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1. You wish to prepare 1.0 L of 0.25 M KMnO4 from solidKMnO4. How many grams of solid KMnO4 should you use?2. You wish to prepare 1.0 L of 0.25 M KMnO4 from aconcen...

Question

1. You wish to prepare 1.0 L of 0.25 M KMnO4 from solidKMnO4. How many grams of solid KMnO4 should you use?2. You wish to prepare 1.0 L of 0.25 M KMnO4 from aconcentrated stock solution. How many mL of 1.0 M KMnO4 should youuse to prepare 1.0 L of 0.25 M KMnO4?3. You have prepared the KMnO4 solution but you are notsure the concentration of KMnO4 is exactly 0.25 M. You standardizethe solution by using a titration and the followingequation:2 KMnO4 (aq) + 5 Na2C2O4 (s) + 8 H2SO4 (aq) 🡪K2SO4 (aq)

1. You wish to prepare 1.0 L of 0.25 M KMnO4 from solid KMnO4. How many grams of solid KMnO4 should you use? 2. You wish to prepare 1.0 L of 0.25 M KMnO4 from a concentrated stock solution. How many mL of 1.0 M KMnO4 should you use to prepare 1.0 L of 0.25 M KMnO4? 3. You have prepared the KMnO4 solution but you are not sure the concentration of KMnO4 is exactly 0.25 M. You standardize the solution by using a titration and the following equation: 2 KMnO4 (aq) + 5 Na2C2O4 (s) + 8 H2SO4 (aq) 🡪 K2SO4 (aq) + 2 MnSO4 (aq) + 10 CO2 (g) + 10 Na2SO4 (aq) + 8 H2O (l) 0.896 grams of Na2C2O4 is needed to completely react with 10.50 mL of the KMnO4. (A) Using the mass of Na2C2O4, determine the moles of Na2C2O4 used in the titration. (B) Using your answer from (A) and the mole ratio from the equation, determine the moles of KMnO4 used in the titration. (C) Using you answer from (B) and the volume of KMnO4 specified in the problem, determine the exact concentration of KMnO4.



Answers

1. You wish to prepare 1.0 L of 0.25 M KMnO4 from solid KMnO4. How many grams of solid KMnO4 should you use? 2. You wish to prepare 1.0 L of 0.25 M KMnO4 from a concentrated stock solution. How many mL of 1.0 M KMnO4 should you use to prepare 1.0 L of 0.25 M KMnO4? 3. You have prepared the KMnO4 solution but you are not sure the concentration of KMnO4 is exactly 0.25 M. You standardize the solution by using a titration and the following equation: 2 KMnO4 (aq) + 5 Na2C2O4 (s) + 8 H2SO4 (aq) 🡪 K2SO4 (aq) + 2 MnSO4 (aq) + 10 CO2 (g) + 10 Na2SO4 (aq) + 8 H2O (l) 0.896 grams of Na2C2O4 is needed to completely react with 10.50 mL of the KMnO4.
(A) Using the mass of Na2C2O4, determine the moles of Na2C2O4 used in the titration. (B) Using your answer from (A) and the mole ratio from the equation, determine the moles of KMnO4 used in the titration. (C) Using you answer from (B) and the volume of KMnO4 specified in the problem, determine the exact concentration of KMnO4.

This problem asks us to figure out a polarity of a permanganate solution being tight, traded with oxalic acid, we're given the following information. It required 28.97 mill leaders of the permanganate solution to react completely with 0.105 8 g of oxalic asset, which is H two C 204 The unbalanced equation we were given as I m in 04 minus plus h two C two 04 and that produces them being in these two plus ion and carbon dioxide. Okay, what is the molar ity of the permanganate solution? So our task is molar ity of the m N 04 solution, okay. And this is done in in an acidic, um, environment. Okay, so a first order of business is going to write a balanced going to be dread a balanced chemical equation. In order to do that, we're gonna use half reactions and let me just get started. We're gonna have, um, almost to the manganese first. So I've got em, and 04 could be switched colors and M and two. Plus, this is one that gets done so much. It just isn't that hard to dio, so I have to add four waters, which gives me eight hydrogen ins and the eight hydrogen. Like I said, this is just one that gets done so much, and that should be it. Let me see if I wrote that down correctly. 58 11 and four. Perfect. Now let's write down the oxalic acid and that's going to have, um, feel, too. And I'm gonna need to hear. So my oxygen's air good, my carbons air good. I need to hide regions on this side, which means I will also need two electrons on this side. Now I see I've got a two and a five. So let's pick an unrelated color here, and I'm gonna have to multiply each of these equations by two and five, respectively. So I'm going to write, Can 16 to two and eight here. I'm going to write by tanned when I feel like I'm doing something wrong right here. I did because I forgot my to. So that's 10 and 10. So these crafts are. Let's add these two together and get our final equation. I have 10 h plus its and six age pluses gives meat six h plus is on this side. I have five h two, the 20 fours, and to remain grenades on this side, I have to making these two plus to Theo twos. Eight waters. We don't have any h plus is And that was I have 10 of these. See a mistake. Okay, too Tannin. Eight. There's my equation. There's my balanced chemical equation and regarding states on this, um, the waters a liquid And this the gas, everything else is a quis. Now our next step is to figure out a mill. Araji and we were told that we had 0.1058 grams of age to see 204 Let's convert this two moles using the molar mass which I cheated and just typed in the chemical formula, which isn't really cheating. And I got 90 0.34 said I was looking at three. Then I'm going to use my mole ratio, which is 52 more more m n 04 and H two C 204 to get 4.700 times 10 to the minus fourth bulls of permanganate. Well, polarity equals moles per leader. Similarity equals R malls, which is 4.700 times 10 to the minus fourth balls divided by way back up here we had our mill leaders, which is 0.0 2897 Leaders door math here and we will get 1.6 Plenty of state Biggs 22 times 10 to the minus two Moeller h two c two 04 And here's our answer. We did it.

This question says that a solution of permanganate the standardized by Titra ation with oxalic acid it required 28.97 milliliters of the permanganate solution to react completely with 0.1058 grams of oxalic acid. And it could just be unbalanced equation for their action up top here. So I've broken his down into the half reaction so that we can bounce this equation first. Start by balancing the non oxygen hydrogen atoms. Uh, and manganese is balanced in this reaction. And in the other reaction, um, we have, uh, two carbons, but only one over here, so I'm going to put it to here. Next, we're going to balance the oxygen's. Therefore auctions ends over here. And I could balance that by adding four waters over here and down here, there are four oxygen's on both sides. Next I can balance the hydrogen Sze, there are eight. Hydrogen is up here, so I need to add eight high legions to the left side. And down here there are 200 yards on the left, so I'm going to add £200 on the right. Okay? The next step is to balance the charges. Top reaction There is. There are eight positive charges and one negative. So it's plus seven on the left. It's plus two on the right. So I need to add five electrons to the side and then in the bottom, reaction there to positive charges on the right. None on the left. So I need to add two electrons to bounce that. Okay. Now I need to find with the lowest common multiple is between two and five to get the number of electrons to cancel on the left and right sides that blows calm multiple is 10. So I'm going to multiply the top reaction times two, you know, going to multiply the bottom reaction times five. While I do this, I'm gonna try to see if I can, uh, cancel things out so that we can get the final equation here on this page. Electrons. We have 10 and 10. Those will cancel. We have eight times to a 16. Hydrogen is on the left, and in the bottom, we have two times 5 10 Henderson's on the right. Said difference. Um, between 16 and 10 is six hydrogen sze across this out to say that I've taken care of it. Um, Emma No. Four minus. You have now two of those. And the last thing on the left side of the equation, Gross up is a speech to go four, and we have five of those. I'm sorry. Five age to see two fours were oxalic acid. Okay, that's taken care of. On the right side, we have manganese, and we have two of them. And we have, um, four times too. Eight waters. And then we have on the bottom to carbon dioxides. Times five is dead. 10. There. Okay, now, we can, um, double track that all of this makes sense. We have six plus 10 hydrogen sze 16 and they're 16. Over here, we have to manganese to manganese. We have eight plus 20 28 oxygen's. And on this side, we have eight plus 2020 oxygen's. We have, uh, 10 carbons, 10 carbons. Okay, so everything balances out now, the actual solving the problem, it tells us that, um, we're going to read, be reacting with point 1058 aquariums of oxalic acid so we can figure out what the number of most of acid that is by dividing by the molar Mass. That's 90 0.3 grams, uh, each to see to 04 per one bowl H two c 24 Next we can do the Moler conversion between moles of H to see to Go four and that is from this bounce equation. Five. So five morals of H two c two four We're selling for the Promenade solution and their two moles of that houses two moles a man four minus. Then we can, um, to buy by the volume. It tells us that we have 20 ain't 0.97 milliliters of that solution. And finally, we can convert that toe leaders. They're 1000 mill leaders in one leader, so they should leave us with moles of M N 04 minus over leaders grams of oxalic acid cancel moles, oxalic acid cancel and middle leaders cancels and we're left with moles of a metaphor over leaders. And if you won't find out, you would see the 1.62 two times 10 to the negative. Second more. That is a concentration of the permanganate solution

But a fly more love is to or do this to pull off him in or for bless. Six. Mohler. It's positive and do a one off. Amen. Let's do this. Five. Mourn off or through Bless Airman Off is too Oh, in but be volume off a minute before is it will do. 30 c explained for four more is it? Where do 30 c explained 44 Multiply 10. Raised to the power minus tree, the impute in concentration off game in or four is equal. Do little points, you know. 16 1652 polarity and volume off is to or do is it will do. 25 more is it Will do 25 months play. 10. Raised to the power minus tree d M. Few in concentration Off is to or two is equal to unknown number off. More love Immuno four is equal to concentration off mn 04 into volume off him in for number of moral off immuno four is big. Will do concentration off Immuno four Ease 6.19 It multiply turned rest with the power minus four. More concentration and volume product. You 6.1 98 Multiply can embrace to the power minus four more. So do more. UH, you may know four ratio fire small off is to or toe is equal to nine. Music went toe. Nine 0198 Multiply, then rest to the polar minus four MOL Eggs X is equal to in Is to or do music. What do one point Why, as you don't nine for nine multiply 10 raised to devour minus tree. More concentration off is or toe is equal. Two months off is to or two Divided by William Month is to or too easy well do. 1.504 nine months of Blyton raised to the power minus tree, more divided by 25.25 multiplied, then raised to the power minus three. The AM Pew guns in Frisian Off is to or through is equal to 0.6 polarities

Problem. 98 Greedo. Similar maker off the rivers Problem 1st 1 wish each solution. We see the polarity within. Avoid long. We should calculate that fresh. So I do. Right now. 90 a and I have been God, I am in home. Full your vehicle and and so far why we don't Just because I'm a know for use in this equation, So they should be equal. Boiko 03 sit for four leader. Why one? Oh, what's it by dough? Him. So we have this vehicle Sit, boy O t 00 Thai 10 millet e four ma. And now we're I a question Do Mangane thus by battle side and thus sit grow tall And we have five hours each and produce and do my head and do I am have must a water And now for this question within more radio Do more Mother never find more Barossa and now But boy Oh do Oh no! So what? Are we happy? I had to find City boy Maybe I don't know about it Mickley No, I do Mom Touma, We'll find more here. So now that sit boy Oh duo Tiny ready for I still have a fight. Time for this amount. Carol. Side divide by two on. When you have the mall off the peroxide and you're more Larry the Volvo Barasa you can cover the modernity now. More clarity. Oh, I still go. You cool and not dried. Careful for the beginning of then sit, boy 020 I did lie for two more balloon boy. Oh, to Fi Oh oh, Later, right, All scientific. Yeah, Pacific And now what we have here I will have boy Oh, see So euro to him Yeah, a man named for equal Oh, no, no, By rocks I


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