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Gero TebraChloride (C CUli Cumnman chunecal Caibon hes alon< ma55 0f 12, Chlrne Almic Me 0l 35 5 u [Anch; how nial Arrutete Motniie mass 0f 2 Llonmm Cubon Tel, h...

Question

Gero TebraChloride (C CUli Cumnman chunecal Caibon hes alon< ma55 0f 12, Chlrne Almic Me 0l 35 5 u [Anch; how nial Arrutete Motniie mass 0f 2 Llonmm Cubon Tel, hox many molas dbas Lhis recres9nt Round anstyer Io one number past %0 decinal pont

Gero TebraChloride (C CUli Cumnman chunecal Caibon hes alon< ma55 0f 12, Chlrne Almic Me 0l 35 5 u [Anch; how nial Arrutete Motniie mass 0f 2 Llonmm Cubon Tel, hox many molas dbas Lhis recres9nt Round anstyer Io one number past %0 decinal pont



Answers

Calculate the mass in grams of the following. $\begin{array}{ll}0.331 \mathrm{~mol} \mathrm{Fe} & 2.1 \mathrm{~mol} \mathrm{~F}\end{array}$ $$ 0.034 \mathrm{~mol} \mathrm{CO}_{2} $$ $1.89 \mathrm{~mol} \mathrm{~K}_{2} \mathrm{CrO}_{4}$

In this situation, we have given three particles of mass. That is one kg 2 kg and three kg. And are situated at the corner of equilateral triangle of side B. Then we have to find the coordinates of the center of mass is So first of all, and growing the diagram for this given to shin. So this is the equilateral triangle. We have given to us societies be so each side of the secular triangle is B. No, let this point is A. This is B. And we can see this. This point is C. So I'm going to show the coordinates of this point, like this is our origin. So the coordinate of this point is zero comma zero, comma zero coordinate of this point is given by this is B comma zero comma zero. And coordinate of this point is given by that is the few. The X coordinate is, This is B by two and why coordinated Be rude, three x 2. And their coordinate is zero. This is actually what a reason. So this is white plane. And this is our explain. So just coordinate is zero. So finally we can say that X coordinate of center of marches. You mean by that is anyone into X one plus M two, X two plus M three X three upon this is and one plus M two plus M three. I put all the data in this equation. So here the masses, one kg mass. So this is one in 20 plus this is to into B plus this is three and to be by two upon this is one plus two plus three. So finally we will get this is seven B upon well and why coordinate of central masses? That is why. So um is given by that is and one by one plus M two by two plus M three by three upon the and one plus M two plus M three. I'll put all the detainees equations. So this is one into Euro plus, this is too into Europe plus, this is three and 2. This is Beirut three x 2 upon one plus two plus three. So finally we will get diseased three road three and to be upon well. So this is the Y coordinate. So we can say that coordinate of the center of mass is given by dirties seven be upon 12. Coma three route three, B upon 12. So this is our answer for this, given to shin and we can say for that option correct option is option C. And yet coordinated zero. Thank you.

Question. We have to point masses that are located at this same plane and distance from the mass, one of the center of mass. So are one, it is equal to 3.0 m. Are one is the distance of the center of mass from mass one and distance from us to to the center of mass. That is our two is equal to 1.0 m. We have to determine what is anyone buy em too. Okay, the ratio of the mass M 12 mass too. So since the center of mass is located at some distance, so we can write that M one R one plus M two R two, this will be equal to zero. Or we can write that M one R one. That will be quick to M2R 2. Okay, because the distance will be one uh opposite direction to the other. So from here we can write that anyone buy em to this will be equal to our to buy carbon. So we have both the value. So our two is given as 1.0 m developed by our one, which is 3.0 m. So from here we get ratio of Mask and 12 M two Equals to one x 3. Okay, so this becomes the answer for this question. And from the given options, we can see that option. E is the correct answer. Okay, option is the correct answer. Okay.

Everyone. So in this question there are to determine the mass in grams of each of the following is 1.35 more of everything. So e 1.30 for you mold of a thing. That is equal to. So any sequel to W. Into um is he called to W. Pond young therefore W. Is equal to come into em. So your knees one plane 30 for you into Muller was 55 point 84 for you. And the discipline to do 75 point 391 graham and therefore myself. Yeah. Yeah. 1.25 More of a fee. I think that is equal to 75 391 glass men be part .876 mall of calcium. Mhm. Yeah. So N. Is equal to W. Upon him and therefore W. Is equal to and into em. And that is equal to point 876 to 40 points 078 in the dis equal to 35 point we learned grand and therefore myself. Yeah. Mass of blamed 876 mall of calcium. That is equal to 35.11 then see But Well yeah. Uh huh. 24.5 moles of oxygen And the four point for you mall of oxygen. So w is he called any into em. And that is equal to 24.5 into motor mass of auction. 15 points Triple nine. And that is equal to 391.976 g. Therefore, loss of 24.5 more of oxygen. Speech 96 22, 391 97 grand. Thank

Yeah. To calculate the mass in grams that correspond to each of these mole quantities, we simply need to know the molar mass. In the case of an element, we go to the periodic table and it's found just below the chemical symbol. The molar mass of iron is 55.845 g per mole. Multiplying this mass value by the moles, moles cancel and we get 11.4 g iron to the three significant figures we started with If we have .79 mold floor een on the periodic table, 18.998 g of Florina is one mole. Multiplying these two numbers together gives us to just two significant figures 15 g Florentine. And if we have 58 moles carbon dioxide multiplying that by the molar mass of carbon dioxide, which is the mass of one mole carbon plus the massive two moles, oxygen given us 44.1 g per mole Gives us to just two significant figures 260 g carbon dioxide. And for the last one we have 48.1 moles potassium chrome eight. The molar mass is going to be the massive two molds, potassium plus the mass of one mole chromium and four moles of oxygen. Given us a total mass of 194 19 g per mole. So 48.1 moles corresponds to to just three significant figures 9340g


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