5

An unknown compound contains 74.02g C, 8.71g H, and 17.27g N. 121.71g of this of compound contains 0.75mols.a. Find it's empirical formula.b. find it's em...

Question

An unknown compound contains 74.02g C, 8.71g H, and 17.27g N. 121.71g of this of compound contains 0.75mols.a. Find it's empirical formula.b. find it's empirical formula.

An unknown compound contains 74.02g C, 8.71g H, and 17.27g N. 121.71g of this of compound contains 0.75mols.a. Find it's empirical formula.b. find it's empirical formula.



Answers

A compound is $17.2 \%$ C, $1.44 \%$ H, and $81.4 \%$ F. Find its empirical formula.

We're told in this question that we have 48 point 64% of carbon and 8.16% of hydrogen. What? This compound is a carbon hydrogen oxygen compound only therefore taking the difference from 100 we confined that we have 43.20% oxygen. Want to assume that we have 100 grams of the compounds? And by doing so, that means that we have 48.64 grams of carbon, 8.16 grams of hydrogen and 43.20 grams of oxygen that will convert all of these two moles using their respective molar masses. 0.16 Mole of hydrogen 28.64 divided by 12 would give me 4.53 moles of carbon 43.20 divided by 16 would give me 2.7 Moles of oxygen we're going to now divide by The smallest number of moles were just dividing all them by 2.7. Give me 1.5 and 8.162 point seven here would give me three. I can't have 1.5 racial, 1.5 Harbin's So to get a whole number, they're gonna double everything to give me 36 and two therefore of whole numbers here so we can take this racial here and come up with my empirical formula, which is C 33 carbons h six for six Oxygen's.

So we have given the chemical compound contain carbon hydrogen oxygen. So we have 48.6 the scent of carbon April when? 6% off. Hodgins. So what would be the empirical formula? So, first of all, we have to found ah, oxygen percentage so we can post if with their calculations. So they're also 10% teacher should be equals to 12% house of tractor, percentage of carbon and also sort of a sand age off hydrogen. And we should be able to find that, um ah, yes equals to 43 0.24%. All right, you know that you found there empirical forming that. We're going to found a number almost off each compound. And also we go each element in the compound, and they are going to find ah, simples way show. All right, so Ah. Okay. So from here, Well, let's assume we have ah, 100 gram off our compound that we don't know his formula, and therefore we would have ah, um coming. We have ah, corresponding in 48.6 graham hydrogen to be 8.16 gram hostage in to be for this week. 0.24 gram. So we're going to convert that to Lambeau Most so 48 points. 85 12. Wherefore point all five and then 400. We have 8.16 most and then for oxygen were 43.2 40 wide by 16. And then we have around Troop on seven, though most okay, so we're going to the letter away show betraying toppings, two hydrogen to our situation. So this way, she, of course, was four point all five to a 0.16 to 2.70 we're going to sympathize just racial by divide the whole thing by, ah, about the smallest number. So we're going to divide everything by 2.7. So we have a 4.0, Friday or by 2.7. We have 1.5 and then for a point in theory. But there are 3.0, and that we have one. And also you see that we don't have a whole number, so we have to make it to be a whole number. So we have a free 2622 and this would be our, um um simply put, we show and and ah, and pickle for everybody goes to C three h six. Oh, too

In this problem, first time writing the tissue sees to adjust to seven is too old is equal to 18.5 by the world. Each to 1.55 By one. Each to 55.04 By 35.5 Is to 24.81. Bye Sistine, which is equal to one is 2, one is 2, one is 2 one. So empirical formula is equal to c h c l o According to the option. Option eight, correct here. C h c l o. I hope you understand me solution of this problem.

Hi there. Empirical formulas are frequently determined experimentally. So that is what we're gonna look at how to do here experimentally we have We have a compound here that experimentally has been determined to be 52.2 percent carbon, 13 0.0 percent hydrogen and 34.8 percent oxygen. To determine the empirical formula from this information, we have a few steps we need to follow. The first step is, is that we need to know these numbers in terms of mass however percent right now, but we need to know a mass. The second step is, once we have that mass, we're going to convert it to moles, with the third step being finding that smallest whole number ratio between those molds. Once we know that whole number ratio, those air going to become the subscript in our formula. So let's get started. As I mentioned, the first step is we need to know how many grams of each of these we have. Well, regardless, the size of the sample, these percentages will hold true. So let's make it easy on ourself. Let's just assume we have a 100 g sample, so assume our samples 100 Gramps. If that's the case, then we don't really even need our calculator to see that 52.2 g would be due to carbon, 13 g would be due to the hydrogen and 34.8 g would be due to the oxygen. So that was our first step figuring out how many grams of each substance we have. The second step is in order to get an empirical formula, we need to know the mole ratio of those atoms in the molecule. So we need to convert each of these two moles. We're going to do that by dividing each one by its Moeller Mass. So looking at the periodic table, Mueller Master carbon is 12.1 g in every mole dividing 52.2 by 12 point no one gives me 4.35 Okay, moles of carbon moving to the hydrogen. Let's convert it to moles the same way. But using the molar mass for hydrogen, there's 1.8 grams of hydrogen in every mole of hydrogen doing the math. There, I get 12.9 moles of hydrogen. Finally, for the oxygen notice. It's just the element oxygen. It's not 02 It's just the atom. Looking at the periodic table, it's 16.0 g of oxygen for every mole of oxygen taking 34.8 divided by 16. Well, give me 2.18 Moles of oxygen, that was step two. Step three is finding the smallest whole number ratio between these numbers. The ratio is not always gonna cooperate and jump right out at us. But there's a little trick. Weaken Dio to quickly help us find the ratio. And what that trick is is to vote to divide each of these by the smallest number we see here. So we have 4.35 moles. We have 12.9 moles. We have 2.18 moles, 2.18 is, of course, the smallest number. So if I divide 2.18 moles of oxygen by 2.18 I get one mole of oxygen. If I take 12.9 moles of hydrogen divided by that same 2.18 I get six moles of hydrogen and moving up to my carbon. If I take 4.35 divided by 2.18 I get to. So now I can more clearly see the mole ratio for every two moles of carbon, it needs six moles of hydrogen and one mole of oxygen. I can write the formula for this. Now It's going to contain carbon, hydrogen and oxygen and the amount of each one Are these whole numbers So to carbon six hydrogen and one oxygen. But of course, in a formula, we don't write ones. So C two h 60 his are empirical formula for this compound. Hey, thanks so much. I hope you found this useful.


Similar Solved Questions

5 answers
Homework: Section 4.4 Homework Score: 0 of 2 of 10 (0 complete SaveHW Score: O%, 0 of 10 pts4.4.5Question HelpFind the area of the region enclosed by f(x) and the x-axis for the given function over the specified interval.X +3x+4 X<3 f(x) = on [ - 1,5] 4x+10 x23The area is square units_ (Simplify your answer)Enter your answer in the answer box and then click Check Answer
Homework: Section 4.4 Homework Score: 0 of 2 of 10 (0 complete Save HW Score: O%, 0 of 10 pts 4.4.5 Question Help Find the area of the region enclosed by f(x) and the x-axis for the given function over the specified interval. X +3x+4 X<3 f(x) = on [ - 1,5] 4x+10 x23 The area is square units_ (Si...
5 answers
16-52 Rank the following aromatic compounds in the expected order of their reactivity toward Friedel-Crafts alkylation: Which compounds are unreactive? (a) Bromobenzene (b) Toluene (c) Phenol (d) Aniline (e) Nitrobenzene (0) p-Bromotoluene
16-52 Rank the following aromatic compounds in the expected order of their reactivity toward Friedel-Crafts alkylation: Which compounds are unreactive? (a) Bromobenzene (b) Toluene (c) Phenol (d) Aniline (e) Nitrobenzene (0) p-Bromotoluene...
5 answers
6value: 7.69 pointsIf 4 =20 3what values of xmake det A= 0?O x=7,x=3E-X 'O-Xx= 0,X= 7x= 0,x=7,x-3
6 value: 7.69 points If 4 = 2 0 3 what values of xmake det A= 0? O x=7,x=3 E-X 'O-X x= 0,X= 7 x= 0,x=7,x-3...
5 answers
Product? Mnaat I major Wpart Axnpound snown #8No:NoConaOCH,CO,nACVNO:NEEN*ClNaNOJHCI, 0"€OHOHAIClsHsCA II,IiiB. !,VC. !,IV,VD. IlI;, VE: /,I
product? Mnaat I major Wpart Axnpound snown #8 No: No Cona OCH, C O,n ACV NO: NEEN*Cl NaNOJHCI, 0"€ OH OH AICls HsC A II,Iii B. !,V C. !,IV,V D. IlI;, V E: /,I...
5 answers
[-/2 Points]DETAILSSCALCCC4 6.8.005.MI:MY NOTESPRACTICE ANOTHERLet f(x) 1 + x2 (a) For what value of c is f a probability density function?For that value of c, find P(-5 < X(Round your answer to three decimal places:)Need Help?Read ItWatch_Maater L
[-/2 Points] DETAILS SCALCCC4 6.8.005.MI: MY NOTES PRACTICE ANOTHER Let f(x) 1 + x2 (a) For what value of c is f a probability density function? For that value of c, find P(-5 < X (Round your answer to three decimal places:) Need Help? Read It Watch_ Maater L...
5 answers
Rnx coora2.24 Pn the Ist set of axes below, draw a PE diagram for a rxn with a AH -150 kJ On the Znd set of axes below draw a PE diagram for and Ea (no catalyst) = 120 kJ and Ea (catalyst) 80kJ a rxn with a AH = 50 kJ and Ea (no catalyst) = 200 kJ and Ea (catalyst) = 60 kJ 300 300 250 250 200 2 200 1 150 reactants 150100reaclantsreactcn coordinatereaction coordinate
rnx coora 2.24 Pn the Ist set of axes below, draw a PE diagram for a rxn with a AH -150 kJ On the Znd set of axes below draw a PE diagram for and Ea (no catalyst) = 120 kJ and Ea (catalyst) 80kJ a rxn with a AH = 50 kJ and Ea (no catalyst) = 200 kJ and Ea (catalyst) = 60 kJ 300 300 250 250 200 2 200...
5 answers
~A randam sample of 100 COS students produced the following results concerning (ood preferences alian Khle _ Chines FexicanFemzAt the 0.05 level, test the clalm that food preference Indepenelent of gender. Claim:Opposite:Significant Level:Test Stalistics:P-Value:Decisioa:Ccrclusion:
~A randam sample of 100 COS students produced the following results concerning (ood preferences alian Khle _ Chines Fexican Femz At the 0.05 level, test the clalm that food preference Indepenelent of gender. Claim: Opposite: Significant Level: Test Stalistics: P-Value: Decisioa: Ccrclusion:...
5 answers
Determine the Inverse Laplace Transform of the functions and simplify.323 11 Vi(s-18)213 SVw(s+1) 25 3 4. 8 + s2+8 s2_8 3
Determine the Inverse Laplace Transform of the functions and simplify. 3 2 3 11 Vi(s-18)2 13 SVw(s+1) 2 5 3 4. 8 + s2+8 s2_8 3...
5 answers
Compare Venus's continents with those on Earth. What do they have in common? How are they different?
Compare Venus's continents with those on Earth. What do they have in common? How are they different?...
5 answers
Find the sum of the Geometric Series (show all work necessary to suppOry your answer):3n+1 2
Find the sum of the Geometric Series (show all work necessary to suppOry your answer): 3n+1 2...
5 answers
Jaelencaubla dneEtueWrlch of lha following is NOI a Newman projection of 2-methylpentana? 0A CHZCHzCHsCH; O8 HsC CH;CH30c H3CCH;HCH3Et
Jaelencaubla dneEtue Wrlch of lha following is NOI a Newman projection of 2-methylpentana? 0A CHZCHzCHs CH; O8 HsC CH; CH3 0c H3C CH; H CH3 Et...
5 answers
1 1 lectrophile in Tre (1 Poinl) V!
1 1 lectrophile in Tre (1 Poinl) V!...
5 answers
3 Answver 1421*7 point) Let j(9)1
3 Answver 1421*7 point) Let j(9) 1...
5 answers
Bez Bez Bez Bez more and more Bez more stable stable are than stable than both than either 'Zag more Bez: Bez and stable Bez zag pue Bez than more Bez: more stable stable than than Bez ZagV diagram, Bez and 8 the de1 8 lower energy 8 dzp 8 than the 8 MO as shown below 8029
Bez Bez Bez Bez more and more Bez more stable stable are than stable than both than either 'Zag more Bez: Bez and stable Bez zag pue Bez than more Bez: more stable stable than than Bez Zag V diagram, Bez and 8 the de1 8 lower energy 8 dzp 8 than the 8 MO as shown below 8 02 9...
5 answers
0 0 The Establish Reciprocal iiii l J: sin Isin the from lidentity: HH the sin and taaadi and and previous Isimplifying S3 simplifying step then IVH | sin using what?
0 0 The Establish Reciprocal iiii l J: sin Isin the from lidentity: HH the sin and taaadi and and previous Isimplifying S3 simplifying step then IVH | sin using what?...
4 answers
Verify that the Divergence Theorem Is true for the vector field on the region E Give the flux: F(X, Y, 2) =Xyl Yzj ZXk E Is the solid cylinder x2 5 121, 0 $ 2 $ 5.
Verify that the Divergence Theorem Is true for the vector field on the region E Give the flux: F(X, Y, 2) =Xyl Yzj ZXk E Is the solid cylinder x2 5 121, 0 $ 2 $ 5....

-- 0.023878--