5

When carbon is burned in air, it reacts with oxygen to formcarbon dioxide. When 18.0 gg of carbon were burned in thepresence of 59.7 gg of oxygen, 11.7 gg ofoxygen...

Question

When carbon is burned in air, it reacts with oxygen to formcarbon dioxide. When 18.0 gg of carbon were burned in thepresence of 59.7 gg of oxygen, 11.7 gg ofoxygen remained unreacted. What mass of carbon dioxide wasproduced?Express your answer to three significant figures and include theappropriate units.

When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 18.0 gg of carbon were burned in the presence of 59.7 gg of oxygen, 11.7 gg of oxygen remained unreacted. What mass of carbon dioxide was produced? Express your answer to three significant figures and include the appropriate units.



Answers

When elemental carbon is burned in the open atmosphere, with plenty of oxygen gas present, the product is carbon dioxide.
$$C(s)+\mathrm{O}_{2}(g) \rightarrow \mathrm{CO}_{2}(g)$$
However, when the amount of oxygen present during the burning of the carbon is restricted, carbon monoxide is more likely to result.
$$2 \mathrm{C}(s)+\mathrm{O}_{2}(g) \rightarrow 2 \mathrm{CO}(g)$$
What mass of each product is expected when a $5.00-\mathrm{g}$ sample of pure carbon is burned under each of these conditions?

It's problem asked us the sol for how much of product is generated when we were given the initial amount. So we have to do a dimensional analysis this all for it. So wherever you a more one more carbon, there's told grams per mole. That would be the Mueller vast Kurban for everyone more Kurban We have one more of Sio two and probably one more Theo too. We have 44 grams of co two and something that out We would get five divided by 12 times 44 which comes out to be 18.3 grams from sea. Go to product. We move on to the second part, which is with restricted oxygen, but we still assume that it's in excess. So we're able to do this problem if it wasn't excessively talk to do you a limiting reactant and thrown Know how much 02 there is? So you have 12 rounds of them too, Actually, No, Sorry, we have 12 grams. Um see everyone move. I see every two the there is two more CEO and for every one more feel there is 12 16 grams. Let's see you. That would be using the molar mass conversions. So calling that and we get fired about 12 times 38 Earth. What? Three is 28? All right. And that comes out to be 11 0.7 grams. You That's how you did this problem.

So this video we're gonna talk about Question 46 from Chapter two, which tells us in a combustion reaction 46 grams of ethanol reacts with 96 grams of oxygen to produce water and carbon dioxide. If 54 grams of water is produced, what massive carbon dioxide is produced. So conservation of mass tells us that mass is neither created or destroyed over the course of a chemical reaction. So we know that the massive products must be equal to the massive reactive is that we started with, um so the mass of our reactive is 46 plus 96 grams. Um, so we know that that minus one of our products, water should give us the mass of our remaining product, Carbon dioxide s o. The combined mass of our reactant is 142 grams. So we know that we must have 142 grams of reactive, which means we must have 142 grams of products, so 142 grams minus 54 grams gives us 88 grams of carbon dioxide

All right. So we know 46 grams of the ethanol. We don't actually have to know the chemical form of this. So we have 46 grams of ethanol is gonna put e are actually out of. We don't even need symbol. We didn't know the mass. So I will put down here at the knowledge is so we know for six grams of what, pull us 96 grams of oxygen. I'll put that right here on 96.0 grams that I'll put oxygen. That was feel to You have to know this part. I'm just keeping track of it for you. And we know that it's going to make 54 grams of water. Put that down. 54.0 grams of H 20 plus some amount. What is that amount going to be? While this is actually really easy question, you have to know something called the Law of Conservation of Mass and how it applies to a chemical equation. Law of conservation on right that I got down again. Law of Conservation of mass. Well, this just tells us that matters not created nor destroyed. So in other words, for chemical equation that means is that the mass must be mass is the same. Write this down is the same in the reactant and product acting's and products. And when I say mass, I don't mean massive certain camp climbing the total mass. So let's put a little note here, too. We can put total massive feel like that's going to trip you up. Total mass is the same in the reactions and products. So let's take a look out what the masses in the reactive. So in the reactant, we have 96 plus 46. That's going to give us a nice number. 152. What's 142 142 point of Grant spoke, and that's gonna equal whatever is on the right side. So 54 plus some numbers and call X. We're gonna actually just solve this. Using some simple algebra put, the programs here is complete, So to get a calculator, if you need it will be 1 40 to minus 54. That's going to give us 88 grams of X equals 88 grams. So that's how many grams of CO two all right. That's all

This is a bit of a longer question, but let's kind of break down, pull out the information and see what we're working with. We've been told that carbon and oxygen to form Judy for compounds compounds one, and it can also combine that form compound to so Compound one has four point 82 grams of carbon, every 6.44 oxygen where's has 21 3 of carbon and 53 seven grams of oxygen. So we're looking for the ratio of carbon to oxygen for the two compounds, specifically with a fixed ratio of oxygen. Which dress means when we do all of our ratios. We want oxygen to be the same number from Compound one A compound to. So all I'm going to do is for Compound one take, um, a ratio of carbon to oxygen. So my 4.82 divided by 6.44 and that'll give me my, um, ratio of carbon oxygen. And by putting oxygen on the bottom of this fraction, oxygen will be reduced. Eventually, toe one right through the math. So we gets 10.75 carbon for every one oxygen. Let's go ahead and do the same thing for compound to again take carbon oxygen. So for this case, we've got 20.13 for every 53.7 grams of oxygen, which, when you put that into a calculator, you get 0.37 carbons for everyone. Oxygen. Um, Okay, so now since we have the same oxygen's right now, we can just compare our carbons. So we have 0.75 revert back to black fittest. So comparing, um, one to to write just for carbon, we're gonna take 0.75 0.37 which is approximately 2 to 1.


Similar Solved Questions

3 answers
Euler c eqaiicz to tbe Conch - erai eolution gene 02+&12 122 3. Find
Euler c eqaiicz to tbe Conch - erai eolution gene 02+&12 122 3. Find...
5 answers
2. *Find a formula for k(k +1). Prove that your formula is correct using mathe k=l matical induction.
2. *Find a formula for k(k +1). Prove that your formula is correct using mathe k=l matical induction....
5 answers
Matrix for Group 4 -1~1
Matrix for Group 4 -1 ~1...
5 answers
Question 5A0.100 mol Laqueous solution of CHaNHz has a pH of 11.82 at 25 C. Calculate the baseconstant; Kb, to CHzNHz and choose the correct option:4,91 . 101,51 . 10-126,61 10- :4,67 10-42,14 . 10
Question 5 A0.100 mol Laqueous solution of CHaNHz has a pH of 11.82 at 25 C. Calculate the base constant; Kb, to CHzNHz and choose the correct option: 4,91 . 10 1,51 . 10-12 6,61 10- : 4,67 10-4 2,14 . 10...
5 answers
Convert thc modcl bclowskcletal drawingSticyJabelsYou do not have t0 explicitly draw H atoms_PreviousNext
Convert thc modcl bclow skcletal drawing Sticy Jabels You do not have t0 explicitly draw H atoms_ Previous Next...
5 answers
"eargtoSetOuestIon 3esmplng Oistnb-tcn 0( sJmp < maans}AcadelIrany DattElamlAceeccnDCOLiCjserI IrotFugAntcAce ecuionofamhemiejns memWuciAtci ecc onol ps uc pacts trcm rarotumolingVourz [0 Uneo-exicn preucnls charzes to InaMacBook Ali
"eargto Set OuestIon 3e smplng Oistnb-tcn 0( sJmp < maans} Acadel Irany DattElaml Aceeccn DCOLiCjserI Irot FugAntc Ace ecuionofamhemiejns mem Wuci Atci ecc onol ps uc pacts trcm rarotumoling Vourz [0 Une o-exicn preucnls charzes to Ina MacBook Ali...
5 answers
Use the expression in Problem 65 to find $(a)$ the maximum range of a projectile with launch speed $v_{i}$ and (b) the launch angle $ heta$ at which the maximum range occurs.
Use the expression in Problem 65 to find $(a)$ the maximum range of a projectile with launch speed $v_{i}$ and (b) the launch angle $\theta$ at which the maximum range occurs....
5 answers
3 x8(x L %o) xod(x _ %o) 4 6(22 ~ a2) = 2a [S(2 _ a) + S( + a)] ,a # 0 5_ J f(o) (x)dx = -f' (0) O0
3 x8(x L %o) xod(x _ %o) 4 6(22 ~ a2) = 2a [S(2 _ a) + S( + a)] ,a # 0 5_ J f(o) (x)dx = -f' (0) O0...
4 answers
To use nonparametric methods, the distribution of the populationshould be ______. A) Normal C) Uniform B) Binomial D) anydistribution E) None of the alternaitives above are correct.
To use nonparametric methods, the distribution of the population should be ______. A) Normal C) Uniform B) Binomial D) any distribution E) None of the alternaitives above are correct....
5 answers
8. [12 points] Find the standard matrix for the linear transformation T : R" _ R" that reflects all points across the line X , =31 followed by counterclockwise rotation of 30" about the origin, followed by another reflection across the vertical axis x; = 0
8. [12 points] Find the standard matrix for the linear transformation T : R" _ R" that reflects all points across the line X , =31 followed by counterclockwise rotation of 30" about the origin, followed by another reflection across the vertical axis x; = 0...
1 answers
An explorer in Antarctica leaves his shelter during a whiteout. He takes 40 steps northeast, next 80 steps at 60$^{\circ}$ north of west, and then 50 steps due south. Assume all of his steps are equal in length. (a) Sketch, roughly to scale, the three vectors and their resultant. (b) Save the explorer from becoming hopelessly lost by giving him the displacement, calculated by using the method of components, that will return him to his shelter.
An explorer in Antarctica leaves his shelter during a whiteout. He takes 40 steps northeast, next 80 steps at 60$^{\circ}$ north of west, and then 50 steps due south. Assume all of his steps are equal in length. (a) Sketch, roughly to scale, the three vectors and their resultant. (b) Save the explor...
5 answers
MCE Mldsbes dleiulalcu LwU-umcisiuie Luuiuiiidle #Ysleiii ds iuiiuws at (3.0 m, 4.0 m}, 2.0 kg at (-2.0 m, 0.0 m), and 1.0 kg at (0.0 m; -2.0 m) (see figure}. The X coordinate of the center of mass of this system of massesy (m)3.0 kg (3.0, 4.0)2.0 kg (-2.0, 0.0)t+ x(m)1.0 kg
MCE Mldsbes dleiulalcu LwU-umcisiuie Luuiuiiidle #Ysleiii ds iuiiuws at (3.0 m, 4.0 m}, 2.0 kg at (-2.0 m, 0.0 m), and 1.0 kg at (0.0 m; -2.0 m) (see figure}. The X coordinate of the center of mass of this system of masses y (m) 3.0 kg (3.0, 4.0) 2.0 kg (-2.0, 0.0) t+ x(m) 1.0 kg...
5 answers
A concert promoter sells tickets and has marginal-profit function given below; where (x) is in dollars per ticket: This means that the rate of change of total profit with respect to the number of tickets sold X,is '(x) Find the total profit from the sale of the first 60 tickets , disregarding any fixed costs.P' (x) = Bx - 035The totab profit (Round to the nearest cent as needed )
A concert promoter sells tickets and has marginal-profit function given below; where (x) is in dollars per ticket: This means that the rate of change of total profit with respect to the number of tickets sold X,is '(x) Find the total profit from the sale of the first 60 tickets , disregarding a...
5 answers
(20 potns) Lct fl)-r' 2with * < 0 , Jnd g(x) = jr+$(4} Find Uo fkx)(b) () Find f(2)Find &-8463) 2563*+5).(3) (3x +5x-6x-16) ax -15x +i6y +30 (d) m Find Make stulc the domain and thc rangc of both and(c) (4) Graph andon the same axcs, from pant (d)
(20 potns) Lct fl)-r' 2with * < 0 , Jnd g(x) = jr+$ (4} Find Uo fkx) (b) () Find f(2) Find &-8463) 2563*+5).(3) (3x +5x-6x-16) ax -15x +i6y +30 (d) m Find Make stulc the domain and thc rangc of both and (c) (4) Graph and on the same axcs, from pant (d)...
5 answers
The trapezoid below undergoes 2-D geometric transformation and is shown in the sketch below in its original position: The coordinates of the vertices are given as (x,y) below and labeled. The trapezoid is B rotated about the z-axis 300 CCW about Point D and then uniformly scaled about the origin to be 1/4 of its original size. Determine the final transformed coordinates of the vertices: A , B' , C , and D'Initial Coordinates: A(3,2), B(5,5) , C(6,5), D(7,2)
The trapezoid below undergoes 2-D geometric transformation and is shown in the sketch below in its original position: The coordinates of the vertices are given as (x,y) below and labeled. The trapezoid is B rotated about the z-axis 300 CCW about Point D and then uniformly scaled about the origin ...
5 answers
-{10 PointsDeifeIilk 'uaae
-{10 Points Deife Iilk 'ua ae...

-- 0.020715--