Question
F4polmaWITATAP644UyNotoDirteld 0l btz -um Oetdncenutonoih=WanmtttOc #xllon; 0,41MelettobtrrerColculaieEfnclvnAetatemicbondMpnaThomentele UrdHeeEtnMnamtect6pin bc'on moophong &LtdulertucotdetedJoci
F4polma WITATAP644 UyNoto Dirteld 0l btz -um Oetdn cenut onoih= Wanmttt Oc #xllon; 0,41 Melett obtrrer Colculaie Efnclvn Aetatemicbond Mpna Thomentele Urd HeeEtn Mnamtect 6pin bc'on moophong &Lt dulertucot deted Joci
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licre the ycllow and orangc precipirares arc, rcspectively (a) $\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}, \mathrm{~K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{-}$ (b) $\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}, \mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}$ (c) $\mathrm{Na}_{2} \mathrm{CrO}_{4}, \mathrm{~K}_{2} \mathrm{CrO}_{4}$ (d) $\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}, \mathrm{~K}_{2} \mathrm{CrO}_{4}$
As we know that, as we know that under root burk is equal to and is equal to reflective index is equal to reflective index, which is demands. And lace. Richard diamonds and diamonds and Elise went pretty so diamonds and so diamonds and will be equal to am not L not he not option D is the correct answer for this problem. I hope you understand the solution.
In this problem, just look at it carefully. BB I too, will react in pageants of BSE here, too. ECU was to give compound Are we change which aid 80 cl here, which it A d c L. Here? So this is white PPT. They said white PPT. Therefore, according to the option option, age, correct and said for this problem, A d c l a will be the white PPT in this problem.
K two Cr awful gives a yellow precipitated it's a yellow policy heated on reaction with on reaction with Be a two plus, as well as B B two plus, therefore, option C and option the uh, correct answer for this problem, Option C and option B. R. Correct answer for this problem.
But here we need to computer reaction. So it is L. two and so forth. All three 13 is too disappointed present. And the presence of Us too, This will provide product which is there wouldn't be policy. So here we need to identify abc. So let's write the reaction. The reaction will be like this area too and so forth. All three A teenage too. On here. On here and in the presence of water will give here too. L. two, s. 0. 4 3 One further hitting at 800° and figure it will give able to 43 There's three times of school. Uh huh. We can identify our product. This is Mhm. This is B. And this is C. And so we see that option A. Is that it?
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