different religions here to find a products of mutual investment. The first one is you know, that's a day trip. Undergrowth night. Reason this group is You know, Tom, donating between the presence of little pair of electrons from the atoms addition to the engine drink. That's the reason have alone. Bear here. This long pair will be auto para directing. So the product is me. It's an agree it to do it so forth. For it will be And you do here on the para position off the table. PhD, The second component? No. Along with that, they will get deep photo product also. Mhm. Yeah. And you The second reaction. Mhm Rome. Oh, Rome. A terrible CS three. We are right. They treated with the mechanism leader on D two. Good. But on the second day, toe my life. Yeah, normal phones and de beer. Okay, I continue to be tools. Okay. The three places we are with deuterium atom. Yeah, the next companies and his whole react ended that cynical hydrate. Maybe it's any soul he has been with six cynic and hydrate in prisons off 11 employees. That's good place. And then it is highlighted. Water to that. Well, CSP on the product. Ince's mania Auto para products. Okay. Mhm, Yes. Feel everyone cool. See? It's cool. She is to see a lines. We'll see if prepare a public here. Well, well, ladies. Right Next is the compound, right? A secondary of Campbell. Great great moments. Domination. And then it goes now, auto, I'm fed up for its okay. Yeah, or more wonderful people. Yes, but for more me are Mexican movies. Dorgan ST Written when Norman on 10 Beauty. Um, all by corporate today. What is Brahman under, Like condition? It's new that bombs. They are citing domination. Treatment of this lithium. Okay, then reads cierto away doing Onda Who presided you tell quickly. Yeah, Mhm. William Reid. What's the likeness on this Further? Yes, Thank you, Bob. Say do fall The alcohol that quite government see obtain is coordinated in prison. So official tree. Well, the track monetary group is like a directing because of the strong, strong drawing nature. So when we get c f three here and you're in here


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