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What is the ground state electron configuration for N} ?(01.)2(01.*)2(02.)?(G2.*9?(Tzp*)' (01)(01.*9?(G2.)"(G2.*)(7zp) (Gzp)? (1)"(1.*)(o2.)"(G2...

Question

What is the ground state electron configuration for N} ?(01.)2(01.*)2(02.)?(G2.*9?(Tzp*)' (01)(01.*9?(G2.)"(G2.*)(7zp) (Gzp)? (1)"(1.*)(o2.)"(G2.*)(G2p)?(72p) (Tzp")" (01)"(1.*)(o2.)" (G2.*)(#2p) (Gwp)'What is the bond order for N; ?bond order:

What is the ground state electron configuration for N} ? (01.)2(01.*)2(02.)?(G2.*9?(Tzp*)' (01)(01.*9?(G2.)"(G2.*)(7zp) (Gzp)? (1)"(1.*)(o2.)"(G2.*)(G2p)?(72p) (Tzp")" (01)"(1.*)(o2.)" (G2.*)(#2p) (Gwp)' What is the bond order for N; ? bond order:



Answers

Identify the atom with the following ground-state electron configuration:

Let's solve the problem from chemical bonding. This problem is based on the electronic configuration of elements and the irons. Here we are given salary, um, to negative iron, for which we have to write the expected ground state electron configuration. Since here tell a room is in the excited state. So first we will write the configuration of this iron Atomic number of delirium is 52 and this iron contains two electrons. Extra widget has gained, so a number of electrons in the iron would be 52 plus two that is 54. So the configuration of T E two negative can be written, as one is to do is to two p six. Three is too three basics forest, too. Three Deaton 46 five ways to 40 10 and five p six. So configuration can also be written in this way crept in, then fourty 10 52 fi B six. This is the configuration of iron. Since the iron has two electrons gained the neutral element that is, the delirium in the ground state would have 52 electrons, so we can write the configuration of ground state delirium as one is to towards to two p. Six 32 three p six forest, too three D 10. Four p six 52 Full Deaton Fight be four or we can also write it in this manner Krypton, then 40 10 five ways to five p four. This is the ground state electron configuration of delirium.

So when you're considering the potassium Adam, you know that there is atomic number 19. There's 19 protons for potassium, which is a simple K. And if you want, consider keep plus ion. That means it has a net positive charge instead of being a neutral atom in the neutral case, just potassium. You have 19 protons. You also have 19 electrons that will be electrically neutral overall. But when it has, um que plus, that means there's going to be still always the 19 protons. But we won less electrons. I wanna look shall be stripped away. That means there's gonna be 18 electrons, which I'm labeling e minus as we need to find the ground see configuration. So, um, you can use, like, spectroscopic rotation. So, um, there's different quantum numbers, so you can think of that. There's the quantum number of the principal quantum number. End there, see an incremental quantum number l. And then, um, for each l value. There's also the magnetic orbital quantum number ml. So, um, there's ah, we add up all the number of, like, basically sub shells in each of these Sanger Momentum l values. So the number off electrons will be for l plus to because you're gonna have you No. Ml, um goes from my cell to l. So you have. They see twice l and you also have the, um l equals zero. And then you also are, um, considering that there's diesel routes around sitters, two spin states as well. And in we use, um, the new Haitian for like there's eligible zero l equals one. These also have a label like S p. D. Um, since this is the thing my, uh, encounter more in, like chemistry than quantum physics. But, um, mechanics explains chemistry. So we just start listing off the the ground say configuration by listening off the and Eagles one s needs l equals zero. And then there's, too. I like to spin states, so it's two electrons in that state resemble cannellini zero. Then there's and Eagles to l equals zero from the two s to state angles to l equals one. And then there's gonna Then we can use this this formula for when l equals one, we're gonna have six electrons nasty. Then we can go to the n equals three level. So have l equals zero for us, too. on three p six. So, um, we're just following the ground sake figuration up until we have the Asian electrons. So we see that there's two plus two. What's this? Teachers? Six Times Street is 18. So this is all the 18 elections in their lowest energy state. So you can usually find this girl say configuration, Um, in textbooks, starting out with a one s two to s to to be six. Yes, to because you're looking at busy just filling up the lowest and in a few levels, um, for each of these end and l values, just making for all the lowest ones are filled first because this is the ground state that we're interested in.

To determine the bond order of N2, we first need to draw its molecular orbital diagram. The molecular orbital diagram for nitrogen is as follows, The lowest is sigma to s then sigma to a star and different from oxygen. We have the pie to peas coming before the sigma to pee. Then we have the P two P stars and the sigma to pee With 10 valence electrons for N2 will plug in the 10 valence electrons, lowest energy molecular orbital's first and then singly occupied the degenerate Equal Energy P two, P orbital's before doubling them up and then plug in our electrons last of all in the sigma. Toupee The bond order. Then it's going to be 1/2 multiplied by the number of electrons in bonding molecular orbital's That's eight minus the two in anti bonding molecular orbital's giving us a bond order of three.


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