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Question

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Answers

$\begin{array}{|c|c|}\hline \text { Codon on mRNA } & {\text { Amino Acid }} \\ \hline \mathbf{G C A} & {\text { alanine }} \\ \hline \mathbf{A A G} & {\text { lysine }} \\ \hline \mathbf{G U U} & {\text { valine }} \\
\text { AAU } & {\text { asparagine }} \\ \hline \mathbf{U G C} & {\text { cysteine }} \\ \hline \mathbf{U C G} & {\text { serine }} \\ \hline \mathbf{U C U} & {\text { serine }} \\ \hline \text { UUA } & {\text { leucine }} \\ \hline \text { UAA } & {\text { stop }} \\ \hline\end{array}$
You are given three mRNA sequences:
1. 5’-UCG-GCA- AAU-UUA -GUU-3’
2. 5’-UCU-GCA- AAU-UUA -GUU-3’
3. 5’-UCU-GCA- AAU-UAA -GUU-3’
Using the table, write the peptide encoded by each of the mRNA sequences.
a. 1. Serine-alanine-asparagine-leucine-valine
2. Serine-alanine-asparagine-leucine-valine
3. Serine-alanine-asparagine(-stop)
b. 1. Serine-phenylalanine-asparagine-leucinevaline
2. Serine-alanine-asparagine-leucine-valine
3. Serine-alanine-asparagine (-stop)
c. 1. Serine-alanine-asparagine-leucine-valine
2. Serine-alanine-asparagine (-stop)
3. Serine-alanine-asparagine-leucine-valine
d. 1. Serine-alanine-asparagine-leucine-valine
2. Serine-arginine-asparagine-leucine-valine
3. Serine-alanine-asparagine(-stop)

Okay. We're just listing the corresponding Marin A sequences that correspond with this standing sequence. So ruled remembers that t goes to time and we'll go to a They will go to you. Jeeva, go to C and C will go to G. So without further ado, let's get started for our first strange We're gonna have a au so a you g you a huge eu Then we have G a c g Oops C g a si You see? You see a see you see a inordinate that's trend. Next, we're gonna have to do the other friend Which will be you CCU you a c c u u a Then we're gonna have Ah you g c a u g c A Next we have a G uh g a u c so g a UC Next we have g a, you see. And lastly, we have g and T. Thank you for watching and a Sergey end. Um, you thank you for watching. And I hope this helped

This question involves the topic of base pairing and the general process of transcription. First. Let's see about about base pairing. Remember that you have for D. N. A. You have four naturally no spaces adding. Okay, You have one in, you have cytosine and you have saving for R. N. A. For any type of RNA. The only difference is that instead of timing you have in your arsenal. Okay, that's the only difference. Now. Remember that happening piers with timing or your asylum case of RNA and wanting bears with cyrus in. Now let's talk a little bit about. A DNA. DNA is made of two cents. Okay, this is going to stand and this is the other stand. It just has a name. For example, I suppose this instant is the cold instant according to stand and this is the template strand. The coding strand is called like that. Because when this DNA undergoes the process of transcription, it means the process by which uh M. R. N. A. Is produced. The M. R. Name is going to have the same nucleotide sequence than to the coding standards A. D. N. A. It means if the coding system has a has a following sequence of A then the the M R. N. A is going to have the sequence A. Two. If it is a G C. T then it is going to be G. C. You remember that you use your brazil instead of timing in the in the RNA. Okay, so that's the coding stand talking about a temporary stand. The temporary sent as its name says, it is useful as a template for transcription. So for example and it is going to have the complementary sequence than the M. RNA. For example. Let's give another example. Not this. Let's suppose the template is A C. G. D. A. Okay, so what will be the sequence of the M. RNA? As I mentioned, the template has the complementary sequence to the M. RNA. So the marinade, it's going to be that what binds what place a dining remember it pairs with uracil? So they're going to be in uracil uracil, G C. E. In you. It is going to be the aymara name. Okay. And if you want to know that coding a son for DNA, well it is going to be this sequence. But remember that with time instead of curiosity, it means that calling a son would be T T G C A. T. Okay, so with this knowledge let's transcribe this sequence. Okay, this is the first sequence. Um The question says that all the sequences they are providing us are the template DNA sequences. It means this is the complementary strand to the marina. So our marina is going to be the complementary strength to this. It means instead of tea it is a instead of G it is a C. Instead of a. It is you you the G a do g c c a U G G and you Okay. This is the M r n A produced from this template. A strand of the DNA. Now let's subscribe the next DNA sequence. Okay, as this is the template, the stand then the nitrogenous base that pairs with G. Is see the original space that with C. S. G. A nitrogenous base. That there's a your A C. The G A U U U. She U a n G. Okay. This is the M RNA produced from this is simply the strand of DNA.

All right. So for this problem we are given a strand of RNA and this is going to be M RNA. And I drew it here in black. And let's just describe what we're looking at. Because what we need to answer ultimately is how is this transcribed? What would the D. N. A. That gave the code for the RNA? What did that look like based on information given to us? So what we know is we have the five prime end of the RNA here, the three prime. And here then we have a series of nucleotides. So we have a U A C G A U U A. So we have adenine, uracil, adenine, cytosine, guanine and and so forth. So these letters are just representing the actual names of uh nucleotides. So this is an R N A M R N. A. And what we No is that MRNA is synthesized or transcript ID transcribed right through transcription from DNA, which is ultimately synthesized before. So then we can make R. N. A. As a result of the DNA that we have. So when this happens, uh they both run five primary three prime, but they run in different directions, meaning one is upside down when his right side up, in a sense, that's how I like to think about it because if it is running this way, let's say this is also running this way, but for them to be able to transcribe, they need to be facing one another, right? So facing this way and facing this way. So the directions are different, different orientations, right? It's like going left versus telling your friend to go left, who's in front of you, He's going to go his left which is going to be your right, that sort of thing. So now we just need to know what bases pair for transcription because the thing is they change in the process of going from DNA to RNA. So for example adding comes from a timing. So that's going to be this transcription here. Then you're a sill actually comes from A. D. Nine and D. N. A. So we just need to know the matches so we can make a little key here and then you can solve a respite for yourself ultimately so timing for DNA turns into adding as we just showed love at an inn for DNA turns into yourself. For RNA cytosine for DNA turns into guangming for RNA. And then guanine for DNA turns into cytosine for RNA. So that's the key. That's what we need to keep in mind so we can complete the rest of this. If you are quick on your feet you could probably go ahead and beat to the punch. But we can just do it together just to make sure we understand. So if I mean must make asinine guanine must make citizen, the magazine must make guanine for I mean must make adrenaline editing must make your sl we have two of those. If I mean must make adding again this is what the D. N. A. Had to have looked like. I had to have looked like in order to give uh this m r n A sequence that we have here. So which answer is consistent with this answer option? It is of course going to be interruption A, which runs in his three prime to five prime direction because of the different orientation that we just talked about. Think about the example of your left being different from your friends left, that sort of thing. The answer is of course, a.


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