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E 9.32/y ugGo 43152 ~43 LJSL 122S 34.6125~ 3l 1330_ 1#.3&1Z LL~poykd dta w hwe Joa 11,1734,332_42,43,42_42,42,49,51An >432 1131.9 = 39Gh:Te) F4Xl6'36. 9...

Question

E 9.32/y ugGo 43152 ~43 LJSL 122S 34.6125~ 3l 1330_ 1#.3&1Z LL~poykd dta w hwe Joa 11,1734,332_42,43,42_42,42,49,51An >432 1131.9 = 39Gh:Te) F4Xl6'36. 92~ 36Hx~[z&1111 0.3233-&1~ 33Erv): Z FIx&1*19+ 11*37+2.3*42+2.4X4}+9-Sx48 +255x5L 1uxt]+ 238XY+932*43+195*34+1x17 940.59 920iii)ruerd J -qoubd dota Mediaa 43(v) Jom Hu Aouped data Scanned with Mod Ics) 17 RY} CamScanner

E 9.32/y ugGo 43152 ~43 LJSL 122S 34.6125~ 3l 1330_ 1#.3&1Z LL ~poykd dta w hwe Joa 11,1734,332_42,43,42_42,42,49,51 An > 432 11 31.9 = 39 Gh: Te) F4Xl6' 36. 92~ 36 Hx~[z& 11 11 0.32 33-&1~ 33 Erv): Z FIx& 1*19+ 11*37+2.3*42+2.4X4}+9-Sx48 +255x5L 1uxt]+ 238XY+932*43+195*34+1x17 940.59 920 iii) ruerd J -qoubd dota Mediaa 43 (v) Jom Hu Aouped data Scanned with Mod Ics) 17 RY} CamScanner



Answers

MATHEMATICAL CONNECTIONBe vector
$\mathrm{PQ}=\langle 4,1\rangle$ describes the translation of $\mathrm{A}(-1, \mathrm{w})$
onto $\mathrm{A}^{\prime}(2 \mathrm{x} | 1,4)$ and $\mathrm{B}(8 \mathrm{y}-1,1)$ onto $\mathrm{B}^{\prime}(3,3 \mathrm{z})$ .
Find the values of $\mathrm{w}, \mathrm{x}, \mathrm{y},$ and $\mathrm{z}$ .

Solution for party or each concentration off or each negative is it will, too. 0.62 moles off barium hydroxide to buy did by one little solution. Multiply to mall off hydroxide ein divided by one mall. I'll birdie, um, hydroxide. So here, or its concentration is equal to 0.12 Malaria ity solution for part B buffer solution. Here is we have concentration off in each four. Positive is equal to to multiply 0.315 Morality is equal to 0.63 morality and B K is equal to 9.26 for in it for positive. So be it is equal to peak it it, plus log concentration off in his three. Divided by concentration off in each for positive is equal to 9.26 plus lock zero point 486 Divided by 0.6 30 it's equal to nine point 51 So here always concentration is equal to one point for multiplied and rest to the power minus five Milan ity solution for part C. So here we have a buffer solution here in each four positive plus Ohh in his fourth visit you from in his foresail and or it from anywhere it here in the three plus each toe. All 0.68 morality in here. Zero in here, 0.96 in here unknown. So pH Is it well to peek a plus log concentration off industry divided by concentration off in each for positive is it Walter? 9.26 plus log zero point 196 Dealogic Body 0.68 is equal to 9.7 to P, or H is equal to 4.28

Were given sets on your ass to construct a non deterministic finance state atomic recognize each of these sets. So the first set were given Is the sec containing Lambda in this string zero. But as zero be the start state, then machine should accept the empty string Lambda. So as zero should be a final state, the input is zero. Then we'll move on to another final. States and Syria should be accepted. Called his final state s one. And from this, we've obtained in non deterministic financier Tom Adan that will recognize strings Lambda and zero, but no other strings in part B. We're giving this set zero 11 now, but s zero be a start state since the empty string Lambda should not be recognized. It follows that s zero should a non final state. Now, if the first input is a zero, Emma wants to move from s zero to final State s one because zero should be accepted by the machine. Now, if instead, first input is a one, then we'll move from s zero to a non final state s to don't remain s zero because this would imply that any string with just the sequence of ones should not be accepted while 11 should be accepted. Now suppose that the next input is a one. In other words, we have a one at S two and we'll move from s to to a final state which we can just use the same final state from before s one because 11 should be except And so the resulting non deterministic finance state Thomason recognises only strings zero and 11 in part C. We're getting set 011 000 In a sense will be adapting the previous machine to make this machine. So once again, well, let s see. Rabia starts date And since lamb dish not be accepted, we have the S zero is again a non final state. Now it's the input is zero and we'll move from s zero to a final state s one, since the string zero should be accepted Now, if the input is zero, see at s one and we want to move from s one to a non final state s two since 00 should not be accepted. And finally, if the input is a zero that as to and we'll move to a final state as three. Since 000 should be accepted. Now, we're not moving back to the final state s one because we don't want any sequins of triples of zeros beaks accepted. We just want 000 to be accepted. Suppose instead that the input initially is a one, and we'll move from as zero to a non final state. This will be a new non final state s for because the string one should not be accepted. And if the next input is a one at this state s four and we want to move from S four to a final state and here we can reuse one of the previous final states s three.

So given this coding scheme we have over here, we want to decipher these four words. So let's go ahead and start with a capital A. So we would start from the left, so it's gonna be zero. So we don't have anything for that. That it 01 still don't have any thing for that? Then we have 011011 that's going to be represented by T. All right, then we move on to 11 is represented by E. Then. So we already said that 01 wasn't anything. So we can look at 010 So I don't say anything there. But then we have 01 00 and this is s. And then we have 011 which again we already said that was t so a is a coating for the word test. Right? So now let's move on to be here So we don't have anything for zero or double zero or three zeros. But we do have something for a 0001 And so this is the letter be ah, one we already said was the ease that's gonna be and then we have one again. So that's another E. And then lastly, we're going to have so 0000 So that's are all right. Now, let's move on to see, All right. So again, we don't have anything for zero or 01 Um, 010 Nothing. But we do have something for a 0100 And this is s all right, then. One again is hey, and then so 01 We don't have anything. 010 Nothing. Zero ones there. One Nothing. But we do have 01010 in. This is X. So see is a coding for sex. Then for de So again we would dio so zeros Nothing. 01 Nothing's there. 111011 is t thin. You could see that zero zero's one is a And then again, we already said that. 010101 Well, this is X. So D is a coating for the word tax.


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