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(Aseignment CnptgProblem 6-31 EnhancedFeedbackMoet40iuKebulle pluteJ shulor #rjno mth EANttanalnmnt A4n In renrncJum Hedna oruvam (PEr 170achtrug ntenlt Enoonius Du @mru conmccudaetaantGeu ueiledentna Eul EEuExpruatLanliemnl IouredStnPtrtioyi 4nnon AetraeaeamntetFigureUIncortuct; Tr Aonin_ atomply remalnirgPar HDulecuanoConluc | Intca ?HaGInnbwier Vainudlaniticoni ( quruaContac omd"Couaac dunid

(Aseignment Cnptg Problem 6-31 Enhanced Feedback Moet 40iuKebulle pluteJ shulor #rjno mth EANttanalnmnt A4n In renrncJum Hedna oruvam (PEr 170 achtrug ntenlt Enoonius Du @mru conmccu daetaant Geu ueiledentna Eul E Eu Expruat Lanliemnl Ioured Stn Ptrtioyi 4nnon Aetraeaeamntet Figure UIncortuct; Tr Aonin_ atomply remalnirg Par H Dulecuano Conluc | Intca ? HaGI nnbwier Vainu dlaniticoni ( qurua Contac omd" Couaac dun id



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Which of rhe following merhods is uscd to form a ncutral fcrric chloridc solution? (a) Adding onc ro rwo drops of $\mathrm{NH}_{3}$ to an $\mathrm{FcCl}_{3}$ solurion. (b) Addirion dilure I ICl to an FeCl, solurion followcd by rhe addirion of an NaOI I solurion.(c) $\Lambda$ dding an excess of $\mathrm{NH}_{3}$ to ar $\mathrm{FeCl}_{3}$ solution. (d) $\operatorname{Addin} g$ an excess of $\mathrm{NaOH} \mathrm{t} \circ$ an $\mathrm{TeCl}_{3}$ solution.

Hello agreement Further given bar chart off journalistic question equation can be written. It's even plus half rule. We went square is called P two plus half route. We two square Yeah, are even is called Tau P two plus half row. We do we square minus b one square. Or it can be also written us a half rope. We even is squared a one upon a to holy square minus one using equation off. Continue t using a one B one is called toe to veto. No, sister, I grow that son, Thanks for about

Question number 15. He had given her dynamic. Yes. Everyone living here. Yeah. 100 okay. So there are designs. Oh. Mhm. Right. This is yeah baby. It's just sleep okay. And that to date girls Are by 2nd 1. But so it is doing that. This is. Yeah. And and and and so it has given that anyway. But when the black too and we've got to um so sc sc baby perfect to end and the the particular part you have to prove that amy and severe congo and do it. I don't expect strict french sanitizer. No. Yeah. So fast track Mondays. Mhm. To them and we left. Oh um that's your spirit time. Excellent. So then we d but not to them. Same reading. Now these two again said that he bought a perpendicular then. Yeah and put to each other. Both sm VD are pendergraft both in Germany So one and 2. So now are they even a member of parliament life? I'm in my name. Apartment two. That's right. And a B parlamento. See because. Yeah. Brandon. Thank you. So you can see here uh now from from J. C. But at the end we development then and both as a performer to them. So you can clearly see it there sc parlamento Bernie. Right? What? So woman two. Ok. So now you can see both operate in Gaza parallel to each other. Also SCS perpendicular to. Really? Okay. Yes, I guess you're number two city and I see our motto and we Okay. So as uh I can say that the anger C equal banda could be the all of entity. Right? First mm. Okay. So to about the size of A B. C. D. Are parallel and all understand every day. Okay. So then we can read baby sit here is a rectangle. Mhm. Nice. Your parents you get better below. Uh huh. 56. If we have time. But then apologize and also condemned to each other. Thanks for them. Right? Yeah. Yeah. Maybe I'm going to. Mhm. Listen, cause as we see liver. Yeah. Okay. Uh huh. For your service Us. What our world? Right Hands book. Oh, thank you.

Hello Agreement in this problem again, we have toe using the bar chart off knowledge, education using watch art of more knowledge. Equation too. Right equation We went plus half rope. We really squared. Plus roadie vibe on it's called Toe B two plus half role B two square with people is called Tau P two and we want to be zero. Be too. We will get root off G vibe on on The situation will be like this this Sisto And this is one. This is 82 This is Yeah, but that's all, Thanks.

This question tells us there are two elimination products obtained from this E to reaction and part A assets with those products are. So if you'll notice we have this private groups, we have this primary bro mean right here that's going to be eliminated. And so the only adjacent carbon we have is this one, so we can either take off a hydrogen or deuterium for our elimination. So if we were to take off the hydrogen, we would be left with the deuterium left behind or beer to take off the deuterium. It would be left with the hydrogen on the product. So those are our two products. And then part be asked which is formed in a greater yield and tells us a za hint to see Problem 91. Problem 91 tells us that it is harder to break. It takes more energy to break a C D bond than a C H bond, so the one that is formed in greater yield is probably going to be the one that's easier for me to be breaking the c H bond on. And so if we're breaking the C H bond, that means the deuterium is left over, so this one with the deuterium left over, will be formed in greater yields


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