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Calculate Mean_ Median, Mode; Quartile Deviation, Standard Deviation and CV Marks in 10 20 30 40 50 60 70 90 0 - 10 Stats 20 30 40 50 80 100 No.Ol 10 Students...

Question

Calculate Mean_ Median, Mode; Quartile Deviation, Standard Deviation and CV Marks in 10 20 30 40 50 60 70 90 0 - 10 Stats 20 30 40 50 80 100 No.Ol 10 Students

Calculate Mean_ Median, Mode; Quartile Deviation, Standard Deviation and CV Marks in 10 20 30 40 50 60 70 90 0 - 10 Stats 20 30 40 50 80 100 No.Ol 10 Students



Answers

Find the mean deviation about median for the following data : $$ \begin{array}{|c|c|c|c|c|c|c|} \hline \text { Marks } & 0-10 & 10-20 & 20-30 & 30-40 & 40-50 & 50-60 \\ \hline \begin{array}{c} \text { Number of } \\ \text { Girls } \end{array} & 6 & 8 & 14 & 16 & 4 & 2 \\ \hline \end{array} $$

So here we are, given a data set, were asked to find the main median and mode of this given set, which is 10 12 2015 and 20. So first, to find the main, which is X bar, is able to x y, which are data points over and which is our number. So here we would add up 10 plus 12 plus 20 plus 15 plus 20. And then divide that by five. Forget this a mean value of 15.4. Mhm, mhm. Next we want to find the median. Yeah, yeah, which is the middle value. So we're going to want to add our Liston in order from greatest police. So we have 20 15, 2 twenties, 15, 12, 11, 10. So here are median is 15. Yeah, and last. We want to find the mode, which is just the most. It's a good way to think of it. So again, listing out our data set, you can see that the only number that really repeats is 20. So our mode will be 20 Mhm

Hell in this problem we have to calculate the mean deviation about meeting each for the age distribution of 100 persons by using the given data. We have given the following table. Now, first of all, we will convert the given data into continuous frequency distribution by subtracting 0.5 from the global limit and adding 0.2 to the upper limit of each class interval. So we get here, we have the following modified class. Now we will find the mid value. That is exciting. It would be 18, 23 28 33 28 43 48 and 53. Now, in order to find me in division about meeting, first of all, we will find a cumulative frequency, it would be 55 plus six is 11, 11 plus 12 is 23 23 plus 14 is 37, 37 plus 26 is 63, 63 plus 12 is 75, 75 plus 16 is 91 and 91 plus nine is 100. Here we have an is equals 200, so we get and upon two is equal to 100 upon to Which is equals to 15. Therefore, medium class would be 35.5 to 40.5, so we get median is equal to 35.5 plus 50 -37 are born 26, It would be equals two, 35.5 Plus 2.5, Which is equals to 38. Now we will find the absolute value of deviation from the median, it would be AB -28 is 20 as we're finding the absolute value, so we will ignore the minus sign, 23 -38 would be 15, 28 -38 is then 33 -38 is by you, 38 -38 is zero, 43 -38 is five, 48 -38 is Dane, And 53 -38 is 15. Now we will find a fly into absolute value of deviation from median, it would be five into 20 years, 100 16 to 15 is 90 12 and detain is 120 14 into 5, 70, 26 20 is zero, 12 into five is 60 16 into 10 is 160, and 19 to 15 is 135 And the submission is 735. Now, main division about meeting as equals two, one upon N sigma, F I into absolute value of division from me. Well, I goes from one to and by substituting the known values, we get 735 upon 100 It would be equals to 7.35. Hence we get main deviation about meeting Is equal to 7.35.

Here in this problem, we have to find the main division about me by using the given data. So here we have given X I and F I now, in order to find the main deviation about main. First of all, we will find the main for that we have to find a fi exile. So here we have 10 into four is 40, 13-24 is 7, 20, 15 to 28 is 1400 17 to 16 is 1120 and 19-8 is 720, And the submission of FIXi is 4000. Now we know that mean is equal to yeah, one upon and sigma, if I x I there I goes from one to and by substituting the known values, we get one upon 80 into 4000 As equals to 15. Now we will find the value of absolute deviation from the mean, that is excited minus 15. Since here we are finding the absolute values, so we will ignore the negative sign. So we get 10 -50 is 40, 30 -50 years, 20 50 -50 is 0, -50 years, 20 and 90 -50 is 14. Now, in order to find the mean division about me, we will find, if I ever do deviation about me, It would be 14-4, is 160 20 to 24 is 480 zero into 28, zero, 29-16 is 320 and 14- eight. A 320. And the submission of this function is 12, Now, we know that main division about mean is it was too yeah, run upon end into cigna if I into X, I minus mean, bad, I goes from one to win. Now by substituting the known values, we get main deviation about mean is equal to one upon a day into 1280, it would be equal to 16. Therefore, we get main division about mean is equal to 16

Hell in this problem we have to find main invariance by using the given data. So here we have given the following table. First of all, we will find the mid values that is X I. So we get five 15, 25 35 and 45. Let assumed mean as equals two 25. So in order to find the mean, first of all, we will find you Y which is equal to X I minus assumed mean Upon 10. So we get EYS minus two minus one 01 two. Now we will find a fi you Y it would be five into -2 is -10 18 to -1 is -8, 15 in 2, 0 is zero 16 into one is 16 and six into 2 is 12. Similarly, we will find similarly, we will find a fire you a square. So we get 20 seat zero 16 and 24. The submission of F i U I is then and The submission of FIUS Square is 68. Now we know that Mean as equals two assumed mean plus sigma, F I U Y. Upon submission of F I into age here edges the height of the class interval by substituting the known will use we get Mean as equals two 25 plus 10 appoints stay into 10 by simplifying it. We get 25 Plus two which is equals to 27. Now we will find variance. We know that variances equals two hide square a bone and square and do and into sigma. F I U I square minus sigma. F I U Y who square by substituting the known will use we get penn square are born 50 square into 15: 68 -10 sq. By simplifying it. We get 100 upon 2500 Into 30 400 0. It would be equals two. Run upon 25 into 3300, Which is equals two, 132. Hence we get me as equals two. Mhm. 27 variances equals two 132.


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