5

PeecMETnordisnnce d =0A79 lun Ulc Fitend 4 boam u4 Lha liauo ne bOjd / Gupponted buard E uniton Icnoth / (hree cabias. Find tha tension andma : J0,5 kg; and weaht I...

Question

PeecMETnordisnnce d =0A79 lun Ulc Fitend 4 boam u4 Lha liauo ne bOjd / Gupponted buard E uniton Icnoth / (hree cabias. Find tha tension andma : J0,5 kg; and weaht Inc Dureon cablo (In NJ}: (Duc to Your calculanone ne ManI utni; problain; Illuding 7nsyery subinlttes Webession ) nal USU rounded mLLumcolntn tel_Tnteuton nox beointcaulnLuponnakh cabla {alisUJble ?Atwnal Icaon Aolainis CC ITlmin7Tromteran,Dojue

peecMETnor disnnce d =0A79 lun Ulc Fitend 4 boam u4 Lha liauo ne bOjd / Gupponted buard E uniton Icnoth / (hree cabias. Find tha tension andma : J0,5 kg; and weaht Inc Dureon cablo (In NJ}: (Duc to Your calculanone ne ManI utni; problain; Illuding 7nsyery subinlttes Webession ) nal USU rounded mLLumcolntn tel_ Tnteuton nox beoint cauln Lupon nakh cabla {alis UJble ? Atwnal Icaon Aolainis CC ITlmin7 Tromteran, Dojue



Answers

Find the tension in each of the two strings shown in Figure $6-30$ for general values of the masses. Your answer should be in terms of $m_{1}, m_{2}, m_{3},$ and $g$.

Okay in this problem were given two different scenarios where we have a weight hanging off of some chords and you're asked to calculate the tension and each one of the chords here. So let's draw our situation. We have, um, our first diagram here, and we have our weight hanging off. And we have, um, see, eh? And B, and the record is at a thirty degree angle. And ah, record here is at a forty five degree angle to the ceiling. So my mark points one and to here, and we're going to drive force body diagrams for each point. So the first body force body diagram for one is pretty simple. You just have cord. See the tension in that pointed upwards and you'd have, ah, the weight of our object pointed downwards. And our second force body diagram. We have a few different forces pointing in different directions. So we have a pointed off like so he directed upwards and now see is pointed directly below. And just so we have throwing our reference frame here. So I'm gonna break down and be here into the components of sea just s. So we stay within the um, X y reference frame that I have established. So, um, we see that sea we'Ll just stay the same. And if we break the beyond and the components on the vertical component of the attention do the court B will be be sign of forty five degrees and the horizontal component that is be co sign a forty five degrees, and we're going to do the same thing with cord A. We see the vertical component is going to be a time's the sign of thirty degrees, and the horizontal component is a times the CO Sino verity degrees. Okay, so we have a fourth body diagrams. Um, we have three unknowns and our tensions in the three different chords. And let's see. Ah, we're gonna have three equations were going to set up here. So from everybody but diagram, number one, we just have the tension to seem minus the weight sequel to zero. Um, assuming no acceleration. So we see that sea is just equal to W um, and our second part, let's do the horizontal components first. We have being times to co sign of forty five degrees minus and co. Sign of thirty degrees equals zero. And here, um, we have ah, bee sign of forty five degrees plus hey, sign of thirty degrees minus C is equal to zero. Um, so first things first I see econ substitute wn for sea here and move it over to the other side on DH. That will give me this equation here and then. Now I have a system of equation with two unknowns and two equations, Um, here and here. So I want to eliminate one of my, um, unknowns here and solve for the other. So we can use our knowledge of trig to say that co sign of forty five degrees is equal to sign and forty five degrees. So if we just subtract these two equations from each other, um, the first terms and each one will cancel each other out. So, um, that would leave us with negative, eh, co Sign of thirty degrees. Um, plus sign of thirty degrees is equal, Tio, um, negative W So those negative signs and either side cancel out. And in the end, you get that is equal to, um w over co sign of thirty degrees plus the sign, Ah, thirty degrees. And, um, when you plug in the numbers for coast on thirty and sign of thirty degrees you'd get that is equal to zero point seven three two Ah W Now let's move over here toe. Now solve for B S O. From this equation, we can get B in terms of a So it would just be a times the co sign of thirty degrees, long times the co sign of forty five degrees. And I mean probably inappropriate values for A and B. I get that This is equal Teo zero point, um eight, nine seven W So in the end, we saw further tensions and all the chords we found C um A in terms of W and, um be here. So with that, we are ready to move on to the next part. So let's look at scenario B. Here. You're given something that's hanging in the corner, the ceiling, and we have one chord coming down from the ceiling, one coming from the wall than at the intersection Point of two chords. We have one cord hanging down and again, we have some weight hanging off of this, and our angles have changed a little bit. Here we have a sixty degree angle at the bottom and a forty five degree angle on top. So just like before, I'm going to make a force that body diagram for two points we have here we have See, W again can't forget my reference frame here. Always a good thing. The label. So that's one. And then two, we're gonna have, um, another free body diagram where we have the forces pointing and all different direction. So we need to break down some of them into their components so that we can write out Newton's second law equations. So, um, when I break a down into the components, the vertical component will be a Times Co sign of sixty degrees here. And, um so go had in label. That and the horizontal component will be eight times the sign of sixty. And Virgil Cole Component be will be co sign twenty five degrees, and the vertical component will be equal to B times a co sign or sign of forty five degrees. But those are synonymous anyways, so just like last time on what I set up my noon second law equations. I've seen mice w equals zero. So, like in the previous part. We have just c is equal to w um Then we have, uh, church. Hey, Sign of forty five degrees minus a coz I know sixty minus c and I'm just gonna insert in w now, since we are, I know that equals zero. So be signed. Forty five degrees Linus, a co sign of sixty degrees is equal to W Then another equation we have be co sign of forty five degrees is ah, the positive part and their report of as a sign of sixty degrees and that would all be equal to zero. So again we see that we have two terms that equivalent since sign and co signed forty five degrees or equivalent. So if I subtract these from each other, we would get um eh and ah, I'm just going Tio, keep this coefficient positive for now And you'LL see I'll leave the negative that you get here inside or parents sies so isolating a Here we get that is equal to this expression And when plugging in the proper values for the sign and co sign of sixty degrees, I find that a is equal to two point seven three W and just like before, we can use one of our equations here The the cosign forty five degrees minus a sign of sixty degrees equals zero to put use. Ah, defined be in terms of a So we have He is a time sixty degrees co sign Ah, forty five degrees. And so this is going toe, um increase the value of a so that he is ah larger attention force and is equal to three point three. Bye w seven. We have now once again solved for the tension in the three cords kind of crossed out the answer there in this picture.

For this problem on the topic off Newton's laws, we want to calculate the tension in each court in the figure has shown, if the weight off the object that is suspended is w. So before we start well, let our vertically upward direction be positive. Why and to the right as our X axis. So plus X for part. A. We know that detention in quad C T. C. Is equal to W. We also know that we can balance the vertical components off the retentions, or t. A sign off 30 degrees. Yes, TV sign off 45 degrees must equal to detention called C T C, which is w balancing the horizontal components. We have t a times the co sign off 30 degrees minus TV. I'm the co sign. 45 degrees is equal to zero now for the last two equations. Since signed 25 degrees is equal to cost 45 degrees. We add the two equations and we get t A into he co sign off 30 degrees. Plus he's sign off. 30 degrees is equal to W. And so from here we confined detention and called a in terms of W. T. A is equal to w over everything in the bracket, which is 1.366 And so we get t A to B 0.732 Thanks w And then similarly, we confined TV so TV we put it into the equations above. We get TV to be tha into costs off 30 degrees over cost 45 degrees from Substitute Ian. They we get TV to be 0.897 w So those are our tensions in A and B for part a off a problem. Now we do the same for part B now. Similarly, TC is again equal to W. But in this case we have minus t a times the co sign off 60 degrees plus TV times. A sign off 45 degrees is equal to W and also t a sign off 60 degrees minus TV times. The co sign off 45 degrees is equal to zero. So again we have two equations, and if we add the two equations we get t A. Is equal to W, divided by the sign off 60 degrees minus the co sign of 60 degrees. And so we get t a in terms of w to be to 0.73 w and then we can calculate TV so TV is simply t a times he signed off 60 degrees over the cosine 45 degrees, which gives us attention. Could be to be three 0.35 w.

So let us consider a seaman bag the chance from three wires. Why one Quiet too. On Viatri It is in this phone. So this is why I won. This is why I to this is why a tree No two wires make anger theater one and theater to with the horizontal. It is considered this to be t one, This TBT too on this to be 3 83 The weight off the Symon bag is given to be m G or we can tell or it is given to be f t. Is this what is given to us? So when the system is in equilibrium system in equilibrium, then what happens is the t three. Is it culture? OMG know where this G is? The acceleration due to gravity. Now we have to resolve t one and t two in science Tita on cost theater companies on then put it in the equilibrium condition. So when they put thes resolving in the Librium condition we'll get that t one cause theater one equal to teach to boss theater too anti one sign Peter one equal to t to sign Peter too equal to t three. That is it calls to empty. It is considered this to be equation number one. I just consider this should be equation number to now from one. We get that from a question number one, we're getting that t two equal to the one into almost eight. A one upon our state A took. Now, when you're substituting, it is considered this to be three. Now we're substituting the value off 20 in equation number two. So substituting question number three in equation number two. What we're getting is what we get this t one sign, Peter one plus, Do you want Ball State? Er one divided by false data to into scientific tattoo equal. Do empty. It is equals to the one sign pita one plus t one boss theater one into time, Peter one. So you can see that too equal to M G. So from this weekend, take it even as common. So it will become t one in two. Sign theater one plus cost theater one into 10 Peter too equal to M G. Therefore see, one can be written us mg divided by sine theta one plus pause theater one into 10. Tita too. This is what we get but in the proof you have to get it in a different way. So what can we do is we can write mg divided by sign theater one plus caused theater one in to Tante tha can return A scientist upon cost data the science theater to upon across the tattoo. So we're taking L C m next So it will be mg divided by sign Peter one into cost theater too plus or theater one into science. Pita too. Why did bite divided by cost The tattoo which is equal to t one equal toe mg. You will take Boss Tita upward mg into post theater too divided by sign off Peter one plus theater too, which is also equal to weekend. Right? It us t one equal to f d MD physical Swifty F d cause theater too divided by sign off, Peter one plus Tita too. This is the required equation that we have been asked for

According to Newton's second Law of Motion, the Net force acting on an object is directly proportional to the exploration of their object. It is difficult to m a, uh, equilibrium condition of force according to the equilibrium, condition and force. The necked force acting on an object is zero. So let the attention and the courts be the T. V and B See now draw the diagram we have. This is the object. Yeah, I say it's TV, of course, 45. And this is the A cause 30. Yeah. Sorry. This is lying tension T b mhm p a angle. We started 45 45. 30. This is T V Sign 25 and t a sign 30 this detention T c W So the night force acting in the horizontal direction that is F X is they called to submission of f x I so f x is t b cost 45 degrees minus t a sign 30 degrees and the net force acting in the vertical direction is why so f i is d a sign to t plus d be signed 45 minus 2 50 Newton. Since the whole arrangement is an equilibrium. The net force acting in the horizontal direction. Horizontal and vertical direction. The piece you know, it is the 9 30 degree plus TV signed 45 my sorry. 45 minus 2. 15. Newton must be zero. So the scientific committee less TV sign. What if I degree is it cool to to 15 years less? Equation one so and f X is equal to zero, That is, um, the air cost to T minus T v sign 45. Oh, sorry, cause 45. Difficult to zero. So from this t A S t B was 45 upon because 30 there is a cool two point 816 The the so substituting this value in aggression one, um, we have 0.816 TV scientific study bless TV signed 45. We're going to to 50. So from this tension in string B is 2. 24 Newton and substituting the value of TV in equation too to a physical to the refined 816 in 2 to 24 newton. So t is 1 83. Nathan. Um, the net force acting on the block is, um PC minus W is zero so PC minus W is to 15 year 10. So PC is too d Yet in the tension in each cards are 1 83 to 24 2 50. Now, um, second, let the tension in the car Bt 80 bn TC. So the diagram will be Do you object that they see the A 60 w Do you because 45 this is the egg sign 60. You have a 63 angle here, 60 degrees. This is the air 60 days a year we have 45 45 degrees 45 So I d be signed 45 degree. So, um, the Net force acting in the horizontal direction is Phoebe cause 45 My nasty A sign 60 and in the vertical direction TV signed 45 minus the air cost 16 minus w Let s t v signed 45 degree minus three EKO 60 minus 2, 15 18 Since the whole arrangement is in equilibrium. So the net force acting in the horizontal but vertical direction zero. So if X is equal to right TV cause 45 degree minus the air signed 60 is equal to zero From this to a physical Who TV? Because for every degree upon science 60 degree is there a 0.816 b B and F I S t V signed 45 minus t a core 60 my next to 15 or 20 0. Identification. Three. No, we have, um TB 9. 45 degree minus 0.81 60 b Cost. 60 degree is a call to to 15 year 10. So from this TV is 2 15 year 10 upon Signed 45 nagre minus 0.816 Cost 60 degrees. That is approximately 8 36 newton. Now substituting this value in equations one, that's only three We'll get TV Is the girls too? So the idea is according to a six 82 Newton net force acting on the block is TC minus. W is zero. So we have t c is equal to 2. 15 Newton. Therefore, the tension in each court is 6 82. Yeah, 36 2 50. You didn't


Similar Solved Questions

5 answers
Jestions: Using equation (3), the current balance can be used t0 calculate the value of the permeability of free space if all other parameters are measured: Based upon the accuracy of your data, is this a good method of obtaining /o? Jlo12 8 mg 2 TaWhat current would be required in your experimental setup to produce a force of IN?
Jestions: Using equation (3), the current balance can be used t0 calculate the value of the permeability of free space if all other parameters are measured: Based upon the accuracy of your data, is this a good method of obtaining /o? Jlo12 8 mg 2 Ta What current would be required in your experiment...
5 answers
Iaunch pointIaunch pointaxis
Iaunch point Iaunch point axis...
5 answers
Acredit card has a balance of $650 on October 6.A payment of $320 is made on October 20,and a purchase 0f $115 is made on October 30. If the billing date is November 6,what is the finance charge if the finance rate is an annual 18.5%?
Acredit card has a balance of $650 on October 6.A payment of $320 is made on October 20,and a purchase 0f $115 is made on October 30. If the billing date is November 6,what is the finance charge if the finance rate is an annual 18.5%?...
5 answers
RRRRsIn the circuit above, R1 is 5 ohms, R2 is 10 ohms, R3 is 15 ohms, R4 is 20 ohms, and RS is 25 ohms. The battery has an emf of 10 volts. What is the current that flows through the battery?
R R R Rs In the circuit above, R1 is 5 ohms, R2 is 10 ohms, R3 is 15 ohms, R4 is 20 ohms, and RS is 25 ohms. The battery has an emf of 10 volts. What is the current that flows through the battery?...
5 answers
A meterstick is made tO pivot without friction 30 cm from its end as shown. A metal cylinder is suspended with string from the end of the meterstick (ie, 30 cm from the pivot). The meterstick balances horizontally, remaining at rest as shown The mass of the string is so small that it can be ignored.culinder
A meterstick is made tO pivot without friction 30 cm from its end as shown. A metal cylinder is suspended with string from the end of the meterstick (ie, 30 cm from the pivot). The meterstick balances horizontally, remaining at rest as shown The mass of the string is so small that it can be ignored....
5 answers
(): By using corwolution thcormn finlthe irerseof following cquation(52+ @i)(s +02Hint: youmigh fin tke tigormtric idertitysin A cos Bz [sin(A B) + sin(A = 8)];Disuss both cascs whenw Wo a w
(): By using corwolution thcormn finlthe irerseof following cquation (52+ @i)(s +02 Hint: youmigh fin tke tigormtric idertity sin A cos B z [sin(A B) + sin(A = 8)]; Disuss both cascs whenw Wo a w...
5 answers
Froblejoc % Ceiitne the relation & oi Z ag followg: For all integerg m and %, ww & % if and only if 5 divideg (? Js 1 $ (-9)11) 1 2 $ 137Js (-8) $ 27
Froblejoc % Ceiitne the relation & oi Z ag followg: For all integerg m and %, ww & % if and only if 5 divideg (? Js 1 $ (-9)1 1) 1 2 $ 137 Js (-8) $ 27...
5 answers
2x 4y + 2z -18 3x ~ 2y 2z ~11 x -y + S2 = 16
2x 4y + 2z -18 3x ~ 2y 2z ~11 x -y + S2 = 16...
5 answers
138 8 1 3 H 5 1 H H 1 ] { 9 1 1 L 3 2 1 I J J 1H 1 1 1
138 8 1 3 H 5 1 H H 1 ] { 9 1 1 L 3 2 1 I J J 1H 1 1 1...
1 answers
Consider the titration of $100.0 \mathrm{mL}$ of $0.200 \mathrm{M}$ acetic acid $\left(K_{\mathrm{a}}=1.8 \times 10^{-5}\right)$ by $0.100$ $M$ KOH. Calculate the $\mathrm{pH}$ of the resulting solution after the following volumes of KOH have been added. a. $0.0 \mathrm{mL}$ b. $50.0 \mathrm{mL}$ c. $100.0 \mathrm{mL}$ d. $150.0 \mathrm{mL}$ e. $200.0 \mathrm{mL}$ f. $250.0 \mathrm{mL}$
Consider the titration of $100.0 \mathrm{mL}$ of $0.200 \mathrm{M}$ acetic acid $\left(K_{\mathrm{a}}=1.8 \times 10^{-5}\right)$ by $0.100$ $M$ KOH. Calculate the $\mathrm{pH}$ of the resulting solution after the following volumes of KOH have been added. a. $0.0 \mathrm{mL}$ b. $50.0 \mathrm{mL}$ c....
1 answers
Find the sum using the formulas for the sums of powers of integers. $$\sum_{n=1}^{15} n$$
Find the sum using the formulas for the sums of powers of integers. $$\sum_{n=1}^{15} n$$...
5 answers
Usa a table andlor graph to decide whether the limit exists If a limil exists, find Its value: X + 2x - 15 X-3What i5 the value of the Iimit? Select tha corract choica bokw and fill in any answar boxes in your choice.0A Tne Iimit I5(Simplify your answer ) 00 The Iimit doos nol oxist
Usa a table andlor graph to decide whether the limit exists If a limil exists, find Its value: X + 2x - 15 X-3 What i5 the value of the Iimit? Select tha corract choica bokw and fill in any answar boxes in your choice. 0A Tne Iimit I5 (Simplify your answer ) 00 The Iimit doos nol oxist...
5 answers
Why was liver of rat chosen as the target organ for cellular fractionation?
Why was liver of rat chosen as the target organ for cellular fractionation?...
5 answers
In his book, Caesar’s Last Breath, author Sam Kean states that acolumn of air around the Eiffel Tower in Paris weighs more than thetower itself. The tower reaches a height of 324m and occupies asquare base 125 m on a side. The pressure exerted by the EiffelTower is estimated to be 4.5 kg/cm^2. If the density of air istaken to be 1.19 g/L, what is the pressure exerted by a column ofair, 325 x 125 x 125 m?
In his book, Caesar’s Last Breath, author Sam Kean states that a column of air around the Eiffel Tower in Paris weighs more than the tower itself. The tower reaches a height of 324m and occupies a square base 125 m on a side. The pressure exerted by the Eiffel Tower is estimated to be 4.5 kg/...
5 answers
Evaluate the following: 5s/2 L-1 82 _ 4
Evaluate the following: 5s/2 L-1 82 _ 4...
5 answers
As result of a glancing collision with surface, the velocity of a 0.2 kg mass changes from 9 m/s directed downward, to 8 m/s directed 60 degrees below the horizontal What is the magnitude of the change in momentum of the mass?2.9 kg*m/s0.9 kg*m/s2.0 kg*mls4.0 kg*mls
As result of a glancing collision with surface, the velocity of a 0.2 kg mass changes from 9 m/s directed downward, to 8 m/s directed 60 degrees below the horizontal What is the magnitude of the change in momentum of the mass? 2.9 kg*m/s 0.9 kg*m/s 2.0 kg*mls 4.0 kg*mls...

-- 0.025968--