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Answer the following questions for this $S_{\mathrm{N}}$ 2 reaction: $$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Br}+\mathrm{NaOH} \longrightarrow \quad\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}+\mathrm{NaBr}$$(a) What is the rate expression for the reaction? (b) Draw the reaction profile for the reaction. Label all parts. Assume that the products are lower in energy than the reactants. (c) What is the effect on the rate of the reaction of doubling the concentration of 1-bromobutane? (d) What is the effect on the rate of the reaction of halving the concentration of sodium hydroxide?

Okay. In the place of this is compound, which is having destructive Mhm. You're trying real emotional. Passion here is well feel. See it screen on Odalis that I didn't picked up. He also hiding in an adult. Well, I just want to go Mhm. Okay. See and be Oh, she forced four minus new global tracks and a person nuclear while Okay. And against from the back seat, Yes. Into fashion. Yeah, with an investment Computational day attacking center on We get the trends Dynasty cage or see all see extreme on a lot People seed escape mhm an eight year. So there is an emotional consideration. Now the other trends compound the others is compelled. I was just having the opposite congregation or C O. C. S three again. This is attractively for people. She is three minus in the same impression in the backseat. Exactly opposite to that 40 years. And, uh, the product found is what's U S history? That's what Andi was your solicitor. These two are in entry words, and the reactions are she was specific. We do Reactions are serious basically, and you get some, uh I mean trans molecules. Mhm it for an entirely different, um, mechanism. Yeah. Look. See that? We want gold. Four more years. Thank you. Or C Oh, well, see everyone. Hold four Minus. Okay. He is Faith. No, Andi. 40 years. Yeah. All right. Initially on intra molecular, the same to make and some operates. And, well, they living leaves the monitored before the nuclear power comes in the depths. So this is something like an and given assistance assistance of this law Blue and expelling the audience so that bombs Well, see, extreme. They also you tell us Well, so it won't intimidate like this. No, this is attracted by they see it stain c o minus. Either Congress side or from the cell. Mhm. Yeah. Yeah. So we will get right. C 00 c s three on D C or CST three. Yeah, seriously? Yeah, her nice, you know. Mhm. Yeah, yes. C o See it stayed and she oh, secrets to So we since the equal probability of attack on this carbon all this carbon Because this yeah, the positive charge can really localized. This can resonate or here and hence the equal cost possible to protecting on either of the government. This will give harassment myself. That is why the trans combo undergoes this conversion in a sequence of two essential reactions on the second century reaction off course in two different models, which gives a reason a concern. The trans community more reactive because in the case of plants combined, do it's simple reaction circle to a central reactions occur. First one intra molecular intra molecular listen to which is normally faster than an intermodal, they seem to reaction. I'm second, a second essential reaction, all a high energy intermediate. I send you own high energy, intermediate having destructor. I am. Therefore, since this is how high energy, the second district is also fast, so Eataly essential reactions is faster compared toa desist compound, which undergo a single reaction on a neutral starting material. No date the reactive species, so the trans come bold use a faster reaction than the system

Let's look at a reaction. Get three products out of that. The rate expression is K times the concentration of our reactant. It's we can ah, look at the reaction progress on a graph reaction. Progress is going to be on the bottom and the potential energy will be on the side. There we start off. We've been to a transition state and then finish off with quite a bit less energy. This is what our reactant looks like. It's also hydrogen to move into our transition state. You have a couple things happening, double bond forming, and then our final molecule Looks like that if we double this reactant, then our rate of reaction would double. If we decrease in a way each by say, half, then our all right with decrease by two.

This is the answer to chapter 20 to problem number 47 fromthe Smith Organic chemistry textbook. Ah, this problem asks us to draw the product formed when fennel acetic acid is treated with the tree agent. And we're told that with summary agents, no reaction occurs. Ah, and there are 12 of these. So I'm just gonna go ahead and get started because this is gonna take a little bit of time. Okay. S o for a Ah, we have sodium bicarbonate. Uh, that's gonna act as base. Um, and we have a car back so weak acid that we're starting with. Oh, and I drew fennel acetic acid at the top of the screen here. Rather than redraw the aromatic ring 12 times, I'm just gonna use a pH to abbreviate it. Since the ring itself is not participating in any of these reactions. Okay, s O sodium bicarb here is gonna act as a base. And so we're gonna get an asset base reaction and will de protein, eight hour carb oxalic acid. Ah, and we'll get the sodium ion as the counter I on here. Okay, s so that's a for be, um, again be Is a base. Ah, and so the exact same thing is gonna happen as in a we will de protein eight. Ah, and we'll have the sodium ion as our counter ion. Okay. Ah, see, we're using signing chloride. Remember, signing chloride, um, takes a carb oxalic acid to the acid chlorides, and so we'll have an acid chloride for a product there. And C D is just salt table salt. There's gonna be no reaction here. Okay, s so then e um and actually, let me move these up a little bit. Okay? So in e our using one equivalent of ammonia. Ah, and so that is going to just act as a base. And so again, we're gonna get D prone nation. Ah, and no further reaction. So Deep Throat Nation, and then we'll have the ammonia my eye on as the counter ion. Okay. Ah, for F. We're using ammonia, followed by heat. Um, and so that is actually going to drive this reaction. And so, rather than just a pro nation here, we're actually going to make the A mite. Okay, so there we go. There's f moving on to the next page here. Fergie were using methanol and then sulfuric acid. Um, and so we're going to get the Esther product here on DSO Since we're using methanol will get the methyl ester for H. We're gonna try to do the same thing, but instead of using acid, we're gonna use base. Um, and so that's not going to work. Ah, and so we will end up just deep resonating. Okay. For I AA were using sodium hydroxide, um, followed by on acid chloride. And so, uh, this is going to create the mixed and hydride. So we d pro Nate. Ah, and then our deep throat nated oxygen is able to act as nuclear file Ah, and kick out the chlorine. Um, in the acid chloride that were using is the second re agent in this sequence. And so we end up making the next anhydride. So then, for j r. Using Mesilla mean ah, in D c c. And remember D c. C. Is gonna act as a dehydrating agent here, and so that is going to allow us to form the A mine. Instance for using meth will mean our product is going to be metal. A my okay for kay, we're gonna use. Sign your chloride. Um, and then we're gonna use problem meid. Um and so the final chloride is gonna make the acid chloride. Um, And then, uh, the pro chloride is going to, um, add to that. And so we end up with the A mine. So 123 Okay. Ah, and s o l is going to be similar. Um, but we're not using a mean, so we're not gonna get in a mine. Ah, we're using an alcohol. And so we'll get an Esther. So the Esther will be the Pro Bowl. Esther. Okay, so there we go. Um, yeah. So that's all of the products to these reactions. Ah, and that's the answer to chapter 20 to problem number 47.

In this problem, I am writing the reaction that happened in this questions. So just look at it carefully to any BR to any beer Plus Cl two will react to form to any Cl plus BR two. This is brown color and who Any I will react with cl 2 to form to any Cl plus I, too. This is of violate colored. Therefore, according to the option option B, iodide is correct answer for this problem.