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1 1 Two 8 hour; do1s 1534 2 Ja83 Tur JO4n U areine average Fdtc 0i 1 1 aui umOD nighayintne same dleOne (ravels...

Question

1 1 Two 8 hour; do1s 1534 2 Ja83 Tur JO4n U areine average Fdtc 0i 1 1 aui umOD nighayintne same dleOne (ravels

1 1 Two 8 hour; do1s 1534 2 Ja83 Tur JO4n U areine average Fdtc 0i 1 1 aui umOD nighayintne same dle One (ravels



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Use an inequality and the five-step process to solve each problem. The Mecklenberg County Public Schools stipulate that a standard school day will average at least $5 \frac{1}{2}$ hr, excluding meal breaks. For the first four days of one school week, bad weather resulted in school days of $4 \mathrm{hr}, 6 \frac{1}{2} \mathrm{hr}, 3 \frac{1}{2} \mathrm{hr},$ and $6 \frac{1}{2} \mathrm{hr} .$ How long must the Friday school day be in order to average at least $5 \frac{1}{2}$ hr for the week?

So we have this Charmaine visiting her grandmother's house, so we know that it took her three hours. So oh, I will say this is her house and say This is her grandma's house. And on the way up it took her three hours to get there. But on the way back, there was less. There's more traffic. So it took her 3.6 hours, and then on the way back there is more traffic and took her four hours and then the rate that which she was going. So we had a certain fixed right here. The right issues going on the way back is going to be five minus that. So we didn't want to take the averages of her rate on Sunday, so so we can use a distance rate. He goes, rate multiplied by time formula. So Sunday Saturday morning, her distance is the same. We don't exactly know what our distance was, but her rate is going to be our earlier time is going to be 3.6 on Sunday afternoon. Distance is still the same. Her rate is going to be her rape from her Saturday morning Dr minus five, multiplied by four because it took her four hours to get there. Now we need to figure out what our is. And so since our distances are the same, that means that these two equations have to be equal to each other. So we have 3.6 are has to be equal to AR minus five times four. So the first thing we do is gonna distribute this for So I have 3.6 r equals four R minus 20. I'm going to subtract this. 3.6 are from both sides. And then at the same time, I'm gonna add this 20 to both sides. So that gives me 20 equals. 0.4 are divide off 0.4 on both sides. So I'm going to calculate 20 divided by 0.4, and that will give me 50. So her rate is going to be 50 MPH. Her speed is 50 and then for Sunday we need AR minus five for Sunday. So that's 50 minus five. So her rate for Sunday is going to be 40 45. Sorry,

Okay, Number 10. There are 24 hours in one day. And for every two hours. Well, we have a blank amount of minutes. So if you don't have this off the top of your head, you should know that there are 60 minutes in one hour. So just multiply that by two. You're going to get 120 minutes.

8.5 hours and we're to turn this into minutes. So key thing here is that there's 60 minutes in every one hour hours. Cancels with ours 8.5 times 60 is 510 minutes.

All right so we have an odometer reading um for Times .96 hours to 1.5 hours. Um And first we want to figure out the average speed from 1 to 1.5 hours. So we're going to take the speed at one point oh five hours. This is just the change in the y. Value minus the chain are over the change of the X. Value. So here's the change in the y. Value. Here's the change in the x. -1. Okay so that's going to be 2.4 over 0.05. I think that means multiplied by 20. Okay so this is going to be 48. Um And do they give us units miles an hour? Right So we're going about 48 mph. Yeah. Um A little past one hour and that's just estimate the speed one hour into the trip. So you could take all these averages. Maybe you could go from 1 to 1.1 and 1 to 1.2. Um I think 1 to 1.1 might be like a little bit of an anomaly. Like maybe you were going slightly slower there. So I think this one that they ask for is actually a pretty legitimate estimate and then maybe we want to do the same thing for as long as we have data for before one hour. So I'm going to do the same thing, I'm going to find the average speed Um from .96 hours to 1.00. Um And then maybe we'll take an average of the two or something like that. So same thing changing. Why? So I'm starting with the one hour um Odometer reading -196 A Dominant Reading. And that gives me 1.8 over .04, dividing by .04 I think is multiplying by 25. Uh, so I think that's 45 mph. Okay, so, um, A little before an hour, we were going 45 mph, a little after we were going, Um, So I'm going to say we were going approximately 46.5 mph At the one hour point.


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