4

Owad}g- In which situation the mean, median and mode are equalIf the values of all data elements in a distribution are not identical,In distributions with higher co...

Question

Owad}g- In which situation the mean, median and mode are equalIf the values of all data elements in a distribution are not identical,In distributions with higher concentration of lower values and a long tail towards higher values.For perfectly symmetrical distributions of dataIn distributions with higher concentration of larger values and a long tail towards lower values_?h- What is coefficient of variationIt is the ratio of the standard deviation to the mean of a data setIt is used to express t

owad} g- In which situation the mean, median and mode are equal If the values of all data elements in a distribution are not identical, In distributions with higher concentration of lower values and a long tail towards higher values. For perfectly symmetrical distributions of data In distributions with higher concentration of larger values and a long tail towards lower values_ ?h- What is coefficient of variation It is the ratio of the standard deviation to the mean of a data set It is used to express the standard deviation as percentage of the mean. Is especially useful when comparing data sets, which have different units All of the above :ssi obhmi i - If smaller data elements are to be given greater importance than the :larger data elements you should use Mode Median Arithmetic Mean None of the above :ssi 51i



Answers

In this problem, we explore the effect on the mean, median, and mode of multiplying each data value by the same number. Consider the data set 2,2,3,6,10. (a) Compute the mode, median, and mean. (b) Multiply each data value by $5 .$ Compute the mode, median, and mean. (c) Compare the results of parts (a) and (b). In general, how do you think the mode, median, and mean are affected when each data value in a set is multiplied by the same constant? (d) Suppose you have information about average heights of a random sample of airplane passengers. The mode is 70 inches, the median is 68 inches, and the mean is 71 inches. To convert the data into centimeters, multiply each data value by $2.54 .$ What are the values of the mode, median, and mean in centimeters?

So in this problem, we're taking a look at outliers, which are important to identify, to see if that we see if we've made a error in our data collection data entry or if we just have an unusual data value and one way to detect outliers, just use a box and whisker plot. So we're given students heights that are in the statistics plus and for party. We want to go ahead and make a box and whisker plot of the data so we can see that the low value is for the high value is 80. Yeah, and we want to find our portals. Sochi one is the 25th percentile, so 25% of the values will fall below that. So we have key 1, 61.5, and then our median or Q two is our 50th percentile. Um, we just want to order our data in order from least to greatest, so we can find our, uh, middle value, which, by doing that, we can see that our median is 65.5. And that's because we have an odd data set. So whenever you have or even data set. So when you have two values that are left in the middle. You just add them together and divide them by two to get your media. And then our Q three or the 75th percentile, um, is going to be 71.5. And so from this we can see that our inner portal range is going to be 10. So a plot looks like this. We have a four then at 61.5 60 65.5 in 71.5 in the 80. And this isn't inches. And then we find the value of the inter quartile range. So we just did that in part A. So we can make our plot. So it's just going to return. Mhm. See, we went to multiply that intercourse salary and try 1.5 to find the lowered upper limits. So the low is going to be 61.5 minus 10 times 1.5. So we get 46.5 and are high. Limit is 71.5 minus plus 10 mhm 1.5, which is equal to 86.5. So Part D asks if there is any data values below the lower limit and above the upper limit. So we want to list any suspected outliers and what might be an explanation for the outlier, So we can clearly see that are outlier is going to be that for value. Um, and this could be that they incorrectly wrote the wrong number. Or it could be in feet. Um, as an explanation for this outlier, Yeah.

And this video will be looking at one criteria or one way that you can see if you have an outlier in your information. So what I'm gonna do is I'm going to start by entering the information into my calculator to make a box plot. So I select stat number one and I'm going to enter the information in. Now I will enter a couple of the items and then I'll stop and I'll enter it in. So you don't have to sit here and watch a magic hand enter values into the calculator. So now I'm entering the last value. I like to use the calculator when my information isn't already in order for me. So now I need to look at the the box plot so I will choose second Y equals stat plot. I see my plot is already on but if yours is not select one, press enter when your cursor is on the word on cursor down and over to select the second box plot. And it should already be default to list one. Now I want to look at my graft so I select zoom, zoom nine zoom stat and there's my box plot and then I can select the zoom oops wrong button. Sorry then I can select the trace button and the trace button automatically starts on the median And I can see my median is 65.5. Q 1 61.5. There's my minimum it for Q three at 71.5 And 80 is my high value. So I went ahead and copied the plot and put it on my screen here so that I could write on it. So this value was for Q one was 61.5. The median value 65.5. Q371.5 and the maximum value is 80. So it does appear that I have an outlier. My whisker here appears to be very, very long. But believe it or not, there's actually a formula for that. The formula is to take Q one -1.5 times the inter quartile range and Q two minus or plus 1.5 times the inter quartile range. And anything outside of these values is most likely an outlier. Or another way to look at it is if you're Whisker is 1.5 times larger than your box, you most likely have an outlier. So let's do this. The official way will take Q1 which was 61.5 and then the inter quartile range Would be 71.5 61.5. So I open up my calculator again and 61.5 minus 1.5 times the inter quartile range And I'll see that I have a value of 46 point five. So anything below 46.5 is most likely an outlier. And then let's just check the rest of the range so I'm gonna do the other value. I'll do cue too. So that was with Q one. So I'm gonna do Q two 71.5 plus. I said cute too, didn't I? Q 3? I apologize accused to. Is the median Q three is 71.5 Plus 1.5 times the inter quartile range. So I'm gonna do a little trick with my calculators. Don't have to re type all that second enter. There's the information written out for me In place of 61.5, I will type 71.5 plus And that tells me that the high end of my range is 86.5, So anything below 46.5 or above 86.5 is most likely an outlier and obviously four is way below. So yes, it does appear that there is an outlier. Now, what is the reason for this? Well, the outlier is below. Could be any number of reasons, but these this is information from a statistics class that students recorded. So chances are this might have been and an error and entry. So perhaps the student meant to type in 42 Or 49 instead of four. So it's a very good chance that that is a data entry error. Or perhaps somebody is actually that tall Because these are all heights of students in a class. So I highly doubt somebody is 4" tall.

Okay. Now, first of all, we have a table with us. Now. How many values are there on the table? 123456789 10 11 12 13 14 15 16 17 18 1920. So there are 20 values of n happens to be 20. In this case, the number of observations is 20 right? The first one says the first part. A says, Do any of the scores look like outliers now? Water outliers. Outliers are the data points which happened to be, let's say, the observation that fall well outside the overall pattern of the data. Right, that that lie very far away from the rest of the data points. So I can say that yes. Two and four appear to be like out lives. Right? So this is part a two and four can be thought of as outlets. These are unusually law. Great. These scores are low Now. The second part says visas compute the usual Mean what does the usual mean, usual mean expert is given by the submission of all the values that I have upon. And that is the number of observations. So if I add all the values that I have. I'm going to use a calculator for this one. Okay, so this is two plus four plus 15 plus 15 plus 16 plus 16 plus 16 plus 17, plus 19 plus 20 plus 21 plus 21 plus 21 plus 24 plus 25 plus 25 plus 26 was 27 plus 27 plus 28. Okay. Okay, so the submission is 3 85. So we divide this by 20. So this is 3 85 divided by 20. All right, so this is going to give us 19.25 This is our average, right? Yeah. Okay. After that parses compute 5% trimmed. Mean of that, I don't know. What is 5% of 20. Okay, 5% of 20. So this is going to be one value, right? One value from the bottom and one value from the top. What we are going to do is we are going to take only 18 values. We will delete the first, the lowest value and the highest value. So we will remove two and 28. So what will our addition be in that case in that case, our addition will be 3 to 5 minus to minus 28 which is nothing but 3. 55 right, 3 55 by 20 3. 55 by 20. Right, So this is 3 55 divided by 20 which is 17.75 17 points. In fact, this is our 5% trimmed mean in part D. We have to compute the 10% trimmed mean of the data, 10% means we will remove the lower 10% values and the higher 10% values, which means to 4, 27 and 28. Right, So two plus 46 plus 27 is 33 plus 28 61. So we will subtract 61 from 35 3 85. 61 is 3 24. So 3, 24 right? Just a moment. So this is 3 24 divided by now. It is going to be 16, right? And Oh, and we just made a mistake over here. This should be 18. Just a moment. They should be 18 for 5% trend. I mean, this should be 18. So this is 3 55 divided by 18, which is 19.72 Okay, 19 point seven two. All right, so this is 19.72 now. 3 24. Divided by 16. 3. 24. Divided by 16. Now this turns out to be 20.25 All right? Now, the last part, that is part is has compared the means in parts B two t. Okay. Now, which are the three means provide the best measure for the center of the data. Now, the mess best measure will always be given. If you're calculating the means, it will always be given. Then you have removed the out lives, right? So I would say that in this case, the best measure is given by Part D. That is a 10% trimmed Dean. Why? Because you are removing two and four, which are unusually low. Right? So we would say that part D gives the best measure. Why? Because you have removed the outliers in this case.


Similar Solved Questions

3 answers
Question 5 (1 point) You have developed the following Iinear regression output from the promotion data on the left of the regression output: Your boss decides that a "Go big or g0 home" strategy appropriate t0 penetrate the market: He asks the question "what kind of sales can we expect if we spend S90OK on advertising and price our computers at S892" Use the linear regression iodel to predict the expected value of sales55,90596'/ 74
Question 5 (1 point) You have developed the following Iinear regression output from the promotion data on the left of the regression output: Your boss decides that a "Go big or g0 home" strategy appropriate t0 penetrate the market: He asks the question "what kind of sales can we expe...
5 answers
(10%)1 . Find the area of the region bounded by the curves y = 4x-x and
(10%)1 . Find the area of the region bounded by the curves y = 4x-x and...
5 answers
Find the crOss product Z x € where & = 8i 63 3kand & = ( - 3, 4,4).ixi=Question $ of 10 Points possible: This attempt of 4.Continue
Find the crOss product Z x € where & = 8i 63 3kand & = ( - 3, 4,4). ixi= Question $ of 10 Points possible: This attempt of 4. Continue...
5 answers
Be sure t0 Tnser all parts:Report42.07-L flexible flask at 1S'C contains miture ofNz, He; and Ne at partial pressures of 0_JOL atm for N0.193 atm for He; and 0.457 atm for NeCalculate the total pressure of the mixtureSolubiGuided SoeatmFEME(6) Calculate the rolume liters at STP occupied by He and Ne if the N is remov€d selectiveh:
Be sure t0 Tnser all parts: Report 42.07-L flexible flask at 1S'C contains miture ofNz, He; and Ne at partial pressures of 0_JOL atm for N0.193 atm for He; and 0.457 atm for Ne Calculate the total pressure of the mixture Solubi Guided Soe atm FEME (6) Calculate the rolume liters at STP occupied...
5 answers
IS 9 chcra ( So (u Iia n D Sin 2 ^ 04 glag mal C Cosi ^ + diffc ren Iia / (4u4fi dn 2 - 4LL ht re C ah d 0 are Cans fants ihe Sol4lid n of fhe difkrenhi #Ke a | find eyu a fion Iken (c Parli Cul ar Give n Yha ! 9 ( 0) 0 3 an d 3 ( 0) = 2t
iS 9 chcra ( So (u Iia n D Sin 2 ^ 04 glag mal C Cosi ^ + diffc ren Iia / (4u4fi dn 2 - 4LL ht re C ah d 0 are Cans fants ihe Sol4lid n of fhe difkrenhi #Ke a | find eyu a fion Iken (c Parli Cul ar Give n Yha ! 9 ( 0) 0 3 an d 3 ( 0) = 2 t...
5 answers
Wcek Hoclcs Shesen 490 3upolny Cuetion Kemps 012InconectYour ens ver E InconectFind an equation forthe line belowt
Wcek Hoclcs Shesen 490 3upolny Cuetion Kemps 012 Inconect Your ens ver E Inconect Find an equation forthe line belowt...
5 answers
6.1 Section Exercise 41Question 23 of 29 (1 point) Find the value that corresponds to the given area in the figure belon Use Table E and enter the answrer to 2 dccimal places (Note Figure not drawn to scale )0.2708
6.1 Section Exercise 41 Question 23 of 29 (1 point) Find the value that corresponds to the given area in the figure belon Use Table E and enter the answrer to 2 dccimal places (Note Figure not drawn to scale ) 0.2708...
5 answers
Find & =[:] such that: min %a" [-G 2 aJa+([4]-[~J)" a subject to Problem € : 1 | a = 0 -1 at < a = a Jsc[1] where G is the Gram matrix
Find & = [:] such that: min %a" [-G 2 aJa+([4]-[~J)" a subject to Problem € : 1 | a = 0 -1 at < a = a Jsc[1] where G is the Gram matrix...
5 answers
0.0o pointsPercent Thes Be sure Percent abundance HL abundance of IOB: 0 all 0 1 parts. and Calculate 1 the attompts U and 50C6o0"n9 PL Check my 1 work H isotopes: The average Aaomin
0.0o points Percent Thes Be sure Percent abundance HL abundance of IOB: 0 all 0 1 parts. and Calculate 1 the attompts U and 50C6o0"n9 PL Check my 1 work H isotopes: The average Aaomin...
5 answers
P2(3) =51314
P2(3) = 5 13 14...
5 answers
Initially there are 3 moles of an ideal gas at constant pressure and temperature of 0.6 atm and 1JO %C respectively After moles of the gas are added_ what is the change In iInterna energy of the system? AH '232 ].22.5 kJ 0-220.] 022.1kJ -0.657 kJ 0220_
Initially there are 3 moles of an ideal gas at constant pressure and temperature of 0.6 atm and 1JO %C respectively After moles of the gas are added_ what is the change In iInterna energy of the system? AH '232 ]. 22.5 kJ 0-220.] 022.1kJ -0.657 kJ 0220_...
5 answers
Laxalele computor Uvulor Iot 51,0120 Iha Iralce shoda Iaruie A/0,W1G,NJO Ha cun allord Io puy $2,200 wthin 10 days ol (he ueolce Iut punun taanvocatand nanlnunelthin Itt D0dot(XI TuDAaniy Eredend [ Ine nccounI ky Ino $2.200 paymanl; and hon much Is sUM dud?craulliladeantelto dcceurt Ft IWouv lu Iru aoe comv (CON]42A00 @whenl IeQutalanuna buarcl(Round Io Ua nonroel cenim nora |
Laxalele computor Uvulor Iot 51,0120 Iha Iralce shoda Iaruie A/0,W1G,NJO Ha cun allord Io puy $2,200 wthin 10 days ol (he ueolce Iut punun taanvocatand nanlnunelthin Itt D0dot(XI TuDAaniy Eredend [ Ine nccounI ky Ino $2.200 paymanl; and hon much Is sUM dud? craulliladeantelto dcceurt Ft IWouv lu Iru...
5 answers
Using the appropriate table, the probability that a column among16 columns will fail is 0.05. What is the probability that at most3 will fail?a. 0.0359b. 0.9571c. 0.9930d. None of the above
Using the appropriate table, the probability that a column among 16 columns will fail is 0.05. What is the probability that at most 3 will fail? a. 0.0359 b. 0.9571 c. 0.9930 d. None of the above...
5 answers
Cylindrical log 15 cm in diameter and 52 cm long is glowing red hot in a fireplace.Part AIf its emitting radiation at the rate of 30 kW what is its temperature? The log's emissivity is essentially Express your answer using two significant figuresAzdSubmitRequest Answer
cylindrical log 15 cm in diameter and 52 cm long is glowing red hot in a fireplace. Part A If its emitting radiation at the rate of 30 kW what is its temperature? The log's emissivity is essentially Express your answer using two significant figures Azd Submit Request Answer...
5 answers
28). How is the process of X-chromosome inactivation similar to genomic imprinting? How is it different? 3 points
28). How is the process of X-chromosome inactivation similar to genomic imprinting? How is it different? 3 points...
5 answers
3) (Modified from problem by Kesten & Tauck): For each of the three circuits shown below, determine the current through each resistor in the figure: Also, determine the total power consumed by the entire circuit:a)b)10 93 9 M129 W93 Q M12 98 Q M 2 Q910 Q MV59808 94912 V6 V100 V
3) (Modified from problem by Kesten & Tauck): For each of the three circuits shown below, determine the current through each resistor in the figure: Also, determine the total power consumed by the entire circuit: a) b) 10 9 3 9 M 129 W 9 3 Q M 12 9 8 Q M 2 Q 9 10 Q MV 59 80 8 9 49 12 V 6 V 100 V...

-- 0.020968--