Question
If ΔG of the following reaction is –114 kJ, what is the E0 ofthe reaction?A2+ (aq) + 2B(s) → A(s) + 2B+ (aq)Answers: A. +0.59 V B. –0.9 V C. –0.59 V D. +0.00059 V E.+0.09 V
If ΔG of the following reaction is –114 kJ, what is the E0 of the reaction? A2+ (aq) + 2B(s) → A(s) + 2B+ (aq) Answers: A. +0.59 V B. –0.9 V C. –0.59 V D. +0.00059 V E. +0.09 V
Answers
What is the value of $x$ for the following reaction if $E^{\circ}=1.43 \mathrm{V}$ and $\Delta G^{\circ}=-414 \mathrm{kJ} ?$
$$\mathrm{A}+\mathrm{B}^{x+} \longrightarrow \mathrm{A}^{x+}+\mathrm{B}$$
Hello students. In this question we have to calculate the delta jeannot for the reaction having cape columbarium equals to 10 to the power five. And the temperature is 1 27 degrees integrate this is equal to 400 Calvin. Okay so we know that delta is not, it is equals to the rt minus RT Ln K equilibrium. So minus of our which is 8.314 manipulated by temperature T. Which is 400 Calvin and Ellen of natural log of 10 to the power five. So this value will be in the jewel per moles, converting it into the collegial per mole by dividing by 1000. Okay So after solving this value, Delta Jeannot will be obtained as -38.294. Kill a jewel per mole. Okay so from the given options option A Here is the correct answer for this problem. Okay so by using this simple formula we can calculate the free energy for any reaction when we have given the calvary. Okay thank you.
To answer this question, there's a series of equations that are available in the textbook that you can use. That relates Delta G standard to E. Standard two K. These are four of those equations. So for the first one, if we're given delta G and kill a jewels, all the equations requires us to use jewels. So to solve for E standard, the standard will be equal to negative rearrange this equation, the standard is equal to negative delta G over N. F. F is constant, Faraday's constant. We get negative .0985V and then K is going to be equal to tend to an E Over the .05916. We get 4.69 times 10. The negative four For the next one we know e standard. So delta G standard can be calculated using this equation And we get -6, jewels. And then K can be calculated using this equation and we get 15 to The last one. K is .95. So delta G can be standard. Delta G. Standard can be calculated using this equation negative are multiplied by T, multiplied. Let the natural log of K. We get 127 And then for the last one he standard can be calculated using this equation with the K value provided and we get negative 659 times 10 the negative four.
We know that the formula to calculate downtown this to call witness sort is Linus Elka each right, They're using this formula. Old equations. Let's start. Okay. We have got a each to be my mystery 85. Or I could cry to 98 with temperature. I think it's you. 1.29 Hello, Jewell. Per Kelvin will be. We have again minus creating fried. I could break 77 like two fries. Kill a jewel for Kelvin. CS minus 100 Came to have a break. You 98 Is your mind this morning? Treat a Cree killer actual Per Calkins. My looks created Cree Joel Per Kelvin and finally the we have minus woman for cab driver pricing These seven, that is he was minus one point for AEG killer chill for killing music Welcome minus 1.48 and pretend to part minus three Children account
Hello students in this question we have given a reaction for which the change in and therapy delta H. Is 82.8 kg jewel at temperature T equals to 25 C that is 2 98 Calvin. So we have to determine changing internal energy DELTA you. So we know that meant to educate is equal to dental floss dente angie Marie claire by RT. So Delta H. is 80 2.8 kg jewel. This is equal to delta U. Plus N. G. Which is the changing number of moles which can be seen from the occupation is one and our which is 8.3 and four temperature is 2 98 Calvin. And they were by 1000 to convert it into the kalamazoo. So delta you from here after solving He's obtained as 80.3 to kill Jews. Okay so from the given options option B. Here is the correct answer for this problem. Okay thank you.