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Delernugk Hensinncnble AB Io eilibnum Suppose that F = 90 N; (Figure 1) throt signifcant figures and include the #ppropriate unilsExpress vour ansneValueUnitsFigure...

Question

Delernugk Hensinncnble AB Io eilibnum Suppose that F = 90 N; (Figure 1) throt signifcant figures and include the #ppropriate unilsExpress vour ansneValueUnitsFigureSubmitKeoetaneterpuletminiLerislancable AC' Ior equlibn um Entess Vou Anecvor (Hl significant- nguiet and include the approprlale unitValueUnitsSbmlleRledlnaansnVan

Delernugk Hensinn cnble AB Io eilibnum Suppose that F = 90 N; (Figure 1) throt signifcant figures and include the #ppropriate unils Express vour ansne Value Units Figure Submit Keoetaneter puletmini Lerislan cable AC' Ior equlibn um Entess Vou Anecvor (Hl significant- nguiet and include the approprlale unit Value Units Sbmlle Rledlnaansn Van



Answers

Add $5.131022 \mathrm{cm}$ and $6.83103 \mathrm{mm},$ and multiply the result by $1.83104 \mathrm{N}(\mathrm{N}$ is the SI unit of force).

Okay, So, um, to get the projected components, I'm gonna have to get, um, the vector coordinates of the force from A to C and the force from A to B. And so you start by drawing the diagram point. A out here be is over here and see is over here. Force be is we'll call this and force. See, is what I'll call this. So I'm gonna begin with you from a to B. So in the X direction, that's three meters. Uh, negative three meters in the Y direction. It is negative. 0.75 meters. Uh, and in the Z direction, it's going up one meter. You A c again. Negative three. I, um it's going one meter in the Y direction and in the Z direction is 1.5. All right, So if I dio f so be equals s dot u sabi use of a B. I mean over you a B that should work now. F is given as 60 I plus 12 j minus 40 k in news. So, um, get the calculator going here using desmond's dot com and sadly, Dismas dot com can't do vector operations. Otherwise, I just take this all in. But let's just do the X component. The X component is going to be 60 IMEs. Negative three over U A B. Which is gonna be the square root of negative three squared for us. Negative 0.75 Where'd plus one squared That gives me. Ah, no, I'm gonna have enough room negative. 55 point for I I'm gonna put in the negative 0.75 minus 13 0.8 j and then, um, detected Teoh put in the one plus 18 point five. Okay. And this is in news. Let's check that answer on page. I mean, question 117. Uh oh. Okay. We just need the magnitude of that. So do a bunch of square roots. Here were it of 55.4 square looks plus 13.8 where plus 18.5 squared. Use me 60 Newtons. Mm. Unfortunately, it says 70.5. So guess I need to look for a mistake here because that's not the correct answer. So 18.5 13.8 hiss 60. Oh, silly me. Excuse me. Oh, excuse me again. Oh, my goodness will never stop, man. Excuse me 1/3 time. Okay, Silly me. I got ahead of myself, all right? When I changed to the negative 0.75 I have to change to the, uh 12. So that's going to be 12 times negative 0.75 divided by U A b And so that's going to give me minus 2.7218 actually, around it J. And then it's gonna be 40 times one negative 40 times would want, um, minus 12.3. Okay. And and that's all in Newton's. Now we do the square root. Ah, 2.8 squared and 12.3 squared. But, Stanley, I still have the wrong answer. That gives me 56.8. All right? I investigated the book and look for something that I missed, but I don't believe that I'm missing anything significant. Ah, misunderstanding. Anything. 56.8 is the answer that I'm getting, which is very different than the 70.5 in the book. Um, hey, f sub See is gonna be f dot Now I did notice that I have been using u A b in you a see when I really meant our A B in our a c the distance to those points. And so I should have been writing our a b r a b down here because ah, this divided by this is u A b. So, um, our a c over our a c So I'm gonna put that into a calculator. Actually, I'm going to write it over here. So it is 60 dot negative three over our A b r a c I mean, which is negative. Three squared plus one squared plus 1.5 squared. So that gives me negative 50 one going for I, um Then we put in a 12 dots Pro Caps one. So that's going to give me plus 3.4 j. And then I put in a negative. 40 uh, times 1.5 nominator stays the same. Already be the same in all of them. That gives me negative 17.1 K That's in Newton's. So I put that into Pythagorean theorem, basically. So it's 51.4 squared, plus your 0.4 squared and plus 17.1 square That gives me 54.3 News, which is again, is not what showed, but I double checked everything. And I believe that my work is correct. I'm gonna triple check here. And I just realized what I did wrong. Um, the dot product is a scale. So, uh, in my answer here, there's no I no j and there's no que same down here. There's no I. There's no j. And there's no que There's no need to use the Pythagorean theorem here because the dot product is a scale. And so I could have done this all in one swoop. Um, the point is negative. 55.4, mine is 2.8 minus 12.3. Use me in negative negative 70.5 Newtons for F B um Teoh, which is correct. And then f c is just going to be, um and I shouldn't have a line on top of it, either. Negative 51.4 plus three point for minus 17.1 negative trade right here. Negative 65.1, which is correct. Okay, so my major mistake waas the dot product is a scale. And so up here that should be a scaler right here. That should be a scale. The dot product is a scaler. And so, um, when you get to like down here, you just have to add those together to get the answer and same over here. Think I was a bit rusty and that's why I had some trouble with that. Um, Also due to the rusty this I was using are a B r is using u A b when I meant or a B okay.

We have our number 45 in which, given that considered 100 Newton weight suspended by two wires as makeup thing figure find their magnitudes and components off the vectors. Force vectors often have to magic components of the force. Victor. So Okay, so in this case, we have to draw a horizontal lion battle toe This. So, yes. Now, these two are parallel lines, So this will be 30 degree as alternate. Angle this 3 45 degree as the ultimate angle. So the eso the components components will be for F One component will be, ah, phone calls theater. That is this horizontal component. This will be a phone cost theater, and this will be a fun sine theta. Similarly, this will be of to cost data and ah, I have to sign theta here. So it's horizontal component will be if one cause 30 degree. Okay. And I fun. We have to use magnitude and vertical component will be have to Ah, sorry. F one model s that it Magnitude sign 30 degree. Similarly, for victor that is forced backdraft tow. Our little component will be f two cause 45 degree and have to that is managed only sign 40 finally. So this is the original component for a fun. This is the vertical component of fun. This is the original component to this is the vertical component of have to. Now we have to find the magnitudes for the phone. Enough to you Say, we can see that these two are gentle components that have fun enough to balances each other. So let's create or gentle components off a phone. Enough to that is often magnitude caused 30 degree equal toe. Have two magnitude cause 45 degree. So have fun. Magnitude will be equal to of two magnitude cause 45 degree by cause 30 degree. So after magnitude cost 45 days, one barrel too. Cost 30 is route three by two. Okay. Okay, so this will be a have to in two by a row two and two, Road three. So this will be, uh this can be too. Can Britain has to? These two will get canceled out so to three under route F two. So this is a fun this relation between. Have fun enough to magnitudes three Question number one. Now, one thing more to be noted. That the vertical components off. Both the forces have fun. Have to balance. Is this Sunday Newton Force? So let us add up these two vertical. It has had these these two vertical components that is often signed theater. That is a fun sign. Yeah, F for one sign that degree. Plus after magnitude assigned 45 degree equals two, uh, equals toe that is 100 eaten. Okay, let us avoid new writing. Newton here. No f one have this value to buy. Three under route have to magnitude and signed thirties one by two. Plus have two magnitude signed 45 ways. One barrel too equal to one. And there. So yeah, this can. Britain has have two magnitude as common. This will be ah to route to that is one by a little too. And 23 How cool. Place one by two. Equal toe. 100. Okay. Yeah. So this is f two. And if you take a sim off these two, which will be route to into route three, so here it will be one plus the route three equal to 100. So magnitude after will be equal toe. 102 two and two or three. Divide by one place or three. So by using calculator, we have 102 under route six, divided by one class on the road. Three that 89.6575 Okay. Uh huh. So 89.65 75 Newton. That is the magnitude of have to now plug in a question number one. Ah, fun magnitude will be to buy three under root managing of have to That is 89.6575 which will be called toe. Okay, okay. Two or three. This is 73.2073 point 2050 Okay, so the magnitudes wow have fun off for the fun will be equal to 73 73.2 Newton and have to will approximately be equal to 89 point seven 89.7 Newton. As this is five and one can better here to approx for approximation. And the components now will become components off. F one will become simply 73 point toe. This is how a gentle component cost 30 degree horizontal component vertical component 73.2 signed 30 degree similarly components for F two will become 89.7, cause 45 degree and 89.7 sign 45 degree. All are in Newton's Thank you so much.

What? So if we want to try to find these four specters, the first thing I would do is draw these right triangles like I'm doing here. So both of those are going to be right triangles. So this first one over here notice we can find what is going to be like, the X and the Y components of this, uh, by doing the following. So let me just write one over here. Notice If we do co sign of 30 degrees to start, this should be equal to the angle adjacent to this. So adjacent is going to be X and then our, um, other one for why? Oh, actually, our hypothesis almost proud about that, which is br magnitude of f one. So if you want to solve for what X is this is going to be X is equal to the magnitude of F Times co sign of data. But one thing we need to keep in mind when we're doing this, at least with how I'm going to set up like this force diagram is that anything to the left of here is going to be negative, So we would actually not just have the absolute value here, but we would have the negative of this, all right. And now we can do something similar for why? So we want to figure that out. Now, we can go ahead and sign of data so it would be sign of 30 degrees, which should be opposite, which is why over hypotenuse magnitude of f one. And in this case, we're going to want this to be positive, because this force vector should be pointing upwards. Actually, I mean, if we look at it going like this, you can see how it's pointing up as opposed to going to the left. Um, so, yeah, the y component should be positive. So again, we just multiply that over and we get that Why is equal to the magnitude of F one times sine of 30? Actually. Don't know why I wrote co sign of data here. Um, and actually, we can go ahead and figure out what these are because co sign of fada should be Route 3/2, and then sign of data should just be one half. So if you want to write F one as a vector, so f one should be equal tubes I'll put a vector hat over this. So negative. The magnitude of F one times, Route 3/2, and then the magnitude of F one times, one half. Okay, Now let's do the same thing for F two over here. So if we try to set these up in a similar fashion, well, first want to co sign of 45 degrees, which is going to be adjacent. So now this is our X, and then this is our Y. So there's going to be different access and wise. Um, so the adjacent would be X. This will be over the absolute value of or not perhaps the value, our magnitude of f two. But keep in mind that since we're heading to the right, this X value should be positive. So this one is going to be positive, unlike the other one we had. Okay, so, um, which I just go ahead and rewrite this So co sign of 45 is Route 2/2. So if we want to get X by itself, we just multiply that over. So it would be rude to over two magnitude of F two, and this should be equal to X Let me break that on the left side. Tax is equal to this. Now we go ahead and do the same thing. But for why? So this is going to be coast on our side of 45 degrees. So this should be opposite over hypotenuse. So the opposite is why the hypotenuse is at two. So why over the magnitude of two and once again you can see how the why should be positive, since this is oriented upward. Okay, so we have that. And then again, we just multiply over. And this should be also route to over two. So, in this case, why should just be Route 2/2, The magnitude of ft. Okay. And then, actually just right. What this for SPECTRE is right here. So this should be equal to the absolute value of the magnitude of F two. Route 2/2. And then this should be the absolute value. I don't know why one keeps absolute absolute magnitude of F two, uh, times route to over two. So it ends up being the same. Okay, Now, what we want is something that counteract this. Wait here. So if we were to think about it. Mhm. This would be going straight down or the weight. And so this is supposed to be 100 Newtons, so we don't need to multiply it by, like, acceleration or anything. So if we were to think about it, this should be, um zero. Because it's not moving left to right, and they would just be negative 100. So I'll call this W for our weight. So let me go ahead and add that down here so w is equal to zero Negative. 100. Now, if we were to add all of these up, um, so just, like add all them up, this left side here should be equal to the zero vector and then the right side, while we would add each of these components. So, um, I should let me do it like this. So first, do these in blue. So if I add all those up, that would just be the magnitude of F two. Route 2/2, minus the magnitude of F one, Route 3/2. And then for this other component here we would just add all of these up, which would give us the magnitude of F two, Route 2/2. And then plus the magnitude of F one times, one half. Okay, so we have this open almost forgot. Minus 100. Okay, so we have this now. Now, this is zero vector. Um, if I actually rewrite it is just going to be 00 like that. Yeah, And at this point, we can just set this equal to each other. So it be zero is equal to F two's magnitude route to over two bias. The magnitude of F one, Route 3/2. And then the second one here, we would set that equal. So to be zero is equal to have to route 2/2 and then plus 9 to 2 f one what? Half minus 100. And now we have a system of equation that only depend on two variables, and we can just go from here. And so, uh, so the first thing I'm going to do is multiply this top equation by two. Um, and so if we do that, better yet, I'll just go ahead and set up a matrix to do this instead. So I'm going to add that 100 over first so just be 100 now is equal to that. And then a matrix we would be able to set up would be the following. So I want f one first, actually, so I'll just leave. Have to first, I'll just kind of write this above. So I remember it's have to. So this would be route to over two, and then this would be rude to over two. And then over here, this would be negative. Route 3/2, and this would be one half. And then this should be 0 100 all right? And now we can just go ahead and do all of our reproductions and stuff in order for us to solve this. Actually, let me rewrite that. The Route 3/2. Okay, so first notice that we can just go ahead. And actually, now, I think the Matrix is actually over doing this a little bit, because those we can actually just set equal to each other pretty quickly, actually, Yeah. Sorry. I'll just go ahead and do that instead. Um, because I think that will be the quicker way. So, actually, if we add that over and actually multiply each side by two. Kind of like what I was saying before that would give magnitude of F one. Route three is equal to magnitude of F two, Group two, and then I'm just going to go ahead and solve for F one. So we divide Route three over, so that would be the magnitude of F one is equal to the magnitude of F two and then be route to over route three. And now we can take this and plug it in over here. So take that market in. So doing that would give us 100 is equal to. And actually, we could just go ahead and multiply each side by two here as well, like we did before. So let me do that first. So I'm just gonna multiply each side of this by two. So that would be 200 is equal to route to magnitude of F two, uh, plus just magnitude of F one. All right, now we can replace this with a magnitude of F two route to over route three, and if we were to just go ahead and divide each side by route to that would give us 200 over root two is equal to the magnitude. Well, they have to plus the magnitude of F +21 over root three. And then if we add these are actually just factor out the route or the magnitude about two. That should give us one plus one over root three, which, I mean, if you want, you could rewrite as just Route three plus one over root three. So this is 200 over root two, and then we can go ahead and just divide that over so we get that are magnitude of F two. Should be 200 um, times Route three over root two times, Route three plus one. Uh huh. And then if we want to find what f one is, we can just come up here and then plug this up. So let's do that. So this implies. So it would be 200 times Route three over to Route three, plus one times route to over Route three. And actually the root two's council, the Root three's Council. And we would just be left with how the magnitude of F one is equal to 200 over Route three plus one and our last step, we could just come up here and then plug everything in. Mhm. So if we plug these two values into here now, this should give us So for F one, this is going to be so negative F one times this. So actually, the twos can just cancel. Uh, it would be 100. So it would be negative. 100 Route three over route three, plus one. And then here, that would just be one over root three plus one. Because the one half and two councils and then down here, if we were to plug F two n, uh, does anything cancel? So the route to cancel. But then we say, Oh, and the two also does so then it would be 100 actually. Let me pull this down. So I'm not trying to decipher that. Yeah, so we divide that by two of the route to cancels. Uh, so it would be 100 Route three over over, uh, route three plus one. If I'm not mistaken, which makes sense, because these two should sum up to give us a zero. Okay. And then this here is going to be Earth. Not this here. So the route to the council of the 100 councils. So then it would be 100 over. That should be three plus. No, that's right. So 100 the route to and then we have the route three in the numerator, and then we just have the route three plus one in our denominator. Then let me look through this really fast to make sure I may have, uh or so I didn't do any kind of weird, um, algebra somewhere. Yeah, and actually, all those look good. Um, yeah. So we got our magnitudes of top here, and then we have our vectors here, so I mean, you could approximately as if you want, but, I mean, we normally want to be as exact as we can if we can, and in this case, we could be exact.

So consider that we have this 100 Newman wait. Suspended by the two wires and the picture show only wanted by the magnitude and components of the force. Spector's F one and two. So, yeah, this here is going to be completely suspended without moving or anything. We're goingto want that the force of vector to go to the origin and by the origin. I mean, if I were to place this here as the origin of where the blue and the green lines intersect and going straight down is where the waiters we want these three so called us three We want these vectors to sum up to zero vector. We want f one plus two plus every to equal to the zero vector. And I should put in Victor's on top of all of these. So first noticed that F three Wilson's were just walking straight down the X axis. That force is just going to the all going straight now. So it has a weight of 100. Any vector direction of zero negative one. So, maybe on the side, I should I remember. All vectors can't be Britain, abs. The magnitude times their unit direction vector. So in this case, the direction picture of that three, like I said, is going to be zero negative one and the magnitude so we can rewrite this as one plus two plus 100 times zero negative one, which would be zero minus 100 is the zero vector. And then we can go ahead and subtract that vector open, which would tell us that we want one most left, too, to equal to 0 100 All right, now, let's go ahead and find out what our components should be. And then we can go from there. So over here, or our vector F one So I'll do that in blue. So if we just look at this triangle here So we know this here is 30. And all we know is that this here is the magnitude of one. So we don't know what it is. Just No, its magnitude. What? We want to find the components the X and Y components. We can use some trig. So from 30 degrees, we have that. This here is adjacent. So this is gonna be 30 co sign or co sign of 30 times the magnitude of F one and the other one is going to be magnitude of one sign of 30 degrees. So we have that. And now let's go ahead and do the other one as well. So here, we're going to have that The magnitude of have to man up here. We had 45 degrees. So, uh, adjacent to this is up here. So it's gonna be f two times co sign of 45 degrees and the opposite will be magnitude of two. Let me go So magnitude over to sign of 45 degrees like that Now. Well, we know what co sign sign of 30 and 45 or so. We can just go ahead and write that we no one is going to be equal to. So whatever the magnitude of F one is times the direction vector so co sign it. 30 is going to be 1/2. But since we're going to the left, we want to be negative. 1/2 so negative won't happen. And then first sign of 30. Well, that's going to open. Actually, uh, this doesn't want half or negative what happened. It's negative. Square root of three halves because sign of 30 is 1/2 all right, and then or f to this is going to be the magnitude of F too. Times the direction vector. So co sign and side of 45 are going to be square root of two over too square breathe. Oh, so we have this and we want to add these two together. So first we can distribute our magnitudes into here. And when we do that, we get that F one plus two and you got all my little hat songs for me. But those roof. So this is going to be equal to minus three square root to over two magnitude of one waas square root of two over too magnitude of two. And then the second component is going to be 1/2 magnitude of F one plus magnitude for square root to over two magnitude of on. We know even more that we wanted that to equal 0 100 So this year is going to be 20 100. So if we said each of these component wise you go to each other, we're going to get that we want actually minus three scrolls to over two of magnitude about one plus square root of two over two magnitude of two, equal to zero. And also, we're goingto want that 1/2 magnitude of F one plus the square root of two over too. Half to two, equal to 100 right? So let's go ahead and simplify these equations a little bit just to make it a little bit easier for us to do the algebra to solve them. I'm gonna scoot this over a little. So this top equation here, I'm going to multiply and divide by square root of So I'm gonna multiply by two and divided by the square root of two, which would leave the equation negative. Three one plus two magnitude is equal to zero. And the bottom equation I'm just gonna multiply that by two. So we're going to get F one plus square root of two. I have to is equal to 200. So now that we have that, let's go ahead and solved for F too. So in this first equation here, we're going to get that F too is equal to 31 and then we can use this. Plug it into the other equation to solve for after one. So taking this and plug in that and that's going to give. So it's gonna be three times the square root of two F two and then F One day we factor out that one to get one plus three scrambled. Too busy, too. 200. Divide that over and it's going to give us that. F one is equal to 200 over one plus three square groups of two. So we found the magnitude off F one on the zoo not a little bit more. And then we can go ahead and use this plug it into here to find too. So that tells us that F two is going to just be this times three, which is gonna be 600 over one plus three square groups of and that's equal to the magnitude of two. So we know the magnitudes of each of these, and now just to write out the actual vector of it, we can go ahead and plug both of these values in two. These equations right here. So let's go ahead and do that up here. So that tells us f one is going to equal to so 200 over one plus three scrambled too. Times negative. Square root of three to one. Huh? So this is our first specter, and then the second vector of two is going to be so. First we need to multiply by. The magnitude, which is 600 one, cost three square with you. And the directional vector we found was square root of two over too. Square into two over, too. And this year would be the other vector. So important pieces that we needed for this question are here, here, the two vectors and the two magnitudes of each of those factors.


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Population Change The rabbit population on a small island is observed to be given by the function $$P(t)=120 t-0.4 t^{4}+1000$$ where $t$ is the time (in months) since observations of the island began. (a) When is the maximum population attained, and what is that maximum population? (b) When doe...
5 answers
Trees grow faster and form wider rings in warm years and grow more slowly and form narrower rings in cooler years. The figure shows ring widths of a Siberian pine from 1500 to 2000.(a) What is the range of the ring width function?(b) What does the graph tend to say about the temperature of the earth? Does the graph reflect the volcanic eruptions of the mid-19th century?
Trees grow faster and form wider rings in warm years and grow more slowly and form narrower rings in cooler years. The figure shows ring widths of a Siberian pine from 1500 to 2000. (a) What is the range of the ring width function? (b) What does the graph tend to say about the temperature of the...
5 answers
Iaa uinuRelalonthap Krterrt Sane alanm Iablctand Deletinim€ Eatlern QuestionUsing the lincar relationship graphed above; estimate the percent of over S75 purchases If there are 40% on-call senvice represcntalivcs.Provide your answer bclon:FEEUUACRMure insiRucIiONsubmit
Iaa uinu Relalonthap Krterrt Sane alanm Iablctand Deletinim€ Eatlern Question Using the lincar relationship graphed above; estimate the percent of over S75 purchases If there are 40% on-call senvice represcntalivcs. Provide your answer bclon: FEEUUACR Mure insiRucIiON submit...
5 answers
9 PointsIn a large city; telephone calls to 911 come 0n the average of two calls every 5 minutes.01.1 PointsSuppose 911 receives at least 10 calls in an hour: What is the probability that 911 receives at most 20 calls in an hour?Enter youi answer here01.2 5 PointsAt 11:15 pm, 911 received a call for an emergency request Since then; no calls came for next 40 minutes. What is the the probability that 911 would receive a call before midnight?
9 Points In a large city; telephone calls to 911 come 0n the average of two calls every 5 minutes. 01.1 Points Suppose 911 receives at least 10 calls in an hour: What is the probability that 911 receives at most 20 calls in an hour? Enter youi answer here 01.2 5 Points At 11:15 pm, 911 received a ca...
5 answers
Ci:cn vx2] Jndv-3i 31, Trd] W3 #elc besxeem WQ &'Uneemgeseneem anq w is #fpmorimoe) QR? %r sllavalar im depns Ctu Fivz @oWic} Qinil foz fina| #nssen. "zr DIsulroc: {us Mhss Toeenesd Uzjiko &s msztlet
Ci:cn vx2] Jndv-3i 31, Trd] W3 #elc besxeem WQ & 'Uneemgeseneem anq w is #fpmorimoe) QR? %r sllavalar im depns Ctu Fivz @oWic} Qinil foz fina| #nssen. "zr DIsulroc: {us Mhss Toeenesd Uzjiko &s msztlet...
5 answers
0364 [7+7] Figure shows (wO eleclrons and proton , each electron is a a distance r = 1.50 * 10-1Cm Irom Ihe proton Compute the magnitude and direction 0the net electric Iorce they (Le_ electrons) exert on the proton: The charge on a proton iS Ap = +1.607 x 10-1%C and the charge on an electron is qe 1.607 * 10-"9C4 4 65.09r =LS0 * 10-10m | Fkure
0364 [7+7] Figure shows (wO eleclrons and proton , each electron is a a distance r = 1.50 * 10-1Cm Irom Ihe proton Compute the magnitude and direction 0the net electric Iorce they (Le_ electrons) exert on the proton: The charge on a proton iS Ap = +1.607 x 10-1%C and the charge on an electro...
5 answers
The dcosity of sulfuric acid (HSO4) solutioa from solutod L 3 S6M calculate:battery 1225 g fmL Ifthismolality oas perceut of sulfuric aciq molc faction of wtct Calculatc thc Gcezing Potat nnd boiling point of a 0.55 m CH;OH in watcr. 0- S Ckg mol; k" 0.51 ICkg/mol)
The dcosity of sulfuric acid (HSO4) solutioa from solutod L 3 S6M calculate: battery 1225 g fmL Ifthis molality oas perceut of sulfuric aciq molc faction of wtct Calculatc thc Gcezing Potat nnd boiling point of a 0.55 m CH;OH in watcr. 0- S Ckg mol; k" 0.51 ICkg/mol)...

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