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Qucstion 33poiniaLta Lilne~solution contumg 10" * moles of NOH anil tinal volurte is 0.50 L Wh:t e the pH of this solution?10 ' moles of HC into comfiner...

Question

Qucstion 33poiniaLta Lilne~solution contumg 10" * moles of NOH anil tinal volurte is 0.50 L Wh:t e the pH of this solution?10 ' moles of HC into comfiner and Ihen walcr udded until Uie(Hint: pH POH N4 to8~logtoand [hI - ~oslo (OH w)00 14 250au0 E

Qucstion 3 3poinia Lta Lilne ~solution contumg 10" * moles of NOH anil tinal volurte is 0.50 L Wh:t e the pH of this solution? 10 ' moles of HC into comfiner and Ihen walcr udded until Uie (Hint: pH POH N4 to8 ~logto and [hI - ~oslo (OH w) 00 14 250 au 0 E



Answers

(a) Calculate the $\mathrm{pH}$ of $0.55 \mathrm{MHCN}$, if $K_{\mathrm{a}}=6.2 \times 10^{-10}$ (b) Calculate the $\mathrm{pOH}$ of $0.044 \mathrm{M} \mathrm{HIO}_{3},$ if $\bar{K}_{\mathrm{a}}=0.16$.

To calculate the p o. H from the hydroxide concentration, we simply take the negative log of the hydroxide concentration. Then once we have the P. O. H, we subtracted from 14 to get pH. So the answers are six and eight. Again. If we have the hydroxide, concentration will take the negative log of it in order to get P O. H 3.19 and then subtracted from 14 to get Ph. 10.81 when the concentration of hydroxide this 6.5 times 10 the negative four We have the hydrogen ion concentration at 3.6 times 10 to the negative. Nine will take the negative log of that to get a pH of 8.44 subtracted from 14 to get our p o H of 5.56 Again. If we have the hydrogen ion concentration this time a 2.5 times 10 the negative two will take the negative log of it to get Ph two point are 1.60 subtracted from 14 to get p o. H. 12.40

Let's ask the question, asked us to look at acid base equilibrium. Were given this initial acid at this concentration with this K. A value. And asked to calculate the ph of the solution. Um that will result from that starting concentration. And so have the first thing to do would be sort of to look at what the reaction of that acid would look like. And I'm kind of simplifying here. But basically that acid is going to dissociate into protons and a conjugate base why minus here and solution. And this proton concentration is going to tell me ultimately, you know, give me the ability to calculate the ph of this solution. So since I'm given the CA here, let's set up the expression for it K. A. For this reaction, it's going to be hydrogen ions times can get base over the undecided associated form of the acid. And I know the K. A value right? And I know my starting concentration. So let's plug that information. And I got 1.50 times 10 to the -4. And I know that both the hydrogen ion and the conjugate base are going to be the same concentration. I just don't know what that concentration is yet. So let me just call that X. Okay. And I know that at equilibrium the concentration of my acid is going to be reduced by X amount. So I'm going to plug that value in and that will give me the equilibrium concentration of my acid basically, if I solve for X here, that will ultimately get me to my ph calculation. So let's work on that next. So when I look at the problem, want to simplify it as much as possible. And since this is a pretty low value for K. A. It's pretty weak acid, I'm going to make the assumption here. Since I'm starting with a fairly concentrated acid to I'm just going to try this out and see if I can ignore the value of Acts with respect to that's starting concentration. So that just allows me then to multiply the K value by simply .175. And when I do that I get this value of 2.6 times 10 to the negative five. That equals X squared here. So the next step then is to take the square root of this number to get me X. And remember again that acts is going to give me my hydrogen ion concentration. So when I do that X, which again is my hydrogen ion concentration equals 5.1 times 10 to the negative third. Okay. And I could just check my assumption here about ignoring The contribution and just subtract it this value of X from .175 and see if I get the same value. So I'm going to do that next. So what I found when I did the subtraction is I actually did get and noticeably different Um concentration value. And so the .175 I noticed that my value here went down 2.170. And so this this means it wasn't a good assumption to make that I could ignore the contribution from X. So that means instead I need to utilize the quadratic equation to more precisely solve for the value of X. Here. So what did I do? Put X back into the equation and multiply the values out so that I could put this in a form which is um the proper format to utilize the quadratic equation. And so when I multiply these values out I get 2.62 times 10 to the negative five -1.50 Times 10 to the -4 X equals X squared. I want to make that all equal to zero. To utilize the quadratic equations. So I carried over these values. Set it equal to zero and now pain in the rear end. I know but we can utilize the quadratic equation here. two more precisely solve for X or the hydrogen cat eye on value for to determine overall the ph So let's go ahead and do that. Next. The second part of the question asked us to calculate the P O. H. For a weak acid with the same starting concentration. And so the K value is even a little bit stronger for this asset. And so um already sort of no because a larger K value, the contribution for acts is going to be a bigger factor and that we're also going to need to use the quadratic equation here and so set up the K. Expression as we did in the first example give us the value of CA is two times 10 to the negative too X squared is going to be the ion concentration in 0.175 minus X. The un dissociated asset. And then what I did is multiplied this out and put it in the form that we can utilize for the quadratic equation and solve for X. And when all is said and done the value of access 0.50 molar hydrogen ion and calculate the ph we're gonna take the negative log of that value. And when we do that we get a ph value of 1.30. But the question asked for P. O H. So there's one final step here, ph plus P O H equals 14. So if I plug in that 1.30 value, I can determine the p o. H. Of the solution And that's going to be 12.70. So kind of a lot of work to go through. But when all is said and done, we've been able to determine what the questions asked for by utilizing, um, best practices here.

So were given one point girl times 10 to the negative three. Most of the CEO and we have our bombing, which is he is equal to 5.0 leader. We'll have to find the page in the pew, so recall our polarity of a deal that's equal to our moves of It's over. It's falling five point old leaders, which is me to 0.0 times 10 to the negative four and of you now we know about the concentration of H Plus is equal to that of a deal, which is equal to two point girl times 10 to 4 polarity. Therefore, our P H is equal to the negative log of R H plus, which is two point girls times 10 to the negative, and that gives me a p ages 30.7. And now that we have a page of 3.7, we can plug it into our formula. So are PhD quit soon 3.7 plus purity minded or is equal to 14 so we don't have the fuel, which is equal to 14 minus 3.7, which gives me 10.3

Okay, So, first question, we have to calculate the pitch on the p o h of our awkward solutions at attempt a cure of 298 Kelvin, the report A We have a constitution of always two women at the pool is equal to the native log. Oh, the concentration of our so h minus said at one point go 10 to 6. Taking that into captivity. We have six, and we you call that the pH P O H 26 is equal to 40. So we see that r p H is equal to eight, and we could do the same for 40. We have that are appealing. Physical, too. Negative log of 6.5 times 10 to the negative force, which gives me 3.2 and solving our pH feel h is equal to 14. Equation. You see that P. H is equal to 10.8. Okay, No reports. He has a concentration of h plus. So I mean, the pH is people sitting like a log, uh, 3.6 times 10 to the night of nights. And that gives me 8.4 and we get a pillow difficult to 14 minus 8.4, which used a 5.6. And lastly, we have party, so we have a pH. You be good tonight. 2.5 time tension in the room, too. And that gives me one point appeal, which is equal to 14 minus 1.6, which gives me 12 point work.


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