4

The following...

Question

The following

the following



Answers

Name the following:

This problem. We are naming compounds. So for a we have both and all keen and an alcohol here. The alcohol needs to be the lowest number we can make it because that is the highest priority thing on this compound. So if we go from this side, it would be 1234 on this side, it also be four. So we're gonna go from this side because that makes full, uh, the l keen and alcohol the lowest that they could be. So 1234 567 So we have, uh, seven carbons on here, so that is helped. And then, um, the l Keen will name first. That will be two second carbon een. And then the alcohol's on carbon force of four all helped to Ian or all. You could also say to have teen for all. That would also be correct, because the two will imply that that is the position of the first sing in the name. The parenting name for B. We have an Al Qaeda and Al Keen. We're gonna make these the lowest numbers they can be, so we'll start over here with 1234 567 So again we have seven carbon, so that is helped. And then our team is on number one. So 1 18 Or you could just omit the number and say, Hef teen, that would imply that it was on carbon one. But adding number one is also not incorrect. Um, and then our eyes on five. So five I have one in five and then first see again, we have to. We have a term bonds and a double bond, and we want them to be the lowest numbers possible. So 123 4567 again, we have that helped. And then our, uh, in is on four. So have four mean one I'm. It would also be correct to say four helped Jeanine because you don't need the one. But it's OK, it's there, and the four can either go next to the E in or out in front

So in this example we're just naming some structures. So firstly, we have three me fell three hack scenes or long is carbon chain is six carbons have a double bond of the third carbon and also me 1000 Stitch went on that third carbon. It is also e so that is our trans confirmation. Next, we're looking at E eight missile for Nani. So we have a nine carbon length structure with a double bond, our fourth carbon. And we also have a me tal group on eighth Carbon. Next, we have e nine Brumer to non ain. So again, we have a nine carbon structure double bond in our second carbon Ramin attached to our final carbon again, it's trends. A few more examples. Well, we have 24 dime Ethel one pentti. So we have a double bonded off first carbon in a five carbon chain Onda meet. I'll group on the first on the second and fourth Carbon. Next we have to We thought one pen teen. So we have a five carbon chain with a double bond on the fast carbon on to carbon chain. So following this we've got sad to Penn teen so we have a five carbon chain where we have sis confirmation and we have a double bond on that second carbon.

To name these compounds. First, we're gonna find out their names. And then afterwards, a sign our s structures. So or part A, we're gonna count our carbon chain. So we have 123456 So we know that we will have a heck sane. We don't have any double triple bonds, Renee, most will the body or the parenting will be heck sane. And if we look at our substitue INTs, we have a metal group and a chlorine. So we will put these in order the correct order so you'll start by giving the one with the chlorine. The card with the chlorine, this will be carbon free. And then one of the month will be carbon. For we won't to the other way. We won't have three metal forklore. Oh, because the chlorine has priority over the metal group. So it will be three chlor Oh, and then four metal vaccine. And then we can go back and at the structures. So we will have three are since carbon three is has our structure and four s. Since Hermann four has structures, we have three are for us. Three koro for metal axing for part B. We have this structure again, working a start with to find the longest carbon chain. So this will be here We have 12345 carbons. That's our longest carbon chain. So we know that we have something plantains and no double dribble bonds who contain as our parent name. And the groups we have is we have a bro main and a chlorine group. So we will have to bro Mo three Koro Pantene. And if we look at Kurban too, which is this one? It has our structure. So to our in carbon three as a structure, so three s. So we have to artery s to Roma three Claro plantain. And the reason that he's assigned this is carbon one. And you have to bring on three claro and not this is carbon one. This one here because we want our numbers to the lowest. We have to borrow three. Claro, if we started with just as carbon 123 you have three chloral for Bruno. And those aren't those numbers. So we have to Burma. Three core plantains for Percy. We have 12345 carbons in our parent structure. So we will have, um Well, use pent for our parent name and its cyclic. We will have cyclo contain. We also have an alcohol. So that will go in are a pair name So cyclo Penton all. And we also have a roaming group on carbon three since Theo waged on carbon one. So we will have three bro mo Cyclops, fentanyl and carbon one with the O. H has our structures. We will have one are carving three with the bro. Mean has a structure sort of three s. So one R three s, three rooms, cycle fentanyl and Robert de you will identify our long carbon chains. So we have one Carmen here. 123 or five. So we have contained and we have to Korean groups. So you have to three guy Chlor. Oh, plantain and carbon to has our structure. So too are in carbon three also has pra structure. So to r three R 23 die. Claro plantain


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