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Imagine a cart with an open top that moves without any loss ofspeed due to friction. Suppose that you begin to gently pour waterinto the cart so that you do not aff...

Question

Imagine a cart with an open top that moves without any loss ofspeed due to friction. Suppose that you begin to gently pour waterinto the cart so that you do not affect its overall momentum. Whatchange do you expect to see in the motion of the cart? Support youranswer by considering the equation for momentum and reasoning aboutwhat happens as the mass gets bigger when amount of momentum isconstant.

Imagine a cart with an open top that moves without any loss of speed due to friction. Suppose that you begin to gently pour water into the cart so that you do not affect its overall momentum. What change do you expect to see in the motion of the cart? Support your answer by considering the equation for momentum and reasoning about what happens as the mass gets bigger when amount of momentum is constant.



Answers

When you are traveling in your car at highway speed, the momentum of a bug is suddenly changed as it splatters onto your windshield. Compared with the change in the momentum of the bug, by how much does the momentum of your car change?

Hi. So this question we're told that a removable bounces of a brick wall and the collisions were clear lasting and soon as this is a brick wall. When do over ball for my hits comes and hits it. The brick wall is not going to move because there's a war and since conclusions pretty elastic, the robot will bounce back in the same with the same velocity kim or in the opposite direction. So we're going to have So this this was 10 m/s and it's going to be my understand mentors for a second. So I changed momentum change in velocity will be turned minus minus 10 and I'll change momentum from the momentum is being called to envy appears to mass members of velocity after mass with the philosophy. PCT is the momentum. So for changing momentum we have M. V. P. M. V initial final. All right. That this is final, this is initial. and so we have our final as 10. And our Angel has also tend to um, time stand minus m times minus 10, and We get 10 times 20 And the masses at 1.2. So we have to point 24 24 program. I mean, that's what's happened as I change in momentum. Yeah. So basically explain can't find in the momentum Here and then I was planned by two because this rebounds with some velocity and direction. So that's it.

So in this problem we have a cart that's traveling along a horse on a track and it having bad that falls on it. And we want to know what happens to the speed of the cart and then represent their process with an impulse momento bar chart. Well, thespian of the cart, because the minimum is momentum is conserved in the horizontal direction. Here, the speed of the car. It's going to slow down. We'll see that mathematically in a minute, but are impossible. Madam Bar chart is actually pretty simple because there's there's no impulse in the X direction. There's obviously one in the Y direction when this bag hits. But the momentum before and the momentum after are the same. The velocity is different because the masses different. Now we can see that if the momentum is before and after are equal than the new velocity is the mass of the cart divided by the mass of the cart plus the mass of the bag. And since this is greater than this, this will be less than being one

As we all know that impulse J. Is the product of fourth and time. And also I can write the value of four. F. Is equal to M. A. So from both the Express and I can develop day which is equal to M. E. Multiplication T. Which is equal to a multiplication B minus you by T. Multiplication T. On solving it further, I can write the expression for J. Which is equal to a multiplication B minus you, which is equal to M. B minus emu, which is changing momentum. So from this relation changing momentum is equal to the product of force applied and the time interval. So the two cards we have been applied the same amount of food, eaten, equal interval, so the changing momentum it's same for both the card, so correct ups. And here is so the correct option. Age see in this problem.

We have two cards, we can say M someone equaling some mass. M sub two Equalling two times this mass because the second part is two times bigger than the first cart. And we're pushing the lower mass card, we can just say delta X equaling 35 centimeters. And then for the other car at the same distance with the same force, So Delta X equaling 35 centimeters and they both have some force imparted. Now they're asking for a change in momentum, but this only occurs when the cart is there is some sort of force or there's some sort of collision or something happens to the cart in order for that change in momentum to occur. So here, because there's no there's no additional information, there's only a cart being pushed and a heavier car being pushed. We could determine the difference amount, different amount of the different amounts of work being done on either cart. But in terms of the change in momentum, delta P. That can't be determined. So here the correct option is deep. There isn't enough information to tell which to which of the two cards experience the larger change in momentum. That is the end of the solution. Thank you for watching.


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