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At&T7:51 PM4 0 92%Energy Lab.docxrgy Lab. Entrg, Srate Parc Dasics 0.1.19 a l CC CtuCo LYu` 40 &SarchEnergyM 0metersSlow Molon NormalSkate Park: Basicshis l...

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At&T7:51 PM4 0 92%Energy Lab.docxrgy Lab. Entrg, Srate Parc Dasics 0.1.19 a l CC CtuCo LYu` 40 &SarchEnergyM 0metersSlow Molon NormalSkate Park: Basicshis lab you will be using the Phet simulation riction. he screen shot for the set up. There will be runs ch run you will change either the mass from um to large using friction of none, medium vill have nine runs. For each, record the fina EtI

At&T 7:51 PM 4 0 92% Energy Lab.docx rgy Lab. Entrg, Srate Parc Dasics 0.1.19 a l CC CtuCo LYu` 4 0 & Sarch Energy M 0 meters Slow Molon Normal Skate Park: Basics his lab you will be using the Phet simulation riction. he screen shot for the set up. There will be runs ch run you will change either the mass from um to large using friction of none, medium vill have nine runs. For each, record the fina EtI



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Jay rides his 2.0-kg skateboard. He is moving at speed 5.8 m/s when he pushes off the board and continues to move forward in the air at 5.4 m/s. The board now goes forward at 13 m/s. Determine Jay’s mass and the change in the internal energy of the system during this process.

So far the for a duck on an incline starfish the normal force and has the perpendicular competent off And we keys MGI plus I intake now the wage on which dressing it is pushing it down by this force and it is trying to move to the left. So the force from the devil will have a confident in this direction. That's what it if x and here and we have why And definitely there is weight of the block weakest MGI So now this normal forces acting at an angle theta. So if we decompose it, we have and signs that, uh and in the downward direction and prostate So we immediately see that effects it was and signed there and And these mg co signed Did, uh so MGI scientists are co sign data. Andi. Then we will have If why, It was MGI thus and we'll sign. Did uh, Leakey's MGI? Well, science where Toyota So that another reaction force f equals MGI scientific was signed Tetteh I had the US and thus em Well, Sanskrit data G. Jay had taking this to be I on this to be J

First part working by non conservative by scatter. It's greater than work done by friction. So addition of those birds Oh mm. Give 42 below. So his total mechanical energy mm total mechanical energy increased since and speak to the bridges. So going into energy also decrease. But his potential energy will replace because he is going up in be part weapon by non conservative forces. Got involved and by no conservative, forcible and non conjugated to it's got to change in mechanical energy. Find that minus initiative Vulcan by non conservative force. But I was woken by non conservative, too. Thank you. Believe it half and we have to square. Plus yeah, M g h f huh? Everybody is quick, um, so it can be returned to us. Mhm half and we finally squared minus b initially square less energy and finally minus imagination. So data edge. You will get working by non conservative force ball worked in by non conservative force to yeah, minus half, and we finally square. We initially square divided by Putin, and our substitutes have been involved in by non conservative Force One is given 3420 by second. It is 715 half mast is a given find and velocity 4.2 initial is 2.5 and even into 9.8. So it is to me 3.65 We do their son. Thank

Good day in this question we will be solving for the mosque of the far too. So we are given that Must of back one is able to point to kill a grubs. So you see a creation 1967 and 68 with elastic coalition and the subsequent projectile motion. We know that the both box at the same time of faulty during their product projectile motion. Therefore That the X. two is equal to B. two times time. Where The other X two is equal to D. And Delta X. one is equal to v. one d. Where The X one is equal to negative to the so we have 52 From the equation 67 1967 and 68 where veto it was um one He waited by M. one blast. And to feel one i. And we won is equal to M. One minus M. Two divided by M. One plus M. Two B. One. I. We divide the first equation to the second aggression. So substitute thing here we have the it was we duty and from here and here is the -2 d. is equal to be won. T. So we substitute The values of v. two and we want and it's great that time the time we will have D Divided by -2 D. Is equal to two M. 1 divided by M. one Less M. two be when I the divided by I am 1 -M2 Divided but I'm one us M two 3 1 i. D. So constantly we want I. D. A. And the D. We are loved. Weird negative one half is equal to two M one divided by anyone. Bless em too Over M one -M 2. I want this and to We can write this and substitute .2 kg to solve for and do we have negative one half times? Point to minus M. Two. Invited. My point to my nurse plus M. Two. Yes. You go to two times point to Divided by .2 plus and two. Now solving where must do are the mass of back to? We have one kilogram. Thank you.

So let's take a look at what we would get if we follow the directions in this. So let's try launching adam a with very amounts of energy. Good. Let's see what will happen if this is below the transition state of the potential energy line. The total energy. Let's say it would need to be just under this one. Okay, so look, okay, so it looks like the reaction do not occur. Okay, so the transition state is going to be here. So that's when the reactions basically are transitioning into the products. So let's try it again. This reset and then this time let's put the energy way above that we have. Okay, so it looks like we were able to get this reaction to occur. A new bond is formed as you can see. So this is because this part of the graph here, which is the difference in energy between the reactions and the transition state is the activation energy. The molecules. Did you have enough energy to overcome the activation energy in order for the reaction to occur? That's why when we move the energy to above this lying here, we're able to see the reaction has occurred


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