In this question, we want to compare the content with land for an electron. Which that, too for proton. Okay. And then I want to also determine the value of the content we play for a proton. And the ratio uh the maximum content with like, shift or scattering by electron to get for scattering by a proton. Okay, so to solve this problem, okay. He content with playing. He is um H over M. C. Okay. So uh scenes the mass of a proton is greater than the mass of the electron. Okay, So the content with playing for proton will be less than the content with land For electronic. Okay, so the answer for parquet. Yes, last name. Okay. So and the explanation is by the formula of content with playing. Okay, then in part B uh we are shorter. Okay. And then Poppy went to find a content with playing for proton. So Amanda C. P. Is equal to H over M P. C. We're just putting their values. Okay? And then you use your calculator. Okay. And we're playing Yes, 1.38 Times 10 to the -15 m. Okay. So it's a much uh shorter with name. Yeah. Compared to that of electron, which is 2.43 and standard a negative child. Um, he does he he then Patsy want to find a ratio of the maximum content event shift by electron uh, to that by a proton. Okay. So the maximum something his name shift is good to to land at sea. He can calculate the ratio uh, um, so you take the ratio. The two doesn't matter. So the London see of electron if I buy the land at sea proton. Okay. H over M E C by H over MPC. Okay, so the asian see you cancers. Okay. So we have um, M P. D by by M E. Yeah. So you put in the aggressive proton and electron and calculated to be 1830. Okay, so this is the answer for pussy and that's all for this question.