Identify the conjugate base for each acid.conjugate base of HzCO3conjugate base of HzPO4conjugate base of NHA...

What is the conjugate acid of each of the following? What is the conjugate base of each?
$$
\begin{array}{l}{\text { (a) } \mathrm{H}_{2} \mathrm{S}} \\ {\text { (b) } \mathrm{H}_{2} \mathrm{PO}_{4}^{-}} \\ {\text { (c) } \mathrm{PH}_{3}} \\ {\text { (d) } \mathrm{HS}^{-}} \\ {\text { (e) } \mathrm{HSO}_{3}^{-}} \\ {\text { (f) } \mathrm{H}_{3} \mathrm{O}_{2}^{+}} \\ {\text { (g) } \mathrm{H}_{4} \mathrm{N}_{2}} \\ {\text { (h) } \mathrm{CH}_{3} \mathrm{OH}}\end{array}
$$

Good base of each of the given species. First one is H. Two S. When H. Two S accepts a proton, it becomes a three S. Plus. And when sts loses a proton it becomes Hs minus. So HTS plus is the conjugate a seed of phase two S. And H. S minus is the conjugate base. Now next one is H. Two P. 04 minus. When it accepts support on it becomes a C. P. 04 So a CPO four is this conjugate acid and we need to P. 04 minus, loses a proton. It becomes eight P. 04 to minus. So it's the conjugate better. H. Two P. 04 minus. Next one is p three ph three when except support on it becomes P. H. Four plus. So this is the conjugated cedar ph three. And when ph three loses support on it becomes P H two minus. And this is the conjugate base up ph three. Now next one is eighties minus. When it accepts supporter it becomes H. Two S. And H two S. Is the conjugate acid of hs minus and hs minus. When loses a proton, it becomes S two minus. S two minus is the conjugate base off Hs minus. Next eight S. 03 minus. When except Supporter it becomes H two S. 03 H two S. 03 is the conjugate acid of H. S. 03 minus. And when H. S. 03 minus loses supporter, it becomes S. 03 to minus which is the conjugate base up 83 miners Next FH. three or 2 plus. When it accepts a proton it becomes 84 Or two plus and when it loses supporter it becomes H 202. Now, next one is 8 four and 2. When this one accepts a proton it becomes into age five plus, and when it loses a proton it becomes 10 to age three minus. So N two H five plus is the conjugate sc dot H four N two and N 283 minus is the conjugate Based off age four and last one is a little alcohol. When it accepts a proton, it becomes CS 30 H two plus, which is the conjugate A c dot c S 308 And when c s 308 loses a proton, It becomes CS 30-, which is the conjugate base up, See a 308.

So when we're taking a look up of the systems, the compound, which has a tendency to accept a proton, is known as the Contras base. So we take a look at the fast example. Yeah, Paula, C, O H and C O minus and the one with the former negative charges likely to act as a conduit based again, move on to the next part a part B. We have all an age, too. UH, H three positive charge and again, here are N H two is likely to act as our contact base. Next in part C H two p o minus four h three p four. The one with a negative charge is likely to act with our contractor base. Last one, we've got h C 03 minus h two co three h c 03 minus is going to act as our contract base.

Problem. Seven from Chapter 14 is asking us to take the molecules that are provided in the question and, uh, give the conjugated asset and base forms of that molecule. So what that means in terms of a conjugated acid, it means that the originally starting molecule must have accepted a proton, and the resulting molecule now has an additional proton. Where and now it has become acidic and that it could lose that proton again in a reverse reaction, The opposite applies for a conjugal base. The original molecule to become the conjugal base must have lost a proton. So the cognac it base is, um, capable of accepting a proton. Um, which is why it is the conjugal base. So let's start. Bye. Um, let's start by answering the question A You're part of the question. So you have ah hydroxide ion. And on one side let's, um this is going to be, um, the addition of a hydrogen. I'll addition of a proton. This molecule on this side is going to be the conjuring it acid, which in this case is water. And when we convert this molecule into its conjugated based form, we are subtracting a proton and we are left with the oxygen atom. Great. So let's move on to part B of this question where we have bicarbonate and just to save, um, some time I'm not going to add the additional proton on top of this side. Just know that everything to the right is going to be the contra get acid form of the molecule. So when we add a proton to bicarbonate, we're going to get carbonic acid. So gains a proton, converting it to carbonic acid. And then when we lose a proton, we are going to get C 03 to Linus again, I'm not going to write the, uh, loss of a proton on the left hand side. So all the things in the left hand side are going to be the conjugal base From now on, next molecule we have is ammonia, and we have, um, we gain a proton. So then this ammonia is going to become ammonia. And on the other side you have a loss of proton, so it's going to become an age to minus, which is a contra get base form of ammonia. All right, The next molecule we have is hydrogen sulfate is gonna go on to the next page again. Right side's going to denote the, um, conjuring acid. So here we are, gaining a proton. So this is going to become sulfuric acid, H two s 04 And on the other side, we are losing a hydrogen ion, and we are left with so fate. Okay, next we have hydrogen peroxide and it's congregate. Acid form is going to be a TSH three. So that H two comes in h three with the additional proton, and this is going to have a positive charge. Well, rights, On the other hand, we are losing a proton to form a conjugal base of this H. The hydrogen peroxide is going to turn into water. Look. Oh, sorry. It's not gonna turn into water. It is going to be a choux to minus waters age to, um next we have Bye, so fine. H s minus. And we're going to add a proton to form the conjugal assets that gives us a TSH to s. And on the other side, we're going to turn it into a con. Trick it base. So we lose this only hydrogen ion that we have and that because the sulfide ion and lastly we have 86 Excuse me, 85 and two plus h five and two plus. So we ah, on the right hand side. So we are gaining a proton to become a contra Get acid. So this h is now going to be in each six and two. And now we have two plus because we gained a proton. Now on the left hand side, we are losing a proton. So instead of h five is going to be aged for each four into with no charge because we lost the positive charge when we lost a proton. So that is the answer for Question seven.

Question. Number 10 is a conjugate acid based question where, given a particular species, you're asked to identify the conjugate acid or its conjugate base. In order to do that, you need to recognize what a conjugate acid is, or a conjugate base is in comparison to the original compound. The conjugate base has one fewer H plus is than the original acid, and the conjugate acid has one mawr H plus than the original base. So if we were given the species C three c 00 h. Sorry C H three C 00 H, and where we were asked to identify the conjugate base to this, it's going to have one fewer H pluses and B C H three c 00 minus. Having lost in H plus, the next one is C and minus, and it asks us to determine the conjugate acid. To this. It's gonna have one mawr H plus and B H C n. Then for part C, it wants the conjugate base to H two s conjugate base will have one fewer h plus is so it will be hs minus. And then for part D. We have H CEO three minus and we want to determine the conjugate acid. To this. The conjugate acid is going to have one mawr hydrogen ion than the original base, so it will be hte to C 03