5

(20 points} Three-point charges cuniet ol Ikc recujele hamn HE Tn Hraly Mc untdant clurges resultant Iield Tedlons calculate thc magnitudc and direction of thc res...

Question

(20 points} Three-point charges cuniet ol Ikc recujele hamn HE Tn Hraly Mc untdant clurges resultant Iield Tedlons calculate thc magnitudc and direction of thc resultant field (b)What thc nct tarcc expencnced hy charge q- 5.00 HC placed point?3,520.0uC0,500m7o_rnn-n917-30.0,c4,715.0HC

(20 points} Three-point charges cuniet ol Ikc recujele hamn HE Tn Hraly Mc untdant clurges resultant Iield Tedlons calculate thc magnitudc and direction of thc resultant field (b)What thc nct tarcc expencnced hy charge q- 5.00 HC placed point? 3,520.0uC 0,500m7 o_rnn-n 917-30.0,c 4,715.0HC



Answers

Charge $q_{1}=1.4 \cdot 10^{-8} \mathrm{C}$ is placed at the origin. Charges $q_{2}=-1.8 \cdot 10^{-8} \mathrm{C}$ and $q_{3}=2.1 \cdot 10^{-8} \mathrm{C}$ are placed at points $(0.18 \mathrm{~m}, 0 \mathrm{~m})$ and $(0 \mathrm{~m}, 0.24 \mathrm{~m}),$ respec- tively, as shown in the figure. Determine the net electrostatic force (magnitude and direction) on charge $q_{3}$

Hello. So the question is from electrostatic given that charge Cuban is placed at a region. So if we draw a line So Q one is placed at origin. Okay. And it's coding it out 00 and other charge Q. Two and Q. Three hour placed it given it you to to all placed it You .1 Age. You intend to the power -8. No Q. To charge. Yes Please stay. And to your .1 and two. So that place is 0.1800. And the charges Q. two. Let me like the magnitude of you going to do to you also. And third charges placed it The U. n. Let us this is the point zero and your .24. And this is guilty. Now the values of Cuban to Cuban is 1.4 into 10. to the power -8. She was too -1.8 into 10. to the power minus eight column and 2 3 is equal to 2.1 into 10. to the power -8 column. Okay now we need to evaluate the value of electrostatic falls on charge. Beauty falls on this charge. So you two is negative so its forces inward and Cuban is positive. So it's false is outward. So this is false on three due to two and this value is false on three due to one. Okay, so let me evaluate the value of after even that is equal to one x 4 by absolute note into mhm. You went you three over All 1. 3 sq In two direction is J. Okay it means positive by access and after they do in the similar ways. Take me like this then I will substitute these values one by four by capsule. A note Q two Q three Over all, 2, 3 square. And the direction is along exits direction is 0.180. and Y it may like you need director you need to factor out to trees. 0.180 into I. Okay minus zero point to fall into. J. Mhm. Divided by squared 0.18 sq plus 0.24 square. Okay, so the value of our +23 unit vector is equal to. Yeah, let me evaluate the value of this unit vectors. Mhm Yeah Square with 0.18 sq 0.18 square plus 0.24 square. Okay, so uh that is taking the reciprocal of it? Multiply 0.18 So that is 0.6 into I Okay minus 0.8 & two. In the similar way we can evaluate the value of our two to you. Also Our 2 3 is equal to Do you .1 age square Plus 0.24 sq. So that will be zero 09 That is our 23 square 0.9 m script. Okay. And I won three. Let me evaluate the value of 13 So when three is okay This is a region and 0.24 sq 0.24 m2 square. Okay. These are the values of our penalty and now it is the time to substitute these falls. Sonett folks will be, let me value it. Victor F. That is victor F. 31 plus F 32 So after everyone is Taking one x 4 by actually not woman. And the country is also woman. They love to trees. 2.1 into 10. To the Power -8. and inside it. So one is 1.4 entertain to the power -8 divided by I want this you're going to fall square and in their direction, J plus you two minus that is already compensated in that direction. 1.18 to 10 to the power minus eight, Divided by 0.09 in two unit rectories. 0.6 I minus 0.8 G. 0.6 i -0.8 G. Okay so let me evaluate the value of this force. So they will be equal to mhm Firstly first x component is 99 into 2.1 E minus eight. X. component I it component multiply 1.80 -8. Do I did by 0.09. Multiply 0.6. So that will be 2.268 to 10 to the power minus five into I Newton. Now the jet component is let me check whether it would be positive will never do. Okay, So that will be 1.4 E minus a. Divided by zero point in your car. Scream minus 1.8. D minus eight. Yeah, divided by multiply biased. You appointed Do I did by 0.09. Multiply 99. 32.1 a minus eight. So that will be one plus 1.56975 into 10. To the power minus five G. This is basically in the vector from now, we need to evaluate the magnitude and direction on charge. Beauty. So magnitude. If we take it victor F magnitude is equal to that's right Plus 2.268 E -5 squared to the power. So magnitude is 2.7 six into tend to the Powerball -5 Newton. And direction is F. Y. Or what fx In general in the world is equal to In the vector from this is this, this is victor F and the magnitude is 2.7, 16 to £20 minus five, and direction is f Y. S 1.569. So do I did buy 2.268, So that will be 34 .7° with respect to the positive x axis. This is like this 34.7 Degree, and this is what this is F F X. This is their flight. So these are the required themselves. So hold this closure.

Okay, so this one is a calm, a little bit of a complex problem. We have three point charges arranged. A such in space. We have to charges that are 2.5 times 10 to the negative. Dying cool looms there. Positive one. Is that negative? 10.5. The other ones at 0.5 this year is the origin zero. Um, and then we have one on the X axis, which is 10.7 meters away from the origin. And that one is three 0.0 times. Tend to negative nine. And the question is, what is the total force acting on this particular charge? Now, we're only focused on what's happening on this charge. So we're going. I'm just gonna draw quick force diagram. They're all positive charges, which means they're going to repel each other. So, um, this charge is going to feel a force of that way from this charge. We'll call this one, will call this, too, and we'll call this three. So one on three is going to make it go that way. And then 213 is going to make it go that way at the same angle. Um and so, um that's gonna be kind of a set up for later. Now the first thing we have to do is we have to. We have to use Cools Law, which is force is equal to K a constant times. Q. One We'll do one in three, first divided by the separation distance between one and three squared. So we're looking for this distance, which we don't know off the top of our heads. But we know this is 0.5, and we know this is point seven, so we can actually use Pythagorean theorem to figure this out. So 70.5 square causes a right triangle. Um, so 0.5 squared plus 0.7 squared is equal to C squared where r squared. I guess I should call it, um, and that will tell us what are is when you plug that in the calculator, you end up getting 0.86 meters. So that's why we're going to use for our are. So let's go ahead and calculate this now that the magnitude of the force So K is nine times 10 to the nine. That's a constant that's just given to you. Um, the first charges 2.5 times 10 to the negative nine. And the second charge is 3.0 times 10 to the negative nine. And that's all over that distance that we just calculated, which is 0.86 squared. Now when you plug that into the calculator, what you end up getting is 9.1 time or, I should say, 9.1 to give a couple more digits 9.1 to 7 times 10 to the negative eight. And so that would be the magnitude of this force. Right here. We'll call this F 13 now F 23 is going to be the same magnitude. Why? Because we have the same charges. The same distance, right? That's still also gonna be 230.86 meters. Everything is gonna be the same. The only difference is the direction. So both of these are going to be the same magnitude. But here's the issue. We can't just add them together and say, Well, that's the total force because we have to include the direction. And if we look at this, I'm going to redraw this over here. Um, here's that charge one forces going like this, the other forces going like this. What we have to do is we have to break them up into X and Y components. So here's the X component for the 1st 1 And then, um, here's the don't sees a different color. Here's the why components and then the X component for the other one is the same. And then the y component is this one like that. So what you're going to see is these two X components are gonna add up to cause a force going that way like that. But these two forces are actually gonna cancel out. So we actually don't even care about the why components, Because they're just going to cancel each other out, and we're just gonna have a net force in the right direction. So the answer is for the direction, at least is going to be going to the right. Now let's find the magnitude. So what we're gonna have to do is we're gonna have to figure out what is the angle here so that we can then figure out, um, how to get this x component. So the way I I found the angle is I looked for this angle because that's gonna equal to that angle. Um, and this angle can be determined by using trigonometry. So if we look at co sign of an angle, we know that CO sign is equal to the adjacent side, divided by the high pot news. So co sign of the angle, which is what we're looking for is the adjacent side is the side that's adjacent or next to. So if this is the angle here, the adjacent side is this 0.7 and then the high pot news was that point groups 0.0.86 To get data by itself, you have to do the co sign in verse on both sides, which cancels that out. But you have to do it to both sides. When you plug that in the calculator, you get 35 points, five degrees, and that's gonna be our angle here. So this both angles, we're gonna be the same again because they're at the same dimensions. So what we're gonna do now is we're going to, um, solved for the, uh, adjacent sides. If I just look at one of these, let's look at this one. This angle here is 35.5 degrees. The magnitude of the force we just calculated to be want 9.127 times 10 to the negative eight. And we're interested in this X component right here. So to figure that out, if I look at it as a right triangle, I can use trigonometry again to find the adjacent side. And so I would just plug in again this co sign, um Fada equation So co sign now theta is going to be 35.5 is equal to the adjacent side, divided by the high pot news, which is 9.127 times 10th and negative eight. Multiply both sides by that value, and I get that the adjacent side is, um, equal to 7.4 three times 10 to the negative eight Newtons. Now that is just one of the X components. But we said it was gonna be two because there's two charges. So all we have to do now is just multiply that by two for both charges. And when we do that, we get 1.4, uh nine times 10 to the negative eighth. Sorry, negative seven Newtons. And that is our final answer. And also we have to add it's going to the right

Hi In the given problem, there is a combination of four charged particles. First of all, this is a positive charge Plus 5.0 Q. Then here this is another identical charge plus 5.0 Q. Then on the line joining them there is a midpoint of these two charges. And from this charge from this mid wind there is another charge that is also positive but Having a magnitude of 3.0 Q. And finally the fourth charge particles, this is negative minus 12 Q. And all these distances are given us B. Each. All these expenses are now as we know, electrical always goes away from the positive charge. So electrical, you do this Plus 5.0 Q will be downward and electrical due to this lower plus 5.0 Q will be upward and these two electric fields will be equal and opposite so we will cancel each other at and this observation point is marked as speak so at point B. Electric fields due to two Plus 5.0 Q charges are equal in magnitude as the distance the same. And the charges also saying so the magnet will be seen, so they are equal in magnitude but opposite in direction. So, net electric field at B. Due to these two charges will be zero. Now the remaining two charges Because of this plus 3.0 Q charge electric field, it is a way from the positive charge And you do this -12q. It is towards the negative charge. Like this. This will be so these are the two electric fields. Let it be even, Let it be E two. So finally, net electric field at this point B will be equal to as these two are opposite in direction, so they will be subtracted. So, first of all, due to this minus 12, you this is K. Q. The magnitude of charge. No need to use a sign as the electrical is a vector country. So this is K 12 Q by distance, which is too deep. The distance of -12 cue from this point, we will become deeply steeped, needs study and minus K trig. You divided by the stance. Again the square. So here it will be electric field at P E P is equal to Okay into 12. You buy for the square. Okay, Into 12. You by four. The square mine escape into three Q by T square. Now this is four. Threes are 12. So finally this is K three cube I. D square minus K three Q by the square. So this comes out to be zero. So there is no net electric field at observation point B. Thank you.

Hello for problems. 16.35 were asked to find the direction and the magnitude of the electric field. We are asked to find this at point P. So the electric field at Point P is just going to be the electric field due to charge one plus the electric field due to charge two. We also know that Charge one and Charge two are equal, but opposite signs. If we use our electric field equation E is equal to K Q over R squared, plugging that in. We can simplify this that the electric field it p is equal to que que all over x plus a quantity squared minus since it's going to be a negative, since the charges are opposite que que all over x minus a quantity squared. Simplifying this out, we get that this is going to be que que times the quantity one over x plus a quantity squared minus one over X minus a quantity square. Here again, what we can do is find the common denominator off these fractions and simplify. Thus, E at point P is just going to be equal to que que all times x minus a quantity squared minus X plus a quantity squared all over X minus a quantity squared times X plus a quantity squared. One more round of simplification for this gives us that E at the point of P is just equal to negative four. Okay, Que a X all over X squared minus a squared quantity squared. Here again, this is just simplification off that fraction. This is our magnitude off our electric force. Notice here that the negative sign very simply means that the field points to the left.


Similar Solved Questions

5 answers
Test: 90 pts possibla 1 Eaf121U L U 540 01 "Von Fal
Test: 90 pts possibla 1 Eaf 1 2 1 U L U 540 01 "Von Fal...
5 answers
Problem 4 (Interpolation Polynomial and Spline function) Let f(z) = e,0 < 1 < 2. a) Find the Lagrange interpolating polynomial to approximate f(x) for the data T1 = 0, T2 = 1 and T3 2 b) Find the quadratic spline to approximate f(z) for the data 11 = 0 T2 = 1 and T3 = 2.Calculate the absolute errors at point 0.5 for the quadratic in- terpolation polynomial in &) and the quadratic spline in b), respectively:
Problem 4 (Interpolation Polynomial and Spline function) Let f(z) = e,0 < 1 < 2. a) Find the Lagrange interpolating polynomial to approximate f(x) for the data T1 = 0, T2 = 1 and T3 2 b) Find the quadratic spline to approximate f(z) for the data 11 = 0 T2 = 1 and T3 = 2. Calculate the absolute...
5 answers
What is the percent vield of Pblz (s) (MW 461.00 g/mole) when 25.00 mL of 0.1240 M KI (166.0 g/mole) solution is combined with 25.00 mL of0.1111 M Pb(NO3l2 (331.22 g/mole) given that 0.3333 g Pblz was recovered: (Hint find the limiting reagent first) 2Klaa) Pb(NO3)2faq) 2KNO3/aq) Pblz(s)
What is the percent vield of Pblz (s) (MW 461.00 g/mole) when 25.00 mL of 0.1240 M KI (166.0 g/mole) solution is combined with 25.00 mL of0.1111 M Pb(NO3l2 (331.22 g/mole) given that 0.3333 g Pblz was recovered: (Hint find the limiting reagent first) 2Klaa) Pb(NO3)2faq) 2KNO3/aq) Pblz(s)...
5 answers
Find all possible rational zeros of813_722-61+8 Write all answers aS reduced fractions, and use "+ to represent the _ symbol.Preview
Find all possible rational zeros of813_722-61+8 Write all answers aS reduced fractions, and use "+ to represent the _ symbol. Preview...
3 answers
(25 pts) Provide syntheses as shown below, starting from benzene and employing any other necessary reagents _ Although not required for full credit, showing intermediates along the synthetic route andlor providing a retrosynthetic analysis does help get partial credit if your answer is not entirely correct (12 pts) Br 22(6) (13 pts)CH3COzH22HO_NHz OH
(25 pts) Provide syntheses as shown below, starting from benzene and employing any other necessary reagents _ Although not required for full credit, showing intermediates along the synthetic route andlor providing a retrosynthetic analysis does help get partial credit if your answer is not entirely ...
5 answers
Pnhoa ojatoocaruon4cos (6oJitmtden
pnhoa ojatoo caruon 4cos ( 6o Jitmtden...
5 answers
Find the consumers' surplus at a price level of p= $110 P=D(x) = 500 - 0. 02x for the price-demand equation below: What is the consumer surplus?
Find the consumers' surplus at a price level of p= $110 P=D(x) = 500 - 0. 02x for the price-demand equation below: What is the consumer surplus?...
5 answers
Using Question 1 18 arrows '8-H show the flow of + in the :Brs following chemical reactioUpload Choose File1
Using Question 1 18 arrows '8-H show the flow of + in the :Brs following chemical reactio Upload Choose File 1...
4 answers
Coune dashboardTima lek 0 59 40Question 3 YcconsueO"uledout 0' 1 80Fc quostionOne of the following statements not correct regarding Sul mechanism?The reaction rate depends on the concentration of onc reactant onlystrong nucleophile is not necessarily neededHc invoives caibocaton intermediateIcis a 1-step reactionPrevious pageNext pageAnnouncementsJump t0
Coune dashboard Tima lek 0 59 40 Question 3 YcconsueO "uledout 0' 1 80 Fc quostion One of the following statements not correct regarding Sul mechanism? The reaction rate depends on the concentration of onc reactant only strong nucleophile is not necessarily needed Hc invoives caibocaton in...
5 answers
Question 3 (6 points) Answer the following questions based on the reaction shown below: HEATWhat is the name of this reaction?2_ What is the name of the missing reagent?Blank # 1Blank # 2N
Question 3 (6 points) Answer the following questions based on the reaction shown below: HEAT What is the name of this reaction? 2_ What is the name of the missing reagent? Blank # 1 Blank # 2 N...
5 answers
SOLUBILITY IN WATER AND IN PHOSPHORIC ACID COLD WATER Ho ALCOHOL STRUCTURE (Yes or n) (Yes no)85% #apd4 (Increase Yes No)n-butylt-butyl cyclohexanol benzylicOXIDATION OF ALCOHOLSCHANGE IN COLOROBSERVATIONSALCOHOLEQUATIONethylIsopropylt-butyl
SOLUBILITY IN WATER AND IN PHOSPHORIC ACID COLD WATER Ho ALCOHOL STRUCTURE (Yes or n) (Yes no) 85% #apd4 (Increase Yes No) n-butyl t-butyl cyclohexanol benzylic OXIDATION OF ALCOHOLS CHANGE IN COLOR OBSERVATIONS ALCOHOL EQUATION ethyl Isopropyl t-butyl...
5 answers
Solve and check the equation: (x2 6x 9)3/4 10 = 17
Solve and check the equation: (x2 6x 9)3/4 10 = 17...
1 answers
Complete each statement using the specified postulate. Multiplication-division law: If $2 x=6,$ then $x=\underline{?}$
Complete each statement using the specified postulate. Multiplication-division law: If $2 x=6,$ then $x=\underline{?}$...
5 answers
Eind ueonsne generated by revolving the curve y = cos 2x about the X-axis,0 Sx s 7/12Dju J Mil % A 0 3 4 8 4 1+#
Eind ueonsne generated by revolving the curve y = cos 2x about the X-axis,0 Sx s 7/12 Dju J Mil % A 0 3 4 8 4 1+#...
5 answers
Given f(x)=x^2 +7x and g(x)=4-x^2 find f+g,f-g,fg and f/g
Given f(x)=x^2 +7x and g(x)=4-x^2 find f+g,f-g,fg and f/g...
5 answers
A friend says, in a profound tone, that light is the only thing we can see, Is your friend correct?
A friend says, in a profound tone, that light is the only thing we can see, Is your friend correct?...
5 answers
Find the direction angle of v for the following wector M#4i+4jWhat is the direction angle of v?(Type an integer oral Idecimal )|
Find the direction angle of v for the following wector M#4i+4j What is the direction angle of v? (Type an integer oral Idecimal )|...
5 answers
Sketch & graph of the function f(z) COs 3( 2) Click the appropriate button based on which pcints you want to graphMiddleAmplitudePeriodShift78/8 .3rta -S3/8 7} 3rr8 3 78Jr/8 T ? 57/8 'tM 7r8Clezr All Draw:
Sketch & graph of the function f(z) COs 3( 2) Click the appropriate button based on which pcints you want to graph Middle Amplitude Period Shift 78/8 .3rta -S3/8 7} 3rr8 3 78 Jr/8 T ? 57/8 'tM 7r8 Clezr All Draw:...

-- 0.021633--