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QUESTION 1A steel cylinder has a volume of 0.582 pints and a density of 7.93 g/mL. What is its mass in kilograms? (1 pt = 4 qt, 1 L = 1.057 qt)...

Question

QUESTION 1A steel cylinder has a volume of 0.582 pints and a density of 7.93 g/mL. What is its mass in kilograms? (1 pt = 4 qt, 1 L = 1.057 qt)

QUESTION 1 A steel cylinder has a volume of 0.582 pints and a density of 7.93 g/mL. What is its mass in kilograms? (1 pt = 4 qt, 1 L = 1.057 qt)



Answers

The standard kilogram is a platinum–iridium cylinder 39.0 mm in height and 39.0 mm in diameter. What is the density of the material?

Quantity of liquid weighs 4.65 lb, with a weight density of £39.. cubic feet. What is its volume? Okay, so we have The force due to the weight, or the weight itself is 4.65 pounds. The weight density, decent w is 39.8 pounds per cubic foot. So we need to find the volume. So by definition, the weight density is the weight per volume, so the volume is the weight per weight density. So, noticing that we have three significant figures, We will get a volume of 0.117 cubic feet.

Okay, We have brought number 11 night. Okay, well, one night. Okay. Well, now you say you measure the months is off and rolling stock to Scilingo's the most of selling this one is one for 35 times the mass off Syringa too. The mask off selling the follow on selling the one his boy not spar. 792 times the volume off selling them to If the dancing surrenders one A 3.85 g over send emit a few watts a density of selling it to. So for this problem, you write this 11 night and therefore Informa's. So you have good. They won ego one equal boy 79 Do we do? Right? And I am one ego. 1035 And do you say here and then you guys the one they want. You go and won over everyone. And this would be evening. One boy 35 And do you go? Boys have one night to read to. And this evil a three boy eight by ground war Sandy meeting you and then So therefore you get they to They gave us Doughboy. Dual sick from

Hello and welcome to Chapter One problem too. For physics for scientists and engineers with modern physics. So this problem is asking estimate another density calculation. But this time for the standard for a kilogram. I'm not sure if you're familiar, but not only is the kilogram the only S I unit that has a prefix, the kilo in front of it, it also has one of the only s I units that you know can fluctuate. It's very vague about what masses. So there's this platinum cylinder held in a remote location in Europe. That is what we define to be a killer ground. It's very valuable, so it's guarded very heavily. But it's little interesting that you know this mask and deteriorate also. So it's very it's very fluctuating honestly, about what kilogram even means Regardless, we need to calculate density for this platinum cylinder. So we here, which is again our row calculation. So we have ro for density is equal to mass over the volume eso We also need to know that the volume of a cylinder is pi times the radius of that still under squared times the height of that Some wonder So we can pretty much just jump right in because we're given were given the mass of this owned or one kilogram and we are given the diameter and the height. So just to start things off, we know that the radius is 1/2 of our diameter. So we just divide are given value for diameter over to we also have to convert Both are diameter and our height two meters to make it a sigh units. So we had 39 millimeters divide that by thousands bring the decimal place over 33 times doesn't really matter, but 0.39 meters. So once we have our radius, we can go into our equation here and we just do one kilogram which is the mass divided by high obviously pie times that value for the radius squared times the height again in meters. So that will give us 21.5 times tended with third kilograms, her meters cute

All right. Here we have the problem. 119 this. We're going to calculate the density of this deal in grams per centimeter cube. So the problem is given the mass off the cylinder equal to 41 grams, and we know the radius of the cylinder. This ink would choose their 0.22 inches, and the radius in the left of the cylinder is a 2.60 ancients, so one inch is equal to two point 54 centimeters. So the radius of the cylinder is equal to 0.22 inch times to 1 54 centimeter per pinch. It would get this number equal to 0.559 centimeters in the lives converted. Two centimeter. We have two points. 60 times, two point 54. And this is secret. You 5.49 centimeter. All right, so we have the radius and length folks in centimeter now. It kept going for the volume of a cylinder is equal to pi r squelch l. So this is pi times 0.559 square times 5.49. You would get the result as five points 39. See him cute. So now volume mess we can carefully for a destiny, density is equal to mass, divided by volumes 41 grams divided by 5.39. You get the result as 7.6 gram per centimeters cute.


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