Okay. Now, first of all, we have a table with us. Now. How many values are there on the table? 123456789 10 11 12 13 14 15 16 17 18 1920. So there are 20 values of n happens to be 20. In this case, the number of observations is 20 right? The first one says the first part. A says, Do any of the scores look like outliers now? Water outliers. Outliers are the data points which happened to be, let's say, the observation that fall well outside the overall pattern of the data. Right, that that lie very far away from the rest of the data points. So I can say that yes. Two and four appear to be like out lives. Right? So this is part a two and four can be thought of as outlets. These are unusually law. Great. These scores are low Now. The second part says visas compute the usual Mean what does the usual mean, usual mean expert is given by the submission of all the values that I have upon. And that is the number of observations. So if I add all the values that I have. I'm going to use a calculator for this one. Okay, so this is two plus four plus 15 plus 15 plus 16 plus 16 plus 16 plus 17, plus 19 plus 20 plus 21 plus 21 plus 21 plus 24 plus 25 plus 25 plus 26 was 27 plus 27 plus 28. Okay. Okay, so the submission is 3 85. So we divide this by 20. So this is 3 85 divided by 20. All right, so this is going to give us 19.25 This is our average, right? Yeah. Okay. After that parses compute 5% trimmed. Mean of that, I don't know. What is 5% of 20. Okay, 5% of 20. So this is going to be one value, right? One value from the bottom and one value from the top. What we are going to do is we are going to take only 18 values. We will delete the first, the lowest value and the highest value. So we will remove two and 28. So what will our addition be in that case in that case, our addition will be 3 to 5 minus to minus 28 which is nothing but 3. 55 right, 3 55 by 20 3. 55 by 20. Right, So this is 3 55 divided by 20 which is 17.75 17 points. In fact, this is our 5% trimmed mean in part D. We have to compute the 10% trimmed mean of the data, 10% means we will remove the lower 10% values and the higher 10% values, which means to 4, 27 and 28. Right, So two plus 46 plus 27 is 33 plus 28 61. So we will subtract 61 from 35 3 85. 61 is 3 24. So 3, 24 right? Just a moment. So this is 3 24 divided by now. It is going to be 16, right? And Oh, and we just made a mistake over here. This should be 18. Just a moment. They should be 18 for 5% trend. I mean, this should be 18. So this is 3 55 divided by 18, which is 19.72 Okay, 19 point seven two. All right, so this is 19.72 now. 3 24. Divided by 16. 3. 24. Divided by 16. Now this turns out to be 20.25 All right? Now, the last part, that is part is has compared the means in parts B two t. Okay. Now, which are the three means provide the best measure for the center of the data. Now, the mess best measure will always be given. If you're calculating the means, it will always be given. Then you have removed the out lives, right? So I would say that in this case, the best measure is given by Part D. That is a 10% trimmed Dean. Why? Because you are removing two and four, which are unusually low. Right? So we would say that part D gives the best measure. Why? Because you have removed the outliers in this case.