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8.i 1 04 (6)conducting rod Whose 120 Qas shown length is 25 cm above The wire and the placed on J U-shaped - magnetic metal wire thac has = feld of strength 0.40T i...

Question

8.i 1 04 (6)conducting rod Whose 120 Qas shown length is 25 cm above The wire and the placed on J U-shaped - magnetic metal wire thac has = feld of strength 0.40T is . rod are placed in the Dlane Of the resistance of left with constant applied out of the paper: = constat the wire? speed of 6.0 IV/s: What is Papcr; An applied force moves the the magnitudte and direcWon rod t0 the the induiced current in 50 mA clockwise 17 mA clockwisu 50 ma counterclockwise 75 mA (ountcrcloxkwise 75 IIA tlockwvl

8.i 1 04 (6) conducting rod Whose 120 Qas shown length is 25 cm above The wire and the placed on J U-shaped - magnetic metal wire thac has = feld of strength 0.40T is . rod are placed in the Dlane Of the resistance of left with constant applied out of the paper: = constat the wire? speed of 6.0 IV/s: What is Papcr; An applied force moves the the magnitudte and direcWon rod t0 the the induiced current in 50 mA clockwise 17 mA clockwisu 50 ma counterclockwise 75 mA (ountcrcloxkwise 75 IIA tlockwvlse



Answers

A conducting rod of length $75 \mathrm{~cm}$ is made to slide over two parallel metal rods as shown in Fig. 8.6. The crosses indicate a magnetic field going into the plane of the paper of strength $0.1 \mathrm{~T}$. The two resistors $R_{1}=50 \mathrm{Ohms}$ and $R_{2}=100 \mathrm{Ohms}$ are attached as shown. The rod moves with a uniform speed of $v=10 \mathrm{~m} / \mathrm{s}$. Calculate the current through the two resistors, the power delivered in each resistor and the force required to keep the rod moving a uniform speed.

Here. So we have this. Did you hear where the rod is living? Right here? So on top of rails and it's moving. And it's the of 1.3 meters per second and it says it has any resistance of 2.5 homes. Tells us this. L the distance of the rail separation war is turning 25 centimeters and it's all in the uniform magnetic fields at this, pointing out of the cage show over here with the magnitude zero put 35 test. So it also says the resistance of the U shaped conductor. So that's be stationary. Bars not be rod that call that. Are you still in the 25 homes at a given in Tokyo? So part ay says calculate the induced you myth Well, because the velocity is perpendicular to the magnetic field and the rod. Then we can use equating 29 3 to find the induced f here. Uninterested in by the magnitude of the magnetic field, times level times be so this becomes so you're a 0.35 Tesla times 0.25 meters important. Three meters per second. We're getting induced enough here. Oh, is there a 0.11 38 votes. Cool, since we've been apart being what is it asked says the current in the U shaped conductor. Okay, well, if this is the induced BMS that weaken his own soul to find the current just Ian, that opened the resistance and we'll have to use the total resistance here. And since the U shaped conductor in the Rod and Siri's, we can have them. So this is a total service is also the Ron Resistance. Plus you should conductor. So that's 01138 boats over 20 James, 27.5 homes. And this is a current of 4.1 38 times 10 to the negative pants, or roughly 4.1 million apps. Okay, cool. It was part see esque. This says calculate, the external force needed to keep the routes velocity constant at that instant. Okay, so the induced current and a rod will be down because this current upward magnetic field there will be a magnetic force to the left. All right. So the I induce it's going this way. So it's down the rod and using the the cross be to find the force of the magnetic field gives you a force pushing to the left. So to keep the rod moving, there must be equal external pulls to the right. So what that is is it's given by I l B needs to be the equal magnitude of this. This is the force to the left. So we need an equal external force to the right. And this is zero. This is 4.1 of the eight times 10 million, three amps times you opponent to five meters time 0135 Tessa. So this is a force of 61 times 10 to the negative four Newtons. This is what our aspects turtle needs to be to keep it being constantly cool.

All right. The human problem there are to battle reels. These are two. A real job connected. The helpful resistance having a value 0125 There is a unique for I need it for years. Did you do the lame O people? And a metallic bar is moving. Or were these reels right? For at a speed all by 50 Niedere for second the roar is named as m m the land off his strong. Or you can see the gap in the reeds is giving a street party. Santa Anita. So the data given here is just a poor Yeah, the body is 25. Thank you, Peter. For you can say this is 0.2 m the magnetic, please. In introduction repented of the people It's 0.7 by Tesla Resistance connected. Joining the boom Parallel reads is CEO wine Do By whom? No, you The first part of the problem. We have to find the Yemen in use Cruz and this Washington You use that girl stomach at a party given by the expression Be in to be a So what? Indians? That he was here For me This is zero point 75 s law. Well, the speed this is fine. Quiet Tzeitel Meter or Seki. And for the length of the offices, 0.25 m. And then because lifted Uh, not me. You off this. You have been used across the bar comes out, you see nine more. This is the American EU. Look this una in news No, the for the direction off the current busting toe this blue we use living's right And the blankness room in which the stretch the come off right? 10 The reaction of motion of the conductor means this is the action of some and the fourth thing that is stretched that action off magnetically which is involved into the plane off paper, then the middle finger Use the action of good using the kind of person this middle finger Rico up the direction off current in the road is strong in i m so in overall blew the direction of parenting use will be You know what? This is the answer from the first part of the problem? No. The second part of the problem we have to find the fools. It should be applied on the road in order to move it in order. It moved me worse. Right? And that forced to be equal to the magnetic force created on this rope and that magnetic forces, even by B into by then I use the car in used in this straight road and that couldn't using also is given as, um I think it was divided by resistance. So I d known millions in here. You know. B is 0.75 Yes, love you may be just found it. 0.9 or whore resistance is given at Cedar Point by phone, and the length is 0.2 m this force, which should be applied on the morning order. He he won't moving it towards site. It should be seven. Um, you know, this is the answer for the second part of not with their part of the problem. We have to find the rate at which work is done by this force. So what? The rate of work with his father, my father or the force is found using the expression Rhoda. This is instead in his power, which is seen by the product, of course. The velocity and the Israeli lives here force we know this is a single 0.7 new been and velocity dish has more. This is why neater for sitting. So this father here comes out to be three point What? This is the part of the problem now in the four part of the problem we have to find are we see depicted in darkness is dense. It's even as I swear up electrical power on June in this Mrs Skins for I know the value of crimes or even bigger use expression ceasefire by our because we know the value of your making news which is 0.94 elsewhere. Very bad instances I do but and then we saw this off himself to be three point By what a g yes. Also choose the conservation off energy All the Julian move The ball is being distributed in the assistance as theatrical NCS eat. Thank you

Hi. In the human problem, there is a U shaped pray made up off a conductor. And there is a roar moving over this You ship cream and there is a magnetic created given by the doors Means the direction of this magnetic really is money out off the lino paper. So this roar is allowed to move in this magnetosphere towards right with a velocity which is given as 1.6 meter for second resistance. Off this roar is our one which is being given asked 2.5 home and resistance off rest off This you ship frame is are you which is being given us 25.0 home and off course, these two resistances will be considered to be in cities. The magnetic field coming out of the plane of paper is given a 0.35 Tesla. So the first part of the problem we have to find emotionally anything used across this moving raw and that is given us b the l. So So when we put these values we get, this is you'll find 35 into for me. This is 1.6 and for lend off, the conductor that Waas, humanise, Harvey Centimeter, or we can say 0.3 meters. So this is 0.3 here. So yes, chef induced emotional enough induced Across this road comes out to be 0.168 world. This is answer for the first part of the problem. No, in the second part of the problem, we have to find currently used in all of this cream rectangular frayed. So this current Indians were beginning by owns law. I was to be by our and never assistance will be equal to the combination the seas combination off the two resistors. So here it becomes you don't buy it. 1 68 divided by 2.5 plus 25 or 0.1 68 divided by 27.5. Um, year. Finally, this current comes out to be 6.11 into Ben Bishop AR minus three. And here this is answer for the second part of the problem. No. In the third part of the problem, we have to find the force necessary force, which we should apply on this roar in orderto keep it moving that force on a straight current carrying conductor is given by the formula B. I l So be here is 0.35 Tesla I we just found a 6.11 into 10 Daschle par minus three Ampere and land we No. 0.3 meters. So finally, this answer for the force comes out to be 6.4 to 10 days to the popover minus. For Newman, this is answer for the third part of the problem. Thank you.

In the given problem, there is a straight current carrying conductor carrying current in upward direction as sure here and there is horizontal drawer like this, which is moving vertically up with the velocity V. The length of the roar is L, and it's left. End is at a distance are from the current carrying conductors. We have to find an expression for the MF induced across this role complete work, so it's different points. The different sections off the road are at different distances from this current getting conductor, so the magnetic field Lynn through them will be different. So we will apply calculus. Here. We consider a small segment in the road having a bit DX, and it is after dispense X from the left end of the road. We consider ah, small segment in the road, having of it DX at a distance X from the left end off the road so its distance from wire becomes our desk because toe are plus X. So using batons, severed slaw, the small magnetic field, the magnetic field passing through this point off. This small segment is given as me not upon four pi. Do I buy artist or I can say you not by four pi toe I buy are plus X So as this small segment off length DX is moving in the magnetic field this with a velocity V so emotionally immigrant being used across it stands So the small emotionally MF induced will be given us be into we into l l for length and that is DX. So it will become new, not by four pipe, do I by our plus x we dx so totally enough induced across the ends of the role will be found by integrating both the sides the constants will come out you not by four pi toe I V will come out and we'll have to integrate one upon our plus X with respect to DX where X will be wearing from zero at the left hand toe the l at right. And so the IMF induced will become new not by four pi toe ivy. The integration of this one upon our plus X is natural log log at this e are less x from zero to l. So we put the limits here So this in a induced will be given by you not by four pipe toe I v Ellen. First we put in place off X as l So it becomes r plus l Then we put in place off x zero. So we get Ln are so the final answer is new, not by four pi do I v Ellen R plus l by our or we can say new not by four pi toe I v Ellen one plus l by our This is the IMF. The net enough induced across the ends off the road and we actually have toe prove it. So we proved it. Thank you.


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