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Question 32.5 ptsWhen predicting if the precipitation will form as two solutions are mixes, Qsp and Ksp are compared. Only when one value is greater than the other;...

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Question 32.5 ptsWhen predicting if the precipitation will form as two solutions are mixes, Qsp and Ksp are compared. Only when one value is greater than the other; the precipitation is going to be formed. A) Which value has to be great; Qsp or Ksp,for the precipitation to form? B) Explain your answer to (A). Given an answer that is specific only for Qsp and Ksp_HTML Editorea12pt

Question 3 2.5 pts When predicting if the precipitation will form as two solutions are mixes, Qsp and Ksp are compared. Only when one value is greater than the other; the precipitation is going to be formed. A) Which value has to be great; Qsp or Ksp,for the precipitation to form? B) Explain your answer to (A). Given an answer that is specific only for Qsp and Ksp_ HTML Editorea 12pt



Answers

Predict whether a precipitation reaction will occur in each of the following situations. Write a net ionic equation for each reaction that occurs.
(a) $\mathrm{NiCl}_{2}(a q)+\left(\mathrm{NH}_{4}\right)_{2} \mathrm{S}(a q) \longrightarrow ? \quad$ (b) $\mathrm{Na}_{2} \mathrm{CrO}_{4}(a q)+\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(a q) \longrightarrow ?$
(c) $\mathrm{AgClO}_(a q)+\operatorname{CaBr}_{2}(a q) \longrightarrow ? \quad$ (d) $\mathrm{ZnCl}_{2}(a q)+\mathrm{K}_{2} \mathrm{CO}_{3}(a q) \longrightarrow ?$

So now we work on problem eighty six from chapter seventeen. So here we're calculating the Mueller Sally ability based on the cast piece SAI Ability product constant. And for the first one were given a generic equation X So we can write the equation for the dissolution of this compound in water. It couldn't be him to plus or m plus or and three pluses. Long as thie ex has the same charge. So it doesn't matter based on this for the story geometry, it's a one to one ratio. So for both of them will be adding s and we have equilibrium. Concentrations of s so caspi is equal to these two concentrations multiplied by each other equilibrium concentrations which is equal to its given in the problem one point two seven times ten to the minus thirty six, which is equal to X squared. So when we take the square root of both sides, we get s is equal to one point one three times ten to the minus eighteen, which is our answer for a So if we move on to party now, were given an actual molecular formula for silver Crow made silver to see R O for solid and could potentially dissolve the form two silver plus ions and one chrome it. So we draw our eyes table Disregard the solid new initial concentrations we had to s because of this co efficient. We add us to S s So we need to draw our equation here. So K s P is equal to silver concentration squared because of the coefficient in chrome eight multiplied bankrupt me and this is equal to from table seventeen point to one point one two times ten to the minus twelve table seventeen point to which is equal to we have to s squared times s so this is equal to four s Cute. If we square inside the princess we get for a squared times s is equal to for us Cute. So to solve here we need to multiply. We need to divide both sides here by four and take the cube root. And when we do this to both sides gets six point five for times ten to the minus five. So for part three for party scene, we're given calcium hydroxide No which can dissolve to form calcium to bless close to hard drugs right in our hands When we draw the ice table we have a change of s for calcium and two es for hydroxide And we'LL have a cool librium Concentrations of s and to us So we drunk A s P is equal to a four point six eight times ten to the minus six from the table table seventeen point two And as I mentioned on the last page, we're due for as Cube because we have to s squared kinds of s And so we divide both sides by four to cancel And then we have to take the cue route as well of everything. And when we do that, we get asked is equal to one point zero five times ten the minus two Mueller which should be the concentration for all of our We should be the unit for all of our answers

Seen this problem, we will have to write down balanced equation and guess be expression for the dissolution ofthe three auntie components off. First we have bury himself at and to write down the question for the dissolution. We have to write the compound in solid form and then we'LL have to set up an equilibrium with the irons that will be formed in the solution. So from from Marion Self, it will have be a two plus. And so for two minus and the case be expression floor. This will simply be the multiplication or the product of the concentration off that ions. So the case be value for for the dissolution of very himself. It will be be it two plus times concentration off SL for to minus, then off in B, we have tto find decoration for the dissolution of B B beer, too. It created in a solid form and after set up they really, really it's ions, which is B B two plus plus B R minus. And since we have to Brahma down here, we'LL have to put it to here and expression for case Be for this. Reassure me on top we will have the concentration off P B two plus and B are Mina's and the strike imagery coefficient will be used as a power off the bromide and concentration and the bottom will. So this will be the case. Be expression for that lead, provide and then see, we have the gumbo on eighty two zero four. We'LL help arranging the solid form. Then you have to set up the equilibrium. Here we have energy plus blood's si r all four and it has a charge off to minus. Since again we have here two silver. We have to put this to here, and the case be expression will be eighty plus and the coefficient of square times sear Oh four still minors. So this is the case the expression for the dissolution ofthe dis compound.

Solving party of this problem. So here precipitation will occur. Mhm. It was The reaction can be given by, I'm just writing the balance reaction any to CO three Ac was plus two A G N 03 ECU as gifts ready to ceo three solid plus to any and or three ECU was now for part B. No precipitated formation occurs when any N 03 when any any three and and I. S 04 are mixed. For part C, precipitation will up good and the balance reaction can be given by I have three and so forth plus B. B and or three hole to Gibbs, B B S. O food plus every and or three hold too. So this is the answer.

For Option A. The precipitation will occur so the reaction will be. And there too. Seal three plus toe Eiji and all three. It will give this 82. See you three plus to any and no tree. So the precipitation will occur. Option being no precipitate formation then any and No three on day and night year so four are mixed. So no precipitation for auction. See, the precipitation will occur if he is so full. Less baby. And with three, two really give us You lived less.


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