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According to the following reaction:2AgNOz (aq) + Cu (s)Cu(NO3) (aq) + 24g (s)What would you multiply 'grams of silver nitrate" by to convert to the units...

Question

According to the following reaction:2AgNOz (aq) + Cu (s)Cu(NO3) (aq) + 24g (s)What would you multiply 'grams of silver nitrate" by to convert to the units "moles of copper"(numbcr)(unit)(numbcr)(unit)grams AgNO3moles Cu(numbcr)(unit)(numbcr)(unit)

According to the following reaction: 2AgNOz (aq) + Cu (s) Cu(NO3) (aq) + 24g (s) What would you multiply 'grams of silver nitrate" by to convert to the units "moles of copper" (numbcr) (unit) (numbcr) (unit) grams AgNO3 moles Cu (numbcr) (unit) (numbcr) (unit)



Answers

According to the reaction $2 \mathrm{AgNO}_{3}+\mathrm{Cu} \rightarrow \mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}+$$2 \mathrm{Ag}$ .how many grams of copper(il) nitrate will be formed upon the complete reaction of 26.8 grams of copper with excess silver nitrate?

We have a reaction between Cooper has ever nitrates. So between these two were at in every way every shoulder produce silver and unknown reacting. So we are going to complete this chemical reaction. And also far the mass off the unknown reacting and also the unknown. Reactive. Okay, so you can see that this is essentially a single displacement reaction. So that means helping in pace the re agent first. So it will cooperate. We we pay silver. Um, we have super over here. And also you will become copper. No treat copper nitrate. Okay, The next step, we're going to bars the chemical reaction because we have to nature under right. So we have to put two nitrate. I mean two infernal super nitrates. And also we have two infernal silver. Okay, so we have to a chemical reaction. And also you filed that the unknown part of will be covered nitrate. So that's that we're going to found a mass off couple in a nitrate. Okay, so we know that the mass off copper he is 65 on five. As if in nitrates, leafy 9.8 scram. So the total mass will be adding both to get her and you can just soaked elevator and you should be able to find out. It would be slow for you wonderfully, Graham. So you just need to add this to together. We have found the total mass of Cooper and super nitrates. Okay, so by conservation of mass, the mass, the total mass of the reaction should not be changing because we don't have any reactions. Are leaving the waiting. We're back. So for several gas can be can be the best. So so But for this game, we don't have a solid and those over increase solution. So the master to the master be the same. So we're given the massive silver is 215.8 gram. So the mass off couple naturally must be equals to our total mess. Sub trick our mass off silver and you should be able to find that the massive silver everybody goes to 187 put a fight crime and disa coded different by a total mess. It's a trick. Our super mass and then we will have the mass of supernatural is 187.5

This question is also a simple unit conversion based upon the story geometry of the balanced chemical reaction. Fortunately they did give us a balanced chemical reaction and we don't need to worry about balancing it. One mole copper reacts with two moles silver nitrate. So if we have 1.95 mg silver nitrate, we can convert the milligrams to grams by dividing by 1000. Then we can convert the grams of silver nitrate two moles of silver nitrate By dividing by the Molar Mass of Silver Nitrate 1 69.87 g. Then we'll look at the sochi geometry of the balanced reaction To Mold Silver Nitrate required just one mole of copper. This will then give us moles of copper, which we can multiply by the molar mass of copper, which we can find from the periodic table Being 63.546 g per mole. This will then give us the mass in grams of the copper required to react with one 95 mg of silver nitrate. This is a relatively small value, 3.65 times 10 to the negative four g. So if we multiply this by 1000 will then get milligrams of 10000.365 mg copper.

In this question, we have to calculate how many grams of copper must react to displace 12 g of silver from a solution of silver 90. Okay, lets write the question between Koper and silver nitrate. Mm mhm produces copper nitrate. Yeah. And some berries displaced from that solution of silver nightie. Now we have to balance this. Let's put through here. So knighted balance to a deal is put to hear. Now this balanced question. Now here, the atomic mass of property 63.54 six. And here atomic mass of silver is 107.8682 and two silver. So two times so uh died two times 107.8682 g silver is displaced. Bye 63.546 g. What part from the silver 90 solution? Therefore, one g silver is displaced. Bye 63.546 grandpa part, divided by two times 107.868 Therefore, well gram silver. Yes, displaced. Bye 63.546 divided by two times 107.8682 times 12 g Co part, and the value is 3.53 g cooper. So 12 g silver is displaced by 3.53 grandma cooper from the solution of silver nitrate.

So in this problem, we want to know how much copper nitrate is produced if we also produce 2.25 grams of silver. So the first thing I did was kind of right out a chemical reaction for the word equation that were given in the problem. And I also went to the periodic table and got some molar masses that we're gonna need. So now let's start with 2.25 grams of silver. So we have here, um, the molar mass of silver, which we're gonna use to convert this two moles. So 107 0.87 grams of silver is ah, mole of silver. And we also have the mole ratio Two moles of silver from our Sochi. A metric coefficients is equal. Teoh one mole of copper night trade. And we also have the molar mass of copper nitrate. So a little of copper nitrate is equal to 187.56 grams. So now it's multiply all that out. We have 2.25 times. Ah 100 in 87.56 divided by 107 0.87 Divided by two and we have 1.96 grams of copper nitrate. What we want to do next is a really similar process for each of the reactant. So let's start with copper. We still convert two moles of silver and then we have the mole ratio of one mole of copper equals two moles of silver, and we use the more massive copper to convert we have one hole of copper is 63.55 grams and we're gonna multiply this out to get 2.25 times 63.55 divided by 107.87 divided by two and we have 0.66 grams of copper. Next, we repeat the process for our silver nitrate. So we have two moles. Uh, silver is equal to two moles of silver nitrate, and we know that from our Miller Mass. One bowl of silver nitrate is equal to 169.787 grams. So now we just have to multiply all this together. 2.25 times two times 169.87 divided by 107.87 divided by two. That gives us 3.54 grams of silver nitrate


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