Question
Question 7 (1 pl)f (z)dz-25iQueston 8 (1 p"} Res;(-2i) = -1Now; consider the regular distnbulion . Txassoclated t0 the (unction Then; x(t) =1 + sgn(t = 1) Question (1 pl) Txts temperedQuestion 10 ( P) TX(t) = 28(t - 1) H(t) sin(t)Question 11 (1 F") T' has compact supportQuestion 12 (1 PY) The Lapiace transtorm € 0i * I5 c(x)(s)Question 13 (Tpl) Tne Founer Y() = transtorm otT" (t) 2e-Zrif H(c) = sin(t)isToshiba
Question 7 (1 pl) f (z)dz -25i Queston 8 (1 p"} Res;(-2i) = -1 Now; consider the regular distnbulion . Txassoclated t0 the (unction Then; x(t) =1 + sgn(t = 1) Question (1 pl) Txts tempered Question 10 ( P) TX(t) = 28(t - 1) H(t) sin(t) Question 11 (1 F") T' has compact support Question 12 (1 PY) The Lapiace transtorm € 0i * I5 c(x)(s) Question 13 (Tpl) Tne Founer Y() = transtorm otT" (t) 2e-Zrif H(c) = sin(t)is Toshiba


Answers
For Problems $1-16,$ solve for $t$ using natural logarithms. $$2 P=P e^{0.3 t}$$
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This question strikes us to solve for tea using natural logarithms. What we know that the first thing we can do is divide both sides by Pee Wee. Then know that we can take the not drawing of both sides. Natural sometimes is one. This leaves us with natural log of B minus natural of p. Remember, this is an equivalent way of writing best. This is equivalent to our times. Teeth getting tea by itself. We have tea. Is the natural order B minus the natural order of P over our
This question instructs us to solve for tea by using natural algorithms. The first step is weaken recon. Use cross multiplication to write three to the power of tea Over two to the power of tea is 5/7. Taking the natural order of book sides. We have the natural log of 3/2 to the power of tea as the natural log of five divided by seven. This fraction over here this leaves us with tea is equivalent to the natural log of five minus the natural of seven. Divided by the natural log of three minus the natural log of two as a decimal, this is approximately negative 0.83
By exercise 14. So by exercise 14 in section 18 points four we have C. To be equal to minus courts. See I legs sign, see G. Then in it's equal to sign, see I floods because C. G. Who is C. G. So this implies that by normal vets to be is C. Well it's mm which is equal to you have your eye, the eye components you have mine. It's cause see saying see the energy components. We have sci fi because see Then UK complainants you have observed zero. So they cross borders of this gives us mine. It's key. That's awesome. We have V. So my next key. You have the two vehicle to -3 cause squared. See sci fi I let's do we same squared see of course. See G. So this implies that A it's equal to the A. D. C. Equals C. D. Uber did see of minus three because squid sea sci fi I last d over DT of three. Science quake. See cause she G. So this implies that the air you ever did see it's going to be equal to de cuba D. T. Uh The Uber did see -3 calls squared T. Sign T. I plus D. Uber D. C. The Uber D. C. You have three. You have three science squared. See who's she G. Okay. So then to find a so shame we have. So this implies that you take the cross radars of minus three cores squared sine cosine squared T. So I see then you have D to D C minus three cause squared C. Saying see then we Uber D. C. Of D you ever did see of minus T. V course quaid C. C. T. Then you have three so squared C. Was see then the Uber D. C. Of three same square T. Cause see they have the Uber D. C. Of D. Uber D. C of three science squid. See this times square T. Cause T close T. Then you have zero for the K. Components And this is equal to zero. So this implies that I was so ashamed, is equal to zero.