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# 22.8 continuedThe electron undergoes downward acceleration (opposite E) , and its motion parabolic while it is between the plates:S 0 L UTIO N Conceptualize This ex...

## Question

###### 22.8 continuedThe electron undergoes downward acceleration (opposite E) , and its motion parabolic while it is between the plates:S 0 L UTIO N Conceptualize This example differs from the preceding one because the velocity of the charged particle is initially perpendicular IO the elee- tric field lines. (In Example 22.7, the velocity of the charged particle is always parallel to the electric field lines ) As result, the electron in this example follows curved path as shown in Figure 22.21. The mo

22.8 continued The electron undergoes downward acceleration (opposite E) , and its motion parabolic while it is between the plates: S 0 L UTIO N Conceptualize This example differs from the preceding one because the velocity of the charged particle is initially perpendicular IO the elee- tric field lines. (In Example 22.7, the velocity of the charged particle is always parallel to the electric field lines ) As result, the electron in this example follows curved path as shown in Figure 22.21. The motion o the electron is the same aS that of massive particle projected horizon- mallv in gravitational field near the surface Of the Farth. Categorize The elecuon is particle field (electric). Because the elecuric field is uniform, constant elecuric force is exerted the elecuron To find the acceleration of the electron, we can model it as particle under net force. Analyze From the particle in Tield model, We know that the direc tion ofthe electric force On the electron is downward in Figure 22.21, oppesite the direction of the electric field lines: From the particle uuder nct force model, therelore , the acceleration of thc electron is downw:rd. Figure 22.21 (Example 22.8) An electron prejected horizontallv into uniform electric field producedby M charged plates Thc pattick Under nct force model Was used to develop Equation 22.H inthe cse in which the electric force O panticlee is the only force. Use this equation to evaluate the component of the acceleration of the electron: "= (1,60 * [0 C)(200 N/C) 4= 9.XIO- kg Substitute HumeTicalvales: 3X 10" m/s

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