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The enthalpy change for converting 1.00 mol of ice at -50.0°C towater at 70.0°C is _____ kJ. The specific heats of ice, water, andsteam are 2.09 J/gK, 4.18 J/...

Question

The enthalpy change for converting 1.00 mol of ice at -50.0°C towater at 70.0°C is _____ kJ. The specific heats of ice, water, andsteam are 2.09 J/gK, 4.18 J/gK, and 1.84 J/gK respectively.For H2O, ΔHfus= 6.01 kJ/mol,and ΔHvap = 40.67 kJ/mol.Please explain to help me study. Thanks!

The enthalpy change for converting 1.00 mol of ice at -50.0°C to water at 70.0°C is _____ kJ. The specific heats of ice, water, and steam are 2.09 J/gK, 4.18 J/gK, and 1.84 J/gK respectively. For H2O, ΔHfus= 6.01 kJ/mol, and ΔHvap = 40.67 kJ/mol. Please explain to help me study. Thanks!



Answers

The enthalpy change for converting 1.00 mol of ice at -50.0°C to water at 70.0°C is _____ kJ. The specific heats of ice, water, and steam are 2.09 J/gK, 4.18 J/gK,
and 1.84 J/gK respectively. For H2O, ΔHfus= 6.01 kJ/mol, and ΔHvap = 40.67 kJ/mol. Please explain to help me study. Thanks!

Hello students in this question we have to calculate the entropy change on freezing of one mole Of water at initial temperature equals to 10° integrate. Two ice, add the final equals two minus 10 C. Okay. And delta Fusion for the entropy of fusion it is equal to 6.03. Kill a jewel per mold, add Jiro degree centigrade. Okay. And we have given the specific heat for the hide water in liquid and solid form. So this changing entropy delta edge will be involved in three process. The first process is cp molecular delta T. And the C P. Is for the water in the liquid form. Okay no plus delta edge for the freezing. Okay. And plus delta C. P. Of solid manipulative delta T. Okay so this is a liquid to conversion into liquid to convert up to zero degrees integrate. Okay and then it is freezing at zero degrees integrated. Then it is converting into solid form up to this minus 10 degrees integrate. So hence we can substitute the value So cp for the liquid. It is given as 75.3 jewel per bowl per kelvin. And temperature difference will be zero minus 10 0 is the final and 10 degrees integrate. Is the initial. Okay plus delta changing and healthy for diffusion. It is this value. So converting this into June so this will be 6030 jule For more. Okay plus 6030 Plus CP for the solid. Which is given as 36.8 jewel per mole kelvin inverse. And the temperature difference will be this is the final temperature up to which it is converted and the initial temperature is geo. So from here after solving we get minus 7 37 53 plus 6030 and minus 3 68. Okay or this value is in the negative. This value will be in the negative because it is the heat of and help it. Okay, so from here after solving we get minus 7151 Or it can this is in the jewel per mole, so it can be converted into a jewel. So delta actual B equals two minus 7.151 Tell a jewel for more. So this becomes the answer for this problem. Okay, thank you.

So in this question, we have a mountain of eyes going from solid water to water. Don't touch. A cop commits that That's a hitch for the reaction. So that's a hit, for the reaction can be obtained by subtracting the deaths. Each of permission of the solid eyes from the death hates information off every water. And to do that. So that's a hatred for us and would be most warm. Roll off the water much apply by page information of water, which is 285 months eggs. Can I just Oh, Andi. I was trusted. Page information off the solid ice, which is 29118 months by one, and vicious gave us is good. More so. We need to know that they're out there. T or this reaction will be there, going from five degrees. Sell shares to zero in every cell ships. So the initial temperatures 25 degrees. So shows and the finance Emperor Julius Social Facility dealt too achy fine on my honesty in this year, and that means a degree in minus 25 degree sells just now be minus 25 degree starship. Also, we need to know that I should be lost by the bridge. And, uh, it's lost by beverage. He's gained. My heist would be negative. Lost five. Beverage. Okay, so it's lost by beverage. Would be must off the bed fridge. Much apply, especially its capacity average. Okay. And this has been negative. Dissident minus. We had thought that the body move The beverage is three history 55 mil and assumed the density of water, which is one ground meal. And we can determine the mass of the beverage because we know that density is mass of the ball. You there for the massive, it decimating. What's black? My volume in over 355 million. What's by by one grams for meal and now he goes on the muscle but their bridge to be 355 grams. So just to be 355 grams, I want to fly by the special tickets capacity. We assume that's a Water Joe's program. Grace. She has much of a lie by the change in temperature Joyce minus 25 degrees Celsius. So you should give us, um, this'd be us three 71 33 Joes and that's it's 1234 That is three points. 7133 Oh, no, that is That's seven 0.133 Giorgio's. So no, from this, uh, dark age of reaction. Oh, no, no, That one. Also, this killer Joe eats will converts. Well, that's Whoa, whoa, whoa. Hi. Studio liquid. Right. Therefore, Tex 7.133 killer Joe will convert, So thanks. Just cross multiply we. That's 7.133 Divided by six. Call him. No, he that 711 complete about six have a 6.18 more. One is nine mole. And we know that, uh, the more llamas off water is 18 points at you. Grounds for a hole. The Air Force 6.189 mole be its implants. Zero to science explains Wanted nine hole And now give us Yeah, just right up on the next page till myself. Highs will be 18.0 to grass mole times 6.1. It's nine more and down. He must 111.5 grams. It has to find a handsome

So when I smelt, it is the chemical. The chemical equation for for that process is solid. Water become liquid water on the anthro p of this reaction is the information off the formation and soapy off liquid water minus information and topi of solid water, which is six killed. Joe promote on the amount of heat that absorbs by the brother beverage you caused to emcee daughter T. So where there's a question we can calculate, we can calculate the amount of heat. Need the amount off heat needs to be taken off from the beverage. They told her amount of heat on the amount of oxygen in the month. The amount off eyes needed to take away this heat equals to the killed divided by doubt by daughter age On the mass off ice equals two equals two in them, which is 110 grams of ice

Lastly, to look over some contextual information. We have definitions for the heat of fusion and the heat of vaporization that stood up with top. So firstly, he effusion is the quantity of energy necessary of heat necessary to change 1 g of assorted to a liquid with no temperature change. Next, the heat of vaporization is to find the same out of heat need. It's down 1 g of a solid into a vapor. So now to look our key values so fastly. We're looking at the heat required to heat from negative 32 0 degrees Celsius, which is 1.1 time sent to the three jewels. Following this, we have a hit fusion, which is 6.2 times 10 to the three jewels. The heat required to heat from no tu 100 degrees Celsius is 7.52 times tense. Part three. Following this, we have the heat required for vaporization, which is 40.7 times turned to the power three. Next, the heat required to heat from 100 to 140 degrees saltiest is 1.45 times 10 to the three. So now we've determined Q one Q two Q three, Q four and Q five. We simply add all these together to get the summer off. So not the product officer. We're not multiplying. We're just adding these values for the total Q volley off 56.8 times, 10 to the three.


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