5

How many different kinds of H are there in chloroethene? Indicate if they are primary, secondary, etc...

Question

How many different kinds of H are there in chloroethene? Indicate if they are primary, secondary, etc

How many different kinds of H are there in chloroethene? Indicate if they are primary, secondary, etc



Answers

Into how many sub levels is the third principal energy level of hydrogen divided? What are the names of the orbitals that constitute these sub levels? What are the general shapes of these orbitals?

H is and healthy, or it's the symbol used to represent Antheil P, and an therapy is heat at constant pressure.

So the first reaction occurs between a missile bromide molecules on lithium and then following this we have the reaction with copper. I had died in order to form or organo cooperate and not looking at our second example. Here we have the reaction between our organo cooperate on ether oxide, followed by H C L. In order to form that alcohol structure. So looking at the start example, we have him. We have an alcohol group on sodium hydride and this is used to remove the proton from the alcohol in order to form prop oxide I, on which we have o minus this. Proposed aside, I don't then reacts with if the alien oxide on HC how in order to form our final products. So I've just got my key down here. Where I got a is lithium B is copper iodide. See, we have ch three very of two of those c u l i d is effort Tyrolean oxide e is hc out f his n a H g is ethylene oxide again and then age is again h c l

So get are given structure here. We have C two, C. Three and Mhm. Two. What? Ct, Ch three and Ch three. For a How many primary carbons are there? So if we identify our primary carbons, we would have won two and three. So for a there are three primary carbons. Yeah, indicated in red. For B. How many secondary carbons? There are one, two, 3, 4, 56 In the ring there. So there are six secondary carbons. And how many to sherry carbons? There are one, two, three tertiary cards. Yeah. Yeah. Mhm.

Okay. This problem is having us draw and name all the ethers that corresponded to the military reform in the C five h 12 0 Okay, So given the fact that I have five carbons and also given the fact that I'm gonna make ethers, I know that I'm gonna have an unknown, symmetrical amount of carbons on each side of my auction. Okay, so a neither by definition, is a auction that is sandwich by a certain number of carbons. I know I'm not gonna have something like 12345 carbons. And then on the fifth carbon, I'm connected to my auction because at that point, I don't have a car, but on this side, right, I ran out of carpet, so it would just be an alcohol at that point. So I know that I'm gonna have carbons on each side of my auction. And because I have five. That's an odd number. I'm gonna have a fewer amount of carbons on one side than the other. So, for example, I might have to carbons on the side, but and then three carbons on the other side. But I have to have uneven amount on either side. So, given all that information, let's start. So I'm gonna start with the simplest version, which is an auction which is connected to four carbons. And then on the other side, I have a connection to that one Carbon. Okay, so let's go ahead and name this right now I have on my longest carbon chain 1234 carbons. So that's beauty. And then on my first carbon, I have this connection, which is my miss oxide subsidy A substitute. So it's, uh, the reasons name that is because I have the ch three. So that's mess. And then the auction corresponds to the meth oxy. Okay, so that's gonna be one meth oxy beauty. And as for the common name, the common name is just whatever is we're considering, basically, my carbons as subsistence. So this is gonna be I have my auction. So that's gonna be my ether so either and then connected to that either I have a beautiful group. So veto. And then I also have a method group. So beautiful metal, either. Okay. What we're basically doing for common aims is using my carbons as substitutes off my either from a doctor. Okay, next up, it's already discovered that one. And then let's do the next one in green. Okay, The next one, I'm gonna have to carbons attached the left side of my auction. It's like this Want to auction and then went to three carbons on the right side. So again, I have to find the lungs. Carbon chain, which is gonna be three carbons. 123 on those three carbons correspond to propane. And then this time, instead of the myth Oxy, I have two carbons. So two carbons attached the auction, meaning that I have connected the carbon one on my lungs. Country so connected to carbon one. I have the one e foxy propane. Okay. And then that's that's all one word. Okay, so next up, let's discover the common name of this. So again, the common name is just making my carbons substitutes off of my oxygen. Okay, so I have purple and I have effort. So Essel purple either. And then, as for the order of substitutes, I do it in alphabetical order. Okay, Next up, let's consider this one. I'll do this one in red. So if our toe have we went from the left side will from one carbon to two carbons if were to go to three carbon, it's like 123 And then here's my auction, and I want to. At this point, this is the same thing as what I had just previously drawn my 1/8 Oxy propane because we always consider our longest carbon shape in this case will be 123 So this isn't gonna be my substitute went off of this carbon chain, right? Because my lungs carbon chain is not this. It's in fact this. So it's still gonna be 1/8 oxy propane in this form. I guess we'll have to think of something else. Have to think of a new confirmation of my molecules that is gonna have in your name. Okay, so let's think about this. I stick with red, Okay, so I can have one carbon attached, my auction. But instead of just straight for carbon chain, I could have a little bit different like this. So there's 12 carbon so far. And then how about what if I attach a meth group right there and then continue my chain? So this is gonna be called 123 There's three carbons, four carbons in the longest carbon chain. So it's gonna be butane, okay. And then attached to not cover number three. Because we want my substitute to be in the lowest number Carbon. So I'm gonna rearrange this to incorporate that. So 1234 My oxygen slash meth Oxy group is attached to my car number two. So that's gonna be too meth Oxy beauty. Okay. And then, as for the common name of this, it's going to be we have a meth oxy, meth Fokker attached that either so metal. And then we also have this sec beetle. Okay, so it's gonna be in alphabetical order. The Beetle the beautiful comes before the M and Metro. So sick, beautiful, mythical. Keep her hit the next step. So let's keep that auction there. It's like this. So and then next up, we're gonna have this in which we don't have the medical, but there any longer, we're gonna move it over one carbon like that. Okay, so this is gonna be called 123 carbons total. So that's gonna be propane and then attached to my first carbon. So I'm gonna rearrange this to corporate that so 123 I'm gonna have the connection to my Miss Oxy So meth Oxy is gonna be in there somewhere, And then we also Oh, sorry. We also have the connection to my to my methyl group. So that's going to be to Bethel. So one meth oxy to metal and then just add my propane over here. Okay, so that would be the systematic, None of that. And now let's figure out the common name. So the common name again is just making my carbons as substitutes off my ether. So either and then my carbon substitutes are this metal group. So it's gonna be methyl something. And then we have this I so beautiful group. Okay, so it's going to be the ice. So Beetle comes before my method. So it's gonna be like this. I so beautiful metal Esser. Yeah, either. Okay, so that's that. And now moving on to the next one. And I used red twice, So let's move on to purple. Okay, so in purple, let's see, it looks like I've run out of options for my just method protest my auction and just changed the branching of my longest carbon chain. So instead I'm gonna have to carbons here now. So two carbons there and then I have my oxygen. And then what if I were to have my three carpets? So we have 123 So that's what I had in the previous one. But what if I have this instead? We're have a branch, so this would be a new confirmation. So let's go ahead and name that I will have one to three carbons in my longest carbon chain. Don't be fooled by the fact that I have my auction here, so we don't always have to be immediately connected to our auction in terms of like our final member. So it's not gonna be 12 and I just ignore this one because technically we have three carpets, so it's gonna be propane, still propane and then connected to the second carbon of that propane have the connection to my auction, which is part of the larger if oxide. So if foxy connected to my second carbon to two with oxy meth, Oxy, propane and the next step, we have the company. So the common name is again labeling my carbons as substitutes off my auction so it's gonna end in either. And then we're gonna have Pethel. And then we also have that isopropyl isopropyl will come after Fo because we don't focus on the I. We focus on the P in purple. Okay, so that's the combination. And then how many do we have? So far we have one. So 12345 Ok, can we have any more? Let's see. So I know that if I have this ether started this Ethel group and then this isopropyl and I've already had a propane as my longest carbon chain I have to think of something new. So let's think about this for a second. If I were to have this compound which I have Miss Oxy, you can really see that. So let's redraw that with Oxy like this. What if I were to do this which I have this How many carpets would that be? That would be 12345 That's perfect. I have to have five carbons. Okay, I just have to have five apartments. Okay, so let's go ahead and name this. So we have one, 23 carbons in my longest carbon chain. So it's gonna be propane. And then we also have this meth oxy tested Carver number two. And we also have attached cover number two, this, um, methyl group. So let's figure this out. We have to meth oxy, and we also have to the metal propane. Okay. And then, as for the common name, the common name of this would be metal, because that is our carbon substance went off in my auction. And then we also have this tribunal group TERT beautiful. And then, as for making sure that's in the correct alphabetic order, my turn beautiful is gonna go after before my method group Soter Beetle Metal and then my either. Okay. And then let's just zoom out to include everything on the same page. Okay? Just like that.


Similar Solved Questions

2 answers
(20 points) Consider the functionif I =for some n € N, otherwisef(z)Determine whether f is Riemann integrable on [0,1]. Explain why or why not_
(20 points) Consider the function if I = for some n € N, otherwise f(z) Determine whether f is Riemann integrable on [0,1]. Explain why or why not_...
5 answers
The potential energy of an object attached to a spring is 2.90 J at a location where the kinetic energy is 1.90 J. If the amplitude A of the simple harmonic motion is 17.0 cm, calculate the spring constant k and the magnitude of the largest force Fspring: maX that the object experiences325.26Fspring, ne55.29
The potential energy of an object attached to a spring is 2.90 J at a location where the kinetic energy is 1.90 J. If the amplitude A of the simple harmonic motion is 17.0 cm, calculate the spring constant k and the magnitude of the largest force Fspring: maX that the object experiences 325.26 Fspri...
5 answers
1 2 3 The matrix A = 0 0 1 is in row echelon form _ 0 1 0True False
1 2 3 The matrix A = 0 0 1 is in row echelon form _ 0 1 0 True False...
5 answers
5.7.2 Lel Yi Yz.Yn be random sample of size (rom normal pdf having Show thal _ 4Ey; consistent estimator [or 0? = Var(Y )
5.7.2 Lel Yi Yz. Yn be random sample of size (rom normal pdf having Show thal _ 4Ey; consistent estimator [or 0? = Var(Y )...
5 answers
Find the general solution to Zmy' + (m? _ k2)y = 0, where m and k are positive constants. Show that the solution can be written in the form: y(r) emx (C1 coshkx + €z sinh kr)-
Find the general solution to Zmy' + (m? _ k2)y = 0, where m and k are positive constants. Show that the solution can be written in the form: y(r) emx (C1 coshkx + €z sinh kr)-...
1 answers
Find the derivative of the function. $$ f(x)=\sin ^{-1} 3 x $$
Find the derivative of the function. $$ f(x)=\sin ^{-1} 3 x $$...
5 answers
4.2-9 bullet leaves the muzzle of riflc with spccd of 340 ms What force (assumed constant) exerted On tnc bullet whlle travcling down the 0,85-m-long barrel the rilc?
4.2-9 bullet leaves the muzzle of riflc with spccd of 340 ms What force (assumed constant) exerted On tnc bullet whlle travcling down the 0,85-m-long barrel the rilc?...
5 answers
Write the abbreviated electron configuration for the following elementsPut superscripts in parentheses. (For example: B is [He] 2s(2)2p(1))(a) Br(b) Sr(c) Ba(d) Te
Write the abbreviated electron configuration for the following elements Put superscripts in parentheses. (For example: B is [He] 2s(2)2p(1)) (a) Br (b) Sr (c) Ba (d) Te...
5 answers
Use the inverse function theorem to find the derivative of log2(x/2)
use the inverse function theorem to find the derivative of log2(x/2)...
5 answers
5T2T4T 3 223Compute(sin €, f(c))6
5T 2T 4T 3 22 3 Compute (sin €, f(c))6...
5 answers
12.5.23Find the equation for the plane through the points Po(1, ~ 4, 4) , Qo( - 4,0,5), and Ro( - 1,3,2).The equation of the plane is (Type an equation:)
12.5.23 Find the equation for the plane through the points Po(1, ~ 4, 4) , Qo( - 4,0,5), and Ro( - 1,3,2). The equation of the plane is (Type an equation:)...
5 answers
13) Find the matrix A satisfying the cquation:('-3" | 171IFA B ar Jx} matrices |JAI-81. tNICe(AF5 :(B"'_ 'y'-[::: Find: I) Matrx B ii) /24 'B' | Iii) Truce(3A+2B)
13) Find the matrix A satisfying the cquation: ('-3" | 171IFA B ar Jx} matrices |JAI-81. tNICe(AF5 :(B"'_ 'y'-[::: Find: I) Matrx B ii) /24 'B' | Iii) Truce(3A+2B)...
5 answers
Point) Use the inner product(f,9) = f(-2)9(-2) + f(O)g(0) + f(2)9(2) in Pz to find the orthogonal projection of f(z) = 4.2 + 62 6 onto the line L spanned by g(a) 322 6xprojL
point) Use the inner product (f,9) = f(-2)9(-2) + f(O)g(0) + f(2)9(2) in Pz to find the orthogonal projection of f(z) = 4.2 + 62 6 onto the line L spanned by g(a) 322 6x projL...
5 answers
Use the given formula to evaluate the following_ (sin (x))" dx 5 6 (sin (c))"-? dx I = [ 7 (sin (c))" dx8 (sin (4))id
Use the given formula to evaluate the following_ (sin (x))" dx 5 6 (sin (c))"-? dx I = [ 7 (sin (c))" dx 8 (sin (4))id...

-- 0.022950--