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Provide tte meagents necessar mate We follawing ethens uaing Williamson synthesis...

Question

Provide tte meagents necessar mate We follawing ethens uaing Williamson synthesis

Provide tte meagents necessar mate We follawing ethens uaing Williamson synthesis



Answers

Outline a synthesis of cyclopentene from each of the following:
(a) Bromocyclopentane (b) Cyclopentanol

So continuing on with our work with Aldo hides in key tones. So what we have in the common functional group is C o What changes is through our groups which can be protons, hydrogen or other carbons where we have to to all groups we have I liked your Philip Carbon. We also have our oxygen atom which has a partial negative charge associated with it. So jumping straight into this reaction we have PCC is are highly selective re agent on. We can use insolvent such a ch two c l two so we can oxidize the primary and secondary alcohols to generate carbon al compounds to for example, we have here Hey, Joe pcc c H two see how to we then generate the following. I'll do hide So the reaction of alcohol hides with lethal magnesium bromide gives on alcohol a swell. So in this reaction, we'll use the material that we had just before in the presence off ch three c h two MGB are e t 20 followed by NH four Seattle Andi water each tour. We don't generate the following So now we have an alcohol instead off and all the hide So then PCC can oxidize the primary and secondary alcohols to our Carbonell compounds. So again we take the above material PCC presence of ch two c l two on What we generate is the following final step. We have the key. Turner's reacted with a grin yard re agent which allows us to add on our hydrocarbon chain that is missing here on we can transform our ketone into our alcohol group in the final step using the following re agents MGB all that is our green Yard re agent in the e t 20 solvent, then followed by and h l C L on h 20 is our final step NH four c l and H 20 allows us to carry out that final chemical transformation. Nothing has changed. Our cyclo hexane or that we have altered is our substitue INTs. And now instead, off that Keith and we haven't o h group, followed by two hydrocarbon chains to generate our final product

So continuing on with our work with Aldo hides in key tones. So what we have in the common functional group is C o What changes is through our groups which can be protons, hydrogen or other carbons where we have to to all groups we have I liked your Philip Carbon. We also have our oxygen atom which has a partial negative charge associated with it. So jumping straight into this reaction we have PCC is are highly selective re agent on. We can use insolvent such a ch two c l two so we can oxidize the primary and secondary alcohols to generate carbon al compounds to for example, we have here Hey, Joe pcc c H two see how to we then generate the following. I'll do hide So the reaction of alcohol hides with lethal magnesium bromide gives on alcohol a swell. So in this reaction, we'll use the material that we had just before in the presence off ch three c h two MGB are e t 20 followed by NH four Seattle Andi water each tour. We don't generate the following So now we have an alcohol instead off and all the hide So then PCC can oxidize the primary and secondary alcohols to our Carbonell compounds. So again we take the above material PCC presence of ch two c l two on What we generate is the following final step. We have the key. Turner's reacted with a grin yard re agent which allows us to add on our hydrocarbon chain that is missing here on we can transform our ketone into our alcohol group in the final step using the following re agents MGB all that is our green Yard re agent in the e t 20 solvent, then followed by and h l C L on h 20 is our final step NH four c l and H 20 allows us to carry out that final chemical transformation. Nothing has changed. Our cyclo hexane or that we have altered is our substitue INTs. And now instead, off that Keith and we haven't o h group, followed by two hydrocarbon chains to generate our final product

So the, um, compounds most reactive in the Williams and either synthesis are also most reactive in any s into reaction. So we'll have most reactive to least. So starting out with a so ch three c age to be our This is a primary Allied. So we first, you know, um, next we will have ch three ch ch three. This is a secondary. How lights a little over act so the least reactive. And then lastly, we'll have a, um, Errol highlight. And this won't react at all. And for b will have a similar similar situation. So we'll have saved three ch two b r. This is a, um, better leaving group cause it's bigger than the ch three ch two c e o. So this is a poor leaving group, and at the very end here we will have ch three c h still wanted to see h I. And this is vanilla, so it won't react at all. Those who don't react

This compound, which I am writing here. Just look at it carefully here. It did two CH two and this compound C S t D. Oil too at sea. Oh, I see 285 can be scientists side directly directly by Williams. Scientists is directly. Bye. William Son scientists is so according to the option option, a option C. R, correct answer.


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