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Please can you answer these two questionsplease!Question 1: Using a series of boxes andarrows define a workflow to sequence a purified protein by massspectrometry. ...

Question

Please can you answer these two questionsplease!Question 1: Using a series of boxes andarrows define a workflow to sequence a purified protein by massspectrometry. Into each box describe the steps of tandem MSsequencing with electrospray ionization.Question 2: Considering your answerto #1 above, if you have two proteins in your sample from a bloodsample collected in the clinic (i.e.; a human subject) could yousequence both proteins? Why or Why not?

please can you answer these two questions please! Question 1: Using a series of boxes and arrows define a workflow to sequence a purified protein by mass spectrometry. Into each box describe the steps of tandem MS sequencing with electrospray ionization. Question 2: Considering your answer to #1 above, if you have two proteins in your sample from a blood sample collected in the clinic (i.e.; a human subject) could you sequence both proteins? Why or Why not?



Answers

Protein sequencing $1 .$ Determine the sequence of hexapeptide on the basis of the following data. Note: When the sequence is not known, a comma separates the amino acids (Table 3.3). Amino acid composition: $(2 \mathrm{R}, \mathrm{A}, \mathrm{S}, \mathrm{V}, \mathrm{Y})$ N-terminal analysis of the hexapeptide: $\mathrm{A}$ Trypsin digestion: $(\mathrm{R}, \mathrm{A}, \mathrm{V})$ and $(\mathrm{R}, \mathrm{S}, \mathrm{Y})$ Carboxypeptidase digestion: No digestion. Chymotrypsin digestion: $(\mathrm{A}, \mathrm{R}, \mathrm{V}, \mathrm{Y})$ and $(\mathrm{R}, \mathrm{S})$

This problem is from organic chemistry, where we have been given a reaction which follows sn one mechanism toe form the product. On the basis of this reaction, we have to answer certain questions. In the first part, we had to write the great expression for this reaction since the reaction follows as in one mechanism in which the rate of the reaction depends on Lee in the concentration of substrate. So the rate expression can be written as next. We have toe brother reaction profile for this reaction and label all the parts in this reaction profile. So the reaction profile is drawn here. The side represents potential energy and this represents reaction. Progress in the reaction profile is shown over here like this here it has been given that the products are lower in energy than the reactant. So this represents the energy of the reactant and this represents the energy of the product. Now all the parts are labeled as here. This is the reactive molecule. This is intermediate and this represents the product which is lower in energy, then the reactive molecule. Next, we have to answer what happens toe the rate of the reaction on doubling the concentration off the reactive molecules. Now on doubling the concentration they read off, reaction will be doubled next. If the concentration off the solvent ethanol is increased, what will happened to the rate of the reaction? The read will not change on increasing the concentration off ethanol as it is independent off concentration off solvent that is, eternal actors nuclear filed, and the reaction rate depends only in the consideration off substrate.

Answer for the question part A. What causes the different positive charges on different particles? Uptick protein. So here, pro donation of the side chains of yeah are and age and determining groups of the protein because it's the different positive charges on different particles of the protein. And so for part B Mm, the M and I said composition in numbers of residues. Perching of egg white list goes on is as follows. So here, what is the maximum positive charge there can be present and an egg white blossoms iron. So here is 19. This comprise comprises positively charged site Jane Mm Change one edge six care 11 are and when manage to and terminals.

We know that End and C terminal are amino acids. And from the cyanogen bromide treatment, we can deduce that meth Yonan is the 10th amino acid aftermath Yone in we get three following amino acids. I will look like this sequence from the chemo trips and treatment we can we get die peptides And by comparing the fragments of the chemo trips and treatment we confined our 11th 12th 13th and or a knife amino acids in the sequence that we're looking for and these air what it will look like from the trips and treatment we got the amino acids in the order g k s y. And obviously these abbreviations stand for amino acids, and we know that this was the result of an end terminal residue. So what we can deduce from this is that no basic amino acids are in the other fragment that we are looking for were given a sequence for the end terminal amino acids. But to be sure that we're getting the right sequence, we have to confirm the n terminal amino acids with the result of the khaimah trips and treatment. And when we do that, we'll get that our 1st 5 mean. Oh, aphids will be in this sequence. Order from the N terminal. Will got we got that. The 1st 3 immuno acids are F i s. So from there we can get the remaining me. You asked that we are looking for six through eight, and it will be these amino acids that we will need in our sequence. So our final sequence that we're looking for it contained these amino acids in this order and I would look back at the problem. See how this corresponds to the fragments who were given and obviously look up the amino acids or write them down for these abbreviations for the sequence.

So again for this one, you need to have your book open because the figure is hard to draw, and I'm not going to do it. Um, it's on page 1 68 I don't think I could draw it if I wanted to. Would be way too confusing. Basically, what we want to know is why? Why are there two peaks? Um, in this in this particular chromatic grams. So at this position, there are two peaks because we each have two copies of every gene. And with that it means that we either, um and this is very, very simplified, but we either have the same. Um, the house is the same base pairs. So where everything reads the same in the two genes look exactly the same. And there's no changes, or there are slight variations their slight changes in one gene or the other that make it a little bit different from one another. It may not change the function of the gene, um, or or in might stop the gene from working completely. But the other gene, because we have two copies of every gene, the other gene is working or is normal, so I'm just gonna try toe try to briefly shows there was, like peaks here and there. Those those would be green. And there's one here and there is another one here, and these are all showing different different letters that are going on. So at one particular spot, there is a peak and another peak on top of it. Um And so like I said, the reason is because we have two copies of every gene and at that particular base pair, that person has one gene with this blue. So I would say the blue means see, So he's got one base pair that's a C and one base pair over here on the other. Jane in that same spot, that's a a T. For example. What of the green is is maybe a t. Um So the answer is, he's a headers. I go, this person is headers. I go at that spot for that particular base pair


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