This question says that a solution of permanganate the standardized by Titra ation with oxalic acid it required 28.97 milliliters of the permanganate solution to react completely with 0.1058 grams of oxalic acid. And it could just be unbalanced equation for their action up top here. So I've broken his down into the half reaction so that we can bounce this equation first. Start by balancing the non oxygen hydrogen atoms. Uh, and manganese is balanced in this reaction. And in the other reaction, um, we have, uh, two carbons, but only one over here, so I'm going to put it to here. Next, we're going to balance the oxygen's. Therefore auctions ends over here. And I could balance that by adding four waters over here and down here, there are four oxygen's on both sides. Next I can balance the hydrogen Sze, there are eight. Hydrogen is up here, so I need to add eight high legions to the left side. And down here there are 200 yards on the left, so I'm going to add £200 on the right. Okay? The next step is to balance the charges. Top reaction There is. There are eight positive charges and one negative. So it's plus seven on the left. It's plus two on the right. So I need to add five electrons to the side and then in the bottom, reaction there to positive charges on the right. None on the left. So I need to add two electrons to bounce that. Okay. Now I need to find with the lowest common multiple is between two and five to get the number of electrons to cancel on the left and right sides that blows calm multiple is 10. So I'm going to multiply the top reaction times two, you know, going to multiply the bottom reaction times five. While I do this, I'm gonna try to see if I can, uh, cancel things out so that we can get the final equation here on this page. Electrons. We have 10 and 10. Those will cancel. We have eight times to a 16. Hydrogen is on the left, and in the bottom, we have two times 5 10 Henderson's on the right. Said difference. Um, between 16 and 10 is six hydrogen sze across this out to say that I've taken care of it. Um, Emma No. Four minus. You have now two of those. And the last thing on the left side of the equation, Gross up is a speech to go four, and we have five of those. I'm sorry. Five age to see two fours were oxalic acid. Okay, that's taken care of. On the right side, we have manganese, and we have two of them. And we have, um, four times too. Eight waters. And then we have on the bottom to carbon dioxides. Times five is dead. 10. There. Okay, now, we can, um, double track that all of this makes sense. We have six plus 10 hydrogen sze 16 and they're 16. Over here, we have to manganese to manganese. We have eight plus 20 28 oxygen's. And on this side, we have eight plus 2020 oxygen's. We have, uh, 10 carbons, 10 carbons. Okay, so everything balances out now, the actual solving the problem, it tells us that, um, we're going to read, be reacting with point 1058 aquariums of oxalic acid so we can figure out what the number of most of acid that is by dividing by the molar Mass. That's 90 0.3 grams, uh, each to see to 04 per one bowl H two c 24 Next we can do the Moler conversion between moles of H to see to Go four and that is from this bounce equation. Five. So five morals of H two c two four We're selling for the Promenade solution and their two moles of that houses two moles a man four minus. Then we can, um, to buy by the volume. It tells us that we have 20 ain't 0.97 milliliters of that solution. And finally, we can convert that toe leaders. They're 1000 mill leaders in one leader, so they should leave us with moles of M N 04 minus over leaders grams of oxalic acid cancel moles, oxalic acid cancel and middle leaders cancels and we're left with moles of a metaphor over leaders. And if you won't find out, you would see the 1.62 two times 10 to the negative. Second more. That is a concentration of the permanganate solution