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1. What is the pH of a weak acid (HA) solution of analytical concentration = 0.53 straight M and Ka = 3.578 times 10 to the power of negative 5 end exponent assumin...

Question

1. What is the pH of a weak acid (HA) solution of analytical concentration = 0.53 straight M and Ka = 3.578 times 10 to the power of negative 5 end exponent assuming open square brackets straight H to the power of plus close square brackets greater than greater than open square brackets OH to the power of minus close square brackets and open square brackets HA close square brackets greater than greater than open square brackets A to the power of minus close square brackets?The pH = Answer2. If w

1. What is the pH of a weak acid (HA) solution of analytical concentration = 0.53 straight M and Ka = 3.578 times 10 to the power of negative 5 end exponent assuming open square brackets straight H to the power of plus close square brackets greater than greater than open square brackets OH to the power of minus close square brackets and open square brackets HA close square brackets greater than greater than open square brackets A to the power of minus close square brackets?The pH = Answer2. If we calculate the pH by assuming that open square brackets HA close square brackets greater than greater than open square brackets A to the power of minus close square brackets is valid when it is not , how will our approximate value compare with the more correct value. Select one of the following options.The approximate pH will be Answerthe more correct pH. please answer it so fast just five mins remainsolve it faster that the light so fast so fast



Answers

Predict which solution in each pair below will have the lower pH. a. $2.56 \times 10^{-2} \mathrm{M} \mathrm{HCl}$ or $4.09 \times 10^{-2} \mathrm{MHBr}$ b. $1.00 \times 10^{-5} M$ acctic acid $\left(K_{\mathrm{a}}=1.76 \times 10^{-5}\right)$ or $1.00 \times 10^{-5} M$ formic acid $\left(K_{a}=1.77 \times 10^{-4}\right)$ c. $22 \mathrm{mM} \mathrm{CH}_{3} \mathrm{NH}_{2}\left(\mathrm{p} K_{\mathrm{b}}=3.36\right)$ or $22 \mathrm{mM}\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}\left(K_{\mathrm{b}}=5.9 \times 10^{-4}\right)$ d. $158 \mathrm{mM} \mathrm{NH}_{3}\left(\mathrm{p} K_{\mathrm{b}}=4.75\right)$ or $158 \mathrm{m} M$ acetic acid $\left(p K_{a}=4.75\right)$ e. $0.00395 M \mathrm{HNO}_{3}$ or $0.00145 M \mathrm{HClO}_{4}$ f. $2.05 \times 10^{-1} M$ propionic acid $\left(K_{2}=1.4 \times 10^{-5}\right)$ or $2.05 \times 10^{-1} M$ fluoroacetic acid $\left(K_{2}=2.6 \times 10^{-3}\right)$ g. 375 m $M$ pyridine $\left(p K_{b}=8.77\right)$ or $375 \mathrm{mM}$ aniline $\left(\mathrm{p} K_{\mathrm{b}}=9.40\right)$ h. $0.555 M \mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{3+}\left(K_{2}=3 \times 10^{-3}\right)$ or $0.355 M \mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{3+}\left(K_{2}=1 \times 10^{-4}\right)$

So we have all of these solutions and we're attempting to match them to a few marks on a ph scale. And, uh, with so many of the solutions, uh, it's, ah, a bit too time consuming to attempt to go through all of the details of each calculation. But if you have been working the earlier problems in the chapter than you are familiar with the K and K B calculations and frequently we write wind up with with, um, X equals the square root of I'm sorry. That's the square root of Casey. The equilibrium, constant times the concentration. Now for the first solution, the sulfuric acid that is a strong acid. And so we don't have to do any equilibrium Calculation at a point. 01 Moeller, if you take the log of point of one, you get to and there will be additional age plus from the second dissociation. And so the pH should be less than two. And so that doesn't really looks like one of the Marxist around 2.1. And so that one does not match up. The ammonium chloride, um, has a pH. Around 4.6. So I had to take the K B for ammonia and used the K W and the K B to get the K A. And so that's Casey. And let's see 4.6. Yeah, that could be Ah, looks to me like that. Mark is at 4.7, but it looks like that one matches the mark there. That's close to five. Ah que i the potassium and the iodine are both acid based Spectators, and so this is a pH neutral solution Ph. Seven solution. And so that is not ah marked on the scale said that one also doesn't match up the metal. A mean I looked up its kay bee and it's high and the polarity is low. And that is the indication that you are not going to be able to do square root of Casey. But rather the initial concentration minus sex. Times K is equal to X squared, and rather than taking the square root of both sides, we have to multiply it out. Anyway, I come up with a pH of 3.13. Does not look like that is marked on the scale here. Ah one. Mueller H oocl Ah, I looked up. It's k A and uh Oh, I'm sorry. Hold on, let me back up. 12 the ammonium. Ah, the middle mean. Ah, that X that I get is not for age plus before oh, age minus. And so this is the P. O. H. And the P H would be 10.87. And there is indeed a mark there. So that that is thedc 0.87. And what did we say? The 4.6 there. And OK, so now continuing with the HCL. I'm sorry. It comes out. Ah, around 3.8. There is nothing marked at 3.8. Um, let's see, We're looking for the one that's gonna pH around, too, and that happens to be the chloral acetic acid. So I looked up. It's k A. And ah, it, um, has a very high K 1.4 times 10 to the minus three. This is a rough estimate, because actually that is 16% association. And so, taking the square root of Casey, you're gonna be significantly off. Ah, but ah, that looks like here were 6% of the initial concentration by on so dropping the X puts us a little off, but this one's going to be close to, uh, 2.5, and it looks like that Mark is closer to around 2.1. And so that is the 3rd 1 The ah chloral acetic acid. It's probably it's Ph is closer to 2.2. We would get a little less value than that, so I'm going to say 2.2, and this one is going to be a very close to 2.5, and so we have matched up some of them.

Solution for part e. We have a region is see is three syllable edge. See the below less it positive K is equal to it's positive. Concentration into C is tree seed of a low. They get to concentration. Divided by see is three see develop each concentration. It's positive concentration as equal to behave See is three. Seed of Alona Get to concentration so get a Is it weird to it's positive All square divided by concentration off See history Cedar Village It's positive concentration is equal to and different Get a into concentration off c'est three CDA below it UK is equal to look okay. Yeah, since the judging we'll use we get it's positive. Concentration is equal to under Route one point 1.7 Multiply 10 raised to the power minus five. I want to play. One is equal to 1.7 magic light In rest of the power minus five be it is equal to minus Look into concentration as positive is it will do 4.76 STP Age is solution for part B in a similar way. It's positive concentration is equal to undershoot. Get a multi play concentration. All CS three in its two substituting values we get here is positive. Concentration is equal to 1.9. Multiply can rest easy power minus 11 multiply. 0.1 is equal to 1.9. Multiply 10 Recipe Barber minus 12 and he is is equal to my knees. Log in due expository concentration. Is it well, too? 11.7 Mr P. It's me and you in solution for part C Using Henderson history. Bold vision we here get here is equal to pH plus log concentration off pursuit devoted by against additional fees. Be it is equal to beat it, minus log concentration off a suit divided by concentration off base here, a suit concentration is equal to 0.3 and Basic Instinct Crecion is equal to 3.7 seats. Such a shooting will use. We get be. It's is equal to P. K. Minus log 0.3 upon 3.7 seats is equal to 3.76 minus log. 0.797 is equal to 3.85 Devalue off. It's

So it's actually a pretty quick problem here. Remember, the pH is equal to in negative law of our concentration of H 20 plus. And so, since we're given this, it's really easy to find Ph. So, for our first scenario here, where are concentration H 20 plus equals 0.44 bowler. You can plug that into this formula and you'll find that pH is 1.35 65 I'm gonna write off two extra so that we'll see why that's important. Prince 0.45 Mueller, we have 1.3467 His point is your 46 Mohler. It is my apologies. 1.3372 And so take a look at what happens. So if we only tapped, for example, three digits overall, In other words, we cut it off here and we rounded. We wouldn't be able to appreciate the difference in the constellation here. Even worse if we decide. Oh, we only have Ah, Michael eyes mark that wrong? A common mistake is to think. OK, well, we have to significantly use here, so, um, we're gonna only keep two right here. And so then if we round, we're gonna end up with the values 1.31 point three 1.4. And this really, truly doesn't capture. The difference in the pH is on this makes appears. If there's only a difference of 0.1 when really work? Um, traversing a little bit more than that. And so, uh, rather it exaggerates it here, and it exaggerates the difference between these two, but under represents the difference. It's abuse to pieces. And so, in other words, instead of cutting it off after two significant figures of the pH, we do it after two decimal points, and then we can have pH. Is that really represent much more accurately what's happening?

So asked h r create the pH of each. So we have the concentration of its Jill. Um, so we know that the equation for a P H is equal to the naval vlog of the concentration of a trio. So what I'm gonna do is just plug them into a calculator. I see that if I plug in the or try to solve for the pH. Uh, when our HBO plus concentration is point girl for four, I plug in to my calculator. Negative log of 0.44 What, you have a name? 1.3565 Let me just double check that negative log. Uh, 0.44 Right. That's fine. So we did the same for it. A concentration of 0.45 That doesn't point 1.3468 and then not for your cage for last one is 1.337 two


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