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A shipment of 30 inexpensive digital watches,including 7 that are defective, is sent to adepartment store. The receiving department selects 10 at random fortesting ...

Question

A shipment of 30 inexpensive digital watches,including 7 that are defective, is sent to adepartment store. The receiving department selects 10 at random fortesting and rejects the whole shipment if 1 or more in the sampleare found defective. What is the probability that the shipment willbe rejected?(Simplify your answer. Type an integer or decimal rounded totwo decimal places as needed.)

A shipment of 30 inexpensive digital watches, including 7 that are defective, is sent to a department store. The receiving department selects 10 at random for testing and rejects the whole shipment if 1 or more in the sample are found defective. What is the probability that the shipment will be rejected? (Simplify your answer. Type an integer or decimal rounded to two decimal places as needed.)



Answers

Suppose you have just received a shipment of 100 televisions. Although you don't know this, 6 are defective. To determine whether you will accept the shipment, you randomly select 5 televisions and test them. If all 5 televisions work, you accept the shipment; otherwise, the shipment is rejected. What is the probability of accepting the shipment?

In this problem, the number of ways to select five television to work can be given by rated B N is equal to 94 c five. So the probability of selecting five television can be given by P is equal to fight port 891018 which is the value of 94. C five by seven fipe 2875 to 0 on solving I get the value of P is equal to 0.7291 So this is the number of accepting the statement. This is the probability of number of X acting the statement. I hope you understand the solution.

1 55 are a We're looking at 16 that are all good. So the first broken at point of nine or 90%? Four sticks of them. So 0.9 times 0.9 times quite nine finds 0.9 times 0.9. So it's 90.9 and 0.9 and nine in 90.9. And why? Which is the same as white? Nine to the six. Uh huh, which equals 0.5314 So what's a probability? The 80%. So you 0.8 raised to the sick 0.8 phrase to this sick gives me 0.262 and report. See, we're looking at 60% SOS 600.6. Raise to the six gives me 0.0, for seven.

In this question it is told that there are 10 items and out of these 10 items you are would affect you and eight items are safe. It is told that we have to take three items and we have to find the probably that at least one. Is it effective? So we can see that this can be given by 1- the probability of no defective items means we are to find no defective and we have to select three. So total ways of selection of three out of 10 is 10 C. Three and there must be no defective. It means that we have to take three from the age safe items. So you can write it as one minus eight C three, divide by 10 C three. Now, after simplifying it we got here one minus 18 to 7 and 26 divide by 10 and 2 19 to 8. And after simplifying it without the required answer that is 8515. This is the answer of the given question here. Thank you.

Alright guys, so for this question here, we're getting a problem about televisions. Okay. And so here's the thing. So the first I'm going to break up the problem is something I like to call opponents square. We use a lot in science. We can also use it in probability. And so talk about this won't be the first television and this over here will be the second. Okay, let's go and make a point square here. Okay? And then I'm gonna go and use um so either the television will second television we pick will be will work or be defective in the first television, same thing will work or be defective. So w stands for work and and the other one is defective, so either they both work or one works and the other is defective. one works and the other is defective or it is possible, of course, for both to be defective. Now, if we look at the probabilities here, we do know that it has a two third chance of working because only two because four of the six televisions are working, which means there's 23 of the chance that works. And then of course there's two television effective. So to have sex and effective means one third chance it doesn't work. So for each w I'm gonna plug in 2/3 and for each d I'm gonna plug in one third, so two thirds, two thirds And this is 2/3 and 1/3, 2/3 and 1/3 again. And finally if both are defective, that's both a 1/3 chance of being defective. Alrighty is let's just do the math here. So the fact that they both work Will be four out of nine or .44. So there's about a .44 chance them both working There is about a .22 chance That one works, one doesn't will be the same over here and then a .11 chance over there. So those are the probabilities we are currently dealing with. Okay, So the first question asks is a the ability of the both televisions work. So both work. The only thing that both were the only ones that both work is this one of the top left corner? Oops one. The only time it both works would be in the top left corner, so that will be right here in the top left corner. One. Both work and that is .44. So let's go ahead and change that. 2.44. All right. The second follow up questions where I will at least one does not work. At least one does not work. That means um wherever we see a defective one, that's what we want. So, this one this one has a defective one. Keep doing that. So let's see that box has a defective one. This is a defective one of those defective one. Okay, So which means it's all three of these combined. Okay. And so the fact that all those don't work, we're gonna get about a let's see. So when at least one shoot, I'm messing up here, so at least one bad Will be a .22 plus 0.22 Plus .11. Which is going to round up. So it's gonna be 55 And that's actually 55. We can't forget about the repeated signs on all these. So those are all repeated, it's a 55 repeated. Which leaves us with a .56. And we're done.


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