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How does one assess the binding is (a) identical, (b)non-identical, (c) independent,(d) sequential(e) cooperative whentwo ligands bind to a given molecule using Iso...

Question

How does one assess the binding is (a) identical, (b)non-identical, (c) independent,(d) sequential(e) cooperative whentwo ligands bind to a given molecule using Isothermal titrationcalorimetry?

How does one assess the binding is (a) identical, (b) non-identical, (c) independent,(d) sequential(e) cooperative when two ligands bind to a given molecule using Isothermal titration calorimetry?



Answers

Which of the following is the best way to judge the relative activation energies between two given chemical reactions?
a. Compare the $\Delta G$ values between the two reactions.
b. Compare their reaction rates.
c. Compare their ideal environmental conditions.
d. Compare the spontaneity between the two reactions.

So this question is asking us what is the best way to compare the relative activation energies of two chemical reactions? Um, and recall that the only thing that activation energy values impact is thespian of the reaction. Um, and this means that you can't compare to chemical reactions of activation energies by their Delta G or by their ideal environmental conditions. Additionally, the spontaneity of two chemical reactions, um, depends on whether or not it's undergone IQ or eggs or chronic. Um, so this gives no information, um, on activation energy. So the only way you can compare the activation energies of two chemical reactions is by comparing their reaction rates. Um, a higher E A. Ah, higher activation energy is a slower reaction, and a lower activation energy is a faster reaction. Um, and as the answer to this question

Let's devise a simple experiment in which we are two. Separate each of the following in a whereas two separate cyclo hexane in and Angeline so a mixture of cyclo hexane own and Angeline reacts with a HCL H 20 solution Solvent Used is a mixture of dia Phil ether in water cyclo, hexane own. It's found in the ether layer and Anna lean as aniline hydrochloride is found in the acquis layer for be well, it's two separate a mixture of cyclo, Hexen and cyclo hexane. All cyclo vaccine reacts with water are rocks with story works with roaming water. Okay to produce a 12 die bro mo cyclo hexane solution. Yeah, Here an electro filic addition. Reaction takes place. Uh, the double bond of cyclo vaccine due to the consumption of Ramin the reddish brown color of rooming disappears in the cyclo. Hexane are molecule The double bonds were absent so there is no electoral filic addition reaction therefore no color change can be observed on the addition of roaming water and proceed We are two separate Ben's Alda hide and cinema lta hide, sit him All the hide undergoes an electoral fill a condition reaction to form one or 23 di promo three fennel pro bono. This is due to the presence of a double bond in the arcane group. Ben's Alta Hide does not react with broom mean, as there is no double bond present in the All King Group for in electoral filic addition, reaction to occur.

Answer for the question here, Uh, the values. Oh blooded. Oh, Texas. Yeah. No Did. Here, set B will go. Okay. Really? You are Mhm. Mhm sick. Model curve always represents Mhm. Mhm. Cooperate. You okay? Binding said air will show mama hyper bolic of Yeah, So the answer should be Set me yeah.

We want to determine for both Endo thermic reactions and part A and exo thermic reactions in part B. How the change in entropy compares between the products and the reactions we start import A by considering Endo thermic reactions. Remember that for a reaction to be endo thermic, the change in m pulpy don't age us to be greater than zero. And so therefore we can include Delta H as a reactant in a general equation of of reacting a going to product be because of that, we can see that a change is equal to a final ST minus and initial state. And in the case of a reaction, it should be the entropy of the products minus the entropy of the reactant. And since this is greater than zero, you can see that the entropy of the products is greater than the entropy of the reactant switch would lead to this built to HB in greater than zero. So therefore we can say that there is a positive change from the reactant to the products in terms of mental P, since the entropy of the products would be greater than the reactant in endo thermic reactions, Rex so thermic reactions. The opposite is true, that is, Delta H. The change in entropy is negative or less than zero and can therefore be written as a product of the general reaction. A goes to B and when this is the case again, considering a final ST minus initial state, see that products minus reactant. Since it's negative, then the entropy of the reactant is greater than the entropy of the products, so that as we move from the reactions to the products, we have a decrease or a negative change in the entropy of that reaction system for extra thermic reactions.


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