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Tta 0, bulb (D) is connected in fourth The circuit is returned t0 its original state_ Parallel with bulb B (not in [atallcl with QHclSketch the bulb in the circuit;...

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Tta 0, bulb (D) is connected in fourth The circuit is returned t0 its original state_ Parallel with bulb B (not in [atallcl with QHclSketch the bulb in the circuit; of each of the three bulbs? What happens to the brightnesshappens to the current flowing through point = Whatpoints 3 and 4? What happens to the potential difference betweenpoints and 2? What happens to the potential difference betweenFor what type of circuit elements does it correctly State Ohm's law in words- describe the beha

tta 0, bulb (D) is connected in fourth The circuit is returned t0 its original state_ Parallel with bulb B (not in [atallcl with QHcl Sketch the bulb in the circuit; of each of the three bulbs? What happens to the brightness happens to the current flowing through point = What points 3 and 4? What happens to the potential difference between points and 2? What happens to the potential difference between For what type of circuit elements does it correctly State Ohm's law in words- describe the behavior? constant resistance? Explain. Is light bulb ohmic? Does light bulb have constant resistance? Explain. Is resistor ohmic? Does resistor have



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The filament of an incandescent lightbulb is made of tungsten. At room temperature of $20.0^{\circ} \mathrm{C}$ the filament has a resistance of $10.0 \Omega$. (a) What is the power dissipated in the lightbulb immediately after it is connected to a $120 \mathrm{V}$ emf (when the filament is still at $\left.20.0^{\circ} \mathrm{C}\right) ?$ (b) After a brief time, the lightbulb filament has changed temperature and it glows brightly. The current is now 0.833 A. What is the resistance of the lightbulb now? (c) What is the power dissipated in the lightbulb when it is glowing brightly as in part (b)? (d) What is the temperature of the filament when it is glowing brightly? (e) Explain why incandescent lightbulbs usually burn out when they are first turned on rather than after they have been glowing for a long time.

My friends as soon in the figure in the given circuit, Get up for electric lab Each offer. Dispense Harmon Harden Our treat Our hope 4.5. Connecting across the battery off a M F nine bolt in the first part, we have to fire the current through each ball. We have to calculate the power developed in each month. See if our hope is removed. They current through each level. The power in each built a part which bulb glow brighter. Let us see it first part in the first part the the distance our toe R three and R four are connected in, you know, Parliament. So the equivalent resistance off 234 buildings 415 upon three That is 1.5 so ever circuit can be reduced toe. This is urban, and this will be our 234 so current flowing through Harbel and 234 when we e upon our equivalent. That is nine upon 1.5 plus 4.5 that is 1.5 and peers hence current through urban is 1.5 appeared no, and cutting toe art are three on our for profit. The same because they're connected in talent on having same resistance so current can equally distributed between them. So, through each baby, 0.5 appears. Now we have to find a power developed in second part. Power is defendants I Urban Square in tow. Urban, that is 1.5 square in tow. Urban, that is 4.5. So it is to me, after calculating it, poverty will get 10.1 Watch power through Are you artery? Are for each having the same madam while five the script into for one fight that is 1.1 to watch. Now see part If our full is removed, then r two and r three are in peril. So it's simple equivalent resistance you will get for while five upon two that is 2.25 home now. Equivalent circuit will be badly. Harmon Yeah, are 23 so current through urban and our 23 will be the same. That is e M f. Upon our equivalent, that is our ventless are to three. You will get nine upon 415 plus 2.25 So it is to be one policy three appear heads current tow our wind up 1.33 MP in and current through R two and R three will be seen and this current will distribute equally because they are connected Independent Andhra distances say so. Its current will be mhm 0.666 Ambien now power across Barman, the department. This is the answer of sea Part. So I Albany square in tow. Carbon that is 1.333 square into 4.5. So you will get the power, Toby. It what and power across are, Well, archery having the same men. That is 0.66 70 square in tow. 415 So it just to be around to watch so urban well, close brightest. Yeah, their salt. Thanks for watching it.

In the given problem, there is a circuit diagram having few bubbles arranged in mixed grouping off cities and better like shown here. This is the resistance. Are one the bulb having resistance off our one? Then this is another bowl having a resistance on four. Then here, this is our to and fun of me. Another ball is joined diagonally here. Having that does this dance are three and a common source off enough! He supplied here on the positive and the negative potentials as shown here. Each resistor is representing a light bulb and all the resistors are having the same value as part given question are when he's a good article is equal toe Party is equal to R four and all are having a value of 4.50 home and the ineffable light is having a very off 9.0 full. No. In the first part of the problem, we have to find the current in each boat for which, first of all, we need to find the next resistance off this combination or which this are true and artery and are four are in parallel. Are too are three and our four are in a parallel combination. So their net resistance if RP the darkie is found using the expression for pattern combination has one upon our peaceful 11 are too less one upon our three Bless someone upon our foot and it becomes one by 4.5 plus one by poor buying five plus one by 4.5 is equal to treat by 4.5. So this art be here comes out to be one one fight on No, this r p is in Siris We are one So next resistance met effective resistance off This combination is R one plus r p means 4.50 home must 1.50 on which comes out to be 6100 Well, so current the net current passing through the circuit I, which will also be equal toe I won is the current passing through this resistors are well as currently insane in cities. So I or we can say I won the current passing through Resistance army is given by Onslow as e by are effective the neck resistance You're the city is nine roll 9100 worlds divided by this 6.0 on. So this current year comes out to be one going five. And you This is one of the answer the current passing to resistance. Ottoman? No, we have to find current in each and every distance. So if we give this square as a name A and B, this terminals are named as a baby so good, and in this barrel combination, we'll also be same. I b r i b. We'll also be seen as this combination is in series with are one and the current will be 1.5 here. Now, this current 1.5 enter will be divided into three parts. As I do, I cream and I for and as all that three resistors are equal to the current will be divided into equal parts. So I do. They re equal toe. I three will be equal toe I fought which is one third off the total current. So we can say 0.5. And here So the three currents are having a value of 0.5 and marriage and the net current or the current through possible is 1.5 in peer. No, the next part off the problem in part B. We have to find the power dissipated in each bulb. So to find the power dissipated, you will use the expression for power, which is ice. Parenteau are so for people. This is I one aspiring toe are one which becomes 1.5 for the whole square multiplied by 4.5. In what? Which will come out to be 10.1 toe. Five What then for be to and B three and people means all the three bolts arranged in parallel. The power dissipated. Maybe seen giving by 0.5 square into 4.5 in each will be having a value off 1.1. Don't by what So here this will leader bright this. No, this is the answer For the second part of the problem, R B counterpart the bulls are four is now removed from the circuit leaving a break in the Vire exposition. So if we remove this are for from the circuit, let him bit more So Now only two resistors are in parallel here. This is R two and R three. So now removing our fourth the net resistance off parallel combination will come out to be 4.5 divided by two Home. What we can say this is group Fine. Do five bomb. So now net resistance effective resistance off the combination will be just to find 25 plus Armand which is 4.5, which will come out to be a 6.7 by home. So now if we have to find the net current passing through this combination, it will come out to be I already with the same current preaches passing through our mind which is like was toe Ivan, divided by email by our so now are effective on August this again 9.0 world divided by 6.75 So this current comes out, we want 133 And yet and similarly its current for that will be divided into two equal parts across R two and r three. So this will be our I do and I treat, which will be 1.33 divided by two. And it comes out from a 0.67 And here these are the no answers for third part of the problem. No. In the fourth part of the problem. We have to find the power dissipated in these bumps. No. So as far as the one is concerned, the power on June impossible again using the same thunder, I swear into our yet it becomes but squared off 1.33 multiplied by 41 fight. It comes out equal toe eight. What on for P two and p three. These will be equal 0.67 whole square multiplied by 4.5 and we'll come out to be approximately two. What? Each? No. In fifth part of the problem, we have to discuss which light bulb glow brighter as a result off removing our four. So then we remove this Arcor, which of the lightbulb really start growing? Glowing more. And here this is the answer. This is this will meet up right? This the first one so we can write it here also the first well, but we have to compare the brightness off these bulbs with their earlier brightness. Then there waas the fourth ball also in circuit. So if we compare these brightness No, we have to compare the perverse These farmers you would have to compare them. These are our sales. So it is clear that the brightness off the first ball has been reduced, as it was earlier. Approximately 10 words. Now it is. It works. So it has been reviews. But the brightness off the other bulls as the increased they were having a brightness off. One approximately one work in Chile. Now they are having a brightness. So you're so we can say the brightness off first belt has been reduced from 10.125 What do Edward and doors off in Batterman has been increased Has bean Ingres increased from 1.1 to fight what toe approximately Do what. And here it becomes answer for fifth part off the problem. And we have to discuss also why there are the different federal on different limbs. So the reason is that then there were people's in this battle in communication, a current off the circuit waas being divided into three parts. So the current was less in these three balls as a current was less toe brightness waas less but then we remove one off the ball. Now the current will divide will be divided only doubles. So now there will be more current in these screwballs. There's the brightness me in Greece. Thank you

In this problem, we are given the circuit and the power that it dissipates. When we connect a source of potential to each of this point, A. B or C. Now that's fine. Are one for part any of the question? We're told that uh huh. When we connect A. And B to the source of potential, The circuit dissipates in power of 75 watts. Now when we connected over here we only have our one. So our one is equal to the total resistance of the serpent. And let's remember that power, let's write that up here because we're going to use that throughout the problem. Power is equal to vote times correct the potential difference times a current and we know that the current can be written as essential difference over the resistance. Therefore we can have power the equal to the potential difference squared by multiplying these two B's over the total resistance of the circuit. So over here our total resistance Is equal to R. one. So now we know that the power mm that portion of the circuit is going to be equal to the potential difference over are one. Therefore are one is going to be equal to the potential difference over the power. And we have everything we need to solve this. We are told that the potential difference is 120 bolts And we are told that anticipates 75 watts And that is going to give us a resistance of 100 92. Mhm correct. Now important B. What we have is the potential, the source of potential connected to A and see. So now the total resistance is no longer our one simply it's going to be our one Plus R. two because they are connected in series ignoring the branch B. We only have R. one R 2 chokes. Now the power from connecting A to C. It's 50 words. So we'll have that the power with people to the potential difference over are one plus are too. And when we solve for R. one or I'm sorry for our two. We already found our one up here. When we solve for aren't too we obtain that. It is equal to the potential difference over the power minus are one. And again we have all we need. We have the potential difference. We had the power from up here and we have the resistance God we found previously and that tells us that this resistance is going to be Equal to 96 arms. Great. Now we want to find the power that would be dissipated if we were to connect the source of potential to B. And C. So when we do that, Our total resistance is our two. So we can use the equation of power that we have been using. Power B. C. Is equal to the potential over the total resistance, so that's our two. Therefore we have 120V squared over 96 Holmes, And that will give us 150 watts. And those are our answers.


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