5

Identify the null hypothesis, alternative hypothesis, test statistic;, P-value, initial and conclusion. Test the claim that less than 48% of the people following a ...

Question

Identify the null hypothesis, alternative hypothesis, test statistic;, P-value, initial and conclusion. Test the claim that less than 48% of the people following a particular diet will experience increased energy: Of 100 randomly selected subjects who followed the diet, 20 noticed an increase in their energy level.

Identify the null hypothesis, alternative hypothesis, test statistic;, P-value, initial and conclusion. Test the claim that less than 48% of the people following a particular diet will experience increased energy: Of 100 randomly selected subjects who followed the diet, 20 noticed an increase in their energy level.



Answers

State the null hypothesis, $H_{o},$ and the alternative hypothesis, $H_{a},$ that would be used to test the following statements. a. $\quad$ Post-self-esteem survey scores were higher than pre-self-esteem survey scores. b. $\quad$ People prefer the taste of the bread made with the new recipe. c. There is no change in weight from weigh-in until after 2 weeks of the diet.

Okay, that's look a question 24 together. Um, so a the no hypothesis is me enough difference between post test and the protest court. A sequel to 15. Well, I'll justify the is equal to post test score minus pretest score. All right. And the alternative hypothesis is you know, if they're friends is greater than 15. All right, move to party. Uh, part B, that Well Oh, just define that. The first. The difference is the change off the weights in a diet. Um, so is going to be the wage after minus the weight off before? Okay. And our no hypothesis is the meaning of change is 10 owned, and the alternative hypothesis is the meaning. No change is greater than 10. Hold. All right. Um, that's what, Cassie? The difference here ISS man means, uh, weight loss. So it's like the weight about the weight off after after waits minus awaits before hint. Our no hypothesis is mean. Off difference is equal to £12. And our alternative hypothesis is me. And of change is greater than career, then well, yeah, it is greater than £12. 10 for D. Our difference is there. Home re assessment. So he is like their friends in. Did you see the difference in money? Uh, and our no hypothesis is me enough. Difference is equal to $200. And the alternative hypothesis is the mean of difference Is smoke for its smaller than $200? It is, according to the question, this is was no more than so by the mean no more. We have this smaller sign here.

Okay, so we know that the null hypothesis h not is that p is equal to 0.75 on alternative hypothesis is that p is greater than the European 75 Okay, So to find the test statistic, we're gonna find pushing p. No, but says screw off peak, you ends. My cute is one minus p andi way. We know also from the question on 3000 five on DSO can calculate our Z value to be 8.48 Okay? By substituting all the values we are given. Okay. All right. So now the P value is equal to 0.0 She's lessons. European Ship one Therefore we can reject. Don't know. Hypothesis sentence. This is our critical.

For this problem. We are given the following claim machines suspense amounts with standard deviation greater than 0.15 oz and we have the following information off to the side. So the first for this hypothesis tests the state or no hypothesis. So each not. We're talking about standard deviation. So sigma And it's gonna be our 1.5 oz are alternative since the claim is stating greater than it'll be sigma, Somebody greater than 0.15. So once we have our go on alternative hypothesis, let's find our testes cystic. Since we're talking about sanity, aviation, we're gonna be using the chi square distribution and the chi square testes cystic can be found by and before end minus one times as squared divided by sigma squared. Yeah, So this is going to be 27 -1. Yeah. Time 0.17 Squared Divide by 0.15 Squared. And the chi square tests should be approximately equal to 33 points 396. So I was the testes cystic, you can do the p value. There's two ways to do the people, you can either do since the sample size 27 we have a degrees of freedom. 26 But in the end -1. Since this degrees of freedom is relatively small, we can find it within the table or we can find the inequality arranged within the table. And since this is a right to test and the high score table, I'm using finds area right to the tip. Other critical values what we wanna do. We don't want to go down the degrees of freedom. Do we get to 26? We want to find the range where 33.396 is between the two numbers. So I found that is between 17 point 292. And it's gonna be less than 35 point 563. So now if we go all the way up we'll find that probably are the area to the right of the curve. So the 17.292 equivalent to 0.935.563 equivalent to 0.1. And now we have our P value. So RP values between 0.9 or 0.1 and 0.9. A more accurate where you can get your P value though is using software is like our you use the Arco p chi square which does it take the input of your chi square testes, cystic degrees of freedom and then lower dot L. Equals true or false. So the lord dot tails telling us whether it's a left tail test or right tail test. Since the right tail test, you want that to be false. If you plug in this information we should get to this p value is about 0.1 509. Which again agrees within the table method table inequality. So if you have the p value can make a conclusion by comparing your p value. What's your alpha. But you can also find your critical values. To find your critical value of critical values. Your again going to your chi square table is gonna be Since we're doing air to the right we just want our alpha. And so we are degrees of freedom. Remember that our alpha is 0.05. Our degrees of Freedom 26. So if we go to our high score table we can find were those two intersect and are critical values. 38 .885. All right. So, you can make conclusion with the critical values and your testes cystic. If you have a chi square distribution looking something like that, you're critical value. The states here Just 38.885. Okay, so you're critical value. We will reject any or don't have process. If it falls within this blue region, this is also called our rejection region. And if it falls anywhere within the non stated region, we will accept it. Which is also called our acceptance region. We see our test statistic as 33.396. So if you try to play set somewhere here that maybe belong around over there. Yeah. So that's archive square test. Yeah. And it falls within our acceptance region. So in this case for comparing test statistics and critical values we fail to reject If you want to compare with the P value and alpha. So a p value is greater than alpha. We failed to reject. H. Not. Yeah. and if P value is less than alpha, we reject H. Not again, we can look really quickly. We have AP value of 0.1509. And after a value of 0.05, our p value is greater than our alpha, so we failed to reject the null hypothesis. So in both cases we came to the same conclusion, which was we fail to reject H not.

Yeah. Okay. So way knows that. Yeah. No hypothesis. H not. Is that p is equal to 0.5 on that alternative hypothesis. H A. The P is not equal to 0.5. Okay, Now we can calculate our proportion, which is excellent. And her ex is 123 on on is 280. Uh huh. She'll give us your credit for For came. Now we can calculate the test statistic value using a calculator which will give us negative. Too unsure. Three. Um, And now you can use that to find the p value using the table. So give us a P value. She is equal to 0.0 for two. Three. Finally, since we know Alfa is your opinions your one under, if you use a two tailed critical value be find the table value for Z Alfa two, which is 2.5 eight. So now, since it's two tailed critical values, Yes, arranged to 58 Okay. And since 0.423 is greater than our the significance level of 0.1 we can fail to reject the null hypothesis. Um, and therefore it could be concluded that there was not sufficient evidence supporting the rejection of the claim that touch therapists use method equivalent around guesses failed to reject.


Similar Solved Questions

5 answers
Discrete TAIGOnL variables that have the following juint probability mass Funct on_Let X and (pmnf)_0.O0 0,01 0.04 0.05001 0.09 0.16 0.040.20 0.10 0.10 U; 0.01 0,00Find marginal pmf of Y . Find P(Y Find P(X < 1,Y 28 Find P(X = 'Y Are X and independent? Find E[X?y]
discrete TAIGOnL variables that have the following juint probability mass Funct on_ Let X and (pmnf)_ 0.O0 0,01 0.04 0.05 001 0.09 0.16 0.04 0.20 0.10 0.10 U; 0.01 0,00 Find marginal pmf of Y . Find P(Y Find P(X < 1,Y 28 Find P(X = 'Y Are X and independent? Find E[X?y]...
5 answers
Consider the funetion y = f (x) graphed below.(a) For what values of x (in the domain of f) is f"(r) = 0 =(6) For what values 0f x (in the domain of f} is f '(x) positive?(c) For what values of x (in the domain of f) is / '(x) negative?(d) For what values of x (in the domain of f) is f"(x) undetined?(e) Based on your answers to the previous questions make sketch of y = f (x) below. Be as accurate a8 possible_
consider the funetion y = f (x) graphed below. (a) For what values of x (in the domain of f) is f"(r) = 0 = (6) For what values 0f x (in the domain of f} is f '(x) positive? (c) For what values of x (in the domain of f) is / '(x) negative? (d) For what values of x (in the domain of f)...
5 answers
Find the transition matrix S from basis E={1, (X-1), (X-1)2} to basis F={1,X,X2}
Find the transition matrix S from basis E={1, (X-1), (X-1)2} to basis F={1,X,X2}...
5 answers
Find the variation constant and an equation of variation where y varies inversely as X andy= 20 , The variation constant is when > =Enter your answer In the answer box and then click Check Answer:Clearpan remainingType here to searchAi
Find the variation constant and an equation of variation where y varies inversely as X andy= 20 , The variation constant is when > = Enter your answer In the answer box and then click Check Answer: Clear pan remaining Type here to search Ai...
5 answers
Suppose 250. mL flask filled withBrz 430.60 mol of BrOCI. The following reaction becomes possibleBrz (g) + OCI, (g) ~ BrOCI(g) + BrCI(g)The equillbrum constant K for this reaction 0.633 at the temperature of the (lask;Calculate the equlllbnum mo/uricy of OCI z Round your utwcidecima plucur0Cl
Suppose 250. mL flask filled with Brz 43 0.60 mol of BrOCI. The following reaction becomes possible Brz (g) + OCI, (g) ~ BrOCI(g) + BrCI(g) The equillbrum constant K for this reaction 0.633 at the temperature of the (lask; Calculate the equlllbnum mo/uricy of OCI z Round your utwci decima plucur 0Cl...
5 answers
Find all points (if any) of horizontal and vcrtical tangency to the following parametric curve: I = 2 _t+2 , "=0Find the arc length of the following parametric ta on the interval (0, 2w]COsV = 0 sin? t,0 <t < 20
Find all points (if any) of horizontal and vcrtical tangency to the following parametric curve: I = 2 _t+2 , "=0 Find the arc length of the following parametric ta on the interval (0, 2w] COs V = 0 sin? t, 0 <t < 20...
5 answers
Letf : Kc R" _ R be continuous o & compact set K and let M = {x € Klfkr) is the maximum of f o K}. Show that M is a compact set
Letf : Kc R" _ R be continuous o & compact set K and let M = {x € Klfkr) is the maximum of f o K}. Show that M is a compact set...
2 answers
Show that if Ais a (2 x 2) nonsingular matrix and U] and U2 are nonzero vectors in R? with ufu2 0,then {Au1, Aug}is linearly independent Please select file(s) Select filels)02 Transpose 15 Points Let A be an (n x n non-singular matrix Show that AT is non-singular:
Show that if Ais a (2 x 2) nonsingular matrix and U] and U2 are nonzero vectors in R? with ufu2 0,then {Au1, Aug}is linearly independent Please select file(s) Select filels) 02 Transpose 15 Points Let A be an (n x n non-singular matrix Show that AT is non-singular:...
5 answers
) If & = 9.0 V, what is the current in the 30-0 resistor? A) 0.30 A B) 0.26 A 0.10 A D) 0.20 A ANS: 4e I2 At20 915 030
) If & = 9.0 V, what is the current in the 30-0 resistor? A) 0.30 A B) 0.26 A 0.10 A D) 0.20 A ANS: 4e I2 At 20 9 15 0 30...
5 answers
H 1 7 Osssi0 M The graph of the parametric equations+(1"0515[- 1 Me Js graph
H 1 7 Osssi0 M The graph of the parametric equations +(1 "0515[- 1 Me Js graph...
5 answers
Find an equation of the slant asymptote. Do not sketch the curve.$$y= rac{2 x^{3}-5 x^{2}+3 x}{x^{2}-x-2}$$
Find an equation of the slant asymptote. Do not sketch the curve. $$ y=\frac{2 x^{3}-5 x^{2}+3 x}{x^{2}-x-2} $$...
5 answers
6 saved23+42+9 Residue of f (2) at 2 = -1is (22+2)(2-3)3d aut Ot9 question1 32 & 2 64
6 saved 23+42+9 Residue of f (2) at 2 = -1is (22+2)(2-3)3 d aut Ot 9 question 1 32 & 2 64...
5 answers
WB_Given the double integral sin(xy) dydx , which of the following Ibe order of integration reversed?equivalen dotble Lurpu aisiu( T) dx dysing W)drdsin( x)drdvsinG xu)dr dy
WB_Given the double integral sin(xy) dydx , which of the following Ibe order of integration reversed? equivalen dotble Lurpu ai siu( T) dx dy sing W)drd sin( x)drdv sinG xu)dr dy...
1 answers
Verify the identity. $$ \frac{\sec u-1}{\sec u+1}=\frac{1-\cos u}{1+\cos u} $$
Verify the identity. $$ \frac{\sec u-1}{\sec u+1}=\frac{1-\cos u}{1+\cos u} $$...
5 answers
Obtain an equivalent system by performing the stated elementary operation on the system. Replace the fourth equation by the sum of itself andlimes the second equation-2 -3w~42 +2w+52 -4w+52-2y +52 6w-2z~ZOB.~42 +Zw-42 +Zw -4y +7z +2w+52+52x -2y +5z 6w ~2 ~Jw~Z ~3w~42 +Zw-42 +2w 12y -7z 1Ow-3+ -27 +2w
Obtain an equivalent system by performing the stated elementary operation on the system. Replace the fourth equation by the sum of itself and limes the second equation -2 -3w ~42 +2w +52 -4w +52 -2y +52 6w -2z ~Z OB. ~42 +Zw -42 +Zw -4y +7z +2w +52 +52 x -2y +5z 6w ~2 ~Jw ~Z ~3w ~42 +Zw -42 +2w 12y ...
5 answers
Propane gas reacts with oxygen according to this balanced equation; CzHe (g) + 5 0z (g) ~ 3 COz (g) + 4 Hz0 (g)How many liters of water are produced at STP when 48.5 g of CzHg completely reacts with oxygen? INCLUDE UNITS IN YOUR ANSWER
Propane gas reacts with oxygen according to this balanced equation; CzHe (g) + 5 0z (g) ~ 3 COz (g) + 4 Hz0 (g) How many liters of water are produced at STP when 48.5 g of CzHg completely reacts with oxygen? INCLUDE UNITS IN YOUR ANSWER...
5 answers
For what value of k does the matrix have one eigenvalue with algebraic multiplicity 2? (7
For what value of k does the matrix have one eigenvalue with algebraic multiplicity 2? (7...
5 answers
2.56. Let a = 0.05 be the traditional threshold of statistical significance. Suppose we test a coin to see if it is fair by flipping the coin 25 times If the coin is fair coin, what is the probability that we reject the null hypothesis that T = 0.52 Why isn t the answer 5%?
2.56. Let a = 0.05 be the traditional threshold of statistical significance. Suppose we test a coin to see if it is fair by flipping the coin 25 times If the coin is fair coin, what is the probability that we reject the null hypothesis that T = 0.52 Why isn t the answer 5%?...
5 answers
The preparation of 240 mL of & 2,5 aqueous solution of HCI requires .Oa) 48 mL HCI; 192 mL waler06) 24 mL HCI, 216 mL walerOc 69 mL HCI; 171 mL waterOd) 40 mL HCI; 200 mL watere) 60 mL HCI; 180 mL water
The preparation of 240 mL of & 2,5 aqueous solution of HCI requires . Oa) 48 mL HCI; 192 mL waler 06) 24 mL HCI, 216 mL waler Oc 69 mL HCI; 171 mL water Od) 40 mL HCI; 200 mL water e) 60 mL HCI; 180 mL water...
5 answers
2.B.39Convem Ihe lollowing quantit 95 27 gtams Goic contimotorno caldhnisJoundtcubc irchClickharo lo_vlaNuiba USCS measurements Clck heroulo vic % comnzn metc Rtclxo; Clckboro_ oxlIne USCS Uplo - conuersicosRoundthe naarestteninneeced )
2.B.39 Convem Ihe lollowing quantit 95 27 gtams Goic contimotor no caldhnis Joundt cubc irch Clickharo lo_vlaNuiba USCS measurements Clck heroulo vic % comnzn metc Rtclxo; Clckboro_ oxlIne USCS Uplo - conuersicos Round the naaresttenin neeced )...

-- 0.019254--