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Which of the following rcacrions is rclcvant ro the microcosmic salt bead test? (a) $\mathrm{CoO}, \mathrm{ZnO} \longrightarrow \mathrm{Co} \angle \mathrm{nO}_{2}$ (b) $\mathrm{CoO}+\mathrm{NaPO}_{5} \quad=\mathrm{NaCoPO}_{4}$ (c) $\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}+3 \mathrm{Na}_{2} \mathrm{CO}_{3} \longrightarrow$ $\mathrm{Al}_{2} \mathrm{O}_{5}+3 \mathrm{Na}_{2} \mathrm{SO}_{4}+3 \mathrm{CO}_{2}$ (d) $\mathrm{Cr}_{y} \mathrm{O}_{3}+\mathrm{BB}_{2} \mathrm{O}_{3} \longrightarrow 2 \mathrm{Cr} \mathrm{BO}_{2} \mathrm{~J}_{3}$

Parque loro. While chlorate salt this salt age our band bye elect two lights is of by electrolyte. Take electoral light pink oxidation of oxidation. Uh, a solution official lucian of Hello green of a solution of clothing salt. Sorry, it is chlorate salt, not clothing salt. It is chlorate salt. Therefore, according to the option of Cindy. Each correct.

In this problem, k i and KI 03 odd the service stance used for preparing used for preparing. I would I'D so g i N, The I 03 used for preparing iodized salt so it's an A and B are correct here. The airport option A and D r correct answer for this problem.

Send a given question. We have to find the value of five plus two wired up on four minus three Erda. We can multiply with the congregate off denominator so you simplify. It will get 20 plus 15 iota plus a Toyota Last six Saturday square, they added by 16 minus nine. Out I square. We know that Toyota is crazy with the minus one, so it is equals to 29 6, which is 14 plus 23 Arda, divided by 16 plus nine. That is 25 So 14 by 25 plus 23 by 25 iota. Right, So this is matching with the option C to the correct option ISTEA.

As we all know that dilute at cl odd As to as of four, he composes self fights with the Evolution with the evolution awful sulfur dioxide, Telephone dioxide. So just look at it carefully. S. 03 to minus Plus two edge plus will react to give as or two plus cash, too. Note the gas can be identified by the green color. Permission went past to S E. D. Fired K two CR 27 solutions, so according to the option option, see each character here.


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