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OSclHAonalemapoint) The figure shows an interactive graph of velocity u(t), melers per second, where lme measuted seconds You car change Uhie value of t IrI Ihe gra...

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OSclHAonalemapoint) The figure shows an interactive graph of velocity u(t), melers per second, where lme measuted seconds You car change Uhie value of t IrI Ihe graph bxy clicking and dragging Ihc red dol along the horizoniae AXlSGraph of velocity y = v(t)Instructions: click and drag the red dot - along the horizontal taxis.(a) Whai I5 Ihe displacement bxtween seconds and { Kconds? S1m1 (iiclude uMl(D)"Whnt u Ina diplacenient belween aecond: and aecond:? (Itclude40Slgned area 1.76(c) What +

OScl HA onalema point) The figure shows an interactive graph of velocity u(t), melers per second, where lme measuted seconds You car change Uhie value of t IrI Ihe graph bxy clicking and dragging Ihc red dol along the horizoniae AXlS Graph of velocity y = v(t) Instructions: click and drag the red dot - along the horizontal taxis. (a) Whai I5 Ihe displacement bxtween seconds and { Kconds? S1m1 (iiclude uMl (D)"Whnt u Ina diplacenient belween aecond: and aecond:? (Itclude 40 Slgned area 1.76 (c) What + (Fvt Ueeplocarrient brlaen saconda /nad Locon4 ? (unchude Wmde Wetcteem (ucalon amnlletnle Nou: Yov Ean Fupt



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Figure $P 2.24$ represents part of the performance data of a car owned by a proud physics student. (a) Calculate from the graph the total distance traveled. (b) What distance does the car travel between the times $t=10 \mathrm{s}$ and $t=40 \mathrm{s} ?$. (c) Draw a graph of its acceleration versus time between $t=0$ and $t=50 \mathrm{s} .$ (d) Write an equation for $x$ as a function of time for each phase of the motion, represented by (i) $0 a,$ (ii) $a b,$ (iii) $b c,$ (c) What is the average velocity of the car between $t=0$ and $t=50 \mathrm{s} ?$.(FIGURE CANT COPY)

For the given problem, we're discussing the speed of a car, um and we have a figure that shows the time to distance graph for a sports car. We want to estimate the slopes of the seconds for PT one, PT 2, PQ three and Q four. Well, unfortunately we cannot show the graph in this video, however, we can verify that to find the slopes of the second lines. We take two points and we find the slope between them by taking y tu minus Y one, okay, Divided by X 2 -11. And upon doing this will end up getting our slopes are 43 46 49 50. So those are going to be um the estimates for our car speed and there'll be somewhere around there, but they may not be exactly those. So it's gonna be a final answer.

All right. Question. 62 states of the changing velocity of a car was represented in the velocity versus time graph showed image that you drew here described everything you can about the motion of the car is in the graph partner sold. We'll go part by part here so we can say that's, um The car initially starts a native 20 meters per second, um, and then slowing down. Zeke, this is going to mean a velocity towards zero. I think positive negative doesn't matter. Uh, I should say, traveling my my my seconds. I'll say in the westerly direction if I establish that positive direction here was given by the easterly direction that's driving away from your efforts point, it slows down, uh, stops at 30 seconds. That was an APP sign 30 seconds where it begins traveling in the positively positive direction Um, X science until, till the region Joan here worked conference beat and then accelerates again. So mostly is me speaking, but seemly. That's the proper idea for what's happening with the car. But be what? The displacement of the car between time zero and 45 seconds. So this placement, that's when it's this increasing acceleration range. What is the displacement? So again we can find the displacement, Um is simply equal to the area under the curve a u C M shuffle here for a velocity versus time graph. So I see their two parts to this a negative portion, a positive portion. So maybe a little bit better. So the Syrian called section one, this region underneath the crater in section two, where it is above the curve of the access under the curve. Technically both of them, but above a bill of the axis. Remember it for kneeling below the access region. One will be negative region to will be positive. So the area of the curve these were two triangles. So the area trying to also be 1/2 base times height. So the base here, this 30 seconds and the height is negative. 20. Right? So that's region one region. D'oh! 1/2 the base goes from 30 to 45. That's 15 and reaches a higher of 10. Still, it's solving for this. We find that the displacement in this time frame is negative. 225 years. So after 30 seconds, the cars there is a car 225 meters west of our reference location. The second part is question Does ask where the path travel. I'll call that P. What's something That's just the total I'll call D. Displacement total. Just a total distance travel. So that would mean it's, um we take this first term and make it positive, right? So that it's a total length travel. Not then that displacement center length. If we were to make the first term, the one here positive, Um, I find that the total distance traveled by the car is simply just 375 meters again. That's just making this term positive and adding it to the other room. Yes, they go 300 meters. Is the path traveled? Artsy This question. What is the average speed of the car during all 70 seconds. So you don't average speed the average. You know, this is speed, not velocity. So I'm going to note that the difference, of course, speed just being overall distance and velocity and takes into account here vectored, um, your vector directions, right? The direction of your timber eventually. Sorry. The direction under terms so that its native contributed negative velocity. But for speed is just general total distance over told time. So what do we can't should break up Our again are lying. Here are a pathway into different sections. This will be three this square before and this little china will be five. So that's five terms Tow me to look at which I'll go in order to determine their total distances. Contributed again for speed. We want total distance, however, for parts one into, we already found that total distance traveled to be three years and five meters. So this is D one plus De tu is already already calculated That part three is a rectangle, so just facetime site. So has it. Based on 15 in height of 10 plus region, for which is that square. It's a base of 10 times the height of 10 in region five, which is a triangle. That's 1/2 Oh, is adding your sorry not play. Um, what happened? Bass again of 10 and high, going from 10 to 20. So it's 10 as well. We're looking for the average speed over the whole time Brain, which was 70 seconds. So you find it just means level. This is a little clear, says the sections one and two. This is region three region for and region five based on your diagram. Just to make that clear, we could find that the average speed for this whole trip 2 to 6 digits isn't the 9.6 meters per second where my average velocity takes into account the negative portion of that first low. So again, that's total distance over total time. Well, then, um, if for velocity, sir, for speed it was the net average. Certain that distance, you want displacement in that time frame. So d over tea for the first region, we found again for one and to determine that to be negative 225 meters where if we added literally, everything else is positive. So we can add the same terms we found previously intergration down here. And we would find that Arnett velocity again over 70 seconds would simply be 1.1 meters per second

Hi, everyone. Here it is given by the three time graph off a car. Using the graph, we have to find the total distance covered by the car distance covered in that time it traveled 12th toe 40 seconds. Using the very three time grab, we have to draw acceleration time, brah. We have to write position and time equation for or to a A to B on B to C. In the last part, we have to calculate average by the city of the car for 02 50 seconds. Let us start solving it as we know that total distance covered by the car will be equal toe area off balance sheet and grab. Here we can write total distance cover is equal to area under the graph now finding the area. So you will get the total distance. Cover half 50 into 15. Bless 50 into 14. You can find the area in four segments toe trying it 0 to 15 2nd. It is a triangle 40 to 50. It is a rectangle. Okay, 40 to 50. It is again trying it. So area off. Trying it area of directing girl again. Area of triangle half waste into white? No. So on solving total distance cover is 1875 m. This is the answer off part eight. No party displacement. Four time interval. 10 to 40 seconds. Our displacement both would be the same in this case area. Oh, Vita graph between 12th to 40 seconds. Yeah, it will be. Have people's 33 and took five plus 50 and to 25. It will be 1457 m. Yeah, lost turkeys acceleration. You have to find Yeah, 80 graph. We have to flow so far. Time duration Jiro toe 15 2nd acceleration is expression is defined as change of velocity with time. So it will be 50 minus Jiro upon 15 minus zero. So it is 3.3 m per second Squared four time interval 15 2nd to 42nd. Velocity is constant, so acceleration you will get zero for 42nd to 50 seconds. Acceleration is Jiro minus 50 upon 15 minus 40. So it will be minus five meter per second square. So here, acceleration time grab will be like this. No. Well, yeah, yeah, yeah, yeah. Gelato. 15 15 to 40 seconds and 40 to 50 time in second. This is acceleration in meter per second. Squared maximum is 3.3 point two and it is minus. Fight no deeper. Yeah, Little in question. We have to for the first part. Like from Otway. We used the occasion Access call to New T plus Uh huh. Off 80 square. So x one is going toe. Zero plus half is 3 23 and tow. T square toe X one is curto 1567 t swept. This is the answer off. 1st and 2nd Xto Hoff 15. Yeah, you are? Yeah. Yeah. You know, in tow 50 minus zero because 50 in two do u minus 15. Yeah, Good. So x two we will range 50 50 minus 3 75. This is the answer of second part. Third 3 75 plus went to five euro plus half minus pipe and to to U minus 14 a square plus 52 to U minus 40. So you will get x three. Toby who? 50 G minus 2553 square minus 4375 m. You know, Never did e part average velocity of the journey. Total displacement upon total time. So total displacement. We have majored. 1875 and time is 50 seconds. Average velocity of the journey is 37.5 m per second. They're so for it. Thanks for watching it.

All right. Question. 61 states of the change in velocity of a car is represented in the blast. A first time graph as I drew here. Um, that's when everything parties is state described everything you can about the motion of the current using the craft. Okay, it's a little students part first. So part a initial velocity of the car or not is, of course, these there's 20 meters per second. After eight seconds after t equals eight seconds in the car starts to slow down to zero and it slows down for 12 seconds. Slows for 12 seconds. Just that's there. Excuse me from Let me have primarily It's you can you couldn't look at the displacement in each of these times, but it's kind of the questions we're asking. It's a lot of do that right now, Barbie. What? The displacement of the car between times 10 and 20 seconds. So remember, we're dealing with velocity versus time graph the area under the equals the displacement right, which has to do with intervals. But, um well, let's look at specific things here. So there you under the clear again represent through displacement. Um however, in order to find. What do you know? This is 10 to 11 between 10 and 20. In order to find this area, we need to find the velocity at 10 seconds. So we can do you know that because the car slowing down there's some acceleration associated with that. So to find what that acceleration is, we can look at the change in velocity over time. So because it's uniform from eight seconds onward, Um, this native acceleration we know we're going from velocity of 20 down to zero so that the negative 20 inter numerator over 12 seconds correspond to an acceleration of a native 1.67 meters per second square where we can find that. So therefore, we need that information. Of course, that your clients find the displacement. At this time point, I'm actually saying something a little bit, so I don't think so. Region news that you know the velocity. Sorry. So the velocity is simply the acceleration type of the time. So you know the exploration 1.67 It wasn't a major these times 10 seconds. We know that this value here recently, 16.7 meters per second. Okay, so therefore Now we can determine the displacement from 10 to 20 seconds as the area under the curve. This this displacement. It's a triangle, right? So would be this region here, cutting it in. That's the area. Uh, I was getting worried because there's a little messy, but that's the idea. It's our big True. So it's never the area of a triangle. 1/2 base times height, the base years 10 because you're going from 10 to 20 sevens and the height of 16.7, which means our displacements would be, uh, 83.5 meters. What did to sing in the figures to be 84 meters. Great import. See, we want to know the average velocity. Sorry, the average speed of the car. So you know, the average Well, that may just be the total distance travel over the whole time. Where we going? We have a little time with 20 seconds. However, means find displacements. So if we could break this into two little segments here he, uh, called directing will part. So part one here, all shaded blue and the other part retreat that's called triangle, part beacon, shaded red. So this will be our average equation be D one our section for the triangle, plus the section for the start of a rectangle in the section for the Triangle D two. And I'll stop using colors just for ease of use. So the rectangle, the area under the curve again, is just the displacement. That's the base times height. So that's eight times 20. And now for the triangle. The bases 12 This time says 1/2 the base Aziz 12 because it starts. We agreed after eight seconds and the height of 20 all over 20 seconds. So it using this, we can find that the overall, uh, average velocity of traveling 2 to 6 digits is 14 meters per second. So you


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