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During the Analysis of Food Dyes, some students analyzed FD&C Green 3 dye instead of the Red 40 dye_The student prepared a stock solution of FD&C Green 3 dy...

Question

During the Analysis of Food Dyes, some students analyzed FD&C Green 3 dye instead of the Red 40 dye_The student prepared a stock solution of FD&C Green 3 dye with a concentration of 63.0 ppm:Next the student prepared a dilute solution by taking an 8.50 mL aliquot of this stock Green 3 dye solution and diluting to 50.0 mL in a volumetric flask:What is the concentration (ppm) of the Green 3 dye of the dilute solution?Your answer should contain 3 significant figures_Answer:

During the Analysis of Food Dyes, some students analyzed FD&C Green 3 dye instead of the Red 40 dye_ The student prepared a stock solution of FD&C Green 3 dye with a concentration of 63.0 ppm: Next the student prepared a dilute solution by taking an 8.50 mL aliquot of this stock Green 3 dye solution and diluting to 50.0 mL in a volumetric flask: What is the concentration (ppm) of the Green 3 dye of the dilute solution? Your answer should contain 3 significant figures_ Answer:



Answers

Suppose you have $100.00 \mathrm{mL}$ of a solution of a dye and transfer $2.00 \mathrm{mL}$ of the solution to a 100.00 -mL volumetric flask. After adding water to the $100.00 \mathrm{mL}$ mark, you take $5.00 \mathrm{mL}$ of that solution and again dilute to 100.00 mL. If you find the dye concentration in the final diluted sample is $0.000158 \mathrm{M},$ what was the dye concentration in the original solution?

This isn't too tough of a problem we're tasked with finding. Let me see if I got my on here. I'm doing a voice over on this one. Sorry about that. We're finding the volume of odd shaped swimming pool. It's not gonna be possible to determine its dimensions and calculate the volume. So what we're gonna do is we're gonna stir in a die. We're going to add 1.0 g of methylene blue. It's a special dye, and it's got this big, long calculation or big lung formula in case you're interested. It c 16 h 18 c l in three s. And this is mixed up in exactly 50 mL of water. So we know the concentration, or we can figure out the concentration. I looked up the Moller Mass of methylene blue and was 319.85 g per mole. Excuse me. So we can figure out the mill Arat e off this methylene blue solution. We've got all the information we need to do that. So the concentration is going to equal of methylene blue. That's MB methylene blue. When we are done in the swimming pool is 4.18 times 10 to the minus eighth molars Clarity equals moles per leader. Leader equals moles Divided popularity. So now we're going to convert our grams of methylene blue 3 to 19.85 g. Permal that's gonna give me malls 0.3126 Moles of methylene blue. Now we're gonna substitute that in for our moles. So the leaders, the volume equals 0.3126 moles divided by 4.1 times 10 to the minus a polarity and the volume is 76.255 or 76,255 leaders 7.6 times 10 to the fourth leaders and that's it.

In this problem, we would like to determine the volume of water in a regular sized pool. We put a solution of dye into the pool consisting of one gram of methylene blue in 50 milliliters of water. We took a sample of the water and found that the molar concentration of the die in the pool is 4.1 times 10 to the negative eight. Moeller. We can start solving this problem by first getting our moles of metal blue So we know that we put one gram of methyl blue into the pool and we can divide by our Mueller Mass to get this in terms of moles. So, doing that math, we find that 0.31 Moles of metal blue are present in the pool. Now that we know the amount of moles of metal blue that are in our solution, we can use the molar concentration of die to solve for the total volume. So we know from our sample that are Mueller Concentration is 4.1 times 10 to the negative eight Moeller and that should be equal to the amount of moles of metal blue divided by our volume which is X. So when we solve for X, we find that we have 7.6 times 10 to the four leaders in our pool.


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