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Minor surgery On norses under field conditlons requires rellable short-term anesthetic producin Dpod muscle relaxatlon_ Minima cardiovasculam respiracon changes, an...

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Minor surgery On norses under field conditlons requires rellable short-term anesthetic producin Dpod muscle relaxatlon_ Minima cardiovasculam respiracon changes, and qulck, smooth recovery with minimal uftereffects s0 that horses be left unuttended An article reports that for sample 76 horses which ketamine was administered under certain conditions; the sumple average laterat recumbency (lving-down) time was 18.91 min and the standard deviation Does this data suggest that true average lateral re

Minor surgery On norses under field conditlons requires rellable short-term anesthetic producin Dpod muscle relaxatlon_ Minima cardiovasculam respiracon changes, and qulck, smooth recovery with minimal uftereffects s0 that horses be left unuttended An article reports that for sample 76 horses which ketamine was administered under certain conditions; the sumple average laterat recumbency (lving-down) time was 18.91 min and the standard deviation Does this data suggest that true average lateral recumbency time under these conditions less tnan min) Test the appropriate hypotheses at level signlficance 0.10 State the appropriate Jleemnalive hypotheses. 0 Ho: # = Ha: # < 20 Ho: M * 20 Ha: # = 20 Ho: # # Z0 Ha: V > 20 Ho: # = 20 Ha: # # 20 State the rejection region(s) for an 0.10 test: the critical region Ided; enter NONE for the unused redion Round Your answers decima places Compute the test statistic value Round vour answer decima Dlaces State the conciusian prob context reject the null hypothesis. There sullicient evidence that the avcrage lying-down time ess than 20 minutes Reject the null hypothesis There not sufficient evidence that the verage Iying down time less than 20 minutes Reject the null hypothesis. Tnert sulficlent evidence that the average Iying down cimc less than 20 minutcs Do not reject the null hypothesis: There sufficient evidence that the average Iving-down time than 20 minutes neeo the appropriate table the Appendix of Tables ansie this question



Answers

Minor surgery on horses under field conditions requires a reliable short-term anesthetic produc-
ing good muscle relaxation, minimal cardiovascular and respiratory changes, and a quick, smooth
recovery with minimal aftereffects so that horses can be left unattended. The article "A Field
Trial of Ketamine Anesthesia in the Horse" (Equine Vet. J.) $176-179$ ) reports that for a
sample average lateral recumbency (lying-down) time was 18.86 min and the standard deviation
was 8.6 min. Does this data suggest that true averal recumbency time under these
conditions is less than 20 min? Test the appropriate hypotheses at level of significance. $10 .$

It's your number. 20 Christian Me. The level off significance is mentioned is all for equal point. You five, then on high process with state that the population mean new is equal to the value mentioned in the claim. So it's mood to new equal 85 mg here, 100 many liter. The alternative hypothesis stated the opposite off the null hypothesis according to the claim, Thus using higher than so each one new is bigger than 80 5 mg be 100. Many leader. The alternative hypothesis states is the opposite of the null hypothesis. According to um so the claim this using hires in is the alternative hypothesis uses less then, so the test is left field. It's alternative hypotheses uses Biggers in then that this ah is right field. Well, if the alternative hypothesis is not equal, then the test is toe field. So the answer will be writing question number. Mhm. Given you equal 85 Zita equal 12 point ah 12.5, and equally. The sampling distribution off the sample mean export is normal because the population distribution X is assumed to be normal. The sampling distribution off the sample mean has has mean mu and the standard deviation Zita over square root and doesn't venue is a sample mean decreased boy population by the population mean divided by the standard division? Is it equal? Export minus new over zita over square root and equal 93.8, minus 85 over 12.5 over square root eight equal 1.99 Question number seat result Fourth A and part B. It snowed to immune equal 85 Billy Graham beer. 100 mL. Which one to new is bigger than 85 mg There 100 million mL and did equal 1.99. The B value is the population off obtaining a value more extreme or equal to the standard test Statics. Then, to remind the probability, using tape e so e equal be off export He's bigger than 93.8 equal Be opposite is bigger than 1.99 equal. Um, what minus? Be office it is less than 1.99 equals one minus 10.9767 Equal 0.233 Question number three Certainty given all for equal going 05 Result. Porc be equal 0.2 33. If the value is a smaller than the significance level Alfa than Donald, Hypothesis is rejected, so P is lesson 0.5 Egypt. It snowed. If we rejected than all hypothesis, then the data is a statically significant at level article. Question number eight result part E it snowed. Two new equal 85 mg pair, 100 mL and each one to mu is bigger than 85 milligram beer. 100 mL isn't part d rejected each node. There is significant. There is significant evidence to support the claim. A gentlemen has an overall average Lucas level higher than 85.

The following is a nova test based on the mean salaries for different metropolitan areas. So the alternative or the null hypothesis is that all the means are the same. So there are six metropolitan areas, I think it goes Chicago, Dallas Miami, Denver san Diego and Seattle. Uh So the null hypothesis is that all the means are the same. And then the alternative is that at least one of them is different. The second step is to find the critical value and you can do that using either software or a table, But they're essentially three things you need. The first thing is your alpha value, your significance level and that's usually given to you the problem and that's .05. Then you need the degrees of freedom for the numerator and the degrees of freedom for the denominator. And the way you find that Is the degrees of freedom for the numerator is the number of categories -1. So there were six cities that we looked at our metropolitan areas, so 6 -1° of freedom would be five for the numerator. And then for the denominators, the total number of data values minus the number of categories. So there were 36 data values minus the six metropolitan areas. So 30 is your degrees of freedom for the denominator. So that should be enough to use a table. But I use a calculator and I wrote a program in here called inverse. F. I'm not going to show you how to how to write the program. You can youtube it if you wish. Um But this is what I do. So um I put in my area which is my alpha value, my degrees of freedom is five and then my degrees of freedom for the denominator is 30 and That gives me my critical value. About 2.534 2534 is my critical value. I call f. star. So 2.534. Okay so anything greater than 2.534. We reject the annual hypothesis that all the means are the same And anything less than 2.534. We failed to reject meaning the h not is true. Okay so the second step is to find the F statistic and there's a formula but it's a bit of a mess. I always use software you know technology is a great thing. So if you go to stat and you can type in your data values. So these are the mean salaries um So again L1 I think was Chicago and then this is the mean salary for Dallas Miami Denver San Diego and Seattle. So there are six categories. And if you go to stat tests and then we're gonna go to the Unova test and then you just type in your columns separated by commas remember there were six columns, six data columns that we used and we need to make sure that all of them are in there and last one and then also you know make sure you separate those by commons, otherwise it's going to read it wrong. So then um that gives us everything we need. So the F. Is the F statistic, that's the third step. So we're looking at this it's about 2.281 as our F. Value. So two point 281 is our f statistic Which is actually barely in the non rejection region 2.281. So that means we fail to reject. Okay and also we can verify that with this p value here. So the p values 0.7 which is a pretty small p value, but it's still in this case greater than the alpha value. So the alpha value remembers point oh five, so it's barely greater than the alpha value. And whenever it's greater than the alpha value, uh we failed to reject, I should probably put H not there, so we failed to reject H not whenever the P values greater than the alpha. Okay. So then the last step is to summarize everything with actual words. So what does this all mean? It just means that there is not sufficient evidence, there is not sufficient. I guess you could say statistical evidence to suggest that the mean salaries from the different metropolitan areas are different. Okay. And that's the five step process for an Innova one way and over test

So we're gonna let d stand for the time of no nap minus the time where they take that four hour nap after having only four hours of sleep. And so are non hypothesis is going to be that that mean difference is Less than a report to zero. And alternately that this no nap time is going to be higher than the nap time. So that D. Is greater than zero and you can go the opposite way as well and have this these signs being reversed. So that's up to you. But I draw my little picture so that's part A Part B. We're gonna end up having our for part B. We have to find that critical value. So we're assuming that we're at zero and there's a cut off point where we have that significance level of point to one and are degrees of freedom is nine. So we want to find that T. Star value that's going to have the degrees of freedom of nine and have the upper tail be 1%. When we look that up, that comes out to be 2.8 to 1, which means our rejection region Will be if the T value we get for our test statistic is greater than 2.8-1. So no one part C. I subtracted all the values and I found that the mean. D the uh d bar value came out to be negative 0.0. Excuse me? Positive .097. Yeah, let me erase that. And we got the standard deviation of those values. So I just I truly put the one value into list one and the other value into list too. And then I have the calculator to list one minus list too. And then I did one variable stats to find the mean and the standard deviation. And this comes out to be about that. So now we need our test statistic, our test statistical have 9° of freedom and we will take that .097 and we will subtract away the mean and we will divide it by the standard deviation Over the square root of 10. And when we do we get the test statistic comes out to be very large 7.14. So we can see that for part E. R. Decision, we can see that this test statistic is way in the way, high, its way into this rejection reason region. So we have evidence to reject the null. And so we would conclude that it does appear that the nap does seem to reduce the time to reduce the runners times run or time in that 20 m dash, I believe.

We want to conduct a pair differences test at the alpha equals 5% level testing the claim that population mean X bar A is greater than population X barbie. We have data a be given here, we assume amounts to mr distribution as you can see on the right. I've already calculated the mean difference D bar 6.125 The sample size and eight and the sample standard deviation of differences SD and 8.7 We complete the five steps us to blow to solve this problem first, let's evaluate the requirements to use a student's T distribution of the hypotheses because of the distribution shape it is appropriate to use a student distribution your degree of freedom and minus 27. No hypothesis mute equals zero. Alternative media is greater than zero and alpha equals 00.5 for confidence nexus, complete the test at and the P value our test that is T equals D. Bar over SDR. Again this gives 2.14 U. T. Table. This gives us a P value between 0.5 point 025 That means we can include that P is less than equal to alpha. So we reject the null hypothesis H not which means that we have evidence and you D. Is greater than zero.


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