5

What is the cocfficient for H " after balancing the following reaction in acidic medium?(Plcase notc that clement X and are NOT Hydrogen , Oxygen group not wri...

Question

What is the cocfficient for H " after balancing the following reaction in acidic medium?(Plcase notc that clement X and are NOT Hydrogen , Oxygen group not write answer in sig. figs )A orclements. Also, becausc this is not calculation, Your aneicr should bc wholc number so doXo4 HzYO3x2+ HYO4"

What is the cocfficient for H " after balancing the following reaction in acidic medium? (Plcase notc that clement X and are NOT Hydrogen , Oxygen group not write answer in sig. figs ) A or clements. Also, becausc this is not calculation, Your aneicr should bc wholc number so do Xo4 HzYO3 x2+ HYO4"



Answers

Complete and balance the equations for the following acid-base reactions. Name the reactants and products. (a) $\mathrm{H}_{3} \mathrm{PO}_{4}(\mathrm{aq})+\mathrm{KOH}(\mathrm{aq}) \rightarrow$ (b) $\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}(\mathrm{aq})+\mathrm{Ca}(\mathrm{OH})_{2}(\mathrm{s}) \rightarrow$ ($\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}$ is oxalic acid, an acid capable of \right. donating two $\mathrm{H}^{+}$ ions. See Study Question 31.)

All right. So today we're gonna be practicing balancing redox reactions in acidic solution. And just on the left. Here we have a quick little rule box for your reference. Obviously, as we scroll down, this will disappear. But just to review first, we want to balance our atoms that are not hydrogen or oxygen. Then we want to balance our oxygen's using water. Then we want to balance. Our hydrogen is using protons a k a. H plus. Then we want to balance or charge using electrons and then adjust for story geometry by multiplying appropriately on that last step is often when we forget. But I just want to remind you that if we are balancing things, we need to make sure electrons cancel out on both sides and sometimes that involves in multiplying rise dry que metric coefficients. And so to start with, we have this problem where oxygen gas is being converted to liquid water, and immediately I'm noticing Ah, discrepancy in both oxygen and hydrants. But I want to start with my oxygen. So we have two of the left, one on the right. We're gonna add another molecule of H 20 and for simplicity's sake. I'm just gonna make us a to great. Now we have to. Oxygen's to oxygen's. But now we have four hydrogen ins, so we're gonna resolve that by adding for h Plus is and that's great. But now we have a charge buildup of plus four. So we're gonna have to add your electrons over here. And so our final equation comes to the following. Beautiful. So that's gonna be our final equation for this one is pretty simple, as you can see. Oh, I forgot a post sign here. Alright. Awesome. Now we have this problem where the sulfate ion is being transformed into. Ah, let me think about this for a second. Uh, H two s 03 It's not sulfuric acid, but it's something similar. So, uh, we have s a fortune minus Asia s a great great Let's look at our silver Adams check. Check one her side. Now let's take a look at our oxygen. So for here, three here, obviously the right hand side is deprived. So let's add in that high that water. And now we have four and four. But we have a big discrepancy in terms of hydrated. So we have to and shoe, which leads to four. And we have zero on the left. So we're gonna need toe immediately. Add 400 to the left. And now let's be careful about calculating are charged. We have plus for minus two from this sulfate, and that is gonna lead us to a plus to build up and obviously, on the right, we have zero. And so what we're gonna need to do is add two electrons to the electron deprive side, which is still the left hand side. So we're gonna add in that two electron. And for finality sake, let's write everything out. Let me just double check that. Awesome. So that is our final equation moving right along you have here. We have hydrogen peroxide being transformed into liquid water. So we're going to start with our oxygen. And I see I have one and two, so we're gonna need to add a second molecule, head of water to the left, right. Ah, and I'm just going to stick in that coefficient there to make things a little simpler. And now I see I have to evidence versus four hundreds. And it might be tempting to just say, Oh, look, let's out of two here. But let's not do that because then we're gonna create more problems with their oxygen, and we're just gonna be going back and forth. So it's important to remember balance out that discrepancy with protons rather than adding more coefficients of something. And now we can see we built up a charge. We're gonna need to remedy that with two electrons. Sorry, I don't know. I keep drawing in next, don't there. And our final equation did as follows to teach to our awesome and now moving on to our final problem, we have entered to minus going to nitrate and so nitrite going tonight treat, uh, I know it's hard to keep track of those. So here, check out our nudged and Adam's First we're all squared away. However, are oxygen's are not. So we're gonna need to add a water molecule to the left hand side because we're missing one oxygen there that fixes things for oxygen. But now we have to hide regions over here that are not on the right. So let's add in our two h plus is, and this is where we actually have a little bit, bit of a more difficult situation for charge. So I see. On the right hand side, I have a minus one plus two. And that is gonna lead me to plus one overall. On the left hand side, we have a minus one from this night, Right member, don't forget about our probably atomic charges. So arm or electron deprive side is the right less e. And so we're gonna need to get this to negative one. We're gonna need to add shoe electrons. And, um, let's make sure all about a squared away. So we have a minus one. We have a plus two when we have a minus two. So that brings us back to negative one. Yes. So let's write this all out. H 20 plus nitrate. Don't forget to charge. Plus this plus two of these plus two electrons. Let me just double check back. Awesome. That is our final answer. And I hope this video is helpful in terms of understanding Redox reaction, balancing

Runs in this question. We're going over acid base reactions. So first up, we have phosphoric acid with potassium hydroxide. So this fast forecast it is going to dissociate into H plus and each two p o for minus. And this potassium hydroxide won't associate into potassium and O H minus. And with acid base reactions of this sort, any tendency in age person and O h minus. You know that gonna combine, inform water and neutralize each other So you have health water, and then you have your leftover K H two p 04 minus and this will be assaults way. We call this the salt the reaction, and that will be an atheist part, right? And next up we have a juicy 204 reacting with calcium hydroxide. So this is going to disassociate this calcium will go to associate it to see a two plus and O. H minus that there's going to be two of them. So I'm going to with that over there's gonna be two of them, and this age to see 204 we're told that it's capable of donating to H plus electrons. So we're going to write this as to H plus plus C +204 to minus. And remember, whenever you ch plus and O H minus in the same solution, they're going to react in for water. So we have to change pasta than +20 H minus. So that's going to form to H 20 and then left over. We have calcium and we have CTO before the Tu minus t. Exactly. And so we'll have calcium C A C 204 That's it. Thank you.

First, we will start with what has been given to us. We know that H 20 is gonna go to go to and I need to write a balanced half reaction for this. There's very know there's very little additional information other than that is it is an acidic solution, so we'll start by balancing our oxygen's. We have two oxygen, one oxygen, so they need to put a two right here for water. So now we have two oxygen. But then we introduced for hydrogen. It's an acidic solution so we can balance the hydrogen is by having hydrogen ions on the right hand side, four of them. But now we have a total of four plus charge on the right and no charge on the left hand side, four hydrogen. That one plus gives us a total four plus. So we need our four electrons so that the charge on both sides the some of the charges on both sides are the same

Considering the unbalanced chemical equation. A chemistry student tries to balance the equation by placing a subscript two after the oxygen atom and H 20 this'll is not oh, correct, as you cannot change sub scripts when balancing. As this changes the chemical formula, you can Onley balance by adding coefficients in front of chemical formulas. The correct balanced equation is written as two H 20 to to H two gas plus o two gas.


Similar Solved Questions

5 answers
Lauren Martin (Student section: SC1O) Main Menu Contents GradesPHGN1OO, Introductory MechanicCourse ContentsDue in 11 hours 33 minutesl 1 point(s)Unit Vector ProductsDetermine the values of the following unit vector products_k-hatJ X ] 2 X k x k k ki-hatIptsSubmit Answer Incorrect. Tries 4/15 Previous_Tries
Lauren Martin (Student section: SC1O) Main Menu Contents Grades PHGN1OO, Introductory Mechanic Course Contents Due in 11 hours 33 minutesl 1 point(s) Unit Vector Products Determine the values of the following unit vector products_ k-hat J X ] 2 X k x k k k i-hat Ipts Submit Answer Incorrect. Tries 4...
5 answers
AM WOR IIILSUHiwii o IcceivecicultApply (irccn's [heorem to lind the value o( Jxx' d+2wy'= Ircb Ihe boundlry ol the region enelosed by y =x ud Yelx-X Anqutne Lul Posilively oriented, icgration, Just ct @pP Ihe conresponding integrl with limniti of
AM WOR IIILSU Hiwii o Icceive cicult Apply (irccn's [heorem to lind the value o( Jxx' d+2wy'= Ircb Ihe boundlry ol the region enelosed by y =x ud Yelx-X Anqutne Lul Posilively oriented, icgration, Just ct @pP Ihe conresponding integrl with limniti of...
5 answers
Q1.1 2 PointsWhat is the relationship between the two products formed when the alcohol reacts with HBr?constitutional somersenantiomersdiastereomersSave Answer01.2 3 PointsDraw picture that illustrates why two products are formed:
Q1.1 2 Points What is the relationship between the two products formed when the alcohol reacts with HBr? constitutional somers enantiomers diastereomers Save Answer 01.2 3 Points Draw picture that illustrates why two products are formed:...
4 answers
Consider thc following = Tcaction #hcre10.5 ot JS0 K2CH,Clzlg)CHA(8): cCu(g)Teacton mixture Wus found conlaln LlSx10 ? moks of CH,Clz(g} 4.34*10-2 moles of CH (g) and 4.24*10-2 moles of CCI(g), in & 00 liter contntntnthc rcaction equilibrium? If noL; what direction mustetdt tcach equilibrum?Thc reaction quoticnt Qc equalsTh rcaetlan FMent the loruurd ditcction Iacl Gmnautti nutAnan thc Feicmc Uucchan I4eh cuIctum Il cquilbriul
Consider thc following = Tcaction #hcre 10.5 ot JS0 K 2CH,Clzlg) CHA(8): cCu(g) Teacton mixture Wus found conlaln LlSx10 ? moks of CH,Clz(g} 4.34*10-2 moles of CH (g) and 4.24*10-2 moles of CCI(g), in & 00 liter contntntn thc rcaction equilibrium? If noL; what direction must etdt tcach equilibru...
5 answers
For the circuit show in Figure, find the potential difference across the capacitor in uts of Volt after long time. Deteqmine the cuent passing tluough the resistor Rz in units of Ampere R; = 15 0 Rz = 600,Rz = 350, Ry = 400,€ = 7pFve € = 7Va) Vc = 1,5; Ikz 0,05 b) Vc = 1,8; IR2 0,06 Vc = 2,1; IRz 0,07 d) Vc = 2,4; IR2 0,08 e) Vc = 2,7: IRz 0,09
For the circuit show in Figure, find the potential difference across the capacitor in uts of Volt after long time. Deteqmine the cuent passing tluough the resistor Rz in units of Ampere R; = 15 0 Rz = 600,Rz = 350, Ry = 400,€ = 7pFve € = 7V a) Vc = 1,5; Ikz 0,05 b) Vc = 1,8; IR2 0,06 Vc ...
5 answers
Atoms are in 20 gram of KsPO4? How many
atoms are in 20 gram of KsPO4? How many...
5 answers
Jaylor Coc # 2 Gunctions 3. Find Hl& @ua Series Sollowicg Poiat 20 and cletermine +2 radiu $ abuu | H&ConuergerceCoskz)2ob-) 2-2 (2+3Xz-L)2o
Jaylor Coc # 2 Gunctions 3. Find Hl& @ua Series Sollowicg Poiat 20 and cletermine +2 radiu $ abuu | H& Conuergerce Coskz) 2o b-) 2-2 (2+3Xz-L) 2o...
5 answers
(5 pts)2677 sin? (n)d (4 pts) 5(-I)" &
(5 pts) 2677 sin? (n) d (4 pts) 5(-I)" &...
5 answers
Use the General Power Rule where appropriate to find the derivative of the following functions.$$f(x)=2^{x}$$
Use the General Power Rule where appropriate to find the derivative of the following functions. $$f(x)=2^{x}$$...
5 answers
Question1 ptsThe system described by the reactioncOlg)+Clz(g)=cOClz(g)is at equilibrium at a given temperature when Pco= 0.3atm, Pclz" 0.15 atm , and Pcoclz= 0.65 atm An additional pressure of Clz(g)= 0.43atm is addedFind the pressure of CO when the system returns to equilibriumExpress your answer numerically in atm using 4 decimal places_
Question 1 pts The system described by the reaction cOlg)+Clz(g)=cOClz(g) is at equilibrium at a given temperature when Pco= 0.3atm, Pclz" 0.15 atm , and Pcoclz= 0.65 atm An additional pressure of Clz(g)= 0.43atm is added Find the pressure of CO when the system returns to equilibrium Express yo...
5 answers
Dalo The 9583 Cl Which 3 'Find 2 1 HapM 1 1 VM < 0 05 Estnlte the proportion E value oi ine Snio lemabe VUIA aq Dino V 4onoun pinor bc H Zobs - 1 evadcncc vote for George display 1 null hypothesis 1 ra6 Buch 8 8 V 160.0 (round your Etcence [0 conclude t[ rextute | Ji 1 543 04 2 ocima 2 1 8 (Zaen =1 8 places) 3 Al Gofe ? Tucr Use
Dalo The 9583 Cl Which 3 'Find 2 1 HapM 1 1 VM < 0 05 Estnlte the proportion E value oi ine Snio lemabe VUIA aq Dino V 4onoun pinor bc H Zobs - 1 evadcncc vote for George display 1 null hypothesis 1 ra6 Buch 8 8 V 160.0 (round your Etcence [0 conclude t[ rextute | Ji 1 543 04 2 ocima 2 1 8...
5 answers
ProblemFind f' (~1) where f (z) is the branch of z' with branch cut 0 = 7/2.
Problem Find f' (~1) where f (z) is the branch of z' with branch cut 0 = 7/2....
5 answers
(bl;) %6i; 25 JlaulA particle (charge = 50 HC) moves in a region where the only force on it is an electric force: As the particle moves 25 cm from point A to point B,its kinetic energy increases by 1.5mJ. Determine the electric potential difference; V B VAV15V40-V6o-V30-V5o-
(bl;) %6i; 2 5 Jlaul A particle (charge = 50 HC) moves in a region where the only force on it is an electric force: As the particle moves 25 cm from point A to point B,its kinetic energy increases by 1.5mJ. Determine the electric potential difference; V B VA V15 V40- V6o- V30- V5o-...
5 answers
Ija Question: 1pl101 comnple ciAteclang? cultqudcdwlhHni Tanhao oltubonnamtedmon knlt fetnakshottet Urleeion cl Ihn rectangle and Il lonotu dnttnri (Round c dcuninlacr n< neeeed]ared ol the rodangk IsMourddMo dorimal paces ncnadEriet Ycun ansk=/ M -ch O"Fr € ans - tneXmi9
Ija Question: 1pl 101 comnple ci Ateclang? cultqudcdwlh Hni Tan hao oltubon namte dmon knlt fetnak shottet Urleeion cl Ihn rectangle and Il lonotu dnttnri (Round c dcuninlacr n< neeeed] ared ol the rodangk Is Mourdd Mo dorimal paces ncnad Eriet Ycun ansk=/ M -ch O"Fr € ans - tne Xmi9...
5 answers
QuestionThe solution of the system X / '-(4 &k;xco)-(8) Select the correct answer x-((3 Josvzt-(-JZ JsinvztJea+-X(-J Jcosvzt+(3, Jsinvzt| e2t x-((? Jcosvzt - IsinvZt/et_ 7(-Josvzt (Ghinze)' nonecosvzt-Isinvztcosvztsinvzt
Question The solution of the system X / '-(4 &k;xco)-(8) Select the correct answer x-((3 Josvzt-(-JZ JsinvztJea+-X(-J Jcosvzt+(3, Jsinvzt| e2t x-((? Jcosvzt - IsinvZt/et_ 7(-Josvzt (Ghinze)' none cosvzt- Isinvzt cosvzt sinvzt...

-- 0.021226--